Home

Tutoring

Subjects

Live Classes

Study Coach

Essay Review

On-Demand Courses

Colleges

Games

Opening subject page...

Loading your content

  1. My Subjects
  2. MCAT Chemical and Physical Foundations of Biological Systems
  3. Flashcards

MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4b Viscosity Poiseuille Flow

Study 4b Viscosity Poiseuille Flow in MCAT Chemical and Physical Foundations of Biological Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

← Back to flashcard decks

What this deck covers

This deck focuses on 4b Viscosity Poiseuille Flow, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Chemical and Physical Foundations of Biological Systems.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4b Viscosity Poiseuille Flow

1

/ 25

0 reviewed

0% Complete

0 reviewing
QUESTION

What is the shear stress magnitude at the tube wall in laminar flow with pressure drop ΔP\Delta PΔP over length LLL?

Tap or drag to reveal answer

ANSWER

τw=ΔP R2L\tau_w=\frac{\Delta P\,R}{2L}τw​=2LΔPR​. Wall shear stress balances the pressure force over the tube's length, derived from force equilibrium in cylindrical coordinates.

Swipe Right = I Know It! 🎉

Swipe Left = Still Learning

All flashcards

Flashcard 1: What is the shear stress magnitude at the tube wall in laminar flow with pressure drop ΔP\Delta PΔP over length LLL?

Answer: τw=ΔP R2L\tau_w=\frac{\Delta P\,R}{2L}τw​=2LΔPR​. Wall shear stress balances the pressure force over the tube's length, derived from force equilibrium in cylindrical coordinates.

Flashcard 2: What is the Reynolds number formula for flow in a tube using density ρ\rhoρ, speed vvv, diameter DDD, and viscosity η\etaη?

Answer: Re=ρvDη\text{Re}=\frac{\rho v D}{\eta}Re=ηρvD​. Reynolds number quantifies the ratio of inertial to viscous forces, using diameter for pipe flow characterization.

Flashcard 3: Which flow regime is typically assumed for Poiseuille flow: laminar or turbulent?

Answer: Laminar flow. Poiseuille flow derives under assumptions of steady, incompressible, laminar conditions with fully developed velocity profiles.

Flashcard 4: Using Poiseuille flow, how does QQQ scale with pressure difference ΔP\Delta PΔP (all else constant)?

Answer: Q∝ΔPQ\propto\Delta PQ∝ΔP. Pressure difference drives flow, resulting in direct proportionality with flow rate in laminar conditions per Poiseuille's law.

Flashcard 5: What is the relationship between maximum and average speed in Poiseuille flow?

Answer: vmax⁡=2vavgv_{\max}=2v_{\text{avg}}vmax​=2vavg​. In parabolic laminar flow, the centerline maximum velocity is twice the cross-sectional average due to the velocity distribution.

Flashcard 6: What boundary condition at the wall is assumed in Poiseuille flow (name the condition)?

Answer: No-slip condition: v=0v=0v=0 at the wall. The no-slip condition assumes fluid adheres to solid surfaces, leading to zero velocity at tube walls in viscous flows.

Flashcard 7: Identify the approximate Reynolds number threshold above which pipe flow tends to become turbulent.

Answer: Turbulence tends to occur for Re≳2000\text{Re}\gtrsim 2000Re≳2000. The threshold indicates transition from laminar to turbulent regimes, where inertial forces dominate viscous damping in pipe flows.

Flashcard 8: If tube radius doubles (r→2rr\to 2rr→2r), by what factor does QQQ change (Poiseuille, constant ΔP\Delta PΔP)?

Answer: QQQ increases by a factor of 161616. Doubling radius raises flow rate by 24=162^4=1624=16 due to the strong geometric dependence in Poiseuille's equation.

Flashcard 9: If viscosity triples (η→3η\eta\to 3\etaη→3η), by what factor does QQQ change (Poiseuille, constant ΔP\Delta PΔP)?

Answer: QQQ decreases by a factor of 333. Tripling viscosity reduces flow rate to one-third, as it inversely scales in Poiseuille flow under constant conditions.

Flashcard 10: If tube length halves (L→L2L\to \frac{L}{2}L→2L​), by what factor does QQQ change (Poiseuille, constant ΔP\Delta PΔP)?

Answer: QQQ increases by a factor of 222. Halving length halves resistance, doubling flow rate since flow is inversely proportional to length in Poiseuille's law.

Flashcard 11: If pressure difference doubles (ΔP→2ΔP\Delta P\to 2\Delta PΔP→2ΔP), by what factor does QQQ change (Poiseuille)?

Answer: QQQ increases by a factor of 222. Doubling pressure gradient linearly increases driving force, thus doubling volumetric flow rate in laminar flow.

Flashcard 12: Two identical tubes are placed in series; by what factor does total resistance RRR change versus one tube?

Answer: Total RRR increases by a factor of 222. Series connection adds resistances linearly, doubling total resistance for identical tubes analogous to electrical circuits.

Flashcard 13: What is the velocity profile v(r)v(r)v(r) for laminar Poiseuille flow in a tube of radius RRR?

Answer: v(r)=ΔP4ηL(R2−r2)v(r)=\frac{\Delta P}{4\eta L}\left(R^2-r^2\right)v(r)=4ηLΔP​(R2−r2). The parabolic profile results from viscous drag, with velocity maximum at the center and zero at walls due to no-slip.

Flashcard 14: What is the definition of dynamic viscosity η\etaη in terms of shear stress and velocity gradient?

Answer: η=τdvdy\eta=\frac{\tau}{\frac{dv}{dy}}η=dydv​τ​. Dynamic viscosity quantifies a fluid's resistance to shear, defined as the shear stress divided by the rate of change of velocity perpendicular to the flow direction.

Flashcard 15: What SI unit is used for dynamic viscosity η\etaη?

Answer: Pa⋅s=N⋅sm2=kgm⋅s\text{Pa}\cdot\text{s}=\frac{\text{N}\cdot\text{s}}{\text{m}^2}=\frac{\text{kg}}{\text{m}\cdot\text{s}}Pa⋅s=m2N⋅s​=m⋅skg​. The SI unit for dynamic viscosity derives from force per area times time, equivalent to pascal-seconds or its breakdowns in base units.

Flashcard 16: What is the definition of kinematic viscosity ν\nuν in terms of η\etaη and density ρ\rhoρ?

Answer: ν=ηρ\nu=\frac{\eta}{\rho}ν=ρη​. Kinematic viscosity represents the ratio of dynamic viscosity to fluid density, indicating momentum diffusivity.

Flashcard 17: What SI unit is used for kinematic viscosity ν\nuν?

Answer: m2s\frac{\text{m}^2}{\text{s}}sm2​. Kinematic viscosity's SI unit is area per time, reflecting its role in momentum diffusion without density dependence.

Flashcard 18: What does it mean for a fluid to be Newtonian regarding the relation between τ\tauτ and dvdy\frac{dv}{dy}dydv​?

Answer: τ∝dvdy\tau\propto\frac{dv}{dy}τ∝dydv​ with constant η\etaη. Newtonian fluids exhibit a linear relationship between shear stress and velocity gradient, maintaining constant viscosity independent of shear rate.

Flashcard 19: State the volumetric flow rate (Poiseuille) equation for laminar flow in a cylindrical tube.

Answer: Q=πr4ΔP8ηLQ=\frac{\pi r^4\Delta P}{8\eta L}Q=8ηLπr4ΔP​. Poiseuille's equation describes laminar flow rate driven by pressure difference, inversely affected by viscosity and length while strongly dependent on radius to the fourth power.

Flashcard 20: State the hydraulic resistance RRR for laminar flow in a cylindrical tube, defined by ΔP=QR\Delta P=QRΔP=QR.

Answer: R=8ηLπr4R=\frac{8\eta L}{\pi r^4}R=πr48ηL​. Hydraulic resistance analogs to electrical resistance, where flow rate relates to pressure drop, incorporating geometric and viscous factors for cylindrical tubes.

Flashcard 21: What is the relation between average flow speed vavgv_{\text{avg}}vavg​, flow rate QQQ, and radius rrr?

Answer: vavg=Qπr2v_{\text{avg}}=\frac{Q}{\pi r^2}vavg​=πr2Q​. Average flow speed equals volumetric flow rate divided by cross-sectional area, assuming uniform density in incompressible fluids.

Flashcard 22: Using Poiseuille flow, how does QQQ scale with tube radius rrr (all else constant)?

Answer: Q∝r4Q\propto r^4Q∝r4. In Poiseuille flow, the fourth-power dependence on radius arises from the integration of the parabolic velocity profile over the tube's cross-section.

Flashcard 23: Using Poiseuille flow, how does QQQ scale with viscosity η\etaη (all else constant)?

Answer: Q∝1ηQ\propto\frac{1}{\eta}Q∝η1​. Viscosity resists fluid motion, so flow rate decreases inversely with increasing viscosity under constant pressure and geometry.

Flashcard 24: Using Poiseuille flow, how does QQQ scale with tube length LLL (all else constant)?

Answer: Q∝1LQ\propto\frac{1}{L}Q∝L1​. Longer tubes increase frictional losses, making flow rate inversely proportional to length for a given pressure drop.

Flashcard 25: Two identical tubes are placed in parallel; by what factor does total resistance RRR change versus one tube?

Answer: Total RRR decreases by a factor of 222. Parallel connection halves effective resistance as reciprocals add, increasing overall flow capacity for identical tubes.