Home

Tutoring

Subjects

Live Classes

Study Coach

Essay Review

On-Demand Courses

Colleges

Games

Opening subject page...

Loading your content

  1. My Subjects
  2. MCAT Chemical and Physical Foundations of Biological Systems
  3. Flashcards

MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4b Buoyancy Archimedes

Study 4b Buoyancy Archimedes in MCAT Chemical and Physical Foundations of Biological Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

← Back to flashcard decks

What this deck covers

This deck focuses on 4b Buoyancy Archimedes, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Chemical and Physical Foundations of Biological Systems.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4b Buoyancy Archimedes

1

/ 25

0 reviewed

0% Complete

0 reviewing
QUESTION

What is the net force on a fully submerged object (positive upward) in terms of FBF_BFB​ and WWW?

Tap or drag to reveal answer

ANSWER

Fnet=FB−WF_{\text{net}}=F_B-WFnet​=FB​−W. Net force is the difference between upward buoyant force and downward weight.

Swipe Right = I Know It! 🎉

Swipe Left = Still Learning

All flashcards

Flashcard 1: What is the net force on a fully submerged object (positive upward) in terms of FBF_BFB​ and WWW?

Answer: Fnet=FB−WF_{\text{net}}=F_B-WFnet​=FB​−W. Net force is the difference between upward buoyant force and downward weight.

Flashcard 2: A cube of volume 1.0×10−3 m31.0\times10^{-3}\,\text{m}^31.0×10−3m3 floats in oil with ρ=800 kg/m3\rho=800\,\text{kg/m}^3ρ=800kg/m3. What is its maximum mass?

Answer: 0.80 kg0.80\,\text{kg}0.80kg. Maximum mass for floating occurs when object density equals oil density, so mass is oil density times volume.

Flashcard 3: A 0.50 m30.50\,\text{m}^30.50m3 object is fully submerged in a fluid with ρ=1200 kg/m3\rho=1200\,\text{kg/m}^3ρ=1200kg/m3. Find FBF_BFB​ using g=10 m/s2g=10\,\text{m/s}^2g=10m/s2.

Answer: 6000 N6000\,\text{N}6000N. Buoyant force equals fluid density times submerged volume times gravity for fully submerged objects.

Flashcard 4: An object has ρobj=800 kg/m3\rho_{\text{obj}}=800\,\text{kg/m}^3ρobj​=800kg/m3 in water. What fraction of its volume is submerged when floating?

Answer: 0.800.800.80. Submerged fraction equals object density divided by water density for floating objects.

Flashcard 5: An object floats in water with 60%60\%60% of its volume submerged. What is ρobj\rho_{\text{obj}}ρobj​?

Answer: 600 kg/m3600\,\text{kg/m}^3600kg/m3. Object density is the submerged fraction times water density for floating equilibrium.

Flashcard 6: A 1.0 kg1.0\,\text{kg}1.0kg object experiences FB=3 NF_B=3\,\text{N}FB​=3N. What is its apparent weight in the fluid using g=10 m/s2g=10\,\text{m/s}^2g=10m/s2?

Answer: 7 N7\,\text{N}7N. Apparent weight equals actual weight minus buoyant force, reducing effective downward force.

Flashcard 7: A 1.0 kg1.0\,\text{kg}1.0kg object displaces 5.0×10−4 m35.0\times10^{-4}\,\text{m}^35.0×10−4m3 of water. What is FBF_BFB​ using g=10 m/s2g=10\,\text{m/s}^2g=10m/s2?

Answer: 5 N5\,\text{N}5N. Buoyant force depends on displaced water volume and water density, independent of object mass.

Flashcard 8: Find the buoyant force on 2.0 L2.0\,\text{L}2.0L of displaced water using ρ=1000 kg/m3\rho=1000\,\text{kg/m}^3ρ=1000kg/m3 and g=10 m/s2g=10\,\text{m/s}^2g=10m/s2.

Answer: 20 N20\,\text{N}20N. Buoyant force equals the weight of displaced water, calculated as density times volume times gravity.

Flashcard 9: Which option is correct: buoyant force depends on object density or on fluid density (for fixed VdispV_{\text{disp}}Vdisp​)?

Answer: It depends on fluid density, not object density. Buoyant force arises from fluid pressure differences and scales with fluid density for constant displaced volume.

Flashcard 10: Identify the correct unit for buoyant force in SI base units.

Answer: N=kg⋅m⋅s−2\text{N}=\text{kg}\cdot\text{m}\cdot\text{s}^{-2}N=kg⋅m⋅s−2. Buoyant force, a force, has units of Newtons, equivalent to kg m s^{-2} in SI base units.

Flashcard 11: What is the formula for buoyant force on a fully submerged object in a fluid?

Answer: FB=ρfluidVdispgF_B=\rho_{\text{fluid}}V_{\text{disp}}gFB​=ρfluid​Vdisp​g. Archimedes' principle states that the buoyant force equals the weight of the fluid displaced by the submerged volume.

Flashcard 12: What does Archimedes’ principle state about the buoyant force on an object in a fluid?

Answer: Buoyant force equals weight of displaced fluid. Archimedes' principle quantifies the upward force on an object as equal to the weight of the fluid it displaces.

Flashcard 13: What is the formula for the weight of a displaced fluid volume VdispV_{\text{disp}}Vdisp​?

Answer: Wdisp=ρfluidVdispgW_{\text{disp}}=\rho_{\text{fluid}}V_{\text{disp}}gWdisp​=ρfluid​Vdisp​g. Weight equals mass times gravity, where mass is the product of fluid density and displaced volume.

Flashcard 14: Which condition determines whether an object floats, in terms of average densities?

Answer: Floats if ρobj<ρfluid\rho_{\text{obj}}<\rho_{\text{fluid}}ρobj​<ρfluid​. An object floats when its average density is less than the fluid's, causing buoyant force to exceed weight when partially submerged.

Flashcard 15: Which condition determines whether an object sinks, in terms of average densities?

Answer: Sinks if ρobj>ρfluid\rho_{\text{obj}}>\rho_{\text{fluid}}ρobj​>ρfluid​. An object sinks when its average density exceeds the fluid's, resulting in weight greater than maximum buoyant force.

Flashcard 16: What is the condition for neutral buoyancy (neither rising nor sinking) in a fluid?

Answer: ρobj=ρfluid\rho_{\text{obj}}=\rho_{\text{fluid}}ρobj​=ρfluid​. Neutral buoyancy occurs when the object's density matches the fluid's, balancing buoyant force and weight.

Flashcard 17: What is the equilibrium force balance for a floating object (neglecting surface tension)?

Answer: FB=WF_B=WFB​=W. At equilibrium, the buoyant force upward equals the object's weight downward for a floating object.

Flashcard 18: What is the fraction of a floating object’s volume that is submerged in a fluid?

Answer: VsubVobj=ρobjρfluid\frac{V_{\text{sub}}}{V_{\text{obj}}}=\frac{\rho_{\text{obj}}}{\rho_{\text{fluid}}}Vobj​Vsub​​=ρfluid​ρobj​​. The submerged fraction equals the ratio of object density to fluid density for equilibrium in floating objects.

Flashcard 19: What is the volume displaced by an object that is fully submerged in a fluid?

Answer: Vdisp=VobjV_{\text{disp}}=V_{\text{obj}}Vdisp​=Vobj​. For fully submerged objects, the displaced volume equals the entire object volume.

Flashcard 20: What is the volume displaced by an object that is floating (partially submerged)?

Answer: Vdisp=VsubV_{\text{disp}}=V_{\text{sub}}Vdisp​=Vsub​. Displaced volume for floating objects is the submerged portion, balancing buoyant force with weight.

Flashcard 21: What is the formula for the pressure difference across a vertical height hhh in a static fluid?

Answer: ΔP=ρgh\Delta P=\rho ghΔP=ρgh. Pressure increases linearly with depth due to the weight of the overlying fluid column.

Flashcard 22: What is the formula for hydrostatic pressure at depth hhh below a fluid surface?

Answer: P=P0+ρghP=P_0+\rho ghP=P0​+ρgh. Hydrostatic pressure adds the contribution from the fluid column to the surface pressure.

Flashcard 23: Which statement best describes how buoyant force changes with depth in an incompressible fluid?

Answer: It is independent of depth for fixed VdispV_{\text{disp}}Vdisp​. In incompressible fluids, buoyant force depends on displaced volume and fluid density, remaining constant with depth.

Flashcard 24: What is the apparent weight of a fully submerged object in a fluid, in terms of WWW and FBF_BFB​?

Answer: Wapp=W−FBW_{\text{app}}=W-F_BWapp​=W−FB​. Apparent weight is the actual weight reduced by the opposing buoyant force.

Flashcard 25: What is the buoyant force on a fully submerged object of volume VVV in a fluid of density ρ\rhoρ?

Answer: FB=ρVgF_B=\rho V gFB​=ρVg. Buoyant force equals the weight of displaced fluid, calculated as fluid density times object volume times gravity.