Motion and Energy Transfer

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Middle School Physical Science › Motion and Energy Transfer

Questions 1 - 10
1

A cue ball (0.20 kg) moving at 3.0 m/s hits a stationary target ball (0.20 kg). After the collision, the cue ball stops and the target ball moves at about 3.0 m/s. Which object gains kinetic energy, and which loses kinetic energy?

Neither ball changes kinetic energy because momentum is conserved.

The cue ball loses kinetic energy; the target ball gains kinetic energy.

Both balls gain kinetic energy because they are both involved in the collision.

The cue ball gains kinetic energy; the target ball loses kinetic energy.

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). In an elastic collision, kinetic energy is conserved (total KE before = total KE after), just redistributed (if cue ball had KE and target had 0, after cue: 0, target: same KE), while in inelastic collisions, some KE converts to thermal and sound. Initially cue ball (0.20 kg at 3.0 m/s) has KE = ½(0.20)(9) ≈ 0.9 J, target at rest has 0 J; during collision, cue exerts force on target doing work (accelerates target to ≈3.0 m/s, KE ≈0.9 J), target exerts opposite force on cue doing negative work (stops cue, KE=0 J); after, cue lost ≈0.9 J, target gained ≈0.9 J, total KE same ≈0.9 J, demonstrating complete transfer from cue (loses KE) to target (gains KE) in this elastic-like collision (masses equal, velocities exchanged). Choice C is correct because it correctly identifies energy transferring from moving object to stationary (cue loses KE, target gains) and properly recognizes energy redistributes between objects during collision. Choice B is wrong because it suggests both objects gain energy (impossible without external input: violates conservation) when actually one loses while the other gains, with total conserved. Energy transfer through motion and collisions demonstrates conservation: energy redistributes among objects through interactions, with total energy constant—before, energy in cue, after in target, total same. Systematic analysis of transfer: (1) calculate total energy before, (2) identify interaction, (3) calculate total energy after, (4) compare totals, (5) identify transfer (cue lost, target gained), (6) account for conversions if any, and (7) verify conservation.

2

A bowling ball ($5,\text{kg}$) rolls at $8,\text{m/s}$ toward a set of pins (total mass $2,\text{kg}$) at rest. After the hit, the ball slows to $6,\text{m/s}$ and the pins scatter with total kinetic energy about $60,\text{J}$. The ball’s kinetic energy changes from $160,\text{J}$ to $90,\text{J}$. Which statement best accounts for the energy changes?

The pins transfer $60,\text{J}$ of KE to the ball, causing the ball to slow down.

The ball loses $70,\text{J}$ of KE; about $60,\text{J}$ is transferred to the pins and about $10,\text{J}$ is converted to sound/heat.

Energy is destroyed because the total kinetic energy after the collision is less than before.

All $70,\text{J}$ lost by the ball becomes new kinetic energy of the pins, so no energy is converted to other forms.

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). For the bowling ball and pins: The bowling ball initially has large KE = ½(5)(8²) = 160 J (5 kg at 8 m/s) while pins at rest have KE = 0, total before = 160 J. Collision transfers energy: ball exerts forces on pins during impact (brief contact, large forces scatter pins), doing work on pins that increases their kinetic energy (pins accelerate from rest to various velocities, total KE of all pins ≈ 60 J after), and pins exert reaction forces on ball doing negative work (oppose ball's motion, slow it down to v' = 6 m/s, KE = ½(5)(6²) = 90 J). Energy accounting: ball lost 160 - 90 = 70 J, pins gained 60 J, difference 70 - 60 = 10 J converted to sound (loud crash) and thermal/deformation (pins compress slightly, generate heat from impact)—so 60 J transferred as KE from ball to pins (pins' KE gain), and 10 J converted to other forms, with total energy conserved (160 J before = 90 J ball + 60 J pins + 10 J sound/thermal = 160 J after ✓). Choice A is correct because it accurately states the ball loses 70 J of KE, about 60 J is transferred to the pins, and about 10 J is converted to sound/heat, properly accounting for all energy. Choice B reverses transfer direction: claims pins transfer to ball when actually ball transfers to pins (moving object transfers to stationary); Choice C claims all 70 J becomes pin KE without accounting for the 10 J difference (pins only gained 60 J, not 70 J); Choice D suggests energy is destroyed because total KE decreased, not recognizing the 10 J converted to sound/thermal (energy conserved, just changed forms). Energy transfer through motion and collisions demonstrates conservation: energy redistributes among objects through interactions (collisions, pushes, pulls), with total energy constant—before interaction, energy might be concentrated in one moving object (all KE in bowling ball), and after interaction, energy is distributed (spread among ball, pins, sound, heat), but total remains the same (just moved and converted, not created or destroyed). This inelastic collision shows partial energy transfer with conversion: most of the ball's lost kinetic energy transfers to the pins as kinetic energy, while some converts to other forms (sound and thermal), demonstrating real-world energy redistribution where not all energy stays as kinetic energy.

3

Cart A ($2,\text{kg}$) rolls at $4,\text{m/s}$ toward Cart B ($2,\text{kg}$) at rest on a smooth track. After they collide, Cart A stops and Cart B moves at $4,\text{m/s}$. How much kinetic energy is transferred from Cart A to Cart B?

$32,\text{J}$

$16,\text{J}$

$0,\text{J}$

$8,\text{J}$

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). For the cart collision: Initially Cart A (2 kg moving at 4 m/s) has kinetic energy KE_A = ½(2)(4²) = 16 J, and Cart B (2 kg at rest) has KE_B = 0 J, giving total KE_before = 16 + 0 = 16 J. During the collision, Cart A exerts force on Cart B (pushes it forward during brief contact), doing work that transfers energy, and simultaneously Cart B exerts equal opposite force on Cart A (Newton's Third Law), doing negative work on A (opposes its motion). After collision, Cart A has stopped (v' = 0 m/s, KE_A = 0 J) and Cart B is moving (v' = 4 m/s, KE_B = ½(2)(4²) = 16 J), giving total KE_after = 0 + 16 = 16 J. Comparing: Cart A lost 16 J of kinetic energy (went from 16 J to 0 J, decrease of 16 J), Cart B gained 16 J (went from 0 J to 16 J, increase of 16 J)—the energy that left Cart A (16 J lost) equals the energy that entered Cart B (16 J gained), demonstrating energy transferred from A to B completely, with total energy conserved (16 J before = 16 J after ✓, just redistributed from being all in A to being all in B). Choice B is correct because it states 16 J is transferred from Cart A to Cart B, matching the calculated energy transfer. Choice A gives only 8 J transferred, which is half the actual amount (Cart A lost 16 J, not 8 J); Choice C gives 32 J, which is double the actual transfer and exceeds the total energy available (only 16 J existed initially); Choice D claims 0 J transferred when clearly 16 J moved from Cart A to Cart B. Energy transfer through motion and collisions demonstrates conservation: energy redistributes among objects through interactions (collisions, pushes, pulls), with total energy constant—before interaction, energy might be concentrated in one moving object (all KE in Cart A), and after interaction, energy is distributed (now all in Cart B), but total remains the same (just moved, not created or destroyed). This perfect elastic collision between equal-mass carts shows complete energy transfer: Cart A transfers all its kinetic energy to Cart B, demonstrating how energy can move entirely from one object to another while maintaining conservation.

4

A 0.2 kg cue ball moving at 3 m/s strikes a stationary 0.2 kg ball. After the collision, the cue ball still moves forward at 1 m/s, and the target ball moves forward at about 2.8 m/s. Which statement best describes the energy changes?

The cue ball loses kinetic energy and the target ball gains kinetic energy; some energy may also be converted to sound/heat.

The cue ball gains kinetic energy because it is still moving after the collision.

The target ball loses kinetic energy because it was hit.

No energy transfer occurs because both balls move forward.

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). In an elastic collision, kinetic energy is conserved (total KE before = total KE after), just redistributed, while in inelastic collisions, some KE converts to thermal and sound (total KE after < before), but total energy is still conserved (the 'lost' KE became thermal/sound, accounted for). Initially cue ball (0.2 kg at 3 m/s) has KE = ½(0.2)(9) = 0.9 J, target (0.2 kg at rest) KE=0 J, total 0.9 J; after, cue at 1 m/s (KE=½(0.2)(1)=0.1 J), target at ~2.8 m/s (KE≈½(0.2)(7.84)≈0.784 J), total ~0.884 J <0.9 J, indicating inelastic with ~0.016 J converted to sound/heat; cue loses KE (0.9 to 0.1, loss 0.8 J), target gains (0 to 0.784 J), some converted, showing transfer with minor loss. Choice A is correct because it correctly identifies energy transferring from moving object (cue loses KE) to stationary (target gains KE), with possible conversion to sound/heat accounting for small discrepancy. Choice B is wrong because it claims cue gains energy (but cue's KE decreased from 0.9 J to 0.1 J—actually lost, not gained; confuses continued motion with energy gain). Energy transfer through motion and collisions demonstrates conservation: energy redistributes among objects through interactions (collisions, pushes, pulls), with total energy constant—before in cue, after shared with target and some converted, total same.

5

A $0.2,\text{kg}$ cue ball moving at $3,\text{m/s}$ hits a stationary $0.2,\text{kg}$ ball. After the collision, the cue ball stops and the other ball moves at $3,\text{m/s}$. Which statement is correct about energy transfer vs. energy conversion?

No transfer occurs because both balls have the same mass.

Energy is destroyed because the cue ball stops moving.

Mostly energy conversion: the cue ball’s kinetic energy turns completely into potential energy.

Mostly energy transfer: the cue ball’s kinetic energy moves to the other ball as kinetic energy.

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). Initially cue ball (0.2 kg moving at 3 m/s) has kinetic energy KE_cue = ½(0.2)(3²) = 0.9 J, and other ball (0.2 kg at rest) has KE_other = 0 J, giving total KE_before = 0.9 + 0 = 0.9 J. During the collision, cue ball exerts force on other ball (pushes it forward during brief contact), doing work that transfers energy, and simultaneously other ball exerts equal opposite force on cue ball (Newton's Third Law), doing negative work on cue ball (opposes its motion). After collision, cue ball has stopped (v' = 0 m/s, KE_cue = 0 J) and other ball is moving (v' = 3 m/s, KE_other = ½(0.2)(3²) = 0.9 J), giving total KE_after = 0 + 0.9 = 0.9 J. This represents energy TRANSFER not conversion: the 0.9 J of kinetic energy moved from cue ball to other ball while remaining as kinetic energy throughout (KE → KE between objects), unlike conversion where energy changes form (KE → thermal or KE → PE). Choice A is correct because it properly identifies this as energy transfer where cue ball's kinetic energy moves to the other ball as kinetic energy (energy changes location between objects but stays same form). Choice B confuses transfer with conversion by claiming KE turns to PE (wrong: energy stays as KE, just moves between balls); Choice C incorrectly claims no transfer when clearly 0.9 J moved from cue to other ball; Choice D claims energy destroyed when it actually transferred (cue ball's KE didn't disappear, it moved to other ball).

6

A 1 kg pendulum bob reaches the bottom of its swing with 20 J of kinetic energy and collides with a 1 kg block at rest. After the collision, the bob stops and the block moves with about 18 J of kinetic energy. Which statement best accounts for the energy changes?

About 18 J of kinetic energy is transferred from the bob to the block, and about 2 J is converted to sound/heat; total energy is conserved.

The bob’s kinetic energy disappears because it stops, so energy is not conserved.

The block created 18 J of kinetic energy because it started from rest.

All 20 J must transfer to the block as kinetic energy, so the block must have 20 J after.

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). In an elastic collision, kinetic energy is conserved, just redistributed, while in inelastic collisions, some KE converts to thermal and sound, but total energy is conserved. For pendulum transfer: Pendulum bob (1 kg) reaches bottom with KE=20 J (moving fast), strikes stationary block (1 kg, KE=0); during collision forces transfer energy: bob does work on block (accelerates it to KE≈18 J), block does work on bob (stops it, KE=0 J); energy accounting: bob lost 20 J, block gained 18 J, difference 2 J converted to sound/thermal; so ≈18 J transferred as KE from bob to block, 2 J converted, total conserved (20 J before = 0 J bob + 18 J block + 2 J sound/thermal = 20 J after ✓), demonstrating swinging pendulum transfers its kinetic energy through collision, with most energy transferring but some lost to other forms. Choice A is correct because it accurately calculates energy lost by one equals energy gained by other (accounting for small losses) and appropriately explains transfer mechanism with conservation. Choice C is wrong because it claims energy destroyed when actually transferred (bob stops: KE didn't disappear, it transferred to block or converted to sound/heat) and suggests energy not conserved, which is incorrect. Energy transfer through motion and collisions demonstrates conservation: energy redistributes among objects through interactions, with total constant—before in bob, after mostly in block plus conversions. Systematic analysis of transfer: (1) calculate total before, (2) identify interaction, (3) calculate after including conversions, (4) compare, (5) identify transfer, (6) account for conversions, and (7) verify conservation.

7

A cue ball (0.20 kg) moving at 3.0 m/s hits a stationary target ball (0.20 kg). After the collision, the cue ball stops and the target ball moves at about 3.0 m/s. Which object gains kinetic energy, and which loses kinetic energy?​

The cue ball gains kinetic energy; the target ball loses kinetic energy.

The cue ball loses kinetic energy; the target ball gains kinetic energy.

Neither ball changes kinetic energy because momentum is conserved.

Both balls gain kinetic energy because they are both involved in the collision.

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). In an elastic collision, kinetic energy is conserved (total KE before = total KE after), just redistributed (if cue ball had KE and target had 0, after cue: 0, target: same KE), while in inelastic collisions, some KE converts to thermal and sound. Initially cue ball (0.20 kg at 3.0 m/s) has KE = ½(0.20)(9) ≈ 0.9 J, target at rest has 0 J; during collision, cue exerts force on target doing work (accelerates target to ≈3.0 m/s, KE ≈0.9 J), target exerts opposite force on cue doing negative work (stops cue, KE=0 J); after, cue lost ≈0.9 J, target gained ≈0.9 J, total KE same ≈0.9 J, demonstrating complete transfer from cue (loses KE) to target (gains KE) in this elastic-like collision (masses equal, velocities exchanged). Choice C is correct because it correctly identifies energy transferring from moving object to stationary (cue loses KE, target gains) and properly recognizes energy redistributes between objects during collision. Choice B is wrong because it suggests both objects gain energy (impossible without external input: violates conservation) when actually one loses while the other gains, with total conserved. Energy transfer through motion and collisions demonstrates conservation: energy redistributes among objects through interactions, with total energy constant—before, energy in cue, after in target, total same. Systematic analysis of transfer: (1) calculate total energy before, (2) identify interaction, (3) calculate total energy after, (4) compare totals, (5) identify transfer (cue lost, target gained), (6) account for conversions if any, and (7) verify conservation.

8

A 1 kg cart moving at 4 m/s collides with a 1 kg cart at rest. After the collision, the first cart stops and the second cart moves at 4 m/s. Which observation is the clearest evidence that kinetic energy was transferred between the carts?​

The carts touch, so energy automatically disappears.

The moving cart changes color during the collision.

One cart slows/stops while the other starts moving faster, showing one lost kinetic energy while the other gained it.

The carts are the same mass, so energy must always be created.

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). In an elastic collision, kinetic energy is conserved, just redistributed (equal masses exchange velocities, KE transfers completely). Here, 1 kg at 4 m/s (KE=½(1)(16)=8 J) hits 1 kg at rest (0 J); after, first stops (0 J), second at 4 m/s (8 J), total same 8 J; observation: one cart slows/stops (loses KE) while other starts moving faster (gains KE), clearest evidence of transfer via speed changes indicating KE redistribution. Choice B is correct because it correctly identifies evidence of transfer (one lost KE via slowing, other gained via speeding up) and properly recognizes energy redistributes between objects. Choice D is wrong because it claims energy disappears when actually transferred (carts touch: KE didn't disappear, it moved to the other cart). Energy transfer through motion and collisions demonstrates conservation: energy redistributes, total constant—before in first, after in second. Systematic analysis of transfer: (1) calculate total before, (2) identify interaction, (3) calculate after, (4) compare, (5) identify transfer via observations like speed changes, (6) account for conversions if any, and (7) verify conservation.

9

A bowling ball (5 kg) rolls at 8 m/s toward pins (total mass 2 kg) at rest. After impact, the ball slows to 6 m/s and the pins move with total kinetic energy about 60 J. About how much kinetic energy was converted to sound/thermal energy in the collision?

0 J

60 J

10 J

70 J

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). In an elastic collision, kinetic energy is conserved (total KE before = total KE after), just redistributed, while in inelastic collisions, some KE converts to thermal and sound (total KE after < before), but total energy is still conserved (the 'lost' KE became thermal/sound, accounted for). For bowling ball and pins: Bowling ball initially has large KE = ½(5)(8²) = 160 J (5 kg at 8 m/s) while pins at rest have KE = 0, total before = 160 J; collision transfers energy: ball exerts forces on pins during impact (brief contact, large forces scatter pins), doing work on pins that increases their kinetic energy (pins accelerate from rest to various velocities, total KE of all pins ≈ 60 J after), and pins exert reaction forces on ball doing negative work (oppose ball's motion, slow it down to v' = 6 m/s, KE = ½(5)(36) = 90 J); energy accounting: ball lost 160 - 90 = 70 J, pins gained 60 J, difference 70 - 60 = 10 J converted to sound (loud crash) and thermal/deformation (pins compress slightly, generate heat from impact)—so 60 J transferred as KE from ball to pins (pins' KE gain), and 10 J converted to other forms, with total energy conserved (160 J before = 90 J ball + 60 J pins + 10 J sound/thermal = 160 J after ✓). Choice B is correct because it accurately calculates the energy converted to sound/thermal as 10 J, accounting for the difference between ball's loss (70 J) and pins' gain (60 J). Choice D is wrong because it claims 70 J converted, not accounting for energy transfer—doesn't recognize that 60 J was transferred to pins as KE (ball lost 70 J total, but 60 J went to pins' KE, only 10 J converted). Energy transfer through motion and collisions demonstrates conservation: energy redistributes among objects through interactions (collisions, pushes, pulls), with total energy constant—before interaction, energy might be concentrated in one moving object (all KE in ball), and after interaction, energy is distributed (spread among pins, some converted), but total remains the same (just moved or converted, not created or destroyed).

10

A 2 kg cart A moves at 4 m/s toward a stationary 2 kg cart B on a smooth track. After the collision, cart A stops (0 m/s) and cart B moves at 4 m/s. How much kinetic energy is transferred from cart A to cart B during the collision?

8 J

0 J

16 J

32 J

Explanation

This question tests understanding that kinetic energy can transfer from one object to another during collisions or interactions, with energy redistributing between objects while total energy remains conserved. Energy transfer occurs when objects interact: in a collision, the moving object exerts force on the stationary or slower object during contact (Newton's Third Law: equal and opposite forces on both objects), and these forces acting through the small collision distance do work (W = F·d), transferring energy from one object to the other—the object doing positive work loses kinetic energy (its KE decreases as it does work), while the object having work done on it gains kinetic energy (its KE increases from the work input). In an elastic collision, kinetic energy is conserved (total KE before = total KE after), just redistributed (if Cart A had 16 J and Cart B had 0 J before, after might be A: 0 J, B: 16 J—same total 16 J, just moved from A to B completely), while in inelastic collisions, some KE converts to thermal and sound (total KE after < before), but total energy is still conserved (the 'lost' KE became thermal/sound, accounted for). Initially Cart A (2 kg moving at 4 m/s) has kinetic energy KE_A = ½(2)(4²) = 16 J, and Cart B (2 kg at rest) has KE_B = 0 J, giving total KE_before = 16 + 0 = 16 J; during the collision, Cart A exerts force on Cart B (pushes it forward during brief contact), doing work that transfers energy, and simultaneously Cart B exerts equal opposite force on Cart A (Newton's Third Law), doing negative work on A (opposes its motion); after collision, Cart A has stopped (v' = 0 m/s, KE_A = 0 J) and Cart B is moving (v' = 4 m/s by momentum conservation, KE_B = 16 J), giving total KE_after = 0 + 16 = 16 J; comparing: Cart A lost 16 J of kinetic energy (went from 16 J to 0 J, decrease of 16 J), Cart B gained 16 J (went from 0 J to 16 J, increase of 16 J)—the energy that left Cart A (16 J lost) equals the energy that entered Cart B (16 J gained), demonstrating energy transferred from A to B completely, with total energy conserved (16 J before = 16 J after ✓, just redistributed from being all in A to being all in B). Choice C is correct because it accurately calculates the energy transferred as 16 J, matching the kinetic energy lost by A and gained by B. Choice A is wrong because it claims 0 J transferred, confusing transfer with conservation—energy didn't disappear; it moved from A to B (A lost 16 J, B gained 16 J, transfer is clear from opposite changes). Energy transfer through motion and collisions demonstrates conservation: energy redistributes among objects through interactions (collisions, pushes, pulls), with total energy constant—before interaction, energy might be concentrated in one moving object (all KE in Cart A), and after interaction, energy is distributed (spread among multiple objects: Cart B now has the KE), but total remains the same (just moved, not created or destroyed).

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