All flashcards
Flashcard 1: Which carbonyl derivative is formed when a carboxylic acid reacts with SOCl2?
Answer: Acyl chloride. Thionyl chloride converts the carboxylic acid to a highly reactive derivative by replacing OH with Cl, releasing SO2 and HCl.
Flashcard 2: What carbonyl derivative is produced when an acyl chloride reacts with NH3 or an amine?
Answer: Amide. The highly electrophilic acyl chloride undergoes nucleophilic acyl substitution with ammonia or amines, displacing chloride.
Flashcard 3: What is the product when an acyl chloride reacts with an alcohol (with base present to neutralize HCl)?
Answer: Ester. Alcohols act as nucleophiles to attack the acyl chloride, forming the ester after chloride elimination, with base neutralizing HCl.
Flashcard 4: What is the product when an anhydride reacts with an alcohol under nucleophilic acyl substitution?
Answer: Ester + carboxylic acid. Alcohol attacks one carbonyl of the anhydride, leading to ester formation and release of the carboxylic acid as the leaving group.
Flashcard 5: Which option correctly states the relative leaving-group ability in acyl substitution: Cl−, RO−, NH2−?
Answer: Cl−>RO−>NH2−. Leaving group ability correlates with conjugate acid strength: HCl (strong) > ROH (weak) > NH3 (very weak), enabling easier departure.
Flashcard 6: What is the key structural difference between aldehydes and ketones at the carbonyl carbon?
Answer: Aldehyde has H; ketone has two carbon substituents. Aldehydes have a hydrogen attached to the carbonyl, while ketones have two alkyl or aryl groups, affecting reactivity and naming.
Flashcard 7: Which is more electrophilic toward nucleophilic addition: an aldehyde or a ketone?
Answer: Aldehyde. Aldehydes have less steric hindrance and fewer electron-donating alkyl groups, making their carbonyl carbon more electrophilic.
Flashcard 8: What is the product type when a carbonyl (aldehyde/ketone) reacts with NaBH4?
Answer: Alcohol (aldehyde → 1∘, ketone → 2∘). NaBH4 selectively reduces the carbonyl to an alcohol via hydride addition, yielding primary from aldehydes and secondary from ketones.
Flashcard 9: What is the product type when a ketone is treated with common oxidants such as PCC?
Answer: No reaction (ketones resist oxidation under mild conditions). Ketones lack an alpha hydrogen attached to the carbonyl like aldehydes, resisting oxidation without carbon-carbon bond cleavage.
Flashcard 10: What is the product when a carbonyl compound reacts with a primary amine under acid catalysis?
Answer: Imine (Schiff base). Acid catalysis facilitates nucleophilic addition followed by dehydration to form the C=N bond in the imine.
Flashcard 11: What is the product when a carbonyl compound reacts with a secondary amine under acid catalysis?
Answer: Enamine. Secondary amines form a carbinolamine intermediate that dehydrates to an enamine via alpha-hydrogen abstraction under acid conditions.
Flashcard 12: What is the product when a carbonyl compound reacts with an alcohol under acid catalysis and excess alcohol?
Answer: Acetal (via hemiacetal intermediate). Acid protonates the carbonyl, enabling alcohol addition to hemiacetal, followed by further substitution to the acetal with excess alcohol.
Flashcard 13: Identify the carbon adjacent to a carbonyl group that can be deprotonated to form an enolate.
Answer: The α-carbon. The alpha-carbon bears acidic hydrogens stabilized by resonance with the carbonyl in the enolate form.
Flashcard 14: Which is more acidic: an α-hydrogen next to a carbonyl or a typical alkane hydrogen?
Answer: α-hydrogen next to a carbonyl. The alpha-hydrogen is acidified by resonance stabilization of the enolate anion, with pKa around 20 versus 50 for alkanes.
Flashcard 15: What is the major product class when an aldehyde reacts with HCN (or CN− then acid)?
Answer: Cyanohydrin. Cyanide acts as a nucleophile adding to the carbonyl, forming a new C-C bond and a hydroxyl group after protonation.
Flashcard 16: Which option lists carbonyl derivatives in order of decreasing electrophilicity: acyl chloride, anhydride, ester, amide?
Answer: Acyl chloride > anhydride > ester > amide. Electrophilicity decreases due to poorer leaving groups and increased resonance stabilization from the heteroatom lone pair to the carbonyl.
Flashcard 17: What is the key resonance reason that amides are less reactive than esters toward nucleophilic acyl substitution?
Answer: Strong nN→πC=O∗ donation reduces electrophilicity. This resonance delocalizes electrons, making the carbonyl carbon less electrophilic and less reactive to nucleophiles compared to esters.
Flashcard 18: What is the general mechanism name for replacing a carbonyl derivative leaving group with a nucleophile?
Answer: Nucleophilic acyl substitution (addition–elimination). The mechanism involves nucleophilic addition to form a tetrahedral intermediate, followed by elimination of the leaving group to reform the carbonyl.
Flashcard 19: Identify the required intermediate formed during nucleophilic acyl substitution at a carbonyl carbon.
Answer: Tetrahedral alkoxide intermediate. Nucleophilic attack on the carbonyl carbon collapses the pi bond, forming a tetrahedral structure before leaving group departure.
Flashcard 20: What functional group is formed when a primary alcohol reacts with a carboxylic acid under acid catalysis?
Answer: Ester. Acid catalysis protonates the carboxylic acid carbonyl, enabling nucleophilic attack by the alcohol followed by water elimination.
Flashcard 21: What is the product class when an ester undergoes base-promoted hydrolysis without acid workup?
Answer: Carboxylate + alcohol (saponification). Irreversible base hydrolysis cleaves the ester, yielding the carboxylate salt and alcohol without protonation.
Flashcard 22: What is the name of the acid-catalyzed reaction that converts a carboxylic acid and alcohol into an ester?
Answer: Fischer esterification. This reversible reaction uses acid catalysis to form the ester and water, shifting equilibrium toward products with excess reactants.
Flashcard 23: Which condition favors Fischer esterification products: excess alcohol or excess water?
Answer: Excess alcohol. Le Chatelier's principle shifts the equilibrium toward ester formation by increasing reactant concentration and removing water.
Flashcard 24: What is the product class when an ester is treated with OH− and then acid workup?
Answer: Carboxylic acid + alcohol. Base hydrolysis cleaves the ester to carboxylate and alcohol, with acid workup protonating the carboxylate to the acid.