Electric Potential Energy - MCAT Chemical and Physical Foundations of Biological Systems

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Question

For the following:

e = 1.60 times $10^{-19}$

k = 8.99 times $10^{9}$

If a charge of magnitude +4e is being held in place 3 nm from a charge of -5e which is also being held in place. What is the potential energy of the system?

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Answer

U= $\frac{kQq}{r}$

Given the equation and plugging in the values of e and k, we get that

U= 1.53times $10^{-18}$

It is important to keep in mind that the charge e is given in the question and must be incorporated into the formula by multiplying each charge by that value.

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