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  2. MCAT Chemical and Physical Foundations of Biological Systems
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MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 5d Carbonyl Chemistry Reactivity

Study 5d Carbonyl Chemistry Reactivity in MCAT Chemical and Physical Foundations of Biological Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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This deck focuses on 5d Carbonyl Chemistry Reactivity, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Chemical and Physical Foundations of Biological Systems.

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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 5d Carbonyl Chemistry Reactivity

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QUESTION

Which carbonyl derivative is formed when a carboxylic acid reacts with SOCl2\text{SOCl}_2SOCl2​?

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ANSWER

Acyl chloride. Thionyl chloride converts the carboxylic acid to a highly reactive derivative by replacing OH with Cl, releasing SO2 and HCl.

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Flashcard 1: Which carbonyl derivative is formed when a carboxylic acid reacts with SOCl2\text{SOCl}_2SOCl2​?

Answer: Acyl chloride. Thionyl chloride converts the carboxylic acid to a highly reactive derivative by replacing OH with Cl, releasing SO2 and HCl.

Flashcard 2: What carbonyl derivative is produced when an acyl chloride reacts with NH3\text{NH}_3NH3​ or an amine?

Answer: Amide. The highly electrophilic acyl chloride undergoes nucleophilic acyl substitution with ammonia or amines, displacing chloride.

Flashcard 3: What is the product when an acyl chloride reacts with an alcohol (with base present to neutralize HCl)?

Answer: Ester. Alcohols act as nucleophiles to attack the acyl chloride, forming the ester after chloride elimination, with base neutralizing HCl.

Flashcard 4: What is the product when an anhydride reacts with an alcohol under nucleophilic acyl substitution?

Answer: Ester + carboxylic acid. Alcohol attacks one carbonyl of the anhydride, leading to ester formation and release of the carboxylic acid as the leaving group.

Flashcard 5: Which option correctly states the relative leaving-group ability in acyl substitution: Cl−\text{Cl}^-Cl−, RO−\text{RO}^-RO−, NH2−\text{NH}_2^-NH2−​?

Answer: Cl−>RO−>NH2−\text{Cl}^- > \text{RO}^- > \text{NH}_2^-Cl−>RO−>NH2−​. Leaving group ability correlates with conjugate acid strength: HCl (strong) > ROH (weak) > NH3 (very weak), enabling easier departure.

Flashcard 6: What is the key structural difference between aldehydes and ketones at the carbonyl carbon?

Answer: Aldehyde has H\text{H}H; ketone has two carbon substituents. Aldehydes have a hydrogen attached to the carbonyl, while ketones have two alkyl or aryl groups, affecting reactivity and naming.

Flashcard 7: Which is more electrophilic toward nucleophilic addition: an aldehyde or a ketone?

Answer: Aldehyde. Aldehydes have less steric hindrance and fewer electron-donating alkyl groups, making their carbonyl carbon more electrophilic.

Flashcard 8: What is the product type when a carbonyl (aldehyde/ketone) reacts with NaBH4\text{NaBH}_4NaBH4​?

Answer: Alcohol (aldehyde →\rightarrow→ 1∘1^\circ1∘, ketone →\rightarrow→ 2∘2^\circ2∘). NaBH4 selectively reduces the carbonyl to an alcohol via hydride addition, yielding primary from aldehydes and secondary from ketones.

Flashcard 9: What is the product type when a ketone is treated with common oxidants such as PCC?

Answer: No reaction (ketones resist oxidation under mild conditions). Ketones lack an alpha hydrogen attached to the carbonyl like aldehydes, resisting oxidation without carbon-carbon bond cleavage.

Flashcard 10: What is the product when a carbonyl compound reacts with a primary amine under acid catalysis?

Answer: Imine (Schiff base). Acid catalysis facilitates nucleophilic addition followed by dehydration to form the C=N bond in the imine.

Flashcard 11: What is the product when a carbonyl compound reacts with a secondary amine under acid catalysis?

Answer: Enamine. Secondary amines form a carbinolamine intermediate that dehydrates to an enamine via alpha-hydrogen abstraction under acid conditions.

Flashcard 12: What is the product when a carbonyl compound reacts with an alcohol under acid catalysis and excess alcohol?

Answer: Acetal (via hemiacetal intermediate). Acid protonates the carbonyl, enabling alcohol addition to hemiacetal, followed by further substitution to the acetal with excess alcohol.

Flashcard 13: Identify the carbon adjacent to a carbonyl group that can be deprotonated to form an enolate.

Answer: The α\alphaα-carbon. The alpha-carbon bears acidic hydrogens stabilized by resonance with the carbonyl in the enolate form.

Flashcard 14: Which is more acidic: an α\alphaα-hydrogen next to a carbonyl or a typical alkane hydrogen?

Answer: α\alphaα-hydrogen next to a carbonyl. The alpha-hydrogen is acidified by resonance stabilization of the enolate anion, with pKa around 20 versus 50 for alkanes.

Flashcard 15: What is the major product class when an aldehyde reacts with HCN\text{HCN}HCN (or CN−\text{CN}^-CN− then acid)?

Answer: Cyanohydrin. Cyanide acts as a nucleophile adding to the carbonyl, forming a new C-C bond and a hydroxyl group after protonation.

Flashcard 16: Which option lists carbonyl derivatives in order of decreasing electrophilicity: acyl chloride, anhydride, ester, amide?

Answer: Acyl chloride > anhydride > ester > amide. Electrophilicity decreases due to poorer leaving groups and increased resonance stabilization from the heteroatom lone pair to the carbonyl.

Flashcard 17: What is the key resonance reason that amides are less reactive than esters toward nucleophilic acyl substitution?

Answer: Strong nN→πC=O∗n_N \rightarrow \pi^*_{C=O}nN​→πC=O∗​ donation reduces electrophilicity. This resonance delocalizes electrons, making the carbonyl carbon less electrophilic and less reactive to nucleophiles compared to esters.

Flashcard 18: What is the general mechanism name for replacing a carbonyl derivative leaving group with a nucleophile?

Answer: Nucleophilic acyl substitution (addition–elimination). The mechanism involves nucleophilic addition to form a tetrahedral intermediate, followed by elimination of the leaving group to reform the carbonyl.

Flashcard 19: Identify the required intermediate formed during nucleophilic acyl substitution at a carbonyl carbon.

Answer: Tetrahedral alkoxide intermediate. Nucleophilic attack on the carbonyl carbon collapses the pi bond, forming a tetrahedral structure before leaving group departure.

Flashcard 20: What functional group is formed when a primary alcohol reacts with a carboxylic acid under acid catalysis?

Answer: Ester. Acid catalysis protonates the carboxylic acid carbonyl, enabling nucleophilic attack by the alcohol followed by water elimination.

Flashcard 21: What is the product class when an ester undergoes base-promoted hydrolysis without acid workup?

Answer: Carboxylate + alcohol (saponification). Irreversible base hydrolysis cleaves the ester, yielding the carboxylate salt and alcohol without protonation.

Flashcard 22: What is the name of the acid-catalyzed reaction that converts a carboxylic acid and alcohol into an ester?

Answer: Fischer esterification. This reversible reaction uses acid catalysis to form the ester and water, shifting equilibrium toward products with excess reactants.

Flashcard 23: Which condition favors Fischer esterification products: excess alcohol or excess water?

Answer: Excess alcohol. Le Chatelier's principle shifts the equilibrium toward ester formation by increasing reactant concentration and removing water.

Flashcard 24: What is the product class when an ester is treated with OH−\text{OH}^-OH− and then acid workup?

Answer: Carboxylic acid + alcohol. Base hydrolysis cleaves the ester to carboxylate and alcohol, with acid workup protonating the carboxylate to the acid.