All flashcards
Flashcard 1: State the formula for equivalent resistance of resistors in parallel.
Answer: Req1=R11+R21+⋯. In parallel, reciprocals of resistances add due to increased conductance from multiple paths.
Flashcard 2: What is the SI unit of electric current, and what does it represent in terms of charge flow?
Answer: Ampere (A); 1A=1Cs−1. Electric current measures the rate of charge flow, defined as one coulomb per second in SI units.
Flashcard 3: State the formula for electrical energy transferred over time by a circuit element.
Answer: E=Pt. Electrical energy is the product of power and time for constant power dissipation.
Flashcard 4: State the power dissipated by a resistor in terms of voltage and resistance.
Answer: P=RV2. Power in a resistor also derives from Ohm’s law, expressed as voltage squared divided by resistance.
Flashcard 5: State the power dissipated by a resistor in terms of current and resistance.
Answer: P=I2R. For resistors, power dissipation derives from combining Ohm’s law with the general power formula, using current squared times resistance.
Flashcard 6: State the formula for electrical power dissipated by a circuit element in terms of I and V.
Answer: P=IV. Electrical power is the rate of energy transfer, given by the product of current and voltage.
Flashcard 7: Find the power dissipated by a 6Ω resistor with a 12V drop across it.
Answer: P=24W. Power dissipation is voltage squared divided by resistance.
Flashcard 8: What circuit quantity is the same across all branches in a parallel connection?
Answer: Voltage V is the same across each parallel branch. In parallel circuits, branches share the same potential difference due to common connection points.
Flashcard 9: State the formula for equivalent resistance of resistors in series.
Answer: Req=R1+R2+⋯. In series, resistances add because the same current flows through each, accumulating opposition.
Flashcard 10: What is the definition of an ohmic device in terms of the I-V relationship?
Answer: It has constant R; I∝V (linear I-V curve). An ohmic device obeys Ohm’s law with constant resistance, yielding a linear current-voltage relationship.
Flashcard 11: State the formula for Ohm’s law relating voltage, current, and resistance.
Answer: V=IR. Ohm’s law states that potential difference is directly proportional to current, with resistance as the proportionality constant.
Flashcard 12: Find the power dissipated by a 4Ω resistor when the current is 3A.
Answer: P=36W. Power dissipation uses current squared multiplied by resistance.
Flashcard 13: What is the SI unit of electric potential difference (voltage), expressed using base SI units?
Answer: Volt (V); 1V=1JC−1. Voltage represents the potential energy difference per unit charge, equivalent to one joule per coulomb.
Flashcard 14: What is the SI unit of resistance, expressed using volts and amperes?
Answer: Ohm (Ω); 1Ω=1VA−1. Resistance quantifies opposition to current flow, defined as one volt per ampere.
Flashcard 15: State Kirchhoff’s current law (KCL) for a node in a circuit.
Answer: ∑Iin=∑Iout. Kirchhoff’s current law enforces charge conservation at a node, balancing incoming and outgoing currents.
Flashcard 16: State Kirchhoff’s voltage law (KVL) for a closed loop in a circuit.
Answer: ∑ΔV=0 around any closed loop. Kirchhoff’s voltage law upholds energy conservation, summing potential differences to zero in a closed loop.
Flashcard 17: What is the relationship between resistance, resistivity, length, and cross-sectional area?
Answer: R=ρAL. Resistance scales with material resistivity and length while inversely with cross-sectional area.
Flashcard 18: If wire length L doubles (same ρ and A), how does resistance change?
Answer: R doubles: R∝L. Resistance is directly proportional to length, so doubling length doubles resistance.
Flashcard 19: If wire cross-sectional area A doubles (same ρ and L), how does resistance change?
Answer: R halves: R∝A1. Resistance is inversely proportional to cross-sectional area, so doubling area halves resistance.
Flashcard 20: Find the current when a 12V battery is connected to a 3Ω resistor.
Answer: I=4A. Ohm’s law gives current as voltage divided by resistance.
Flashcard 21: Find the voltage drop across a 5Ω resistor carrying 2A of current.
Answer: V=10V. Ohm’s law calculates voltage as current multiplied by resistance.
Flashcard 22: Find the equivalent resistance of 2Ω and 3Ω connected in series.
Answer: Req=5Ω. Equivalent resistance in series is the sum of individual resistances.
Flashcard 23: Find the equivalent resistance of 2Ω and 3Ω connected in parallel.
Answer: Req=56Ω. Equivalent resistance in parallel is the reciprocal of the sum of reciprocals.
Flashcard 24: Identify the equivalent resistance of three identical resistors R connected in parallel.
Answer: Req=3R. For identical parallel resistors, equivalent resistance equals individual resistance divided by the number.
Flashcard 25: What circuit quantity is the same through all elements in a series connection?
Answer: Current I is the same through each series element. In series circuits, conservation of charge ensures identical current through all elements.