Compare Gravitational and Electric Forces - Physics
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What is the quantitative ratio $\frac{F_e}{F_g}$ for two particles separated by the same $r$?
What is the quantitative ratio $\frac{F_e}{F_g}$ for two particles separated by the same $r$?
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$\frac{F_e}{F_g}=\frac{k|q_1q_2|}{Gm_1m_2}$. Divide Coulomb's law by Newton's law to compare force magnitudes directly.
$\frac{F_e}{F_g}=\frac{k|q_1q_2|}{Gm_1m_2}$. Divide Coulomb's law by Newton's law to compare force magnitudes directly.
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If both charges change sign ($q_1\to -q_1$, $q_2\to -q_2$), what happens to the electric force direction?
If both charges change sign ($q_1\to -q_1$, $q_2\to -q_2$), what happens to the electric force direction?
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Direction is unchanged (still attractive or still repulsive). Product $q_1q_2$ stays same sign when both flip.
Direction is unchanged (still attractive or still repulsive). Product $q_1q_2$ stays same sign when both flip.
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If $m_1$ is doubled (others fixed), by what factor does $F_g$ change?
If $m_1$ is doubled (others fixed), by what factor does $F_g$ change?
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$F_g$ doubles. Force is directly proportional to each mass.
$F_g$ doubles. Force is directly proportional to each mass.
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If separation triples, by what factor do both $F_g$ and $F_e$ change for point particles?
If separation triples, by what factor do both $F_g$ and $F_e$ change for point particles?
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They become $\frac{1}{9}$ as large. Inverse-square law: tripling $r$ gives $F\propto\frac{1}{(3r)^2}=\frac{1}{9r^2}$.
They become $\frac{1}{9}$ as large. Inverse-square law: tripling $r$ gives $F\propto\frac{1}{(3r)^2}=\frac{1}{9r^2}$.
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If separation doubles, by what factor do both $F_g$ and $F_e$ change for point particles?
If separation doubles, by what factor do both $F_g$ and $F_e$ change for point particles?
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They become $\frac{1}{4}$ as large. Inverse-square law: doubling $r$ gives $F\propto\frac{1}{(2r)^2}=\frac{1}{4r^2}$.
They become $\frac{1}{4}$ as large. Inverse-square law: doubling $r$ gives $F\propto\frac{1}{(2r)^2}=\frac{1}{4r^2}$.
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Which interaction is stronger between two electrons: electric or gravitational (quantitatively)?
Which interaction is stronger between two electrons: electric or gravitational (quantitatively)?
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Electric; $\frac{F_e}{F_g}\approx 10^{42}$ for two electrons. Electric force vastly exceeds gravity for elementary particles.
Electric; $\frac{F_e}{F_g}\approx 10^{42}$ for two electrons. Electric force vastly exceeds gravity for elementary particles.
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Which interaction is stronger between two protons: electric or gravitational (quantitatively)?
Which interaction is stronger between two protons: electric or gravitational (quantitatively)?
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Electric; $\frac{F_e}{F_g}\approx 10^{36}$ for two protons. Electromagnetic force dominates at atomic scales.
Electric; $\frac{F_e}{F_g}\approx 10^{36}$ for two protons. Electromagnetic force dominates at atomic scales.
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What is the correct sign behavior: can electric forces be attractive, repulsive, or both?
What is the correct sign behavior: can electric forces be attractive, repulsive, or both?
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Electric force can be attractive or repulsive. Like charges repel, opposite charges attract.
Electric force can be attractive or repulsive. Like charges repel, opposite charges attract.
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What is the correct sign behavior: can gravitational forces be repulsive, attractive, or both?
What is the correct sign behavior: can gravitational forces be repulsive, attractive, or both?
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Gravitational force is always attractive. Masses always attract; no negative mass exists.
Gravitational force is always attractive. Masses always attract; no negative mass exists.
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Identify the distance dependence shared by $F_g$ and $F_e$ for point particles.
Identify the distance dependence shared by $F_g$ and $F_e$ for point particles.
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Both follow an inverse-square law: $F\propto \frac{1}{r^2}$. Force decreases with square of distance for both interactions.
Both follow an inverse-square law: $F\propto \frac{1}{r^2}$. Force decreases with square of distance for both interactions.
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Which option gives the correct SI units: $k$ in $\text{N}\cdot\text{m}^2/\text{C}^2$ or $\text{N}\cdot\text{m}^2/\text{kg}^2$?
Which option gives the correct SI units: $k$ in $\text{N}\cdot\text{m}^2/\text{C}^2$ or $\text{N}\cdot\text{m}^2/\text{kg}^2$?
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$k:\ \text{N}\cdot\text{m}^2/\text{C}^2$. Coulomb's constant has units of force×area per charge squared.
$k:\ \text{N}\cdot\text{m}^2/\text{C}^2$. Coulomb's constant has units of force×area per charge squared.
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Which option gives the correct SI units: $G$ in $\text{N}\cdot\text{m}^2/\text{kg}^2$ or $\text{N}\cdot\text{m}^2/\text{C}^2$?
Which option gives the correct SI units: $G$ in $\text{N}\cdot\text{m}^2/\text{kg}^2$ or $\text{N}\cdot\text{m}^2/\text{C}^2$?
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$G:\ \text{N}\cdot\text{m}^2/\text{kg}^2$. Gravitational constant has units of force×area per mass squared.
$G:\ \text{N}\cdot\text{m}^2/\text{kg}^2$. Gravitational constant has units of force×area per mass squared.
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What is the ratio $\frac{F_e}{F_g}$ for the same separation $r$ between particles?
What is the ratio $\frac{F_e}{F_g}$ for the same separation $r$ between particles?
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$\frac{F_e}{F_g}=\frac{k|q_1 q_2|}{G m_1 m_2}$. Ratio cancels $r^2$ terms, leaving charge and mass factors.
$\frac{F_e}{F_g}=\frac{k|q_1 q_2|}{G m_1 m_2}$. Ratio cancels $r^2$ terms, leaving charge and mass factors.
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What is the formula for the electric force magnitude between two point charges (Coulomb's law)?
What is the formula for the electric force magnitude between two point charges (Coulomb's law)?
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$F_e = k\frac{|q_1 q_2|}{r^2}$. Coulomb's law gives force between point charges.
$F_e = k\frac{|q_1 q_2|}{r^2}$. Coulomb's law gives force between point charges.
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What is the formula for the gravitational force magnitude between two point masses?
What is the formula for the gravitational force magnitude between two point masses?
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$F_g = G\frac{m_1 m_2}{r^2}$. Newton's law of universal gravitation for point masses.
$F_g = G\frac{m_1 m_2}{r^2}$. Newton's law of universal gravitation for point masses.
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If $q_1$ is doubled (others fixed), by what factor does $F_e$ change?
If $q_1$ is doubled (others fixed), by what factor does $F_e$ change?
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$F_e$ doubles. Force is directly proportional to each charge magnitude.
$F_e$ doubles. Force is directly proportional to each charge magnitude.
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For fixed $m_1,m_2,q_1,q_2$, does changing $r$ change the ratio $\frac{F_e}{F_g}$?
For fixed $m_1,m_2,q_1,q_2$, does changing $r$ change the ratio $\frac{F_e}{F_g}$?
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No; $\frac{F_e}{F_g}$ is independent of $r$. Both forces have same $r^2$ dependence, which cancels in ratio.
No; $\frac{F_e}{F_g}$ is independent of $r$. Both forces have same $r^2$ dependence, which cancels in ratio.
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Find the ratio $\frac{F_e}{F_g}$ for two identical particles with charge $q$ and mass $m$.
Find the ratio $\frac{F_e}{F_g}$ for two identical particles with charge $q$ and mass $m$.
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$\frac{F_e}{F_g}=\frac{k q^2}{G m^2}$. Simplifies since $q_1=q_2=q$ and $m_1=m_2=m$.
$\frac{F_e}{F_g}=\frac{k q^2}{G m^2}$. Simplifies since $q_1=q_2=q$ and $m_1=m_2=m$.
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If only one charge changes sign ($q_1\to -q_1$), what happens to the electric force direction?
If only one charge changes sign ($q_1\to -q_1$), what happens to the electric force direction?
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Direction reverses (attractive becomes repulsive or vice versa). Product $q_1q_2$ changes sign when only one flips.
Direction reverses (attractive becomes repulsive or vice versa). Product $q_1q_2$ changes sign when only one flips.
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Identify the correct constants: $G\approx 6.67\times 10^{-11}$ and $k\approx 8.99\times 10^9$ (SI).
Identify the correct constants: $G\approx 6.67\times 10^{-11}$ and $k\approx 8.99\times 10^9$ (SI).
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$G\approx 6.67\times 10^{-11}$, $k\approx 8.99\times 10^9$. Values show $k\gg G$ in SI units.
$G\approx 6.67\times 10^{-11}$, $k\approx 8.99\times 10^9$. Values show $k\gg G$ in SI units.
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What is the direction rule for the electric force on $q_1$ due to $q_2$?
What is the direction rule for the electric force on $q_1$ due to $q_2$?
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Along the line joining them; toward unlike, away from like. Electric forces act along the line between charges with direction based on sign.
Along the line joining them; toward unlike, away from like. Electric forces act along the line between charges with direction based on sign.
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Identify the units of Coulomb's constant $k$ in $F_e=k\frac{|q_1q_2|}{r^2}$.
Identify the units of Coulomb's constant $k$ in $F_e=k\frac{|q_1q_2|}{r^2}$.
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$\mathrm{N,m^2/C^2}$. Similar to $G$ but with charge (coulombs) instead of mass (kg).
$\mathrm{N,m^2/C^2}$. Similar to $G$ but with charge (coulombs) instead of mass (kg).
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Find $\frac{F_e}{F_g}$ when $q_1=q_2=q$ and $m_1=m_2=m$ (same $r$).
Find $\frac{F_e}{F_g}$ when $q_1=q_2=q$ and $m_1=m_2=m$ (same $r$).
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$\frac{F_e}{F_g}=\frac{kq^2}{Gm^2}$. Simplifies when charges and masses are equal, showing dependence on $\frac{q}{m}$ ratio.
$\frac{F_e}{F_g}=\frac{kq^2}{Gm^2}$. Simplifies when charges and masses are equal, showing dependence on $\frac{q}{m}$ ratio.
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If $m_1,m_2,q_1,q_2$ are all doubled (same $r$), by what factor does $\frac{F_e}{F_g}$ change?
If $m_1,m_2,q_1,q_2$ are all doubled (same $r$), by what factor does $\frac{F_e}{F_g}$ change?
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No change; $\frac{F_e}{F_g}$ stays the same. Ratio cancels the factor of 2 in both numerator and denominator.
No change; $\frac{F_e}{F_g}$ stays the same. Ratio cancels the factor of 2 in both numerator and denominator.
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Which option best compares force strengths for elementary particles: $F_e$ or $F_g$?
Which option best compares force strengths for elementary particles: $F_e$ or $F_g$?
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$F_e\gg F_g$ (by about $10^{36}$ to $10^{39}$). Electric forces dominate by many orders of magnitude at particle scale.
$F_e\gg F_g$ (by about $10^{36}$ to $10^{39}$). Electric forces dominate by many orders of magnitude at particle scale.
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For an electron and a proton, what is the ratio $\frac{F_e}{F_g}$ (order of magnitude)?
For an electron and a proton, what is the ratio $\frac{F_e}{F_g}$ (order of magnitude)?
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$\frac{F_e}{F_g}\approx10^{39}$. Even larger ratio for electron-proton due to electron's tiny mass.
$\frac{F_e}{F_g}\approx10^{39}$. Even larger ratio for electron-proton due to electron's tiny mass.
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For two protons, what is the ratio $\frac{F_e}{F_g}$ (order of magnitude)?
For two protons, what is the ratio $\frac{F_e}{F_g}$ (order of magnitude)?
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$\frac{F_e}{F_g}\approx10^{36}$. Electric force dominates at atomic scale due to large charge-to-mass ratio.
$\frac{F_e}{F_g}\approx10^{36}$. Electric force dominates at atomic scale due to large charge-to-mass ratio.
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What is the formula for the magnitude of the gravitational force between two point masses?
What is the formula for the magnitude of the gravitational force between two point masses?
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$F_g=G\frac{m_1m_2}{r^2}$. Newton's law of universal gravitation with inverse square dependence on distance.
$F_g=G\frac{m_1m_2}{r^2}$. Newton's law of universal gravitation with inverse square dependence on distance.
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If the separation doubles, by what factor does each of $F_g$ and $F_e$ change?
If the separation doubles, by what factor does each of $F_g$ and $F_e$ change?
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Each becomes $\frac{1}{4}$ of its original value. Both forces have $\frac{1}{r^2}$ dependence, so doubling $r$ gives $\frac{1}{2^2}=\frac{1}{4}$.
Each becomes $\frac{1}{4}$ of its original value. Both forces have $\frac{1}{r^2}$ dependence, so doubling $r$ gives $\frac{1}{2^2}=\frac{1}{4}$.
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If the separation triples, by what factor does each of $F_g$ and $F_e$ change?
If the separation triples, by what factor does each of $F_g$ and $F_e$ change?
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Each becomes $\frac{1}{9}$ of its original value. Tripling distance gives $\frac{1}{3^2}=\frac{1}{9}$ due to inverse square law.
Each becomes $\frac{1}{9}$ of its original value. Tripling distance gives $\frac{1}{3^2}=\frac{1}{9}$ due to inverse square law.
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