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This deck focuses on 5c Chromatography Techniques, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Chemical and Physical Foundations of Biological Systems.
Study 5c Chromatography Techniques in MCAT Chemical and Physical Foundations of Biological Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Identify which has larger k′: analyte with tR=6min or tR=3min if tM=1min.
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Analyte with tR=6min has larger k′. Longer retention time yields a higher capacity factor, as k′ increases with greater (tR−tM).
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This deck focuses on 5c Chromatography Techniques, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Chemical and Physical Foundations of Biological Systems.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: Analyte with tR=6min has larger k′. Longer retention time yields a higher capacity factor, as k′ increases with greater (tR−tM).
Answer: Nonpolar stationary phase with relatively polar mobile phase. This setup reverses the polarity gradient, enabling separation based on hydrophobicity rather than polarity.
Answer: Specific ligand–target binding; elution by competitor or condition change. It exploits highly specific interactions for purification, with elution disrupting the complex without denaturing the target.
Answer: Less polar compound travels farther (higher Rf). In normal-phase setup, less polar solutes have weaker interactions with the polar stationary phase, allowing farther migration with the mobile phase.
Answer: Positively charged analytes (cations) bind most strongly. Cation-exchange resins have negatively charged groups that attract and retain positively charged species more effectively.
Answer: Separation by size using porous beads that exclude larger molecules. Smaller molecules enter pores and take longer paths, while larger ones are excluded and elute faster.
Answer: α=k1′k2′ with k2′>k1′. It measures the relative retention of two analytes, where a value greater than 1 indicates potential for separation.
Answer: More polar compound elutes first. Polar compounds interact more with the polar mobile phase, leading to weaker retention on the nonpolar stationary phase.
Answer: Two peaks are fully separated with minimal overlap at baseline. It signifies complete distinction between analytes, ensuring accurate quantification without interference.
Answer: k′=tMtR−tM. This ratio quantifies the time an analyte spends retained relative to the unretained time, indicating partition strength.
Answer: Rf=0.50. The value is the simple ratio of distances, independent of plate size, for consistent comparison across experiments.
Answer: MS (mass spectrometry). MS provides fragmentation patterns and mass-to-charge ratios, enabling structural identification beyond FID's combustion-based detection.
Answer: A polar solid surface (cellulose paper or silica/alumina on a plate). These materials provide a hydrophilic surface that interacts with polar compounds via adsorption or partitioning.
Answer: GC uses an inert carrier gas; LC uses a liquid solvent. The gaseous mobile phase in GC suits volatile compounds, while liquid in LC allows broader analyte solubility.
Answer: More polar mobile phase increases Rf values. Increased polarity enhances solute solubility in the mobile phase, reducing retention on the polar stationary phase.
Answer: Higher salt (increased ionic strength) elutes bound proteins. Elevated ionic strength competes with bound proteins for resin sites, disrupting electrostatic interactions to release them.
Answer: Higher affinity for the mobile phase elutes first. Greater interaction with the mobile phase allows the component to move faster through the column, resulting in earlier detection.
Answer: Separation by net charge via reversible binding to charged resin. Charged analytes bind electrostatically to oppositely charged sites on the resin, with elution controlled by ionic conditions.
Answer: Relative affinity for stationary phase versus mobile phase. Components with greater affinity for the stationary phase are retained longer, while those preferring the mobile phase elute sooner.
Answer: High volatility and thermal stability are required for GC. Analytes must vaporize without decomposition at column temperatures for effective gas-phase separation.
Answer: Rf=distance traveled by solvent frontdistance traveled by spot. This ratio quantifies the relative migration of a compound compared to the solvent, reflecting its partitioning behavior.
Answer: Time for an unretained species to pass through the column. It indicates the minimum time for any substance to traverse the column without retention, accounting for void volume.
Answer: Larger molecules elute first. They are sterically excluded from pores, traveling a shorter path through the column compared to smaller molecules.
Answer: Time from injection to the analyte peak maximum at the detector. It measures how long an analyte is retained in the column before reaching the detector, reflecting its interaction with the stationary phase.