Home

Tutoring

Subjects

Live Classes

Study Coach

Essay Review

On-Demand Courses

Colleges

Games

Opening subject page...

Loading your content

  1. My Subjects
  2. MCAT Chemical and Physical Foundations of Biological Systems
  3. Flashcards

MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4e Atomic Structure Isotopes

Study 4e Atomic Structure Isotopes in MCAT Chemical and Physical Foundations of Biological Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

← Back to flashcard decks

What this deck covers

This deck focuses on 4e Atomic Structure Isotopes, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Chemical and Physical Foundations of Biological Systems.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4e Atomic Structure Isotopes

1

/ 24

0 reviewed

0% Complete

0 reviewing
QUESTION

What quantity does atomic number ZZZ represent for an element?

Tap or drag to reveal answer

ANSWER

Number of protons in the nucleus. The atomic number ZZZ defines the element's identity by specifying the number of protons, which determines its chemical properties.

Swipe Right = I Know It! 🎉

Swipe Left = Still Learning

All flashcards

Flashcard 1: What quantity does atomic number ZZZ represent for an element?

Answer: Number of protons in the nucleus. The atomic number ZZZ defines the element's identity by specifying the number of protons, which determines its chemical properties.

Flashcard 2: Identify the number of electrons in a neutral atom with atomic number ZZZ.

Answer: Electrons =Z= Z=Z. In neutral atoms, electron count equals the atomic number ZZZ to balance the positive charge from protons.

Flashcard 3: Calculate average atomic mass for 35Cl^{35}\text{Cl}35Cl at 75%75\%75% and 37Cl^{37}\text{Cl}37Cl at 25%25\%25%.

Answer: 35.5 amu35.5\ \text{amu}35.5 amu. Weighted average: 0.75×35+0.25×37=26.25+9.25=35.50.75 \times 35 + 0.25 \times 37 = 26.25 + 9.25 = 35.50.75×35+0.25×37=26.25+9.25=35.5 amu.

Flashcard 4: What is the charge (in units of eee) and approximate location of a neutron in an atom?

Answer: Charge 000; located in the nucleus. Neutrons have no net charge and contribute to the nuclear mass while stabilizing the nucleus against proton repulsion.

Flashcard 5: What is the charge (in units of eee) and approximate location of an electron in an atom?

Answer: Charge −1e-1e−1e; located outside the nucleus. Electrons possess a negative charge equal to the elementary charge and occupy orbitals in the electron cloud surrounding the nucleus.

Flashcard 6: What quantity does mass number AAA represent for a nuclide?

Answer: Total nucleons: A=p+nA = p + nA=p+n. The mass number AAA equals the sum of protons and neutrons, representing the total number of nucleons in the nucleus.

Flashcard 7: Identify the formula for neutrons nnn in terms of mass number AAA and atomic number ZZZ.

Answer: n=A−Zn = A - Zn=A−Z. Subtracting atomic number ZZZ from mass number AAA yields the neutron count, as AAA includes both protons and neutrons.

Flashcard 8: What does the notation ZAX^{A}_{Z}XZA​X specify about an atom or ion?

Answer: Element XXX, with mass AAA and atomic number ZZZ. Nuclide notation ZAX^{A}_{Z}XZA​X indicates the element symbol XXX with its specific mass number AAA and atomic number ZZZ.

Flashcard 9: What is the definition of isotopes of the same element?

Answer: Same ZZZ (protons), different AAA (neutrons). Isotopes share the same atomic number ZZZ but differ in mass number AAA due to varying neutron counts.

Flashcard 10: What is the definition of an ion in terms of electrons and protons?

Answer: Species with e−≠p+e^- \neq p^+e−=p+ (net charge not zero). An ion forms when the number of electrons differs from protons, resulting in a nonzero net charge.

Flashcard 11: State the relationship between net ionic charge, protons ppp, and electrons eee.

Answer: Net charge =p−e= p - e=p−e (in units of eee). Net charge arises from the difference between positively charged protons and negatively charged electrons.

Flashcard 12: Find the number of neutrons in 1737Cl^{37}_{17}\text{Cl}1737​Cl.

Answer: 202020 neutrons. Neutron number is calculated as mass number minus atomic number: 37−17=2037 - 17 = 2037−17=20.

Flashcard 13: Find the number of protons, neutrons, and electrons in neutral 1123Na^{23}_{11}\text{Na}1123​Na.

Answer: p=11p=11p=11, n=12n=12n=12, e=11e=11e=11. For neutral sodium, protons equal Z=11Z=11Z=11, neutrons are 23−11=1223-11=1223−11=12, and electrons match protons.

Flashcard 14: Find the number of electrons in 2656Fe3+^{56}_{26}\text{Fe}^{3+}2656​Fe3+.

Answer: 232323 electrons. The +3 charge indicates loss of 3 electrons from neutral iron's 26, leaving 23 electrons.

Flashcard 15: Find the net charge (in units of eee) for a species with p=16p=16p=16 and e=18e=18e=18.

Answer: Net charge =−2=-2=−2. Net charge is protons minus electrons: 16−18=−216 - 18 = -216−18=−2, indicating an anion.

Flashcard 16: Which option best describes a cation: loss of electrons or gain of electrons?

Answer: Loss of electrons. Cations are positively charged ions formed by losing electrons, reducing electron count below protons.

Flashcard 17: Which option best describes an anion: loss of electrons or gain of electrons?

Answer: Gain of electrons. Anions are negatively charged ions formed by gaining electrons, increasing electron count above protons.

Flashcard 18: What is the approximate relative mass of a proton compared with an electron?

Answer: Proton is about 1836×1836\times1836× the electron mass. Protons are much heavier than electrons, with a mass ratio of approximately 1836:1.

Flashcard 19: What is the approximate relative mass of a neutron compared with a proton?

Answer: Neutron mass is approximately equal to proton mass. Neutrons and protons have nearly identical masses, both contributing significantly to atomic mass.

Flashcard 20: Which subatomic particle primarily determines an element's chemical identity?

Answer: Protons (atomic number ZZZ). The number of protons determines the element's position in the periodic table and its chemical behavior.

Flashcard 21: Which subatomic particle primarily changes between isotopes of the same element?

Answer: Neutrons. Isotopes vary in neutron number while maintaining the same proton count, affecting mass but not chemical identity.

Flashcard 22: State the formula for the average atomic mass from isotopic masses and fractional abundances.

Answer: Average mass =∑i(mi×fi)= \sum_i (m_i \times f_i)=∑i​(mi​×fi​). Average atomic mass is the weighted sum of each isotope's mass mim_imi​ multiplied by its fractional abundance fif_ifi​.

Flashcard 23: What is the definition of atomic mass unit in terms of 12C^{12}\text{C}12C?

Answer: 1 amu=1121\ \text{amu} = \frac{1}{12}1 amu=121​ the mass of one 12C^{12}\text{C}12C atom. The amu is defined relative to carbon-12, where 1 amu equals one-twelfth its atomic mass.

Flashcard 24: What is the charge (in units of eee) and approximate location of a proton in an atom?

Answer: Charge +1e+1e+1e; located in the nucleus. Protons carry a positive charge equal to the elementary charge and form part of the dense central nucleus along with neutrons.