Thermodynamics and Energy Changes (5E) - MCAT Chemical and Physical Foundations of Biological Systems
Card 1 of 24
Which sign of $\Delta H$ indicates an exothermic reaction at constant pressure?
Which sign of $\Delta H$ indicates an exothermic reaction at constant pressure?
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$\Delta H<0$. Exothermic reactions release heat, corresponding to a decrease in the system's enthalpy.
$\Delta H<0$. Exothermic reactions release heat, corresponding to a decrease in the system's enthalpy.
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What is the sign convention for $q$ when heat enters the system?
What is the sign convention for $q$ when heat enters the system?
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$q>0$. In thermodynamic conventions, heat absorbed by the system from surroundings is assigned a positive value.
$q>0$. In thermodynamic conventions, heat absorbed by the system from surroundings is assigned a positive value.
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What is the sign convention for $w$ when the system does work on the surroundings?
What is the sign convention for $w$ when the system does work on the surroundings?
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$w<0$. Work performed by the system on surroundings reduces the system's energy, thus assigned a negative sign.
$w<0$. Work performed by the system on surroundings reduces the system's energy, thus assigned a negative sign.
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State the first law of thermodynamics using $\Delta U$, $q$, and $w$.
State the first law of thermodynamics using $\Delta U$, $q$, and $w$.
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$\Delta U=q+w$. The first law states that internal energy change equals heat added to the system plus work done on the system.
$\Delta U=q+w$. The first law states that internal energy change equals heat added to the system plus work done on the system.
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What is the formula for pressure–volume work at constant external pressure?
What is the formula for pressure–volume work at constant external pressure?
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$w=-P_{\text{ext}}\Delta V$. For irreversible expansion at constant external pressure, work equals the negative product of pressure and volume change.
$w=-P_{\text{ext}}\Delta V$. For irreversible expansion at constant external pressure, work equals the negative product of pressure and volume change.
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For an isochoric process, what is the work $w$?
For an isochoric process, what is the work $w$?
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$w=0$. Isochoric processes involve no volume change, hence no pressure-volume work is performed.
$w=0$. Isochoric processes involve no volume change, hence no pressure-volume work is performed.
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For an adiabatic process, what is the heat transfer $q$?
For an adiabatic process, what is the heat transfer $q$?
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$q=0$. Adiabatic processes, by definition, prohibit heat exchange between the system and surroundings.
$q=0$. Adiabatic processes, by definition, prohibit heat exchange between the system and surroundings.
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What is the relationship between $\Delta H$ and $q$ at constant pressure (PV work only)?
What is the relationship between $\Delta H$ and $q$ at constant pressure (PV work only)?
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$\Delta H=q_p$. Enthalpy change equals heat transferred at constant pressure when only PV work occurs.
$\Delta H=q_p$. Enthalpy change equals heat transferred at constant pressure when only PV work occurs.
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What is the relationship between $\Delta U$ and $q$ at constant volume?
What is the relationship between $\Delta U$ and $q$ at constant volume?
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$\Delta U=q_v$. At constant volume, internal energy change equals heat transferred since no work is done.
$\Delta U=q_v$. At constant volume, internal energy change equals heat transferred since no work is done.
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State the definition of enthalpy in terms of $U$, $P$, and $V$.
State the definition of enthalpy in terms of $U$, $P$, and $V$.
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$H=U+PV$. Enthalpy accounts for internal energy plus the energy associated with pressure-volume work.
$H=U+PV$. Enthalpy accounts for internal energy plus the energy associated with pressure-volume work.
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State the ideal gas law relating $P$, $V$, $n$, and $T$.
State the ideal gas law relating $P$, $V$, $n$, and $T$.
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$PV=nRT$. The ideal gas law describes the proportional relationship between pressure, volume, moles, and temperature.
$PV=nRT$. The ideal gas law describes the proportional relationship between pressure, volume, moles, and temperature.
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What is the formula for heat absorbed at constant pressure for a temperature change $\Delta T$?
What is the formula for heat absorbed at constant pressure for a temperature change $\Delta T$?
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$q_p=nC_p\Delta T$. Heat capacity at constant pressure quantifies energy required to raise temperature for a given amount of substance.
$q_p=nC_p\Delta T$. Heat capacity at constant pressure quantifies energy required to raise temperature for a given amount of substance.
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What is the formula for heat absorbed at constant volume for a temperature change $\Delta T$?
What is the formula for heat absorbed at constant volume for a temperature change $\Delta T$?
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$q_v=nC_v\Delta T$. Heat capacity at constant volume measures energy input for temperature change without volume alteration.
$q_v=nC_v\Delta T$. Heat capacity at constant volume measures energy input for temperature change without volume alteration.
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State Hess's law for combining reaction enthalpies.
State Hess's law for combining reaction enthalpies.
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$\Delta H_{\text{net}}=\sum \Delta H_{\text{steps}}$. Since enthalpy is a state function, the net change equals the sum of stepwise changes regardless of path.
$\Delta H_{\text{net}}=\sum \Delta H_{\text{steps}}$. Since enthalpy is a state function, the net change equals the sum of stepwise changes regardless of path.
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State the definition of entropy change for a reversible process.
State the definition of entropy change for a reversible process.
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$\Delta S=\frac{q_{\text{rev}}}{T}$. For reversible processes at constant temperature, entropy change is reversible heat divided by temperature.
$\Delta S=\frac{q_{\text{rev}}}{T}$. For reversible processes at constant temperature, entropy change is reversible heat divided by temperature.
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What is the criterion for spontaneity in terms of the universe entropy change?
What is the criterion for spontaneity in terms of the universe entropy change?
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Spontaneous if $\Delta S_{\text{univ}}>0$. The second law dictates that spontaneous processes increase the total entropy of the universe.
Spontaneous if $\Delta S_{\text{univ}}>0$. The second law dictates that spontaneous processes increase the total entropy of the universe.
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State the Gibbs free energy equation relating $\Delta G$, $\Delta H$, $T$, and $\Delta S$.
State the Gibbs free energy equation relating $\Delta G$, $\Delta H$, $T$, and $\Delta S$.
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$\Delta G=\Delta H-T\Delta S$. Gibbs free energy combines enthalpy and entropy to assess spontaneity at constant temperature and pressure.
$\Delta G=\Delta H-T\Delta S$. Gibbs free energy combines enthalpy and entropy to assess spontaneity at constant temperature and pressure.
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At constant $T$ and $P$, what sign of $\Delta G$ indicates a spontaneous process?
At constant $T$ and $P$, what sign of $\Delta G$ indicates a spontaneous process?
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$\Delta G<0$. Negative Gibbs free energy change indicates the process can occur spontaneously under those conditions.
$\Delta G<0$. Negative Gibbs free energy change indicates the process can occur spontaneously under those conditions.
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What is the relationship between $\Delta G^\circ$ and the equilibrium constant $K$?
What is the relationship between $\Delta G^\circ$ and the equilibrium constant $K$?
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$\Delta G^\circ=-RT\ln K$. This equation links thermodynamic favorability under standard conditions to the equilibrium position.
$\Delta G^\circ=-RT\ln K$. This equation links thermodynamic favorability under standard conditions to the equilibrium position.
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Find $\Delta U$ if $q=-50,\text{J}$ and $w=+20,\text{J}$ for the system.
Find $\Delta U$ if $q=-50,\text{J}$ and $w=+20,\text{J}$ for the system.
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$\Delta U=-30,\text{J}$. The first law calculates internal energy change as the sum of heat and work with proper signs.
$\Delta U=-30,\text{J}$. The first law calculates internal energy change as the sum of heat and work with proper signs.
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Find $w$ if $P_{\text{ext}}=2,\text{atm}$ and the system expands by $\Delta V=3,\text{L}$.
Find $w$ if $P_{\text{ext}}=2,\text{atm}$ and the system expands by $\Delta V=3,\text{L}$.
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$w=-6,\text{L·atm}$. Expansion work against constant pressure is negative the product of pressure and volume increase.
$w=-6,\text{L·atm}$. Expansion work against constant pressure is negative the product of pressure and volume increase.
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Find $q_p$ if $n=2$ and $C_p=30,\text{J·mol}^{-1}\text{·K}^{-1}$ for $\Delta T=10,\text{K}$.
Find $q_p$ if $n=2$ and $C_p=30,\text{J·mol}^{-1}\text{·K}^{-1}$ for $\Delta T=10,\text{K}$.
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$q_p=600,\text{J}$. Constant pressure heat transfer uses molar heat capacity to relate energy to temperature change.
$q_p=600,\text{J}$. Constant pressure heat transfer uses molar heat capacity to relate energy to temperature change.
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Find $\Delta G$ at $T=300,\text{K}$ if $\Delta H=20,\text{kJ}$ and $\Delta S=50,\text{J·K}^{-1}$.
Find $\Delta G$ at $T=300,\text{K}$ if $\Delta H=20,\text{kJ}$ and $\Delta S=50,\text{J·K}^{-1}$.
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$\Delta G=5,\text{kJ}$. Gibbs free energy subtracts the entropy term from enthalpy, ensuring unit consistency in calculations.
$\Delta G=5,\text{kJ}$. Gibbs free energy subtracts the entropy term from enthalpy, ensuring unit consistency in calculations.
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What is the relationship between $C_p$ and $C_v$ for an ideal gas?
What is the relationship between $C_p$ and $C_v$ for an ideal gas?
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$C_p=C_v+R$. The difference arises from the additional work term at constant pressure for ideal gases.
$C_p=C_v+R$. The difference arises from the additional work term at constant pressure for ideal gases.
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