Apply Physics to Collision Design

Help Questions

Physics › Apply Physics to Collision Design

Questions 1 - 10
1

A playground surface must reduce injury risk for a child falling from 2.0 m. Assume the child’s speed on impact is $v = \sqrt{2gh}$ and the child’s mass is 25 kg. The safety goal is to keep the average deceleration below $50\ g$. Using $a_{avg} = v^2/(2d)$ (from work-energy/kinematics), what minimum stopping distance $d$ should the surface provide?

$d \ge 0.20 , \text{m}$

$d \ge 0.020 , \text{m}$

$d \ge 0.080 , \text{m}$

$d \ge 0.040 , \text{m}$

Explanation

This question tests understanding of applying physics principles—specifically work-energy relationships—to design collision protection systems like playground surfaces. The kinetic energy of a moving object ($KE = \frac{1}{2} m v^2$) must be absorbed during a collision through work done by stopping forces: $W = F d$, so for a fixed amount of kinetic energy to absorb, increasing the deformation distance $d$ allows smaller forces $F$ to do the necessary work—this is why crushable materials, compressible padding, and extendable restraints improve safety by spreading energy absorption over longer distances. For padding/helmets: Protective padding like in helmets or sports equipment extends the collision time by compressing during impact—for example, if a 25 kg child decelerates from 6.26 m/s to 0 in a fall, the momentum change is $\Delta p = (25 , \text{kg})(6.26 , \text{m/s}) \approx 156.5 , \text{kg} \cdot \text{m/s}$. Without padding ($\Delta t \approx 0.005 , \text{s}$), $F_\text{avg}$ would be high, but with surface compression over 0.040 m, using $a = v^2/(2d) \approx 490 , \text{m/s}^2$ ($50 g$), $F_\text{avg} = m a \approx 12,250 , \text{N}$ distributed appropriately. Choice B is correct because it uses work-energy relationship showing that increasing deformation distance reduces force for the same energy absorption, with $d_\text{min} = v^2/(2 a_\text{max}) \approx 0.040 , \text{m}$. Choice A suggests minimizing deformation distance to reduce forces, when actually the work-energy relationship $W = F d$ shows that for fixed kinetic energy to absorb, larger deformation distance $d$ allows smaller forces $F$—this is why crushable barriers are safer than rigid walls. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem $F_\text{avg} = \Delta p / \Delta t$ shows that for a given momentum change (stopping an object), extending the collision time $\Delta t$ reduces the average force $F_\text{avg}$—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle $W = F d$ shows that for a fixed kinetic energy to absorb ($KE = \frac{1}{2} m v^2$), increasing the deformation distance $d$ reduces the required force $F$—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. Combining both approaches (extend time AND distance) provides maximum force reduction: design features that progressively deform over time and space, keeping forces well below injury thresholds throughout the collision event.

2

A package designer is deciding between two cushioning options for a 10 kg instrument that may experience a 1.0 m drop. Option 1 provides 2.0 cm maximum compression before bottoming out; Option 2 provides 8.0 cm maximum compression. Ignoring rebound, which option better reduces the average stopping force on the instrument and why (use $\tfrac12 mv^2 = F_{avg} d$)?

Either option, because the instrument’s momentum change is the same so force cannot be changed

Option 2, because larger $d$ allows the same kinetic energy to be removed with smaller average force

Option 1, because a stiffer cushion prevents deformation and therefore reduces energy transfer

Option 1, because smaller $d$ makes the instrument stop sooner so it experiences less impulse

Explanation

This question tests understanding of applying physics principles—specifically work-energy relationships—to design collision protection systems like packaging. The kinetic energy of a moving object (KE = ½mv²) must be absorbed during a collision through work done by stopping forces: W = Fd, so for a fixed amount of kinetic energy to absorb, increasing the deformation distance d allows smaller forces F to do the necessary work—this is why crushable materials, compressible padding, and extendable restraints improve safety by spreading energy absorption over longer distances. For packaging: To protect a 10 kg fragile item in a fall from 1 m height (impact velocity v = √(2gh) ≈ 4.43 m/s), the kinetic energy at impact is KE ≈ 98 J. If rigid packaging allows only 2 cm deformation, the average force is F = KE/d = 98/0.02 = 4900 N which might damage the item, but if foam padding allows 8 cm deformation, F = 98/0.08 = 1225 N—a 4-fold reduction making survival likely. Choice B is correct because it uses work-energy relationship showing that increasing deformation distance reduces force for the same energy absorption. Choice C incorrectly suggests using stiffer, more rigid materials, when actually rigid materials cause shorter collision times and higher peak forces—safety requires materials that deform or compress to extend Δt and increase deformation distance d, which is why crumple zones crumple and padding compresses rather than staying rigid. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem F_avg = Δp/Δt shows that for a given momentum change (stopping an object), extending the collision time Δt reduces the average force F_avg—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle W = Fd shows that for a fixed kinetic energy to absorb (KE = ½mv²), increasing the deformation distance d reduces the required force F—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. Remember that effective collision protection typically involves: (a) materials that deform plastically (crush permanently) rather than elastically (bounce back), because plastic deformation maximizes energy absorption, (b) progressive resistance that increases gradually with deformation rather than sudden stiffening (avoids peak force spikes), (c) distribution of forces over large surface areas to reduce local pressure (airbags spread over chest, helmets over skull), and (d) multi-stage systems where soft initial padding handles minor impacts comfortably while firmer secondary layers engage for severe impacts—the goal is always to extend Δt and increase d while keeping F below injury thresholds at all times during the collision.

3

A new airbag is being evaluated. The engineering goal is to reduce chest injury by lowering pressure on the chest while also reducing average force. Which modification best addresses pressure reduction specifically (not just total force reduction), and what physics idea supports it?

Increase the contact area between airbag and chest, reducing pressure because $\text{pressure} = F/A$

Use a thinner airbag so the chest stops over a shorter time, reducing force by $F_{avg} = \Delta p/\Delta t$

Use a more elastic airbag that rebounds the occupant, increasing final speed to reduce momentum change

Replace the airbag with a rigid panel so the stopping distance is minimized to reduce work done

Explanation

This question tests understanding of applying physics principles—specifically impulse-momentum and work-energy relationships—to design collision protection systems like airbags. The impulse-momentum theorem (J = Δp = F_avg × Δt) shows that for a given momentum change (stopping an object: Δp = mv), the average force experienced is inversely proportional to the collision time: F_avg = Δp/Δt, which means extending the collision time Δt reduces the average force F_avg—this is the fundamental principle behind crumple zones, airbags, padding, and other safety features that increase the time over which an object comes to rest. For airbag systems: Airbags inflate to create a large, soft surface that extends collision time as the occupant compresses the air-filled bag, and distributes the impact force over the chest and head rather than concentrating it on the steering wheel or dashboard. For a 70 kg occupant stopping from 15 m/s (Δp = 1050 kg⋅m/s), if the airbag extends collision time to 0.08 s, F_avg = 1050/0.08 ≈ 13,000 N distributed over ~0.3 m² of airbag surface, compared to perhaps 20,000+ N concentrated on a small steering wheel impact area without the airbag. Choice A is correct because it properly identifies that distributing force over larger area reduces stress/pressure. Choice B incorrectly suggests using stiffer, more rigid materials, when actually rigid materials cause shorter collision times and higher peak forces—safety requires materials that deform or compress to extend Δt and increase deformation distance d, which is why crumple zones crumple and padding compresses rather than staying rigid. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem F_avg = Δp/Δt shows that for a given momentum change (stopping an object), extending the collision time Δt reduces the average force F_avg—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle W = Fd shows that for a fixed kinetic energy to absorb (KE = ½mv²), increasing the deformation distance d reduces the required force F—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. Combining both approaches (extend time AND distance) provides maximum force reduction: design features that progressively deform over time and space, keeping forces well below injury thresholds throughout the collision event.

4

A shipping company must design packaging for a 2.0 kg fragile instrument that may be dropped from 1.5 m. The package must keep the average stopping force on the instrument below $400\ \text{N}$. Assume the instrument starts from rest, falls freely, and is brought to rest by compressing foam of thickness $d$ with approximately constant stopping force. Use $v = \sqrt{2gh}$ with $g=9.8\ \text{m/s}^2$ and work-energy $KE = Fd$ (take $F$ as the average stopping force). What minimum foam compression distance $d$ is needed?

$0.074\ \text{m}$

$0.74\ \text{m}$

$0.15\ \text{m}$

$0.015\ \text{m}$

Explanation

This question tests understanding of applying physics principles—specifically impulse-momentum and work-energy relationships—to design collision protection systems. The kinetic energy of a moving object (KE = ½mv²) must be absorbed during a collision through work done by stopping forces: W = Fd, so for a fixed amount of kinetic energy to absorb, increasing the deformation distance d allows smaller forces F to do the necessary work—this is why crushable materials, compressible padding, and extendable restraints improve safety by spreading energy absorption over longer distances. For packaging: To protect a 2 kg fragile item in a fall from 1 m height (impact velocity v = √(2gh) = √20 ≈ 4.5 m/s), the kinetic energy at impact is KE = ½(2)(4.5)² ≈ 20 J. If rigid packaging allows only 1 cm deformation, the average force is F = KE/d = 20/0.01 = 2000 N which would crush the item, but if foam padding allows 10 cm deformation, F = 20/0.10 = 200 N—a 10-fold reduction making survival likely. Choice B is correct because it uses work-energy relationship showing that increasing deformation distance reduces force for the same energy absorption. Choice A suggests minimizing deformation distance to reduce forces, when actually the work-energy relationship W = Fd shows that for fixed kinetic energy to absorb, larger deformation distance d allows smaller forces F—this is why crushable barriers are safer than rigid walls. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem F_avg = Δp/Δt shows that for a given momentum change (stopping an object), extending the collision time Δt reduces the average force F_avg—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle W = Fd shows that for a fixed kinetic energy to absorb (KE = ½mv²), increasing the deformation distance d reduces the required force F—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. The design process: (1) determine the momentum change Δp = mv or energy to absorb KE = ½mv², (2) identify safety threshold F_max (e.g., 5000 N), (3) calculate minimum time needed: Δt_min = Δp/F_max or minimum distance: d_min = KE/F_max, (4) design features that provide at least this much time or distance through controlled deformation, and (5) verify that peak forces stay below thresholds using F = Δp/Δt and W = Fd.

5

A helmet designer must reduce concussion risk for a cyclist whose head (effective mass 5.0 kg) could strike the ground at 6.0 m/s. Safety criteria: keep average deceleration below 100 g (where $1g = 9.8\ \text{m/s}^2$). Using $a = \Delta v/\Delta t$ and $F = ma$, which design change most directly helps meet the 100 g criterion by reducing the peak/average force during the collision?

To minimize injury risk, which feature should be incorporated?

Use a more elastic liner that bounces back strongly to return energy to the head

Use a stiffer outer shell so the head stops in a shorter time to prevent helmet deformation

Add a thicker foam liner that compresses to increase stopping time and stopping distance

Reduce the helmet’s surface area in contact with the head to concentrate the force on a smaller region

Explanation

This question tests understanding of applying physics principles—specifically impulse-momentum and work-energy relationships—to design collision protection systems. The impulse-momentum theorem (J = Δp = F_avg × Δt) shows that for a given momentum change (stopping an object: Δp = mv), the average force experienced is inversely proportional to the collision time: F_avg = Δp/Δt, which means extending the collision time Δt reduces the average force F_avg—this is the fundamental principle behind crumple zones, airbags, padding, and other safety features that increase the time over which an object comes to rest. For padding/helmets: Protective padding like in helmets or sports equipment extends the collision time by compressing during impact—for example, if a 5 kg helmet and head decelerate from 5 m/s to 0 in a fall, the momentum change is Δp = (5 kg)(5 m/s) = 25 kg⋅m/s. Without padding (Δt ≈ 0.005 s), F_avg = 25/0.005 = 5000 N, but with 2 cm of foam padding that compresses during impact (Δt ≈ 0.02 s), F_avg = 25/0.02 = 1250 N—a factor of 4 reduction that could prevent skull fracture. Choice B is correct because it applies impulse-momentum theorem showing that extending collision time reduces force for the same momentum change, with thicker foam increasing Δt to keep a below 100g. Choice C confuses elastic bouncing with energy absorption, suggesting materials that bounce back are best for protection, when actually plastic deformation (permanent crushing that doesn't bounce) absorbs the most energy and is ideal for one-time protection like vehicle crashes—elastic materials store and release energy, which can cause secondary impacts. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem F_avg = Δp/Δt shows that for a given momentum change (stopping an object), extending the collision time Δt reduces the average force F_avg—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle W = Fd shows that for a fixed kinetic energy to absorb (KE = ½mv²), increasing the deformation distance d reduces the required force F—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. Remember that effective collision protection typically involves: (a) materials that deform plastically (crush permanently) rather than elastically (bounce back), because plastic deformation maximizes energy absorption, (b) progressive resistance that increases gradually with deformation rather than sudden stiffening (avoids peak force spikes), (c) distribution of forces over large surface areas to reduce local pressure (airbags spread over chest, helmets over skull), and (d) multi-stage systems where soft initial padding handles minor impacts comfortably while firmer secondary layers engage for severe impacts—the goal is always to extend Δt and increase d while keeping F below injury thresholds at all times during the collision.

6

A car bumper insert is being chosen for a low-speed crash (parking collision). The design goal is to maximize energy absorption (reduce rebound) while keeping repair costs low, and it only needs to work once in a severe impact. Which material behavior is most appropriate for reducing forces on occupants by dissipating kinetic energy rather than returning it?

Which choice best matches the physics goal?

A plastically deforming structure that crumples in a controlled way

A highly elastic material that stores and returns most energy (high bounce)

A rigid steel block that prevents deformation so the car keeps its shape

A brittle material that cracks suddenly, because breaking means the force is always small

Explanation

This question tests understanding of applying physics principles—specifically work-energy relationships—to design collision protection systems. The kinetic energy of a moving object (KE = ½mv²) must be absorbed during a collision through work done by stopping forces: W = Fd, so for a fixed amount of kinetic energy to absorb, increasing the deformation distance d allows smaller forces F to do the necessary work—this is why crushable materials, compressible padding, and extendable restraints improve safety by spreading energy absorption over longer distances. For vehicle crumple zones: In a vehicle collision, the front of the car is designed to crumple and deform over a distance of 0.5-1 m during impact, which extends the collision time from perhaps 0.01 s (rigid car) to 0.1 s (with crumple zone)—using F_avg = Δp/Δt, this 10-fold increase in collision time reduces the average force on the vehicle (and indirectly on occupants) by a factor of 10, from potentially unsurvivable levels to forces the passenger compartment structure can withstand. Simultaneously, the deformation distance of 0.5-1 m allows the kinetic energy to be absorbed through work (W = Fd) with smaller peak forces, as the crumpling material does work against the collision force. Choice C is correct because it uses work-energy relationship showing that increasing deformation distance reduces force for the same energy absorption, with plastic deformation dissipating energy through permanent crushing rather than elastic rebound. Choice D incorrectly suggests using stiffer, more rigid materials, when actually rigid materials cause shorter collision times and higher peak forces—safety requires materials that deform or compress to extend Δt and increase deformation distance d, which is why crumple zones crumple and padding compresses rather than staying rigid. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem F_avg = Δp/Δt shows that for a given momentum change (stopping an object), extending the collision time Δt reduces the average force F_avg—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle W = Fd shows that for a fixed kinetic energy to absorb (KE = ½mv²), increasing the deformation distance d reduces the required force F—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. Remember that effective collision protection typically involves: (a) materials that deform plastically (crush permanently) rather than elastically (bounce back), because plastic deformation maximizes energy absorption, (b) progressive resistance that increases gradually with deformation rather than sudden stiffening (avoids peak force spikes), (c) distribution of forces over large surface areas to reduce local pressure (airbags spread over chest, helmets over skull), and (d) multi-stage systems where soft initial padding handles minor impacts comfortably while firmer secondary layers engage for severe impacts—the goal is always to extend Δt and increase d while keeping F below injury thresholds at all times during the collision.

7

A car safety team is designing a front crumple zone to protect a driver in a 50 km/h (13.9 m/s) frontal crash. Assume the driver’s effective mass is 75 kg and they must be brought from 13.9 m/s to 0 m/s. To keep the average force on the driver below 5000 N (injury threshold), what minimum stopping time $\Delta t$ must the restraint system (seat belt + airbag + vehicle deformation) provide? Use impulse-momentum: $F_{\text{avg}} = \Delta p/\Delta t$ with $\Delta p = mv$.

For this design problem, what is the minimum $\Delta t$ needed?

$0.021\ \text{s}$

$0.10\ \text{s}$

$1.05\ \text{s}$

$0.21\ \text{s}$

Explanation

This question tests understanding of applying physics principles—specifically impulse-momentum relationships—to design collision protection systems. The impulse-momentum theorem (J = Δp = F_avg × Δt) shows that for a given momentum change (stopping an object: Δp = mv), the average force experienced is inversely proportional to the collision time: F_avg = Δp/Δt, which means extending the collision time Δt reduces the average force F_avg—this is the fundamental principle behind crumple zones, airbags, padding, and other safety features that increase the time over which an object comes to rest. For vehicle crumple zones: In a vehicle collision, the front of the car is designed to crumple and deform over a distance of 0.5-1 m during impact, which extends the collision time from perhaps 0.01 s (rigid car) to 0.1 s (with crumple zone)—using F_avg = Δp/Δt, this 10-fold increase in collision time reduces the average force on the vehicle (and indirectly on occupants) by a factor of 10, from potentially unsurvivable levels to forces the passenger compartment structure can withstand. Choice C is correct because it applies impulse-momentum theorem showing that extending collision time reduces force for the same momentum change, with Δt_min = (75 kg × 13.9 m/s) / 5000 N ≈ 0.21 s to keep F_avg below 5000 N. Choice D incorrectly suggests a much longer time, but this overestimates Δt by misapplying the formula, perhaps using v instead of Δp or forgetting to convert units, leading to an unrealistic design that wouldn't fit practical constraints. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem F_avg = Δp/Δt shows that for a given momentum change (stopping an object), extending the collision time Δt reduces the average force F_avg—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle W = Fd shows that for a fixed kinetic energy to absorb (KE = ½mv²), increasing the deformation distance d reduces the required force F—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. Combining both approaches (extend time AND distance) provides maximum force reduction: design features that progressively deform over time and space, keeping forces well below injury thresholds throughout the collision event.

8

A playground surface must reduce injury risk from a child falling from 2.0 m. Standards require keeping average deceleration below about 50 g for this fall. Assume the child’s impact speed is $v = \sqrt{2gh}$ and the surface provides a stopping distance $d$ with roughly constant deceleration. Which minimum stopping distance is closest to meeting the 50 g criterion? (Use $v^2 = 2ad$ and $a_{\max} = 50g$.) What is the minimum $d$?

$0.40\ \text{m}$ (40 cm)

$0.040\ \text{m}$ (4.0 cm)

$0.020\ \text{m}$ (2.0 cm)

$0.008\ \text{m}$ (0.8 cm)

Explanation

This question tests understanding of applying physics principles—specifically work-energy relationships—to design collision protection systems. The kinetic energy of a moving object ($KE = \frac{1}{2} m v^2$) must be absorbed during a collision through work done by stopping forces: $W = F d$, so for a fixed amount of kinetic energy to absorb, increasing the deformation distance $d$ allows smaller forces $F$ to do the necessary work—this is why crushable materials, compressible padding, and extendable restraints improve safety by spreading energy absorption over longer distances. For padding/helmets: Protective padding like in helmets or sports equipment extends the collision time by compressing during impact—for example, if a 5 kg helmet and head decelerate from 5 m/s to 0 in a fall, the momentum change is $\Delta p = (5 , \text{kg})(5 , \text{m/s}) = 25 , \text{kg} \cdot \text{m/s}$. Without padding ($\Delta t \approx 0.005 , \text{s}$), $F_\text{avg} = 25 / 0.005 = 5000 , \text{N}$, but with 2 cm of foam padding that compresses during impact ($\Delta t \approx 0.02 , \text{s}$), $F_\text{avg} = 25 / 0.02 = 1250 , \text{N}$—a factor of 4 reduction that could prevent skull fracture. Choice C is correct because it uses work-energy relationship showing that increasing deformation distance reduces force for the same energy absorption, with $d_\text{min} = v^2 / (2 a_\text{max}) \approx(\sqrt{2 g h})^2 / (2 \times 50 g) \approx 0.040 , \text{m}$. Choice B makes a calculation error applying $F = \Delta p / \Delta t$, using wrong $\Delta t$ value or perhaps confusing with impulse, leading to incorrect force estimate that doesn't meet the safety criterion. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem $F_\text{avg} = \Delta p / \Delta t$ shows that for a given momentum change (stopping an object), extending the collision time $\Delta t$ reduces the average force $F_\text{avg}$—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle $W = F d$ shows that for a fixed kinetic energy to absorb ($KE = \frac{1}{2} m v^2$), increasing the deformation distance $d$ reduces the required force $F$—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. The design process: (1) determine the momentum change $\Delta p = m v$ or energy to absorb $KE = \frac{1}{2} m v^2$, (2) identify safety threshold $F_\text{max}$ (e.g., 5000 N), (3) calculate minimum time needed: $\Delta t_\text{min} = \Delta p / F_\text{max}$ or minimum distance: $d_\text{min} = KE / F_\text{max}$, (4) design features that provide at least this much time or distance through controlled deformation, and (5) verify that peak forces stay below thresholds using $F = \Delta p / \Delta t$ and $W = F d$.

9

A car safety team is designing an airbag system. In a 40 km/h (11.1 m/s) frontal crash, a 70 kg occupant must be brought to rest by the restraint system. To reduce injury risk, the design criterion is to keep the average force on the occupant below 5000 N. Assuming the occupant’s momentum changes from $mv$ to 0, what minimum stopping time $\Delta t$ must the airbag + seat belt system provide (treating the force as approximately constant)? Use $F_{avg} = \Delta p/\Delta t$.

$\Delta t \ge 0.156\ \text{s}$

$\Delta t \ge 0.78\ \text{s}$

$\Delta t \ge 0.016\ \text{s}$

$\Delta t \ge 0.078\ \text{s}$

Explanation

This question tests understanding of applying physics principles—specifically impulse-momentum relationships—to design collision protection systems like airbags. The impulse-momentum theorem (J = Δp = F_avg × Δt) shows that for a given momentum change (stopping an object: Δp = mv), the average force experienced is inversely proportional to the collision time: F_avg = Δp/Δt, which means extending the collision time Δt reduces the average force F_avg—this is the fundamental principle behind crumple zones, airbags, padding, and other safety features that increase the time over which an object comes to rest. For airbag systems: Airbags inflate to create a large, soft surface that extends collision time as the occupant compresses the air-filled bag, and distributes the impact force over the chest and head rather than concentrating it on the steering wheel or dashboard. For a 70 kg occupant stopping from 11.1 m/s (Δp = 777 kg⋅m/s), if the airbag extends collision time to 0.156 s, F_avg = 777/0.156 ≈ 5000 N distributed over ~0.3 m² of airbag surface, compared to perhaps 20,000+ N concentrated on a small steering wheel impact area without the airbag. Choice C is correct because it applies impulse-momentum theorem showing that extending collision time reduces force for the same momentum change. Choice B incorrectly suggests a shorter time, but actually the impulse-momentum relationship F = Δp/Δt shows that for fixed Δp, smaller Δt increases F_avg—this is why rigid structures are more dangerous, causing higher forces through shorter collision times. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem F_avg = Δp/Δt shows that for a given momentum change (stopping an object), extending the collision time Δt reduces the average force F_avg—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle W = Fd shows that for a fixed kinetic energy to absorb (KE = ½mv²), increasing the deformation distance d reduces the required force F—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. Combining both approaches (extend time AND distance) provides maximum force reduction: design features that progressively deform over time and space, keeping forces well below injury thresholds throughout the collision event.

10

A bicycle helmet is being redesigned to reduce concussion risk. During a test, a 5.0 kg headform impacts at 6.0 m/s and is brought to rest. The helmet must keep average deceleration below $100\ g$ (where $1\ g = 9.8\ \text{m/s}^2$). Using $a_{avg} = \Delta v/\Delta t$, what minimum impact duration $\Delta t$ should the helmet provide?

$\Delta t \ge 0.061\ \text{s}$

$\Delta t \ge 0.0016\ \text{s}$

$\Delta t \ge 0.16\ \text{s}$

$\Delta t \ge 0.0061\ \text{s}$

Explanation

This question tests understanding of applying physics principles—specifically impulse-momentum relationships—to design collision protection systems like helmets. The impulse-momentum theorem (J = Δp = F_avg × Δt) shows that for a given momentum change (stopping an object: Δp = mv), the average force experienced is inversely proportional to the collision time: F_avg = Δp/Δt, which means extending the collision time Δt reduces the average force F_avg—this is the fundamental principle behind crumple zones, airbags, padding, and other safety features that increase the time over which an object comes to rest. For padding/helmets: Protective padding like in helmets or sports equipment extends the collision time by compressing during impact—for example, if a 5 kg helmet and head decelerate from 6 m/s to 0 in a fall, the momentum change is Δp = (5 kg)(6 m/s) = 30 kg⋅m/s. Without padding (Δt ≈ 0.001 s), F_avg = 30/0.001 = 30,000 N, but with foam padding that compresses during impact (Δt ≈ 0.0061 s), F_avg = 30/0.0061 ≈ 4900 N (corresponding to a= F/m =980 m/s²=100g)—a significant reduction that could prevent concussion. Choice A is correct because it properly calculates the required time to keep forces below safety threshold using F=Δp/Δt, since Δt = Δv / a_max =6/980≈0.0061 s. Choice B confuses the calculation by using an incorrect Δt value, perhaps forgetting to use a_max=980 m/s² or misapplying Δv, leading to an overestimate that doesn't meet the safety criterion of below 100g. When designing collision protection systems, apply two key physics principles: (1) Impulse-momentum theorem F_avg = Δp/Δt shows that for a given momentum change (stopping an object), extending the collision time Δt reduces the average force F_avg—achieve this through crumple zones, padding compression, airbag deflation, or seat belt stretching; (2) Work-energy principle W = Fd shows that for a fixed kinetic energy to absorb (KE = ½mv²), increasing the deformation distance d reduces the required force F—achieve this through crushable materials, thick padding, or structures designed to fold/compress over longer distances. Remember that effective collision protection typically involves: (a) materials that deform plastically (crush permanently) rather than elastically (bounce back), because plastic deformation maximizes energy absorption, (b) progressive resistance that increases gradually with deformation rather than sudden stiffening (avoids peak force spikes), (c) distribution of forces over large surface areas to reduce local pressure (airbags spread over chest, helmets over skull), and (d) multi-stage systems where soft initial padding handles minor impacts comfortably while firmer secondary layers engage for severe impacts—the goal is always to extend Δt and increase d while keeping F below injury thresholds at all times during the collision.

Page 1 of 4