NAPLEX Flashcards: Pharmacokinetic Parameters

What this deck covers

This deck focuses on Pharmacokinetic Parameters, giving you a quick way to review the definitions, rules, and examples that matter most for NAPLEX.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: State the formula for half-life in terms of volume of distribution and clearance.

Answer: $t_{\frac{1}{2}} = \frac{0.693\times V}{CL}$. Half-life integrates volume of distribution and clearance, using the natural log of 2 to express time for 50% elimination.

Flashcard 2: State the formula linking half-life, elimination rate constant, and natural log of $2$.

Answer: $t_{\frac{1}{2}} = \frac{0.693}{k}$. Half-life is derived from the natural log of 2 divided by the elimination rate constant for first-order processes.

Flashcard 3: What is the definition of volume of distribution (V or $V_d$)?

Answer: Apparent volume relating amount in body to plasma concentration. Volume of distribution is a proportionality constant linking the total drug amount in the body to its plasma concentration.

Flashcard 4: State the formula for clearance (CL) using elimination rate constant and volume of distribution.

Answer: $CL = k \times V$. Clearance equals the product of the elimination rate constant and volume of distribution in a one-compartment model with first-order kinetics.

Flashcard 5: Calculate $CL$ if $Dose = 500\ \text{mg}$ IV and $AUC = 50\ \text{mg}\cdot\text{h}/\text{L}$.

Answer: $CL = \frac{500}{50} = 10\ \text{L}/\text{h}$. Clearance is dose divided by AUC, reflecting elimination efficiency for IV administration.

Flashcard 6: What is the definition of elimination rate constant ($k$) for first-order elimination?

Answer: Fraction of drug eliminated per unit time. The elimination rate constant represents the proportion of drug removed per unit time in first-order kinetics.

Flashcard 7: Identify the formula for loading dose to reach a target concentration immediately.

Answer: $LD = \frac{C_{target}\times V}{F}$. Loading dose achieves target concentration rapidly by accounting for volume of distribution and bioavailability.

Flashcard 8: State the formula for concentration after time $t$ following an IV bolus in a one-compartment model.

Answer: $C_t = C_0\times e^{-kt}$. Concentration declines exponentially from initial value based on the elimination rate constant in a one-compartment model.

Flashcard 9: What is the definition of bioavailability ($F$)?

Answer: Fraction of administered dose reaching systemic circulation unchanged. Bioavailability quantifies the extent of unchanged drug entering systemic circulation relative to the administered dose.

Flashcard 10: What is the definition of AUC in pharmacokinetics?

Answer: Area under the plasma concentration–time curve. AUC measures total systemic drug exposure by integrating plasma concentration over time.

Flashcard 11: State the formula for accumulation factor ($R$) for first-order kinetics at steady state.

Answer: $R = \frac{1}{1-e^{-k\tau}}$. The accumulation factor accounts for drug buildup at steady state based on elimination rate and dosing interval.

Flashcard 12: Which parameter primarily determines AUC after an IV dose: clearance or volume of distribution?

Answer: Clearance. For IV dosing, AUC is inversely proportional to clearance, which governs the rate of drug elimination.

Flashcard 13: State the formula for volume of distribution using amount of drug in body and plasma concentration.

Answer: $V = \frac{Amount\ in\ body}{C_p}$. Volume of distribution is calculated as the ratio of drug amount in the body to its plasma concentration at equilibrium.

Flashcard 14: State the formula for fraction remaining after time $t$ with first-order elimination.

Answer: $\frac{C_t}{C_0} = e^{-kt}$. In first-order elimination, the fraction of drug remaining decays exponentially with time and rate constant.

Flashcard 15: State the formula for average steady-state concentration during multiple dosing.

Answer: $C_{ss,avg} = \frac{F\times Dose}{CL\times \tau}$. Average steady-state concentration balances absorbed dose against clearance over the dosing interval.

Flashcard 16: Calculate $t_{\frac{1}{2}}$ if $k = 0.2\ \text{h}^{-1}$ for first-order elimination.

Answer: $t_{\frac{1}{2}} = \frac{0.693}{0.2} = 3.465\ \text{h}$. Half-life equals the natural log of 2 divided by the elimination rate constant in first-order elimination.

Flashcard 17: Calculate $V$ if $Dose = 400\ \text{mg}$ IV bolus and $C_0 = 10\ \text{mg}/\text{L}$.

Answer: $V = \frac{400}{10} = 40\ \text{L}$. Volume of distribution is dose divided by initial concentration after IV bolus in a one-compartment model.

Flashcard 18: State the formula for $V$ after an IV bolus using dose and initial concentration.

Answer: $V = \frac{Dose}{C_0}$. After an IV bolus, volume of distribution equals the dose divided by the extrapolated initial plasma concentration.

Flashcard 19: Identify the formula for maintenance dose rate to maintain a target steady-state concentration.

Answer: $\text{Dose rate} = \frac{CL\times C_{ss}}{F}$. Maintenance dose rate sustains steady-state concentration by matching clearance adjusted for bioavailability.

Flashcard 20: State the formula for maintenance dose given dosing interval $\tau$ and target $C_{ss,avg}$.

Answer: $MD = \frac{CL\times C_{ss,avg}\times \tau}{F}$. Maintenance dose ensures average steady-state concentration by incorporating clearance, interval, and bioavailability.

Flashcard 21: What is the definition of clearance (CL) in pharmacokinetics?

Answer: Volume of plasma cleared of drug per unit time. Clearance quantifies the efficiency of drug removal by measuring the plasma volume from which the drug is completely eliminated per unit time.

Flashcard 22: State the formula for clearance (CL) in terms of dose and AUC for IV dosing.

Answer: $CL = \frac{Dose}{AUC}$. For intravenous dosing, clearance is the ratio of dose to the area under the concentration-time curve, reflecting total drug exposure.

Flashcard 23: What is the typical time to reach steady state for first-order kinetics in half-lives?

Answer: Approximately $4$ to $5$ half-lives. Steady state is achieved when input equals output, typically after 4-5 half-lives in first-order kinetics.

Flashcard 24: Calculate $k$ if $t_{\frac{1}{2}} = 6\ \text{h}$ for first-order elimination.

Answer: $k = \frac{0.693}{6\ \text{h}} = 0.1155\ \text{h}^{-1}$. The elimination rate constant is the natural log of 2 divided by half-life for first-order kinetics.

Flashcard 25: State the formula for bioavailability ($F$) using AUC values and doses for extravascular vs IV.

Answer: $F = \frac{AUC_{EV}\times Dose_{IV}}{AUC_{IV}\times Dose_{EV}}$. Bioavailability compares AUCs normalized by doses between extravascular and IV routes to assess absorption efficiency.