All flashcards
Flashcard 1: What is the shear stress magnitude at the tube wall in laminar flow with pressure drop ΔP over length L?
Answer: τw=2LΔPR. Wall shear stress balances the pressure force over the tube's length, derived from force equilibrium in cylindrical coordinates.
Flashcard 2: What is the Reynolds number formula for flow in a tube using density ρ, speed v, diameter D, and viscosity η?
Answer: Re=ηρvD. Reynolds number quantifies the ratio of inertial to viscous forces, using diameter for pipe flow characterization.
Flashcard 3: Which flow regime is typically assumed for Poiseuille flow: laminar or turbulent?
Answer: Laminar flow. Poiseuille flow derives under assumptions of steady, incompressible, laminar conditions with fully developed velocity profiles.
Flashcard 4: Using Poiseuille flow, how does Q scale with pressure difference ΔP (all else constant)?
Answer: Q∝ΔP. Pressure difference drives flow, resulting in direct proportionality with flow rate in laminar conditions per Poiseuille's law.
Flashcard 5: What is the relationship between maximum and average speed in Poiseuille flow?
Answer: vmax=2vavg. In parabolic laminar flow, the centerline maximum velocity is twice the cross-sectional average due to the velocity distribution.
Flashcard 6: What boundary condition at the wall is assumed in Poiseuille flow (name the condition)?
Answer: No-slip condition: v=0 at the wall. The no-slip condition assumes fluid adheres to solid surfaces, leading to zero velocity at tube walls in viscous flows.
Flashcard 7: Identify the approximate Reynolds number threshold above which pipe flow tends to become turbulent.
Answer: Turbulence tends to occur for Re≳2000. The threshold indicates transition from laminar to turbulent regimes, where inertial forces dominate viscous damping in pipe flows.
Flashcard 8: If tube radius doubles (r→2r), by what factor does Q change (Poiseuille, constant ΔP)?
Answer: Q increases by a factor of 16. Doubling radius raises flow rate by 24=16 due to the strong geometric dependence in Poiseuille's equation.
Flashcard 9: If viscosity triples (η→3η), by what factor does Q change (Poiseuille, constant ΔP)?
Answer: Q decreases by a factor of 3. Tripling viscosity reduces flow rate to one-third, as it inversely scales in Poiseuille flow under constant conditions.
Flashcard 10: If tube length halves (L→2L), by what factor does Q change (Poiseuille, constant ΔP)?
Answer: Q increases by a factor of 2. Halving length halves resistance, doubling flow rate since flow is inversely proportional to length in Poiseuille's law.
Flashcard 11: If pressure difference doubles (ΔP→2ΔP), by what factor does Q change (Poiseuille)?
Answer: Q increases by a factor of 2. Doubling pressure gradient linearly increases driving force, thus doubling volumetric flow rate in laminar flow.
Flashcard 12: Two identical tubes are placed in series; by what factor does total resistance R change versus one tube?
Answer: Total R increases by a factor of 2. Series connection adds resistances linearly, doubling total resistance for identical tubes analogous to electrical circuits.
Flashcard 13: What is the velocity profile v(r) for laminar Poiseuille flow in a tube of radius R?
Answer: v(r)=4ηLΔP(R2−r2). The parabolic profile results from viscous drag, with velocity maximum at the center and zero at walls due to no-slip.
Flashcard 14: What is the definition of dynamic viscosity η in terms of shear stress and velocity gradient?
Answer: η=dydvτ. Dynamic viscosity quantifies a fluid's resistance to shear, defined as the shear stress divided by the rate of change of velocity perpendicular to the flow direction.
Flashcard 15: What SI unit is used for dynamic viscosity η?
Answer: Pa⋅s=m2N⋅s=m⋅skg. The SI unit for dynamic viscosity derives from force per area times time, equivalent to pascal-seconds or its breakdowns in base units.
Flashcard 16: What is the definition of kinematic viscosity ν in terms of η and density ρ?
Answer: ν=ρη. Kinematic viscosity represents the ratio of dynamic viscosity to fluid density, indicating momentum diffusivity.
Flashcard 17: What SI unit is used for kinematic viscosity ν?
Answer: sm2. Kinematic viscosity's SI unit is area per time, reflecting its role in momentum diffusion without density dependence.
Flashcard 18: What does it mean for a fluid to be Newtonian regarding the relation between τ and dydv?
Answer: τ∝dydv with constant η. Newtonian fluids exhibit a linear relationship between shear stress and velocity gradient, maintaining constant viscosity independent of shear rate.
Flashcard 19: State the volumetric flow rate (Poiseuille) equation for laminar flow in a cylindrical tube.
Answer: Q=8ηLπr4ΔP. Poiseuille's equation describes laminar flow rate driven by pressure difference, inversely affected by viscosity and length while strongly dependent on radius to the fourth power.
Flashcard 20: State the hydraulic resistance R for laminar flow in a cylindrical tube, defined by ΔP=QR.
Answer: R=πr48ηL. Hydraulic resistance analogs to electrical resistance, where flow rate relates to pressure drop, incorporating geometric and viscous factors for cylindrical tubes.
Flashcard 21: What is the relation between average flow speed vavg, flow rate Q, and radius r?
Answer: vavg=πr2Q. Average flow speed equals volumetric flow rate divided by cross-sectional area, assuming uniform density in incompressible fluids.
Flashcard 22: Using Poiseuille flow, how does Q scale with tube radius r (all else constant)?
Answer: Q∝r4. In Poiseuille flow, the fourth-power dependence on radius arises from the integration of the parabolic velocity profile over the tube's cross-section.
Flashcard 23: Using Poiseuille flow, how does Q scale with viscosity η (all else constant)?
Answer: Q∝η1. Viscosity resists fluid motion, so flow rate decreases inversely with increasing viscosity under constant pressure and geometry.
Flashcard 24: Using Poiseuille flow, how does Q scale with tube length L (all else constant)?
Answer: Q∝L1. Longer tubes increase frictional losses, making flow rate inversely proportional to length for a given pressure drop.
Flashcard 25: Two identical tubes are placed in parallel; by what factor does total resistance R change versus one tube?
Answer: Total R decreases by a factor of 2. Parallel connection halves effective resistance as reciprocals add, increasing overall flow capacity for identical tubes.