Electrochemical Cells and Redox Reactions (4C) - MCAT Chemical and Physical Foundations of Biological Systems
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What is the oxidizing agent in a redox reaction, in terms of what happens to it?
What is the oxidizing agent in a redox reaction, in terms of what happens to it?
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The oxidizing agent is reduced (gains electrons). The oxidizing agent accepts electrons from the reducing agent, thereby undergoing reduction itself in the reaction.
The oxidizing agent is reduced (gains electrons). The oxidizing agent accepts electrons from the reducing agent, thereby undergoing reduction itself in the reaction.
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What is the reducing agent in a redox reaction, in terms of what happens to it?
What is the reducing agent in a redox reaction, in terms of what happens to it?
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The reducing agent is oxidized (loses electrons). The reducing agent donates electrons to the oxidizing agent, thereby undergoing oxidation itself in the reaction.
The reducing agent is oxidized (loses electrons). The reducing agent donates electrons to the oxidizing agent, thereby undergoing oxidation itself in the reaction.
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Which electrode is the anode in any electrochemical cell, defined by the process occurring there?
Which electrode is the anode in any electrochemical cell, defined by the process occurring there?
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Anode = site of oxidation. By definition, the anode is where oxidation occurs, as electrons are released during the loss of electrons.
Anode = site of oxidation. By definition, the anode is where oxidation occurs, as electrons are released during the loss of electrons.
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At $298,\text{K}$, find $\log K$ if $n=1$ and $E^\circ_{\text{cell}}=0.0592,\text{V}$.
At $298,\text{K}$, find $\log K$ if $n=1$ and $E^\circ_{\text{cell}}=0.0592,\text{V}$.
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$\log K=1$. From $E^\circ=\frac{0.0592}{n}\log K$, rearrange to $\log K=\frac{nE^\circ}{0.0592}$, yielding 1 for given values.
$\log K=1$. From $E^\circ=\frac{0.0592}{n}\log K$, rearrange to $\log K=\frac{nE^\circ}{0.0592}$, yielding 1 for given values.
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What is the Faraday law relation between charge passed and moles of electrons transferred?
What is the Faraday law relation between charge passed and moles of electrons transferred?
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$n_{e^-}=\frac{Q}{F}$. Faraday's first law states that the moles of electrons transferred equal the total charge divided by Faraday's constant.
$n_{e^-}=\frac{Q}{F}$. Faraday's first law states that the moles of electrons transferred equal the total charge divided by Faraday's constant.
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In an electrolytic cell, what is the sign of the anode and the cathode?
In an electrolytic cell, what is the sign of the anode and the cathode?
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Anode is positive; cathode is negative. In electrolytic cells, the external power source makes the anode positive to attract anions for oxidation and the cathode negative for reduction.
Anode is positive; cathode is negative. In electrolytic cells, the external power source makes the anode positive to attract anions for oxidation and the cathode negative for reduction.
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What is the direction of electron flow in the external circuit of any electrochemical cell?
What is the direction of electron flow in the external circuit of any electrochemical cell?
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Electrons flow from anode to cathode. Electrons are produced at the anode via oxidation and consumed at the cathode via reduction, driving flow through the external circuit.
Electrons flow from anode to cathode. Electrons are produced at the anode via oxidation and consumed at the cathode via reduction, driving flow through the external circuit.
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In a galvanic cell, which way do cations and anions migrate through the salt bridge?
In a galvanic cell, which way do cations and anions migrate through the salt bridge?
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Cations to cathode; anions to anode. Cations move to the cathode to balance negative charge buildup from reduction, while anions move to the anode to balance positive charge from oxidation.
Cations to cathode; anions to anode. Cations move to the cathode to balance negative charge buildup from reduction, while anions move to the anode to balance positive charge from oxidation.
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What is the definition of standard reduction potential $E^$ for a half-reaction?
What is the definition of standard reduction potential $E^$ for a half-reaction?
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Potential for reduction under standard conditions vs SHE. Standard reduction potential measures the tendency of a species to gain electrons relative to the standard hydrogen electrode under standard conditions.
Potential for reduction under standard conditions vs SHE. Standard reduction potential measures the tendency of a species to gain electrons relative to the standard hydrogen electrode under standard conditions.
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What is the standard cell potential formula in terms of cathode and anode reduction potentials?
What is the standard cell potential formula in terms of cathode and anode reduction potentials?
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$E^\circ_{\text{cell}}=E^\circ_{\text{cathode}}-E^\circ_{\text{anode}}$. The cell potential is calculated by subtracting the anode's reduction potential from the cathode's, accounting for the oxidation at the anode.
$E^\circ_{\text{cell}}=E^\circ_{\text{cathode}}-E^\circ_{\text{anode}}$. The cell potential is calculated by subtracting the anode's reduction potential from the cathode's, accounting for the oxidation at the anode.
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If a half-reaction is reversed, how does its electrode potential change?
If a half-reaction is reversed, how does its electrode potential change?
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The sign of $E^\circ$ reverses. Reversing a half-reaction changes it from reduction to oxidation, which negates the potential value.
The sign of $E^\circ$ reverses. Reversing a half-reaction changes it from reduction to oxidation, which negates the potential value.
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When balancing a redox reaction, how does multiplying a half-reaction by $n$ affect $E^ $?
When balancing a redox reaction, how does multiplying a half-reaction by $n$ affect $E^ $?
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$E^\circ$ does not change when coefficients are scaled. Electrode potentials are intensive properties, independent of the amount of substance, so scaling coefficients does not alter $E^\circ$.
$E^\circ$ does not change when coefficients are scaled. Electrode potentials are intensive properties, independent of the amount of substance, so scaling coefficients does not alter $E^\circ$.
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What is the spontaneity criterion relating $E^\circ_{\text{cell}}$ to a galvanic reaction?
What is the spontaneity criterion relating $E^\circ_{\text{cell}}$ to a galvanic reaction?
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Spontaneous if $E^\circ_{\text{cell}}>0$. A positive cell potential indicates a favorable driving force for the reaction, making it spontaneous under standard conditions.
Spontaneous if $E^\circ_{\text{cell}}>0$. A positive cell potential indicates a favorable driving force for the reaction, making it spontaneous under standard conditions.
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What is the relationship between $\Delta G^\circ$ and $E^\circ_{\text{cell}}$?
What is the relationship between $\Delta G^\circ$ and $E^\circ_{\text{cell}}$?
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$\Delta G^\circ=-nFE^\circ_{\text{cell}}$. This equation links free energy change to electrochemical work, where $n$ is moles of electrons, $F$ is Faraday's constant, and positive $E^\circ$ yields negative $\Delta G^\circ$.
$\Delta G^\circ=-nFE^\circ_{\text{cell}}$. This equation links free energy change to electrochemical work, where $n$ is moles of electrons, $F$ is Faraday's constant, and positive $E^\circ$ yields negative $\Delta G^\circ$.
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What equation relates $E^\circ_{\text{cell}}$ to $K$ at $298,\text{K}$ using base-10 logs?
What equation relates $E^\circ_{\text{cell}}$ to $K$ at $298,\text{K}$ using base-10 logs?
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$E^\circ_{\text{cell}}=\frac{0.0592,\text{V}}{n}\log K$. Derived from combining $\Delta G^\circ=-nFE^\circ$ and $\Delta G^\circ=-RT\ln K$, simplified with base-10 log at 298 K.
$E^\circ_{\text{cell}}=\frac{0.0592,\text{V}}{n}\log K$. Derived from combining $\Delta G^\circ=-nFE^\circ$ and $\Delta G^\circ=-RT\ln K$, simplified with base-10 log at 298 K.
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What is the Nernst equation for a cell potential $E$ in terms of $E^\circ$, $n$, and $Q$ at $298,\text{K}$?
What is the Nernst equation for a cell potential $E$ in terms of $E^\circ$, $n$, and $Q$ at $298,\text{K}$?
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$E=E^\circ-\frac{0.0592,\text{V}}{n}\log Q$. The Nernst equation adjusts the standard potential for non-standard conditions using the reaction quotient $Q$ at 298 K.
$E=E^\circ-\frac{0.0592,\text{V}}{n}\log Q$. The Nernst equation adjusts the standard potential for non-standard conditions using the reaction quotient $Q$ at 298 K.
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Identify the cathode half-reaction given $E^\circ(\text{A})=+0.20,\text{V}$ and $E^\circ(\text{B})=-0.10,\text{V}$ (both as reductions).
Identify the cathode half-reaction given $E^\circ(\text{A})=+0.20,\text{V}$ and $E^\circ(\text{B})=-0.10,\text{V}$ (both as reductions).
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Cathode is A (more positive $E^\circ$). The half-reaction with the higher (more positive) reduction potential has greater tendency to be reduced, thus serving as the cathode.
Cathode is A (more positive $E^\circ$). The half-reaction with the higher (more positive) reduction potential has greater tendency to be reduced, thus serving as the cathode.
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Find $E^\circ_{\text{cell}}$ if $E^\circ_{\text{cathode}}=+0.80,\text{V}$ and $E^\circ_{\text{anode}}=-0.20,\text{V}$ (both reduction potentials).
Find $E^\circ_{\text{cell}}$ if $E^\circ_{\text{cathode}}=+0.80,\text{V}$ and $E^\circ_{\text{anode}}=-0.20,\text{V}$ (both reduction potentials).
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$E^\circ_{\text{cell}}=+1.00,\text{V}$. Using $E^\circ_{\text{cell}}=E^\circ_{\text{cathode}}-E^\circ_{\text{anode}}$, substitute values to get $+0.80 - (-0.20)=+1.00,\text{V}$.
$E^\circ_{\text{cell}}=+1.00,\text{V}$. Using $E^\circ_{\text{cell}}=E^\circ_{\text{cathode}}-E^\circ_{\text{anode}}$, substitute values to get $+0.80 - (-0.20)=+1.00,\text{V}$.
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At $298,\text{K}$, find $E$ if $E^\circ=0.30,\text{V}$, $n=2$, and $Q=10$.
At $298,\text{K}$, find $E$ if $E^\circ=0.30,\text{V}$, $n=2$, and $Q=10$.
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$E\approx^0.27,\text{V}$. Using the Nernst equation $E=E^\circ-\frac{0.0592}{n}\log Q$, substitute values to yield $0.30 - 0.0296 \times 1 \approx 0.27,\text{V}$.
$E\approx^0.27,\text{V}$. Using the Nernst equation $E=E^\circ-\frac{0.0592}{n}\log Q$, substitute values to yield $0.30 - 0.0296 \times 1 \approx 0.27,\text{V}$.
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Which electrode is the cathode in any electrochemical cell, defined by the process occurring there?
Which electrode is the cathode in any electrochemical cell, defined by the process occurring there?
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Cathode = site of reduction. By definition, the cathode is where reduction occurs, as electrons are gained during the process.
Cathode = site of reduction. By definition, the cathode is where reduction occurs, as electrons are gained during the process.
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In a galvanic (voltaic) cell, what is the sign of the anode and the cathode?
In a galvanic (voltaic) cell, what is the sign of the anode and the cathode?
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Anode is negative; cathode is positive. In galvanic cells, the anode accumulates negative charge from electron release, while the cathode is positive from electron consumption.
Anode is negative; cathode is positive. In galvanic cells, the anode accumulates negative charge from electron release, while the cathode is positive from electron consumption.
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