Explain Electromagnetic Induction
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Physics › Explain Electromagnetic Induction
A single loop of wire lies flat on a table. A uniform magnetic field points straight upward (perpendicular to the loop). Which action will definitely induce an EMF in the loop?
Increase the loop’s resistance while keeping $B$, $A$, and $\theta$ constant.
Slide the loop sideways within the same uniform field region without changing its orientation.
Keep the loop fixed and steadily increase the magnetic field strength $B$ with time.
Hold the loop fixed in a constant field and wait longer.
Explanation
This question tests understanding of electromagnetic induction, specifically Faraday's law (changing magnetic flux induces EMF) and Lenz's law (induced current opposes the change). Faraday's law states that a changing magnetic flux through a conductor induces an electromotive force (EMF): ε = -N(ΔΦ/Δt), where N is the number of turns in the coil, Φ is the magnetic flux (Φ = BA cos(θ)), and the rate of change ΔΦ/Δt determines the magnitude of induced EMF—the key requirement is that flux must be changing with time; if the flux is constant (magnet stationary, steady field, constant orientation), then ΔΦ/Δt = 0 and no EMF is induced. When the magnet moves into the coil, the magnetic field strength B at the location of the coil increases, causing the magnetic flux Φ = BA through the coil to change—this changing flux (ΔΦ/Δt ≠ 0) induces an EMF in the coil according to Faraday's law, which drives a current through the circuit if the circuit is complete (galvanometer provides complete circuit). Choice B is correct because it accurately explains that the changing flux is what induces the current, citing Faraday's law. Choice A confuses the presence of a magnetic field with changing magnetic flux—just having a field present (even a strong field) doesn't induce current; what matters is whether the flux through the coil is changing over time, which requires motion, rotation, or varying field strength. To analyze electromagnetic induction scenarios, follow these steps: (1) identify what is changing (magnet position, coil orientation, field strength, loop area), (2) determine if this change affects the magnetic flux Φ through the conductor (Φ = BA cos(θ)), (3) if Φ is changing, then ΔΦ/Δt ≠ 0 and EMF is induced by Faraday's law, (4) the magnitude of induced EMF increases with faster change, more coil turns, and complete circuit allows current I = ε/R, (5) use Lenz's law to predict current direction: induced field opposes the flux change (if flux increasing, induced field points opposite; if flux decreasing, induced field points same direction). Practical applications of electromagnetic induction: generators convert mechanical rotation into electrical power (power plants, wind turbines, bike dynamos), transformers use changing flux in primary coil to induce current in secondary (step up or step down voltage), electric guitar pickups sense vibrating metal strings (changing flux from string motion induces current in coil), induction cooktops create changing field that induces currents in metal pots (heats the pot directly), and metal detectors sense conductive objects by detecting the induced currents (eddy currents) created when the detector's changing field passes through metal.
In a classroom demo, a 200-turn coil is connected to a galvanometer. A bar magnet is moved along the coil’s axis: first pushed into the coil, then held still inside it, then pulled out. During which part(s) will the galvanometer show a nonzero deflection (induced current)?
While the magnet is moving and also while it is held stationary inside the coil
Never, because a permanent magnet cannot induce an EMF without a battery
Only while the magnet is held stationary inside the coil
Only while the magnet is moving into the coil and while it is moving out of the coil
Explanation
This question tests understanding of electromagnetic induction, specifically Faraday's law (changing magnetic flux induces EMF) and the requirement that flux must change for induction to occur. Faraday's law states that a changing magnetic flux through a conductor induces an electromotive force (EMF): ε = -N(ΔΦ/Δt), where N is the number of turns in the coil, Φ is the magnetic flux (Φ = BA cos(θ)), and the rate of change ΔΦ/Δt determines the magnitude of induced EMF—the key requirement is that flux must be changing with time; if the flux is constant (magnet stationary, steady field, constant orientation), then ΔΦ/Δt = 0 and no EMF is induced. When the magnet moves into the coil, the magnetic field strength B at the location of the coil increases, causing the magnetic flux Φ = BA through the coil to change—this changing flux (ΔΦ/Δt ≠ 0) induces an EMF in the coil according to Faraday's law, which drives a current through the circuit if the circuit is complete (galvanometer provides complete circuit); when the magnet is held stationary inside the coil, the flux is constant (ΔΦ/Δt = 0), so no EMF is induced and the galvanometer shows zero current; when the magnet is pulled out, the flux decreases, inducing EMF again but in the opposite direction by Lenz's law. Choice A is correct because it accurately identifies that induction occurs when magnetic flux is changing, not when it's constant. Choice B incorrectly claims current is induced when the magnet is stationary inside the coil, but Faraday's law requires changing flux (ΔΦ/Δt ≠ 0)—when the magnet isn't moving, the flux through the coil is constant, so ΔΦ/Δt = 0 and no EMF is induced, which is why the galvanometer shows zero. To analyze electromagnetic induction scenarios, follow these steps: (1) identify what is changing (magnet position, coil orientation, field strength, loop area), (2) determine if this change affects the magnetic flux Φ through the conductor (Φ = BA cos(θ)), (3) if Φ is changing, then ΔΦ/Δt ≠ 0 and EMF is induced by Faraday's law, (4) the magnitude of induced EMF increases with faster change, more coil turns, and complete circuit allows current I = ε/R, (5) use Lenz's law to predict current direction: induced field opposes the flux change (if flux increasing, induced field points opposite; if flux decreasing, induced field points same direction). Key insight: it's not the mere presence of a magnetic field that induces current, but rather the change in flux—this is why moving a magnet toward a coil induces current (flux increasing), holding it stationary produces no current (flux constant), and moving it away again induces current in the opposite direction (flux decreasing), and why generators work through continuous rotation (flux continuously changing) while a coil sitting in a steady field produces no power.
In a lab, a 200-turn coil is connected to a sensitive galvanometer (forming a closed circuit). A student quickly pushes the north pole of a bar magnet straight into the center of the coil and then holds the magnet completely still inside the coil. Which observation best indicates when electromagnetic induction occurs in this setup (Faraday’s law: $|\varepsilon| = N\left|\Delta\Phi/\Delta t\right|$)?
The galvanometer deflects only after the magnet has stopped moving, because the induced current needs time to build up.
The galvanometer deflects most when the magnet is held still inside the coil because the magnetic field is strongest there.
The galvanometer deflects only while the magnet is moving into the coil, and returns to zero when the magnet is held still.
The galvanometer deflects continuously as long as the magnet remains anywhere near the coil, even if nothing moves.
Explanation
This question tests understanding of electromagnetic induction, specifically when Faraday's law produces an induced EMF (changing magnetic flux) versus when it doesn't (constant flux). Faraday's law states that a changing magnetic flux through a conductor induces an electromotive force (EMF): ε = -N(ΔΦ/Δt), where N is the number of turns in the coil, Φ is the magnetic flux (Φ = BA cos(θ)), and the rate of change ΔΦ/Δt determines the magnitude of induced EMF—the key requirement is that flux must be changing with time; if the flux is constant (magnet stationary), then ΔΦ/Δt = 0 and no EMF is induced. When the magnet moves into the coil, the magnetic field strength B at the location of the coil increases, causing the magnetic flux Φ = BA through the coil to change—this changing flux (ΔΦ/Δt ≠ 0) induces an EMF in the coil according to Faraday's law, which drives a current through the circuit that the galvanometer detects as a deflection. Choice A is correct because it accurately identifies that induction occurs only when magnetic flux is changing (while the magnet is moving), not when it's constant (when the magnet is held still inside the coil). Choice B incorrectly claims the galvanometer deflects most when the magnet is stationary inside the coil, but Faraday's law requires changing flux (ΔΦ/Δt ≠ 0)—when the magnet isn't moving, the flux through the coil is constant, so ΔΦ/Δt = 0 and no EMF is induced, which is why the galvanometer shows zero. To analyze electromagnetic induction scenarios, follow these steps: (1) identify what is changing (magnet position in this case), (2) determine if this change affects the magnetic flux Φ through the conductor (yes, when magnet moves), (3) if Φ is changing, then ΔΦ/Δt ≠ 0 and EMF is induced by Faraday's law, (4) when motion stops, flux becomes constant and induction ceases. Key insight: it's not the mere presence of a magnetic field that induces current, but rather the change in flux—this is why moving a magnet toward a coil induces current (flux increasing), but holding it stationary produces no current (flux constant), regardless of how strong the field is at that position.
A student moves the same bar magnet toward the same coil in two trials. Trial 1: the magnet is pushed in slowly. Trial 2: the magnet is pushed in quickly. The coil has resistance $R$ and is connected to a galvanometer. Which statement best compares the induced current magnitudes, using Faraday’s law $|\varepsilon| = N\left|\Delta\Phi/\Delta t\right|$ and $I=\varepsilon/R$?
Both trials produce the same induced current because the magnet and coil are the same, so $\Delta\Phi$ is the only factor.
Trial 1 produces a larger induced current because slower motion gives the magnetic field more time to act on the coil.
Trial 2 produces a larger induced current because the rate of flux change $|\Delta\Phi/\Delta t|$ is larger.
Neither trial produces current unless the magnet is held stationary inside the coil.
Explanation
This question tests understanding of electromagnetic induction, specifically how the rate of flux change affects the magnitude of induced EMF and current according to Faraday's law. Faraday's law states that the induced EMF magnitude is |ε| = N|ΔΦ/Δt|, where the key factor is the rate of flux change ΔΦ/Δt—faster changes in flux produce larger induced EMF, and since current I = ε/R, this means larger induced current for the same resistance R. When the same magnet moves toward the same coil, the total flux change ΔΦ is the same in both trials (from initial to final position), but in Trial 2 where the magnet moves quickly, this same ΔΦ occurs in less time Δt, making the rate |ΔΦ/Δt| larger—mathematically, if Trial 2 takes half the time, then |ΔΦ/Δt| doubles, doubling the induced EMF and current. Choice A is correct because it accurately explains that faster motion creates larger ΔΦ/Δt and thus larger induced EMF and current, directly applying Faraday's law |ε| = N|ΔΦ/Δt| where larger rate of change produces larger EMF. Choice B incorrectly suggests that slower motion produces larger current because the field has "more time to act," but this reverses the physics—Faraday's law shows that EMF depends on the rate of change, not the duration, and slower motion means smaller ΔΦ/Δt, producing smaller EMF and current. To analyze how motion speed affects induction: (1) recognize that the same motion (same start and end positions) produces the same total flux change ΔΦ, (2) faster motion means this ΔΦ occurs in shorter time Δt, (3) by Faraday's law |ε| = N|ΔΦ/Δt|, smaller Δt means larger |ΔΦ/Δt| and thus larger |ε|, (4) larger EMF drives larger current I = ε/R through the same resistance. This principle explains why generators produce more voltage at higher rotation speeds, why faster-moving magnets in metal detectors induce stronger eddy currents, and why transformers require rapidly changing (AC) current rather than slowly varying DC—in all cases, faster flux changes produce stronger electromagnetic induction effects.
Two coils are placed close together. The primary coil is connected to a battery through a switch (DC source), and the secondary coil is connected to a galvanometer (no battery in the secondary). When the switch in the primary circuit is closed, the galvanometer in the secondary briefly deflects; when the switch is left closed, the galvanometer returns to zero. What best explains the brief deflection in the secondary?
Closing the switch causes the primary current (and magnetic field) to change, changing flux through the secondary and inducing an EMF.
The deflection happens because the secondary coil’s current creates the changing magnetic field in the primary.
A steady current in the primary always induces a steady current in the secondary as long as the coils are near each other.
The secondary needs its own battery, so the brief deflection is just leftover charge in the galvanometer.
Explanation
This question tests understanding of electromagnetic induction between coupled coils, specifically why changing current induces EMF but steady current does not. Faraday's law requires changing magnetic flux for induction—when the switch closes, the primary current jumps from zero to its steady value, creating a changing magnetic field that passes through the secondary coil, inducing an EMF; once the current reaches steady state, the magnetic field becomes constant, flux through the secondary stops changing (ΔΦ/Δt = 0), and no EMF is induced. When the switch in the primary coil closes, the current rises from zero to I = V/R, creating a changing magnetic field that expands outward and passes through the secondary coil—this changing field means changing flux through the secondary (ΔΦ/Δt ≠ 0), which induces an EMF in the secondary coil by Faraday's law, driving current through the galvanometer even though there's no battery in the secondary circuit. Choice A is correct because it accurately identifies that closing the switch causes the primary current and its magnetic field to change from zero to some value, creating changing flux through the secondary that induces EMF—once the current stabilizes, the flux becomes constant and induction ceases. Choice C incorrectly claims that steady current in the primary always induces steady current in the secondary, but Faraday's law requires changing flux (ΔΦ/Δt ≠ 0)—when the primary current is steady (not changing), the magnetic field is constant, flux through secondary is constant (ΔΦ/Δt = 0), and no EMF is induced. To analyze transformer action: (1) changing current in primary creates changing magnetic field, (2) this changing field passes through secondary coil, creating changing flux, (3) by Faraday's law, changing flux induces EMF in secondary, (4) steady current produces steady field and constant flux, so no induction. This explains why transformers only work with AC, not DC: AC provides continuously changing current and flux, while steady DC produces no induction after the initial turn-on transient, and why circuit breakers can create dangerous voltage spikes—rapidly interrupting current causes very large ΔI/Δt and thus large induced voltages.
A single circular loop is connected to a galvanometer. The loop is moved sideways through a region where the magnetic field is uniform and points straight upward. The loop’s plane stays horizontal the whole time (so its area and orientation relative to $B$ do not change). Which statement best predicts what the galvanometer shows while the loop is entirely within the uniform-field region?
A steady deflection, because motion through a magnetic field always induces current
A deflection only if the loop moves faster than a certain threshold speed
A deflection only if the loop is made of iron rather than copper
No deflection, because the magnetic flux through the loop stays constant while fully in uniform $B$
Explanation
This question tests understanding of electromagnetic induction, specifically the requirement for changing flux rather than just motion through a magnetic field. Faraday's law states that a changing magnetic flux through a conductor induces an electromotive force (EMF): ε = -N(ΔΦ/Δt), where Φ = BA cos(θ) is the magnetic flux—crucially, EMF is induced only when flux changes, not merely when a conductor moves. As the loop moves sideways through the uniform field region while staying horizontal, the magnetic field B at the loop's location remains constant (uniform field), the loop's area A remains constant (rigid loop), and the angle θ between the field and loop normal remains constant (both vertical)—therefore, the flux Φ = BA cos(θ) through the loop stays constant. Since the flux is not changing (ΔΦ/Δt = 0) while the loop is entirely within the uniform field, no EMF is induced and no current flows, so the galvanometer shows no deflection. Choice B is correct because it accurately explains that constant flux (even while moving through a field) means no induction—the key insight is that motion alone doesn't guarantee flux change in a uniform field. Choice A incorrectly claims that motion through a magnetic field always induces current, but this confuses motion with flux change—in a uniform field with constant orientation, sideways motion doesn't change the flux through the loop, so no EMF is induced despite the motion. To determine if induction occurs: (1) calculate flux Φ = BA cos(θ) using instantaneous values, (2) check if any factor (B, A, or θ) changes with time, (3) in uniform field with constant loop geometry, sideways motion leaves all factors unchanged, (4) constant flux means ΔΦ/Δt = 0, so no induced EMF or current. Note that the galvanometer would show deflection as the loop enters or exits the field region (flux changing from zero to BA or BA to zero), but not while fully inside the uniform field where flux remains constant—this demonstrates that flux change, not motion itself, drives induction.
A bar magnet’s north pole is pushed straight toward the center of a wire coil connected to a galvanometer. The galvanometer needle deflects to the right. When the same north pole is pulled straight away from the coil at the same speed, what will the galvanometer do?
Show zero deflection because the magnetic field is still present
Deflect to the right with a larger magnitude because the magnet is leaving the coil
Deflect to the right with about the same magnitude because flux depends only on the magnet’s strength
Deflect to the left with about the same magnitude because the flux change reverses sign
Explanation
This question tests understanding of electromagnetic induction, specifically Faraday's law (changing magnetic flux induces EMF) and Lenz's law (induced current opposes the change). Faraday's law states that a changing magnetic flux through a conductor induces an electromotive force (EMF): ε = -N(ΔΦ/Δt), where N is the number of turns in the coil, Φ is the magnetic flux (Φ = BA cos(θ)), and the rate of change ΔΦ/Δt determines the magnitude of induced EMF—the key requirement is that flux must be changing with time; if the flux is constant (magnet stationary, steady field, constant orientation), then ΔΦ/Δt = 0 and no EMF is induced. Lenz's law (the negative sign in Faraday's equation) states that the induced current flows in a direction that creates a magnetic field opposing the change in flux, which is a consequence of energy conservation: work must be done against the induced magnetic force to change the flux. When the magnet moves into the coil, the magnetic field strength B at the location of the coil increases, causing the magnetic flux Φ = BA through the coil to change—this changing flux (ΔΦ/Δt ≠ 0) induces an EMF in the coil according to Faraday's law, which drives a current through the circuit if the circuit is complete (galvanometer provides complete circuit); by Lenz's law, the induced current flows in a direction that creates a magnetic field opposing the incoming magnet to oppose the flux change—this is why you feel resistance when pushing the magnet in, as the induced field tries to push the magnet back out; when the magnet is pulled out, the flux decreases, so the induced current flows in the opposite direction to create a field that tries to maintain the flux (opposing the decrease), resulting in deflection in the opposite direction with similar magnitude if speeds are the same. Choice B is correct because it properly applies Lenz's law to predict that induced current opposes the flux change, correctly predicting the direction reverses while magnitude is about the same for equal speeds. Choice D incorrectly predicts the current direction, getting the opposition backwards: when flux is decreasing (pulling out), Lenz's law requires the induced field to oppose the decrease by pointing in the same direction, which means the induced current must flow in the opposite direction from when flux was increasing. To analyze electromagnetic induction scenarios, follow these steps: (1) identify what is changing (magnet position, coil orientation, field strength, loop area), (2) determine if this change affects the magnetic flux Φ through the conductor (Φ = BA cos(θ)), (3) if Φ is changing, then ΔΦ/Δt ≠ 0 and EMF is induced by Faraday's law, (4) the magnitude of induced EMF increases with faster change, more coil turns, and complete circuit allows current I = ε/R, (5) use Lenz's law to predict current direction: induced field opposes the flux change (if flux increasing, induced field points opposite; if flux decreasing, induced field points same direction). Practical applications of electromagnetic induction: generators convert mechanical rotation into electrical power (power plants, wind turbines, bike dynamos), transformers use changing flux in primary coil to induce current in secondary (step up or step down voltage), electric guitar pickups sense vibrating metal strings (changing flux from string motion induces current in coil), induction cooktops create changing field that induces currents in metal pots (heats the pot directly), and metal detectors sense conductive objects by detecting the induced currents (eddy currents) created when the detector's changing field passes through metal.
A student builds a simple generator: a rectangular coil rotates at constant speed between the poles of a magnet. The magnetic field is uniform, and the coil’s area stays constant. Which change is directly responsible for the induced EMF in the rotating coil?
The current in the coil creates the external magnetic field that causes the flux change.
The coil’s resistance changes as it rotates.
The angle $\theta$ between the magnetic field and the coil’s normal changes, so the flux $\Phi = BA\cos(\theta)$ changes with time.
The magnetic field disappears whenever the coil is parallel to the field.
Explanation
This question tests understanding of electromagnetic induction, specifically Faraday's law (changing magnetic flux induces EMF) and Lenz's law (induced current opposes the change). Faraday's law states that a changing magnetic flux through a conductor induces an electromotive force (EMF): ε = -N(ΔΦ/Δt), where N is the number of turns in the coil, Φ is the magnetic flux (Φ = BA cos(θ)), and the rate of change ΔΦ/Δt determines the magnitude of induced EMF—the key requirement is that flux must be changing with time; if the flux is constant (magnet stationary, steady field, constant orientation), then ΔΦ/Δt = 0 and no EMF is induced. As the coil rotates in the magnetic field, the angle θ between the field and the normal to the coil changes continuously, causing flux Φ = BA cos(θ) to change from maximum (Φ = BA when θ = 0°, coil face perpendicular to field) to zero (Φ = 0 when θ = 90°, coil face parallel to field) and back—this continuous flux change induces a continuously varying EMF that alternates in direction, producing alternating current (AC). Choice B is correct because it accurately explains that the changing flux is what induces the current, citing Faraday's law. Choice C confuses the presence of a magnetic field with changing magnetic flux—just having a field present (even a strong field) doesn't induce current; what matters is whether the flux through the coil is changing over time, which requires motion, rotation, or varying field strength. To analyze electromagnetic induction scenarios, follow these steps: (1) identify what is changing (magnet position, coil orientation, field strength, loop area), (2) determine if this change affects the magnetic flux Φ through the conductor (Φ = BA cos(θ)), (3) if Φ is changing, then ΔΦ/Δt ≠ 0 and EMF is induced by Faraday's law, (4) the magnitude of induced EMF increases with faster change, more coil turns, and complete circuit allows current I = ε/R, (5) use Lenz's law to predict current direction: induced field opposes the flux change (if flux increasing, induced field points opposite; if flux decreasing, induced field points same direction). Practical applications of electromagnetic induction: generators convert mechanical rotation into electrical power (power plants, wind turbines, bike dynamos), transformers use changing flux in primary coil to induce current in secondary (step up or step down voltage), electric guitar pickups sense vibrating metal strings (changing flux from string motion induces current in coil), induction cooktops create changing field that induces currents in metal pots (heats the pot directly), and metal detectors sense conductive objects by detecting the induced currents (eddy currents) created when the detector's changing field passes through metal.
A conducting loop is connected to a galvanometer and placed in a region where a uniform magnetic field points out of the page. The field strength is then increased steadily (so $B$ increases with time). According to Lenz’s law, what is the direction of the induced current in the loop (viewed facing the page)?
Clockwise, so the loop’s induced field points into the page to oppose the increase in outward flux.
Counterclockwise, so the loop’s induced field points out of the page to oppose the increase in outward flux.
No current, because induction requires the loop to move through the field.
Clockwise, because induced current always follows the external magnetic field direction.
Explanation
This question tests understanding of electromagnetic induction, specifically applying Lenz's law to determine induced current direction when external magnetic flux is increasing. Lenz's law states that the induced current flows in a direction that creates a magnetic field opposing the change in flux—if the external flux is increasing, the induced field must point opposite to the external field to oppose this increase, maintaining energy conservation by requiring work to be done against the induced field. When the uniform field pointing out of the page increases in strength, the outward flux through the loop increases, and by Lenz's law, the loop must produce an induced magnetic field pointing into the page to oppose this increase—using the right-hand rule (curl fingers in current direction, thumb points in field direction), a clockwise current produces a field into the page. Choice A is correct because it properly applies Lenz's law: to oppose the increase in outward flux, the induced field must point into the page, which requires clockwise current by the right-hand rule. Choice B incorrectly predicts counterclockwise current, which would create an induced field out of the page—this would aid rather than oppose the flux increase, violating Lenz's law and energy conservation by creating a runaway effect where the induced field amplifies the change. To determine induced current direction: (1) identify the flux change (here, outward flux is increasing), (2) apply Lenz's law—induced field must oppose the change, so if outward flux is increasing, induced field points inward, (3) use right-hand rule to find current direction that produces this induced field (clockwise produces inward field), (4) verify this opposes the change as required. This principle ensures energy conservation in all electromagnetic induction: the induced effects always oppose the cause, which is why motors are hard to turn when loaded (induced EMF opposes applied voltage), why dropping a magnet through a copper tube slows its fall (induced currents create opposing fields), and why transformers require input power to produce output power—the induced effects cannot create free energy by aiding the change.
A wire loop is placed in a uniform magnetic field $B$ that points perpendicular to the loop. The field strength is then increased steadily over time while the loop remains stationary and the circuit is closed. What is the best explanation for why an induced current appears in the loop?
The induced current appears because the loop’s resistance decreases when a magnetic field is present
The magnetic flux $\Phi = BA\cos(\theta)$ through the loop is changing with time, so an EMF is induced
Any magnetic field automatically causes current to flow in a closed loop
The induced current appears because the loop’s area must be changing when the field changes
Explanation
This question tests understanding of electromagnetic induction, specifically how changing magnetic field strength induces EMF even when the conductor remains stationary. Faraday's law states that a changing magnetic flux through a conductor induces an electromotive force (EMF): ε = -N(ΔΦ/Δt), where the magnetic flux Φ = BA cos(θ) depends on field strength B, loop area A, and angle θ—any change in these parameters that changes Φ will induce EMF. In this scenario, the loop is stationary with fixed area A, and the field remains perpendicular (θ = 0°, so cos(θ) = 1), but the field strength B is increasing steadily over time—this means the flux Φ = BA through the loop is increasing, giving ΔΦ/Δt > 0, which induces an EMF in the loop according to Faraday's law. By Lenz's law, the induced current flows in a direction that creates a magnetic field opposing the flux increase—since the external field is increasing upward through the loop, the induced current creates a downward field to oppose this change. Choice A is correct because it accurately identifies that the changing flux (due to changing B in Φ = BA cos(θ)) is what induces the current, properly citing the flux formula and recognizing that time-varying flux is the key requirement. Choice B confuses the presence of a magnetic field with changing magnetic flux—just having a field present (even a strong field) doesn't induce current; what matters is whether the flux through the coil is changing over time, which in this case it is because B is increasing even though the loop is stationary. To analyze electromagnetic induction scenarios: (1) identify all factors in flux Φ = BA cos(θ), (2) determine which are changing with time (here, B is increasing), (3) if any factor changes such that Φ changes, then ΔΦ/Δt ≠ 0 and EMF is induced, (4) the induced current direction follows Lenz's law to oppose the flux change. This principle is used in many applications: variable inductors change B to control inductance, magnetic field sensors detect changing fields by measuring induced currents, and eddy current brakes use changing fields to induce opposing currents that create braking forces.