Photoelectric Effect and Line Spectra (4E) - MCAT Chemical and Physical Foundations of Biological Systems
Card 1 of 25
Which hydrogen series corresponds to transitions ending at $n_f=2$ (visible region)?
Which hydrogen series corresponds to transitions ending at $n_f=2$ (visible region)?
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Balmer series. Balmer series involves transitions to n=2, yielding visible wavelengths.
Balmer series. Balmer series involves transitions to n=2, yielding visible wavelengths.
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Which hydrogen series corresponds to transitions ending at $n_f=3$?
Which hydrogen series corresponds to transitions ending at $n_f=3$?
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Paschen series. Paschen series involves transitions to n=3, producing infrared lines.
Paschen series. Paschen series involves transitions to n=3, producing infrared lines.
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What is the threshold frequency $f_0$ in terms of work function $\phi$?
What is the threshold frequency $f_0$ in terms of work function $\phi$?
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$f_0=\frac{\phi}{h}$. Threshold frequency is work function divided by Planck's constant, where photon energy just equals $\phi$.
$f_0=\frac{\phi}{h}$. Threshold frequency is work function divided by Planck's constant, where photon energy just equals $\phi$.
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Which graph is linear for photoelectric data: $K_{\max}$ vs $f$ or $K_{\max}$ vs intensity?
Which graph is linear for photoelectric data: $K_{\max}$ vs $f$ or $K_{\max}$ vs intensity?
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$K_{\max}$ vs $f$ is linear with slope $h$. $K_{\max}$ increases linearly with frequency per photoelectric equation, unlike independence from intensity.
$K_{\max}$ vs $f$ is linear with slope $h$. $K_{\max}$ increases linearly with frequency per photoelectric equation, unlike independence from intensity.
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What is the Bohr energy formula for hydrogen energy level $n$?
What is the Bohr energy formula for hydrogen energy level $n$?
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$E_n=-\frac{13.6\ \text{eV}}{n^2}$. Bohr model quantizes hydrogen electron energies, negative due to bound states relative to ionization.
$E_n=-\frac{13.6\ \text{eV}}{n^2}$. Bohr model quantizes hydrogen electron energies, negative due to bound states relative to ionization.
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What is the slope and $x$-intercept of a plot of stopping potential $V_s$ versus $f$?
What is the slope and $x$-intercept of a plot of stopping potential $V_s$ versus $f$?
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Slope $\frac{h}{e}$; $x$-intercept $f_0=\frac{\phi}{h}$. From $V_s=\frac{h}{e}f - \frac{\phi}{e}$, slope is $h/e$ and x-intercept is threshold frequency.
Slope $\frac{h}{e}$; $x$-intercept $f_0=\frac{\phi}{h}$. From $V_s=\frac{h}{e}f - \frac{\phi}{e}$, slope is $h/e$ and x-intercept is threshold frequency.
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What is the formula for the speed of light in terms of $\lambda$ and $f$?
What is the formula for the speed of light in terms of $\lambda$ and $f$?
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$c=\lambda f$. Speed of light equals wavelength times frequency for electromagnetic waves in vacuum.
$c=\lambda f$. Speed of light equals wavelength times frequency for electromagnetic waves in vacuum.
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What is the photoelectric equation relating $K_{\max}$, $hf$, and work function $\phi$?
What is the photoelectric equation relating $K_{\max}$, $hf$, and work function $\phi$?
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$K_{\max}=hf-\phi$. Maximum kinetic energy of photoelectrons equals photon energy minus work function, per Einstein's explanation.
$K_{\max}=hf-\phi$. Maximum kinetic energy of photoelectrons equals photon energy minus work function, per Einstein's explanation.
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What is the threshold wavelength $\lambda_0$ in terms of work function $\phi$?
What is the threshold wavelength $\lambda_0$ in terms of work function $\phi$?
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$\lambda_0=\frac{hc}{\phi}$. Threshold wavelength is Planck's constant times speed of light divided by work function, longest $\lambda$ for emission.
$\lambda_0=\frac{hc}{\phi}$. Threshold wavelength is Planck's constant times speed of light divided by work function, longest $\lambda$ for emission.
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What is the stopping potential relation between $K_{\max}$ and $V_s$ for an electron?
What is the stopping potential relation between $K_{\max}$ and $V_s$ for an electron?
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$K_{\max}=eV_s$. Maximum kinetic energy equals electron charge times stopping potential, converting KE to potential energy.
$K_{\max}=eV_s$. Maximum kinetic energy equals electron charge times stopping potential, converting KE to potential energy.
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What is the formula for $V_s$ in terms of $hf$ and $\phi$?
What is the formula for $V_s$ in terms of $hf$ and $\phi$?
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$V_s=\frac{hf-\phi}{e}$. Stopping potential equals photon energy minus work function divided by electron charge, from $K_{\max}=eV_s$.
$V_s=\frac{hf-\phi}{e}$. Stopping potential equals photon energy minus work function divided by electron charge, from $K_{\max}=eV_s$.
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Which quantity must exceed the work function $\phi$ for photoemission to occur?
Which quantity must exceed the work function $\phi$ for photoemission to occur?
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Photon energy $hf$ must be $\geq \phi$. Photoemission requires photon energy at least equal to work function to overcome electron binding energy.
Photon energy $hf$ must be $\geq \phi$. Photoemission requires photon energy at least equal to work function to overcome electron binding energy.
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Identify what changes when light intensity increases at fixed $f>f_0$ in the photoelectric effect.
Identify what changes when light intensity increases at fixed $f>f_0$ in the photoelectric effect.
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Photoelectron number (current) increases; $K_{\max}$ unchanged. Higher intensity provides more photons, ejecting more electrons and increasing current, but photon energy fixes $K_{\max}$.
Photoelectron number (current) increases; $K_{\max}$ unchanged. Higher intensity provides more photons, ejecting more electrons and increasing current, but photon energy fixes $K_{\max}$.
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Identify what changes when frequency $f$ increases at fixed intensity in the photoelectric effect.
Identify what changes when frequency $f$ increases at fixed intensity in the photoelectric effect.
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$K_{\max}$ and $V_s$ increase; emission requires $f\geq f_0$. Higher frequency increases photon energy, raising $K_{\max}$ and $V_s$ if above threshold for emission.
$K_{\max}$ and $V_s$ increase; emission requires $f\geq f_0$. Higher frequency increases photon energy, raising $K_{\max}$ and $V_s$ if above threshold for emission.
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What is the physical meaning of the work function $\phi$ in the photoelectric effect?
What is the physical meaning of the work function $\phi$ in the photoelectric effect?
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Minimum energy required to eject an electron from a metal. Work function represents binding energy of least-bound electrons in metal surface.
Minimum energy required to eject an electron from a metal. Work function represents binding energy of least-bound electrons in metal surface.
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What is the physical meaning of the stopping potential $V_s$ in a photoelectric experiment?
What is the physical meaning of the stopping potential $V_s$ in a photoelectric experiment?
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Retarding voltage that reduces photocurrent to zero. Stopping potential opposes kinetic energy of fastest photoelectrons, halting them at collector.
Retarding voltage that reduces photocurrent to zero. Stopping potential opposes kinetic energy of fastest photoelectrons, halting them at collector.
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What is the slope and $y$-intercept of a plot of $K_{\max}$ versus $f$?
What is the slope and $y$-intercept of a plot of $K_{\max}$ versus $f$?
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Slope $h$; intercept $-\phi$. From $K_{\max}=hf-\phi$, slope is Planck's constant and y-intercept is negative work function.
Slope $h$; intercept $-\phi$. From $K_{\max}=hf-\phi$, slope is Planck's constant and y-intercept is negative work function.
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State the formula for photon energy emitted or absorbed for a hydrogen transition $n_i\to n_f$.
State the formula for photon energy emitted or absorbed for a hydrogen transition $n_i\to n_f$.
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$\Delta E=13.6\ \text{eV}\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)$. Energy difference between levels determines photon energy in transitions, positive for emission when $n_i>n_f$.
$\Delta E=13.6\ \text{eV}\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)$. Energy difference between levels determines photon energy in transitions, positive for emission when $n_i>n_f$.
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Which direction of transition produces emission: $n_i>n_f$ or $n_i<n_f$?
Which direction of transition produces emission: $n_i>n_f$ or $n_i<n_f$?
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Emission occurs for $n_i>n_f$. Electron dropping to lower energy level releases photon energy equal to level difference.
Emission occurs for $n_i>n_f$. Electron dropping to lower energy level releases photon energy equal to level difference.
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Which direction of transition produces absorption: $n_i>n_f$ or $n_i<n_f$?
Which direction of transition produces absorption: $n_i>n_f$ or $n_i<n_f$?
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Absorption occurs for $n_i<n_f$. Electron jumping to higher energy level requires absorbing photon energy matching level difference.
Absorption occurs for $n_i<n_f$. Electron jumping to higher energy level requires absorbing photon energy matching level difference.
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What is the Rydberg formula for the wavelength of a hydrogen spectral line?
What is the Rydberg formula for the wavelength of a hydrogen spectral line?
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$\frac{1}{\lambda}=R\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)$. Rydberg formula derives from Bohr energy differences, with $R$ as constant for hydrogen spectral lines.
$\frac{1}{\lambda}=R\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)$. Rydberg formula derives from Bohr energy differences, with $R$ as constant for hydrogen spectral lines.
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Which hydrogen series corresponds to transitions ending at $n_f=1$?
Which hydrogen series corresponds to transitions ending at $n_f=1$?
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Lyman series. Lyman series involves transitions to ground state, producing UV lines.
Lyman series. Lyman series involves transitions to ground state, producing UV lines.
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Identify the photon with higher energy: one with $\lambda=400\ \text{nm}$ or $\lambda=800\ \text{nm}$.
Identify the photon with higher energy: one with $\lambda=400\ \text{nm}$ or $\lambda=800\ \text{nm}$.
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$\lambda=400\ \text{nm}$ photon has higher energy. Photon energy inversely proportional to wavelength, so shorter $\lambda$ has higher energy.
$\lambda=400\ \text{nm}$ photon has higher energy. Photon energy inversely proportional to wavelength, so shorter $\lambda$ has higher energy.
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What is the formula for photon energy in terms of frequency $f$?
What is the formula for photon energy in terms of frequency $f$?
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$E=hf$. Photon energy equals Planck's constant times frequency, linking wave and particle properties of light.
$E=hf$. Photon energy equals Planck's constant times frequency, linking wave and particle properties of light.
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What is the formula for photon energy in terms of wavelength $\lambda$?
What is the formula for photon energy in terms of wavelength $\lambda$?
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$E=\frac{hc}{\lambda}$. Photon energy is Planck's constant times speed of light divided by wavelength, derived from $E=hf$ and $c=\lambda f$.
$E=\frac{hc}{\lambda}$. Photon energy is Planck's constant times speed of light divided by wavelength, derived from $E=hf$ and $c=\lambda f$.
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