Compare Potential Energy

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Middle School Physical Science › Compare Potential Energy

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1

A box is moved between two shelves. Shelf A is at height $h=1\text{ m}$ and Shelf B is at height $h=4\text{ m}$ (measured from the floor). Which shelf gives the box greater gravitational potential energy, and why?

Shelf B, because gravitational potential energy increases with height ($PE=mgh$).

They are the same, because gravitational potential energy depends only on mass.

Shelf A, because being closer to the ground increases gravitational potential energy.

Shelf A, because moving upward makes potential energy decrease.

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. For static positions on shelves: Shelf A at h=1 m has PE = mg(1), while Shelf B at h=4 m has PE = mg(4), so Shelf B has greater PE by mg(3) due to the higher position—this stored energy difference means the box on B could release more energy if falling to the floor (converting to more KE). The comparison highlights that PE is directly proportional to height for a given mass and g, with the floor as reference (h=0). Choice B is correct because gravitational potential energy increases with height (PE=mgh), so higher shelf B has greater PE. Choice A reverses the relationship: claims closer to ground increases PE, opposite of PE = mgh; Choice C claims same because only mass matters, ignoring h; Choice D says upward decreases PE, again reversed. The position-PE connection is fundamental to understanding gravitational potential energy: (1) PE is energy of position (where you are in gravitational field matters), (2) higher positions have more PE (climbing stores energy by increasing h), (3) lower positions have less PE (descending releases energy by decreasing h), and (4) PE can convert to other forms (primarily KE when falling: PE → KE maintains total energy). Applications: (1) hydroelectric dams store water at height (high PE), release it to fall (PE → KE → turbine rotation → electricity), (2) pumped storage: pump water uphill when electricity cheap (store as PE), release downhill when electricity needed (PE → KE → generate electricity), (3) roller coasters: lift cart to top (add PE), release (PE → KE creating speed for thrilling ride), (4) trebuchets/catapults: raise counterweight (store PE), release (PE → KE → projectile motion).

2

A rock is dropped from a cliff at $h=12\text{ m}$ above the ground (take ground as $h=0$). As the rock falls toward the ground, what happens to its gravitational potential energy?

It becomes greatest at the ground because the rock is moving fastest there.

It stays constant because gravity is constant.

It increases because the rock speeds up.

It decreases because height is decreasing.

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. As the rock falls from the cliff (h = 12 m) toward the ground (h = 0 m), its height continuously decreases, so its gravitational potential energy decreases from PEinitial = mg(12) = 12mg J toward PEfinal = mg(0) = 0 J—the rock loses PE = 12mg J during the fall, with this energy converting to kinetic energy as the rock accelerates downward. The PE decreases smoothly and continuously during the fall: at h = 9 m it has PE = 9mg (lost 3mg), at h = 6 m it has PE = 6mg (lost 6mg), at h = 3 m it has PE = 3mg (lost 9mg), until reaching ground where all 12mg J of initial PE has converted to KE. Choice B is correct because it accurately states PE decreases as height decreases during the fall, following the fundamental PE = mgh relationship where falling means h decreases so PE decreases. Choice A confuses PE and KE: claims PE increases because rock speeds up, when actually speeding up means KE increases while PE decreases; Choice C incorrectly claims PE stays constant because gravity is constant, ignoring that PE = mgh changes with height h even though g is constant; Choice D reverses the relationship, claiming PE is greatest at ground where rock moves fastest, when actually PE = 0 at ground (h = 0) and KE is maximum there. The position-PE connection is fundamental to understanding gravitational potential energy: (1) PE is energy of position (where you are in gravitational field matters), (2) higher positions have more PE (climbing stores energy by increasing h), (3) lower positions have less PE (descending releases energy by decreasing h), and (4) PE can convert to other forms (primarily KE when falling: PE → KE maintains total energy). This principle explains falling object behavior: dropped items accelerate because PE converts to KE, meteorites gain tremendous speed falling through atmosphere as enormous PE (from space altitude) becomes KE, and base jumpers rely on PE at cliff top converting to KE during freefall before parachute deployment.

3

A ball of mass $2\text{ kg}$ is thrown straight up. Using the release point as the reference ($h=0$), it rises to a peak height of $5\text{ m}$. Take $g\approx 10\text{ N/kg}$. What is the change in gravitational potential energy from release to the peak?

$\Delta PE = 0\text{ J}$

$\Delta PE = -100\text{ J}$

$\Delta PE = 25\text{ J}$

$\Delta PE = 100\text{ J}$

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. Moving upward increases PE (climbing stairs, lifting object, rising elevator all gain gravitational PE as they gain height), while moving downward decreases PE (falling, descending, lowering all lose gravitational PE as they lose height), with the change in PE calculated as ΔPE = mg(hfinal - hinitial) = mgΔh (positive if going up, negative if going down). For this upward motion: As the ball rises from release point (h = 0 m, reference where PE = 0) to peak h = 5 m, its gravitational potential energy increases from PE₀ = mg(0) = 0 J to PEfinal = mg(5) = 2105 = 100 J—the ball gained PE = 100 J during the rise, which comes from its initial kinetic energy converting to PE (slowing down to stop at peak). Choice A is correct because it properly calculates ΔPE = mgΔh = 100 J for the position change. Choice B calculates incorrectly: wrong magnitude (25 J too small); Choice C has wrong sign (negative, as if descending); Choice D claims no change, ignoring height increase. The position-PE connection is fundamental to understanding gravitational potential energy: (1) PE is energy of position (where you are in gravitational field matters), (2) higher positions have more PE (climbing stores energy by increasing h), (3) lower positions have less PE (descending releases energy by decreasing h), and (4) PE can convert to other forms (primarily KE when falling: PE → KE maintains total energy). Applications: (1) hydroelectric dams store water at height (high PE), release it to fall (PE → KE → turbine rotation → electricity), (2) pumped storage: pump water uphill when electricity cheap (store as PE), release downhill when electricity needed (PE → KE → generate electricity), (3) roller coasters: lift cart to top (add PE), release (PE → KE creating speed for thrilling ride), (4) trebuchets/catapults: raise counterweight (store PE), release (PE → KE → projectile motion).

4

A person of mass $m$ climbs stairs from the first floor ($h=0\text{ m}$) to the second floor ($h=3\text{ m}$) and then to the third floor ($h=6\text{ m}$). How does the person’s gravitational potential energy change from the first floor to the third floor?

It increases only from the first to the second floor, then stays constant from the second to the third floor.

It increases by $\Delta PE = mg(6-0)=6mg$ because height increases.

It decreases by $6mg$ because the person is moving upward.

It stays the same because mass $m$ does not change.

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. As the person climbs from the first floor (h = 0 m, reference point where PE = 0) to the third floor (h = 6 m), their gravitational potential energy increases from PE₀ = mg(0) = 0 J to PEfinal = mg(6) = 6mg J—the person gained ΔPE = PEfinal - PEinitial = 6mg - 0 = +6mg J during the climb, which represents the work done against gravity to lift them (work = force × distance = mg × 6 m = same 6mg J). Choice A is correct because it accurately states PE increases by ΔPE = mg(6-0) = 6mg when the person rises from h = 0 to h = 6 m, properly using the formula ΔPE = mgΔh with positive Δh for upward motion. Choice B reverses the relationship: claims PE decreases when moving upward, opposite of the actual PE = mgh relationship where PE increases with height; Choice C incorrectly claims PE doesn't change, ignoring that PE depends on height h, not just mass m; Choice D wrongly suggests PE stops changing after the second floor, when actually PE continues to increase as height increases to the third floor. The position-PE connection is fundamental to understanding gravitational potential energy: (1) PE is energy of position (where you are in gravitational field matters), (2) higher positions have more PE (climbing stores energy by increasing h), (3) lower positions have less PE (descending releases energy by decreasing h), and (4) PE can convert to other forms (primarily KE when falling: PE → KE maintains total energy). Applications include hydroelectric dams storing water at height (high PE) to release for electricity generation, and even everyday activities like climbing stairs where you do work against gravity to increase your PE, storing energy that could be released if you jumped down.

5

A pendulum bob is $0.5,\text{m}$ above its lowest point at the left endpoint, passes through the lowest point ($h=0$), and reaches $0.5,\text{m}$ above the lowest point at the right endpoint. Using $PE=mgh$ with the lowest point as the reference, how does the bob’s gravitational potential energy change during one swing from left endpoint to bottom to right endpoint?

High → zero → high (it decreases to the bottom, then increases again).

Zero → high → zero.

It stays constant because the bob returns to the same height.

Low → lower → lowest.

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. Moving upward increases PE (climbing stairs, lifting object, rising elevator all gain gravitational PE as they gain height), while moving downward decreases PE (falling, descending, lowering all lose gravitational PE as they lose height), with the change in PE calculated as ΔPE = mg(hfinal - hinitial) = mgΔh (positive if going up, negative if going down). For the pendulum bob: Starting at left endpoint (h = 0.5 m above lowest point), PE = mg(0.5) = 0.5mg J (high PE); swinging down to lowest point (h = 0, reference), PE = mg(0) = 0 J (zero PE at bottom); continuing up to right endpoint (h = 0.5 m again), PE = mg(0.5) = 0.5mg J (high PE again)—the pattern is high → zero → high as the bob swings through one complete swing. Choice A is correct because it accurately describes PE changes: high at left endpoint (0.5 m up), decreases to zero at bottom (h = 0), then increases back to high at right endpoint (0.5 m up again). Choice B reverses the pattern (zero → high → zero would mean starting at bottom), Choice C incorrectly claims PE stays constant (wrong—PE varies with height even though endpoints are same height), and Choice D suggests PE only decreases (wrong—PE increases again as bob rises to right endpoint). The pendulum demonstrates cyclic PE changes: PE is maximum at the endpoints where height is maximum (0.5 m), minimum at the bottom where height is zero, with smooth variation between—this PE converts to KE at bottom (fastest) and back to PE at endpoints (momentarily at rest).

6

An elevator lifts a person of mass $m$ from the ground floor (Position A, $h=0\text{ m}$) to the 10th floor (Position B, $h=30\text{ m}$). Which expression correctly gives the increase in the person’s gravitational potential energy?

$\Delta PE = mg(0-30)$

$\Delta PE = \dfrac{m}{g}\cdot 30\text{ m}$

$\Delta PE = mgh = mg\cdot 30\text{ m}$

$\Delta PE = mg\cdot 10\text{ m}$ because it goes to the 10th floor.

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. Moving upward increases PE (climbing stairs, lifting object, rising elevator all gain gravitational PE as they gain height), while moving downward decreases PE (falling, descending, lowering all lose gravitational PE as they lose height), with the change in PE calculated as ΔPE = mg(hfinal - hinitial) = mgΔh (positive if going up, negative if going down). For this upward motion: As the person rises from ground level (h = 0 m, reference where PE = 0) to h = 30 m, their gravitational potential energy increases from PE₀ = mg(0) = 0 J to PEfinal = mg(30) = 30mg J—the person gained PE = 30mg J during the lift, which represents the work done by the elevator against gravity (work = mg × 30 m). Choice B is correct because it properly calculates ΔPE = mgh = mg·30 m for the position change (increase). Choice A has wrong sign: positive to negative, as if descending; Choice C uses wrong formula (m/g instead of mg); Choice D uses wrong height (10 m instead of 30 m). The position-PE connection is fundamental to understanding gravitational potential energy: (1) PE is energy of position (where you are in gravitational field matters), (2) higher positions have more PE (climbing stores energy by increasing h), (3) lower positions have less PE (descending releases energy by decreasing h), and (4) PE can convert to other forms (primarily KE when falling: PE → KE maintains total energy). Applications: (1) hydroelectric dams store water at height (high PE), release it to fall (PE → KE → turbine rotation → electricity), (2) pumped storage: pump water uphill when electricity cheap (store as PE), release downhill when electricity needed (PE → KE → generate electricity), (3) roller coasters: lift cart to top (add PE), release (PE → KE creating speed for thrilling ride), (4) trebuchets/catapults: raise counterweight (store PE), release (PE → KE → projectile motion).

7

A hiker stands at two lookout points: Point A at $h=200,\text{m}$ and Point B at $h=50,\text{m}$ above sea level. The hiker’s mass is the same at both points. Which statement is correct about the hiker’s gravitational potential energy?

The hiker has more gravitational potential energy at Point B because it is closer to sea level.

The hiker has more gravitational potential energy at Point A because height is greater and $PE=mgh$.

The hiker has the same gravitational potential energy at both points because mass is unchanged.

Gravitational potential energy depends on horizontal location, so you cannot compare A and B.

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. For the hiker at the two lookout points: at Point A (h = 200 m), PE = mg(200) = 200mg J; at Point B (h = 50 m), PE = mg(50) = 50mg J—since 200 > 50, the hiker has more gravitational PE at Point A (the higher elevation) than at Point B, demonstrating that PE increases with altitude above the reference level (sea level). Choice C is correct because it states the hiker has more gravitational PE at Point A due to greater height, properly applying PE = mgh where the higher position (200 m) gives more PE than the lower position (50 m). Choice A reverses the relationship, claiming more PE at lower elevation; Choice B incorrectly claims PE is same at both points, ignoring the height difference; Choice D wrongly suggests PE depends on horizontal location rather than vertical height. The position-PE connection is fundamental to understanding gravitational potential energy: (1) PE is energy of position (where you are in gravitational field matters), (2) higher positions have more PE (climbing stores energy by increasing h), (3) lower positions have less PE (descending releases energy by decreasing h), and (4) PE can convert to other forms (primarily KE when falling: PE → KE maintains total energy). Mountain climbing exemplifies this: climbers do work against gravity to gain elevation (storing energy as PE), which is why descending is easier—gravity does positive work as you lose PE, and why avalanches are so destructive—massive amounts of PE convert to KE as snow/rock falls from high elevation.

8

A rock of mass $3,\text{kg}$ falls from a cliff at $h=12,\text{m}$ to a ledge at $h=7,\text{m}$. Using $g\approx 10,\text{m/s}^2$, what is the change in gravitational potential energy ($\Delta PE = PE_{\text{final}} - PE_{\text{initial}}$) for this fall?

$\Delta PE = -150,\text{J}$

$\Delta PE = -360,\text{J}$

$\Delta PE = 0,\text{J}$

$\Delta PE = +150,\text{J}$

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. Moving upward increases PE (climbing stairs, lifting object, rising elevator all gain gravitational PE as they gain height), while moving downward decreases PE (falling, descending, lowering all lose gravitational PE as they lose height), with the change in PE calculated as ΔPE = mg(hfinal - hinitial) = mgΔh (positive if going up, negative if going down). For the falling rock: starting at cliff top (h = 12 m) with PE_initial = mgh₁ = (3 kg)(10 m/s²)(12 m) = 360 J, falling to ledge (h = 7 m) with PE_final = mgh₂ = (3 kg)(10 m/s²)(7 m) = 210 J. The change in PE is ΔPE = PE_final - PE_initial = 210 J - 360 J = -150 J, or using the formula: ΔPE = mgΔh = (3)(10)(7-12) = (3)(10)(-5) = -150 J. The negative sign indicates PE decreased during the fall, with 150 J of PE converting to kinetic energy as the rock gains speed. Choice B is correct because it accurately calculates ΔPE = -150 J for the rock falling from h = 12 m to h = 7 m, with negative sign properly indicating PE decrease during downward motion. Choice A shows +150 J with wrong sign, suggesting PE increases when falling, opposite of actual behavior; Choice C calculates -360 J, which is negative of initial PE but not the change (would require falling to h = 0); Choice D claims no change (0 J), ignoring that height decreased from 12 m to 7 m which must decrease PE. The position-PE connection is fundamental to understanding gravitational potential energy: (1) PE is energy of position (where you are in gravitational field matters), (2) higher positions have more PE (climbing stores energy by increasing h), (3) lower positions have less PE (descending releases energy by decreasing h), and (4) PE can convert to other forms (primarily KE when falling: PE → KE maintains total energy). Falling objects demonstrate energy conversion: initial PE at height converts to KE during fall, with the 150 J lost from PE becoming 150 J gained in KE (rock speeds up)—understanding this helps predict impact: higher falls mean more PE to convert, thus higher impact speeds and forces.

9

A skateboarder rolls down a ramp from a platform at $h=4,\text{m}$ to the ground at $h=0,\text{m}$. Which statement correctly describes the skateboarder’s gravitational potential energy during the descent?

It stays the same because gravity is constant.

It depends only on mass, so it cannot change during motion.

It increases because the skateboarder speeds up.

It decreases because height decreases; potential energy is converted to other forms like kinetic energy.

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. Moving upward increases PE (climbing stairs, lifting object, rising elevator all gain gravitational PE as they gain height), while moving downward decreases PE (falling, descending, lowering all lose gravitational PE as they lose height), with the change in PE calculated as ΔPE = mg(hfinal - hinitial) = mgΔh (positive if going up, negative if going down). For the skateboarder descending: rolling from platform (h = 4 m) down to ground (h = 0 m), the gravitational potential energy decreases from PE₁ = mgh₁ = mg(4) = 4mg J to PE₂ = mg(0) = 0 J. The skateboarder loses PE = 4mg J during descent, with this lost PE converting to kinetic energy (speed increases) as they roll down—energy transforms from PE to KE while total energy remains constant. At the bottom, all the initial PE has become KE, making the skateboarder move fastest at the lowest point. Choice B is correct because it accurately states PE decreases as height decreases during descent and correctly identifies that this PE converts to other forms like kinetic energy—the complete explanation of energy transformation during the roll down. Choice A claims PE increases because speed increases, confusing cause and effect: speed increases because PE decreases and converts to KE, not the reverse; Choice C states PE stays same because gravity is constant, missing that PE = mgh changes when h changes even though g is constant; Choice D suggests PE depends only on mass and cannot change, ignoring the height dependence in PE = mgh. The position-PE connection is fundamental to understanding gravitational potential energy: (1) PE is energy of position (where you are in gravitational field matters), (2) higher positions have more PE (climbing stores energy by increasing h), (3) lower positions have less PE (descending releases energy by decreasing h), and (4) PE can convert to other forms (primarily KE when falling: PE → KE maintains total energy). Skateboard ramps perfectly demonstrate energy conversion: starting high with PE and no speed, rolling down converts PE → KE (gaining speed), reaching bottom with maximum KE and minimum PE—understanding this helps skaters judge speed: higher starting point means more PE to convert, thus higher speed at bottom.

10

Two identical carts (same mass) are on different tracks. Cart A is at height $h=8,\text{m}$ and Cart B is at height $h=3,\text{m}$, measured from the same reference level. Which comparison is correct for their gravitational potential energies?

Cart A has more gravitational potential energy because it is at a greater height.

Their gravitational potential energies depend on their speeds, not their heights.

They have the same gravitational potential energy because their masses are the same.

Cart B has more gravitational potential energy because it is closer to the ground.

Explanation

This question tests understanding that gravitational potential energy changes as an object's position changes vertically—specifically, that PE increases with height and decreases when height decreases. Position in Earth's gravitational field determines gravitational potential energy through the height variable in PE = mgh: when an object is at higher position (larger h), it has more gravitational PE because h is larger (more energy stored), and when at lower position (smaller h), it has less PE. Moving upward increases PE (climbing stairs, lifting object, rising elevator all gain gravitational PE as they gain height), while moving downward decreases PE (falling, descending, lowering all lose gravitational PE as they lose height), with the change in PE calculated as ΔPE = mg(hfinal - hinitial) = mgΔh (positive if going up, negative if going down). For comparing the two carts: Cart A at h = 8 m has PE_A = mgh_A = mg(8) = 8mg J, while Cart B at h = 3 m has PE_B = mgh_B = mg(3) = 3mg J. Since both carts have identical mass m and experience same gravity g, the cart at greater height has more PE: PE_A = 8mg > PE_B = 3mg, with Cart A having 8mg - 3mg = 5mg J more potential energy than Cart B. The height difference alone determines the PE difference when masses are equal. Choice C is correct because it accurately states Cart A has more gravitational PE due to its greater height—at h = 8 m versus h = 3 m, Cart A has higher position in gravitational field and thus more stored energy. Choice A reverses the relationship, claiming Cart B (lower position) has more PE when actually lower height means less PE; Choice B incorrectly states equal PE just because masses are equal, ignoring that different heights give different PE even for same mass; Choice D suggests PE depends on speed rather than height, confusing kinetic energy (speed-dependent) with potential energy (position-dependent). The position-PE connection is fundamental to understanding gravitational potential energy: (1) PE is energy of position (where you are in gravitational field matters), (2) higher positions have more PE (climbing stores energy by increasing h), (3) lower positions have less PE (descending releases energy by decreasing h), and (4) PE can convert to other forms (primarily KE when falling: PE → KE maintains total energy). This comparison illustrates why height matters for energy storage: two identical objects at different heights have different energy potentials—the higher one could do more work if released (more PE to convert), which explains why water towers are built tall (more PE for water pressure) and why higher diving boards allow more spectacular dives (more PE → KE → athletic maneuvers).

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