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MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4b Fluid Flow Continuity Bernoulli

Study 4b Fluid Flow Continuity Bernoulli in MCAT Chemical and Physical Foundations of Biological Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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This deck focuses on 4b Fluid Flow Continuity Bernoulli, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Chemical and Physical Foundations of Biological Systems.

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MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4b Fluid Flow Continuity Bernoulli

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QUESTION

Using continuity, if a pipe narrows so that A2=12A1A_2=\frac{1}{2}A_1A2​=21​A1​, what is v2v_2v2​ in terms of v1v_1v1​?

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ANSWER

v2=2v1v_2=2v_1v2​=2v1​. Continuity requires speed to double when area halves to maintain constant flow rate in incompressible flow.

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Flashcard 1: Using continuity, if a pipe narrows so that A2=12A1A_2=\frac{1}{2}A_1A2​=21​A1​, what is v2v_2v2​ in terms of v1v_1v1​?

Answer: v2=2v1v_2=2v_1v2​=2v1​. Continuity requires speed to double when area halves to maintain constant flow rate in incompressible flow.

Flashcard 2: For horizontal flow, if speed increases from v1v_1v1​ to v2v_2v2​ with v2>v1v_2>v_1v2​>v1​, how does pressure change?

Answer: P2<P1P_2<P_1P2​<P1​. Bernoulli’s principle shows that increased speed in horizontal flow reduces pressure to conserve energy.

Flashcard 3: In a horizontal pipe, if v2=2v1v_2=2v_1v2​=2v1​, what is P1−P2P_1-P_2P1​−P2​ in terms of ρ\rhoρ and v1v_1v1​?

Answer: P1−P2=32ρv12P_1-P_2=\frac{3}{2}\rho v_1^2P1​−P2​=23​ρv12​. From simplified Bernoulli’s equation, pressure drop equals the difference in dynamic pressures for v2=2v1v_2=2v_1v2​=2v1​.

Flashcard 4: In a vertical pipe with equal speeds (v1=v2v_1=v_2v1​=v2​), what is P2−P1P_2-P_1P2​−P1​ if h2−h1=Δhh_2-h_1=\Delta hh2​−h1​=Δh?

Answer: P2−P1=−ρgΔhP_2-P_1=-\rho g\Delta hP2​−P1​=−ρgΔh. With equal speeds, Bernoulli’s equation shows pressure difference opposes gravitational potential change.

Flashcard 5: What is the definition of a streamline in fluid flow?

Answer: A curve everywhere tangent to the local fluid velocity. A streamline traces the path where its direction matches the instantaneous velocity vector of the fluid particles.

Flashcard 6: What is the definition of laminar flow in a pipe?

Answer: Smooth, layered flow with minimal mixing between layers. Laminar flow features parallel layers sliding past each other with viscous forces dominating, preventing mixing.

Flashcard 7: What is the definition of turbulent flow in a pipe?

Answer: Chaotic flow with eddies and significant mixing. Turbulent flow involves inertial forces dominating, leading to irregular motion and vortex formation.

Flashcard 8: State the Reynolds number formula for flow in a cylindrical tube.

Answer: Re=ρvDμ\text{Re}=\frac{\rho vD}{\mu}Re=μρvD​. Reynolds number Re quantifies the ratio of inertial to viscous forces using density, speed, diameter, and viscosity.

Flashcard 9: For pipe flow, which inequality indicates a strong tendency toward turbulence using Reynolds number?

Answer: Re≳2000\text{Re}\gtrsim 2000Re≳2000. In pipe flow, Re exceeding approximately 2000 indicates inertial forces overpower viscous damping, promoting turbulence.

Flashcard 10: State Poiseuille’s law for laminar flow rate QQQ through a cylindrical tube of radius rrr and length LLL.

Answer: Q=πr4ΔP8μLQ=\frac{\pi r^4\Delta P}{8\mu L}Q=8μLπr4ΔP​. Poiseuille’s law derives from viscous flow assumptions, showing flow rate proportional to pressure gradient and radius to the fourth power.

Flashcard 11: What is the definition of volumetric flow rate QQQ for a fluid?

Answer: Q=dVdtQ=\frac{dV}{dt}Q=dtdV​. Volumetric flow rate QQQ measures the volume of fluid dVdVdV passing through a cross-section per unit time dtdtdt.

Flashcard 12: State the continuity equation relating flow rate, area, and speed for steady incompressible flow.

Answer: Q=AvQ=AvQ=Av. For steady incompressible flow, volumetric flow rate QQQ equals cross-sectional area AAA times average fluid speed vvv.

Flashcard 13: What is the continuity relationship between two points in an incompressible fluid (111 and 222)?

Answer: A1v1=A2v2A_1v_1=A_2v_2A1​v1​=A2​v2​. Continuity for incompressible fluids ensures constant flow rate, so the product of area and speed remains equal at different points.

Flashcard 14: Identify the correct unit for volumetric flow rate QQQ in SI units.

Answer: m3 ⁣ ⁣/s\text{m}^3\!\!/\text{s}m3/s. In SI units, volumetric flow rate QQQ is expressed as cubic meters per second, reflecting volume over time.

Flashcard 15: What is the definition of mass flow rate m˙\dot{m}m˙ in terms of density and QQQ?

Answer: m˙=ρQ\dot{m}=\rho Qm˙=ρQ. Mass flow rate m˙\dot{m}m˙ is the product of fluid density ρ\rhoρ and volumetric flow rate QQQ, giving mass per unit time.

Flashcard 16: State the relationship between gauge pressure PgP_gPg​ and absolute pressure PabsP_{abs}Pabs​.

Answer: Pabs=Pg+PatmP_{abs}=P_g+P_{atm}Pabs​=Pg​+Patm​. Absolute pressure PabsP_{abs}Pabs​ includes atmospheric pressure PatmP_{atm}Patm​ added to gauge pressure PgP_gPg​, accounting for total pressure.

Flashcard 17: State Bernoulli’s equation for steady, incompressible, nonviscous flow along a streamline.

Answer: P+12ρv2+ρgh=constantP+\frac{1}{2}\rho v^2+\rho gh=\text{constant}P+21​ρv2+ρgh=constant. Bernoulli’s equation conserves energy per unit volume along a streamline, summing static, dynamic, and gravitational terms.

Flashcard 18: Write Bernoulli’s equation explicitly between two points (111 and 222) on a streamline.

Answer: P1+12ρv12+ρgh1=P2+12ρv22+ρgh2P_1+\frac{1}{2}\rho v_1^2+\rho gh_1=P_2+\frac{1}{2}\rho v_2^2+\rho gh_2P1​+21​ρv12​+ρgh1​=P2​+21​ρv22​+ρgh2​. Bernoulli’s equation equates the sum of pressures and energies at two points on a streamline for conservation in ideal flow.

Flashcard 19: What is the definition of dynamic pressure in Bernoulli’s equation?

Answer: 12ρv2\frac{1}{2}\rho v^221​ρv2. Dynamic pressure represents the kinetic energy per unit volume of the moving fluid in Bernoulli’s equation.

Flashcard 20: What is the definition of hydrostatic (gravitational) pressure term in Bernoulli’s equation?

Answer: ρgh\rho ghρgh. Hydrostatic pressure arises from gravitational potential energy per unit volume at height hhh in a fluid of density ρ\rhoρ.

Flashcard 21: Which condition must hold for the continuity form A1v1=A2v2A_1v_1=A_2v_2A1​v1​=A2​v2​ to be valid?

Answer: Steady, incompressible flow. The continuity equation A1v1=A2v2A_1v_1=A_2v_2A1​v1​=A2​v2​ assumes steady flow with constant density, ensuring mass conservation.

Flashcard 22: Which condition must hold for Bernoulli’s equation to apply in its simplest form?

Answer: Steady, incompressible, nonviscous flow on a streamline. Bernoulli’s equation in simplest form requires no viscosity, constant density, steady flow, and evaluation along a streamline.

Flashcard 23: Identify the correct expression for average speed vvv in a tube given QQQ and cross-sectional area AAA.

Answer: v=QAv=\frac{Q}{A}v=AQ​. Average fluid speed vvv derives from rearranging the flow rate equation Q=AvQ=AvQ=Av for a given cross-section.

Flashcard 24: For a horizontal pipe, what does Bernoulli’s equation reduce to between points 111 and 222?

Answer: P1+12ρv12=P2+12ρv22P_1+\frac{1}{2}\rho v_1^2=P_2+\frac{1}{2}\rho v_2^2P1​+21​ρv12​=P2​+21​ρv22​. In horizontal flow, gravitational terms cancel in Bernoulli’s equation, leaving static and dynamic pressure balance.

Flashcard 25: Using continuity, if A2=3A1A_2=3A_1A2​=3A1​, what is v2v_2v2​ in terms of v1v_1v1​ for incompressible flow?

Answer: v2=13v1v_2=\frac{1}{3}v_1v2​=31​v1​. Continuity dictates that speed decreases inversely with area increase to conserve volume flow rate.