Home

Tutoring

Subjects

Live Classes

Study Coach

Essay Review

On-Demand Courses

Colleges

Games

Opening subject page...

Loading your content

  1. My Subjects
  2. MCAT Chemical and Physical Foundations of Biological Systems
  3. Flashcards

MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4b Gas Laws Kinetic Molecular Theory

Study 4b Gas Laws Kinetic Molecular Theory in MCAT Chemical and Physical Foundations of Biological Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

← Back to flashcard decks

What this deck covers

This deck focuses on 4b Gas Laws Kinetic Molecular Theory, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Chemical and Physical Foundations of Biological Systems.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4b Gas Laws Kinetic Molecular Theory

1

/ 25

0 reviewed

0% Complete

0 reviewing
QUESTION

State the combined gas law relating PPP, VVV, and TTT for a fixed amount of gas.

Tap or drag to reveal answer

ANSWER

P1V1T1=P2V2T2\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}T1​P1​V1​​=T2​P2​V2​​. The combined gas law integrates Boyle's, Charles's, and Gay-Lussac's laws for a constant amount of gas.

Swipe Right = I Know It! 🎉

Swipe Left = Still Learning

All flashcards

Flashcard 1: State the combined gas law relating PPP, VVV, and TTT for a fixed amount of gas.

Answer: P1V1T1=P2V2T2\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}T1​P1​V1​​=T2​P2​V2​​. The combined gas law integrates Boyle's, Charles's, and Gay-Lussac's laws for a constant amount of gas.

Flashcard 2: What is the value of RRR in J⋅mol−1⋅K−1\text{J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}J⋅mol−1⋅K−1?

Answer: R=8.314 J⋅mol−1⋅K−1R = 8.314\ \text{J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}R=8.314 J⋅mol−1⋅K−1. This value of RRR is employed in the ideal gas law when energy units (joules) are required.

Flashcard 3: What is the Kelvin temperature conversion formula from Celsius (∘C)\left(^\circ\text{C}\right)(∘C)?

Answer: T(K)=T(∘C)+273.15T(\text{K}) = T(^\circ\text{C}) + 273.15T(K)=T(∘C)+273.15. Absolute temperature in Kelvin is obtained by adding 273.15 to the Celsius temperature to align with the ideal gas law scale.

Flashcard 4: What is the standard temperature and pressure (STP) definition used on the MCAT?

Answer: T=273.15 K, P=1 atmT = 273.15\ \text{K},\ P = 1\ \text{atm}T=273.15 K, P=1 atm. STP conditions provide a reference point for gas properties, with temperature at freezing point of water in Kelvin and pressure at sea level.

Flashcard 5: State the relationship between partial pressure and mole fraction for an ideal gas mixture.

Answer: Pi=xiPtotalP_i = x_i P_{\text{total}}Pi​=xi​Ptotal​. Partial pressure of a gas in a mixture is its mole fraction times the total pressure, assuming ideal behavior.

Flashcard 6: What molar volume does an ideal gas occupy at STP (approximate MCAT value)?

Answer: 22.4 L mol−122.4\ \text{L mol}^{-1}22.4 L mol−1. At STP, one mole of ideal gas occupies this volume, derived from the ideal gas law with P=1P=1P=1 atm and T=273T=273T=273 K.

Flashcard 7: State Dalton's law formula for total pressure of a gas mixture.

Answer: Ptotal=∑iPiP_{\text{total}} = \sum_i P_iPtotal​=∑i​Pi​. Dalton's law states that in a mixture of non-reacting gases, total pressure equals the sum of each gas's partial pressure.

Flashcard 8: Find PHeP_{\text{He}}PHe​ if xHe=0.25x_{\text{He}} = 0.25xHe​=0.25 and Ptotal=4 atmP_{\text{total}} = 4\ \text{atm}Ptotal​=4 atm for an ideal mixture.

Answer: PHe=1 atmP_{\text{He}} = 1\ \text{atm}PHe​=1 atm. Partial pressure equals mole fraction times total pressure in an ideal gas mixture per Dalton's law.

Flashcard 9: State the formula for Boyle's law relating pressure and volume at constant TTT and nnn.

Answer: P1V1=P2V2P_1V_1 = P_2V_2P1​V1​=P2​V2​. Boyle's law describes the inverse relationship between pressure and volume for a fixed amount of gas at constant temperature.

Flashcard 10: State the formula for Charles's law relating volume and temperature at constant PPP and nnn.

Answer: V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}T1​V1​​=T2​V2​​. Charles's law indicates that volume is directly proportional to absolute temperature for a gas at constant pressure and moles.

Flashcard 11: State the formula for Gay-Lussac's law relating pressure and temperature at constant VVV and nnn.

Answer: P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2}T1​P1​​=T2​P2​​. Gay-Lussac's law shows that pressure is directly proportional to absolute temperature for a gas at constant volume and moles.

Flashcard 12: State the formula for Avogadro's law relating volume and moles at constant PPP and TTT.

Answer: V1n1=V2n2\frac{V_1}{n_1} = \frac{V_2}{n_2}n1​V1​​=n2​V2​​. Avogadro's law states that volume is directly proportional to the number of moles for a gas at constant pressure and temperature.

Flashcard 13: State the ideal gas law equation relating PPP, VVV, nnn, RRR, and TTT.

Answer: PV=nRTPV = nRTPV=nRT. The ideal gas law combines relationships among pressure, volume, moles, and temperature for an ideal gas using the gas constant RRR.

Flashcard 14: What is the value of the ideal gas constant RRR in L⋅atm⋅mol−1⋅K−1\text{L}\cdot\text{atm}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}L⋅atm⋅mol−1⋅K−1?

Answer: R=0.08206 L⋅atm⋅mol−1⋅K−1R = 0.08206\ \text{L}\cdot\text{atm}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}R=0.08206 L⋅atm⋅mol−1⋅K−1. This value of RRR is used when pressure is in atm, volume in L, and temperature in K for the ideal gas law.

Flashcard 15: Find nnn if P=2 atmP = 2\ \text{atm}P=2 atm, V=5 LV = 5\ \text{L}V=5 L, T=300 KT = 300\ \text{K}T=300 K, and R=0.082 L atm mol−1K−1R = 0.082\ \text{L atm mol}^{-1}\text{K}^{-1}R=0.082 L atm mol−1K−1.

Answer: n≈0.41 moln \approx 0.41\ \text{mol}n≈0.41 mol. Solving the ideal gas law for nnn gives moles as pressure times volume over RRR times temperature.

Flashcard 16: Find P2P_2P2​ if P1=1.5 atmP_1 = 1.5\ \text{atm}P1​=1.5 atm, T1=300 KT_1 = 300\ \text{K}T1​=300 K, and T2=200 KT_2 = 200\ \text{K}T2​=200 K at constant VVV.

Answer: P2=1.0 atmP_2 = 1.0\ \text{atm}P2​=1.0 atm. By Gay-Lussac's law, pressure decreases with the ratio of temperatures at constant volume.

Flashcard 17: Find V2V_2V2​ if V1=4 LV_1 = 4\ \text{L}V1​=4 L, T1=300 KT_1 = 300\ \text{K}T1​=300 K, and T2=450 KT_2 = 450\ \text{K}T2​=450 K at constant PPP.

Answer: V2=6 LV_2 = 6\ \text{L}V2​=6 L. Using Charles's law, volume increases proportionally with the ratio of temperatures at constant pressure.

Flashcard 18: Find V2V_2V2​ if P1=2 atmP_1 = 2\ \text{atm}P1​=2 atm, V1=3 LV_1 = 3\ \text{L}V1​=3 L, and P2=1 atmP_2 = 1\ \text{atm}P2​=1 atm at constant TTT.

Answer: V2=6 LV_2 = 6\ \text{L}V2​=6 L. Applying Boyle's law, volume doubles when pressure halves at constant temperature.

Flashcard 19: Identify the condition when real gases deviate most from ideal behavior (in terms of PPP and TTT).

Answer: High PPP and low TTT. Real gases deviate from ideality when intermolecular forces and particle volume become significant under high pressure and low temperature.

Flashcard 20: Identify the key ideal-gas assumptions about particle volume and intermolecular forces.

Answer: Negligible particle volume; no intermolecular attractions or repulsions. Ideal gas assumptions simplify behavior by treating particles as point masses with no volume and no interactions except elastic collisions.

Flashcard 21: State Graham's law for the ratio of diffusion (or effusion) rates of two gases.

Answer: r1r2=M2M1\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}}r2​r1​​=M1​M2​​​. Graham's law indicates that diffusion or effusion rates are inversely proportional to the square root of molar masses.

Flashcard 22: State the root-mean-square speed formula urmsu_{\text{rms}}urms​ for an ideal gas.

Answer: urms=3RTMu_{\text{rms}} = \sqrt{\frac{3RT}{M}}urms​=M3RT​​. Root-mean-square speed measures the square root of the average of squared speeds, depending on temperature and molar mass MMM.

Flashcard 23: State the molar-average kinetic energy relation to temperature using RRR.

Answer: ⟨KE⟩mol=32RT\langle KE \rangle_{\text{mol}} = \frac{3}{2}RT⟨KE⟩mol​=23​RT. For one mole, average kinetic energy relates to temperature via the gas constant RRR, derived from per-molecule kinetic energy.

Flashcard 24: State the kinetic molecular theory relation between average kinetic energy and temperature.

Answer: ⟨KE⟩=32kBT\langle KE \rangle = \frac{3}{2}k_BT⟨KE⟩=23​kB​T. Kinetic molecular theory posits that average kinetic energy per molecule is directly proportional to absolute temperature, with kBk_BkB​ as Boltzmann's constant.

Flashcard 25: State the mole fraction definition for component iii in a gas mixture.

Answer: xi=nintotalx_i = \frac{n_i}{n_{\text{total}}}xi​=ntotal​ni​​. Mole fraction represents the ratio of moles of one component to total moles in the mixture.