Gas Laws and Kinetic Molecular Theory (4B) - MCAT Chemical and Physical Foundations of Biological Systems
Card 1 of 25
State the combined gas law relating $P$, $V$, and $T$ for a fixed amount of gas.
State the combined gas law relating $P$, $V$, and $T$ for a fixed amount of gas.
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$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$. The combined gas law integrates Boyle's, Charles's, and Gay-Lussac's laws for a constant amount of gas.
$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$. The combined gas law integrates Boyle's, Charles's, and Gay-Lussac's laws for a constant amount of gas.
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What is the value of $R$ in $\text{J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}$?
What is the value of $R$ in $\text{J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}$?
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$R = 8.314\ \text{J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}$. This value of $R$ is employed in the ideal gas law when energy units (joules) are required.
$R = 8.314\ \text{J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}$. This value of $R$ is employed in the ideal gas law when energy units (joules) are required.
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What is the Kelvin temperature conversion formula from Celsius $\left(^\circ\text{C}\right)$?
What is the Kelvin temperature conversion formula from Celsius $\left(^\circ\text{C}\right)$?
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$T(\text{K}) = T(^\circ\text{C}) + 273.15$. Absolute temperature in Kelvin is obtained by adding 273.15 to the Celsius temperature to align with the ideal gas law scale.
$T(\text{K}) = T(^\circ\text{C}) + 273.15$. Absolute temperature in Kelvin is obtained by adding 273.15 to the Celsius temperature to align with the ideal gas law scale.
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What is the standard temperature and pressure (STP) definition used on the MCAT?
What is the standard temperature and pressure (STP) definition used on the MCAT?
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$T = 273.15\ \text{K},\ P = 1\ \text{atm}$. STP conditions provide a reference point for gas properties, with temperature at freezing point of water in Kelvin and pressure at sea level.
$T = 273.15\ \text{K},\ P = 1\ \text{atm}$. STP conditions provide a reference point for gas properties, with temperature at freezing point of water in Kelvin and pressure at sea level.
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State the relationship between partial pressure and mole fraction for an ideal gas mixture.
State the relationship between partial pressure and mole fraction for an ideal gas mixture.
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$P_i = x_i P_{\text{total}}$. Partial pressure of a gas in a mixture is its mole fraction times the total pressure, assuming ideal behavior.
$P_i = x_i P_{\text{total}}$. Partial pressure of a gas in a mixture is its mole fraction times the total pressure, assuming ideal behavior.
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What molar volume does an ideal gas occupy at STP (approximate MCAT value)?
What molar volume does an ideal gas occupy at STP (approximate MCAT value)?
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$22.4\ \text{L mol}^{-1}$. At STP, one mole of ideal gas occupies this volume, derived from the ideal gas law with $P=1$ atm and $T=273$ K.
$22.4\ \text{L mol}^{-1}$. At STP, one mole of ideal gas occupies this volume, derived from the ideal gas law with $P=1$ atm and $T=273$ K.
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State Dalton's law formula for total pressure of a gas mixture.
State Dalton's law formula for total pressure of a gas mixture.
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$P_{\text{total}} = \sum_i P_i$. Dalton's law states that in a mixture of non-reacting gases, total pressure equals the sum of each gas's partial pressure.
$P_{\text{total}} = \sum_i P_i$. Dalton's law states that in a mixture of non-reacting gases, total pressure equals the sum of each gas's partial pressure.
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Find $P_{\text{He}}$ if $x_{\text{He}} = 0.25$ and $P_{\text{total}} = 4\ \text{atm}$ for an ideal mixture.
Find $P_{\text{He}}$ if $x_{\text{He}} = 0.25$ and $P_{\text{total}} = 4\ \text{atm}$ for an ideal mixture.
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$P_{\text{He}} = 1\ \text{atm}$. Partial pressure equals mole fraction times total pressure in an ideal gas mixture per Dalton's law.
$P_{\text{He}} = 1\ \text{atm}$. Partial pressure equals mole fraction times total pressure in an ideal gas mixture per Dalton's law.
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State the formula for Boyle's law relating pressure and volume at constant $T$ and $n$.
State the formula for Boyle's law relating pressure and volume at constant $T$ and $n$.
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$P_1V_1 = P_2V_2$. Boyle's law describes the inverse relationship between pressure and volume for a fixed amount of gas at constant temperature.
$P_1V_1 = P_2V_2$. Boyle's law describes the inverse relationship between pressure and volume for a fixed amount of gas at constant temperature.
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State the formula for Charles's law relating volume and temperature at constant $P$ and $n$.
State the formula for Charles's law relating volume and temperature at constant $P$ and $n$.
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$\frac{V_1}{T_1} = \frac{V_2}{T_2}$. Charles's law indicates that volume is directly proportional to absolute temperature for a gas at constant pressure and moles.
$\frac{V_1}{T_1} = \frac{V_2}{T_2}$. Charles's law indicates that volume is directly proportional to absolute temperature for a gas at constant pressure and moles.
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State the formula for Gay-Lussac's law relating pressure and temperature at constant $V$ and $n$.
State the formula for Gay-Lussac's law relating pressure and temperature at constant $V$ and $n$.
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$\frac{P_1}{T_1} = \frac{P_2}{T_2}$. Gay-Lussac's law shows that pressure is directly proportional to absolute temperature for a gas at constant volume and moles.
$\frac{P_1}{T_1} = \frac{P_2}{T_2}$. Gay-Lussac's law shows that pressure is directly proportional to absolute temperature for a gas at constant volume and moles.
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State the formula for Avogadro's law relating volume and moles at constant $P$ and $T$.
State the formula for Avogadro's law relating volume and moles at constant $P$ and $T$.
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$\frac{V_1}{n_1} = \frac{V_2}{n_2}$. Avogadro's law states that volume is directly proportional to the number of moles for a gas at constant pressure and temperature.
$\frac{V_1}{n_1} = \frac{V_2}{n_2}$. Avogadro's law states that volume is directly proportional to the number of moles for a gas at constant pressure and temperature.
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State the ideal gas law equation relating $P$, $V$, $n$, $R$, and $T$.
State the ideal gas law equation relating $P$, $V$, $n$, $R$, and $T$.
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$PV = nRT$. The ideal gas law combines relationships among pressure, volume, moles, and temperature for an ideal gas using the gas constant $R$.
$PV = nRT$. The ideal gas law combines relationships among pressure, volume, moles, and temperature for an ideal gas using the gas constant $R$.
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What is the value of the ideal gas constant $R$ in $\text{L}\cdot\text{atm}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}$?
What is the value of the ideal gas constant $R$ in $\text{L}\cdot\text{atm}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}$?
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$R = 0.08206\ \text{L}\cdot\text{atm}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}$. This value of $R$ is used when pressure is in atm, volume in L, and temperature in K for the ideal gas law.
$R = 0.08206\ \text{L}\cdot\text{atm}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}$. This value of $R$ is used when pressure is in atm, volume in L, and temperature in K for the ideal gas law.
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Find $n$ if $P = 2\ \text{atm}$, $V = 5\ \text{L}$, $T = 300\ \text{K}$, and $R = 0.082\ \text{L atm mol}^{-1}\text{K}^{-1}$.
Find $n$ if $P = 2\ \text{atm}$, $V = 5\ \text{L}$, $T = 300\ \text{K}$, and $R = 0.082\ \text{L atm mol}^{-1}\text{K}^{-1}$.
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$n \approx 0.41\ \text{mol}$. Solving the ideal gas law for $n$ gives moles as pressure times volume over $R$ times temperature.
$n \approx 0.41\ \text{mol}$. Solving the ideal gas law for $n$ gives moles as pressure times volume over $R$ times temperature.
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Find $P_2$ if $P_1 = 1.5\ \text{atm}$, $T_1 = 300\ \text{K}$, and $T_2 = 200\ \text{K}$ at constant $V$.
Find $P_2$ if $P_1 = 1.5\ \text{atm}$, $T_1 = 300\ \text{K}$, and $T_2 = 200\ \text{K}$ at constant $V$.
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$P_2 = 1.0\ \text{atm}$. By Gay-Lussac's law, pressure decreases with the ratio of temperatures at constant volume.
$P_2 = 1.0\ \text{atm}$. By Gay-Lussac's law, pressure decreases with the ratio of temperatures at constant volume.
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Find $V_2$ if $V_1 = 4\ \text{L}$, $T_1 = 300\ \text{K}$, and $T_2 = 450\ \text{K}$ at constant $P$.
Find $V_2$ if $V_1 = 4\ \text{L}$, $T_1 = 300\ \text{K}$, and $T_2 = 450\ \text{K}$ at constant $P$.
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$V_2 = 6\ \text{L}$. Using Charles's law, volume increases proportionally with the ratio of temperatures at constant pressure.
$V_2 = 6\ \text{L}$. Using Charles's law, volume increases proportionally with the ratio of temperatures at constant pressure.
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Find $V_2$ if $P_1 = 2\ \text{atm}$, $V_1 = 3\ \text{L}$, and $P_2 = 1\ \text{atm}$ at constant $T$.
Find $V_2$ if $P_1 = 2\ \text{atm}$, $V_1 = 3\ \text{L}$, and $P_2 = 1\ \text{atm}$ at constant $T$.
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$V_2 = 6\ \text{L}$. Applying Boyle's law, volume doubles when pressure halves at constant temperature.
$V_2 = 6\ \text{L}$. Applying Boyle's law, volume doubles when pressure halves at constant temperature.
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Identify the condition when real gases deviate most from ideal behavior (in terms of $P$ and $T$).
Identify the condition when real gases deviate most from ideal behavior (in terms of $P$ and $T$).
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High $P$ and low $T$. Real gases deviate from ideality when intermolecular forces and particle volume become significant under high pressure and low temperature.
High $P$ and low $T$. Real gases deviate from ideality when intermolecular forces and particle volume become significant under high pressure and low temperature.
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Identify the key ideal-gas assumptions about particle volume and intermolecular forces.
Identify the key ideal-gas assumptions about particle volume and intermolecular forces.
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Negligible particle volume; no intermolecular attractions or repulsions. Ideal gas assumptions simplify behavior by treating particles as point masses with no volume and no interactions except elastic collisions.
Negligible particle volume; no intermolecular attractions or repulsions. Ideal gas assumptions simplify behavior by treating particles as point masses with no volume and no interactions except elastic collisions.
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State Graham's law for the ratio of diffusion (or effusion) rates of two gases.
State Graham's law for the ratio of diffusion (or effusion) rates of two gases.
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$\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}}$. Graham's law indicates that diffusion or effusion rates are inversely proportional to the square root of molar masses.
$\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}}$. Graham's law indicates that diffusion or effusion rates are inversely proportional to the square root of molar masses.
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State the root-mean-square speed formula $u_{\text{rms}}$ for an ideal gas.
State the root-mean-square speed formula $u_{\text{rms}}$ for an ideal gas.
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$u_{\text{rms}} = \sqrt{\frac{3RT}{M}}$. Root-mean-square speed measures the square root of the average of squared speeds, depending on temperature and molar mass $M$.
$u_{\text{rms}} = \sqrt{\frac{3RT}{M}}$. Root-mean-square speed measures the square root of the average of squared speeds, depending on temperature and molar mass $M$.
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State the molar-average kinetic energy relation to temperature using $R$.
State the molar-average kinetic energy relation to temperature using $R$.
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$\langle KE \rangle_{\text{mol}} = \frac{3}{2}RT$. For one mole, average kinetic energy relates to temperature via the gas constant $R$, derived from per-molecule kinetic energy.
$\langle KE \rangle_{\text{mol}} = \frac{3}{2}RT$. For one mole, average kinetic energy relates to temperature via the gas constant $R$, derived from per-molecule kinetic energy.
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State the kinetic molecular theory relation between average kinetic energy and temperature.
State the kinetic molecular theory relation between average kinetic energy and temperature.
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$\langle KE \rangle = \frac{3}{2}k_BT$. Kinetic molecular theory posits that average kinetic energy per molecule is directly proportional to absolute temperature, with $k_B$ as Boltzmann's constant.
$\langle KE \rangle = \frac{3}{2}k_BT$. Kinetic molecular theory posits that average kinetic energy per molecule is directly proportional to absolute temperature, with $k_B$ as Boltzmann's constant.
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State the mole fraction definition for component $i$ in a gas mixture.
State the mole fraction definition for component $i$ in a gas mixture.
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$x_i = \frac{n_i}{n_{\text{total}}}$. Mole fraction represents the ratio of moles of one component to total moles in the mixture.
$x_i = \frac{n_i}{n_{\text{total}}}$. Mole fraction represents the ratio of moles of one component to total moles in the mixture.
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