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  2. MCAT Chemical and Physical Foundations of Biological Systems
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MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4a Periodic Motion Mechanical Waves

Study 4a Periodic Motion Mechanical Waves in MCAT Chemical and Physical Foundations of Biological Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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This deck focuses on 4a Periodic Motion Mechanical Waves, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Chemical and Physical Foundations of Biological Systems.

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MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4a Periodic Motion Mechanical Waves

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QUESTION

What is the maximum acceleration of a mass in SHM in terms of AAA and ω\omegaω?

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ANSWER

amax⁡=Aω2a_{\max}=A\omega^2amax​=Aω2. Maximum acceleration in SHM happens at maximum displacement, equaling amplitude times angular frequency squared from the defining equation.

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Flashcard 1: What is the maximum acceleration of a mass in SHM in terms of AAA and ω\omegaω?

Answer: amax⁡=Aω2a_{\max}=A\omega^2amax​=Aω2. Maximum acceleration in SHM happens at maximum displacement, equaling amplitude times angular frequency squared from the defining equation.

Flashcard 2: Find the new period of a simple pendulum if its length changes from LLL to 4L4L4L (same ggg).

Answer: T→2TT\rightarrow 2TT→2T. Pendulum period depends on square root of length, doubling when length quadruples as T∝LT\propto\sqrt{L}T∝L​ under constant gravity.

Flashcard 3: Find the new period of a mass-spring system if the spring constant changes from kkk to 4k4k4k (same mmm).

Answer: T→T2T\rightarrow \frac{T}{2}T→2T​. Period inversely scales with square root of spring constant, halving when constant quadruples per T∝1/kT\propto^1/\sqrt{k}T∝1/k​.

Flashcard 4: Find the new period of a mass-spring system if the mass changes from mmm to 4m4m4m (same kkk).

Answer: T→2TT\rightarrow 2TT→2T. Period scales with square root of mass, so quadrupling mass doubles the period via T∝mT\propto\sqrt{m}T∝m​ in mass-spring systems.

Flashcard 5: Find the period TTT if a wave has frequency f=8 Hzf=8\ \text{Hz}f=8 Hz.

Answer: T=18 s=0.125 sT=\frac{1}{8}\ \text{s}=0.125\ \text{s}T=81​ s=0.125 s. Period is the reciprocal of frequency, converting cycles per second to time per cycle for oscillatory or wave motion.

Flashcard 6: Find the frequency if a wave has speed v=20 m/sv=20\ \text{m/s}v=20 m/s and wavelength λ=5 m\lambda=5\ \text{m}λ=5 m.

Answer: f=4 Hzf=4\ \text{Hz}f=4 Hz. Frequency derives from speed over wavelength, using f=v/λf=v/\lambdaf=v/λ for the provided wave parameters.

Flashcard 7: Find the wavelength if a wave has speed v=12 m/sv=12\ \text{m/s}v=12 m/s and frequency f=3 Hzf=3\ \text{Hz}f=3 Hz.

Answer: λ=4 m\lambda=4\ \text{m}λ=4 m. Wavelength calculates as speed divided by frequency, applying the fundamental wave relation v=fλv=f\lambdav=fλ to given values.

Flashcard 8: Identify the phase difference in radians for two points separated by λ4\frac{\lambda}{4}4λ​ on a sinusoidal wave.

Answer: Δϕ=π2\Delta\phi=\frac{\pi}{2}Δϕ=2π​. For sinusoidal waves, phase shifts by 2π2\pi2π per wavelength, so quarter-wavelength gives π/2\pi/2π/2 radians difference.

Flashcard 9: Identify the phase difference in radians for two points separated by λ2\frac{\lambda}{2}2λ​ on a sinusoidal wave.

Answer: Δϕ=π\Delta\phi=\piΔϕ=π. Phase difference scales with path length over wavelength times 2π2\pi2π, yielding π\piπ for half-wavelength separation in sinusoidal waves.

Flashcard 10: What physical property of the medium determines wave speed, and what property does not determine it?

Answer: Speed set by medium; frequency set by source (not medium). Medium properties like density and elasticity dictate wave speed, while source determines frequency independently of the medium.

Flashcard 11: What is the key distinction between transverse and longitudinal mechanical waves?

Answer: Transverse: oscillation ⊥\perp⊥ travel; longitudinal: ∥\parallel∥ travel. Wave types differ by particle oscillation direction relative to propagation: perpendicular for transverse, parallel for longitudinal.

Flashcard 12: What is the definition of wavelength λ\lambdaλ for a traveling periodic wave?

Answer: Distance between points in phase (e.g., crest to crest). Wavelength measures the spatial period of a wave, defined as the shortest distance between identical phase points in the cycle.

Flashcard 13: State the wave speed on an ideal string in terms of tension TTT and linear density μ\muμ.

Answer: v=Tμv=\sqrt{\frac{T}{\mu}}v=μT​​. String wave speed balances tension restoring force and inertial mass density, yielding the square root expression for transverse waves.

Flashcard 14: State the speed of a wave in terms of frequency fff and wavelength λ\lambdaλ.

Answer: v=fλv=f\lambdav=fλ. Wave speed equals frequency times wavelength, relating temporal and spatial periodicity for propagating waves.

Flashcard 15: What is the kinetic energy of a mass in SHM in terms of mmm and instantaneous speed vvv?

Answer: K=12mv2K=\frac{1}{2}mv^2K=21​mv2. Kinetic energy in SHM represents motion energy, calculated classically as half mass times velocity squared at any instant.

Flashcard 16: What is the spring potential energy as a function of displacement xxx for an ideal spring?

Answer: U=12kx2U=\frac{1}{2}kx^2U=21​kx2. Spring potential stores elastic energy quadratically with displacement, following Hooke's law integration for conservative force.

Flashcard 17: State the total mechanical energy of an ideal mass-spring oscillator in terms of kkk and amplitude AAA.

Answer: E=12kA2E=\frac{1}{2}kA^2E=21​kA2. Total energy conserves as maximum potential energy at amplitude extremes, expressed via spring constant and squared amplitude.

Flashcard 18: What condition must hold for a pendulum to be treated as simple harmonic motion?

Answer: Small angles: sin⁡θ≈θ\sin\theta\approx\thetasinθ≈θ (in radians). The small-angle approximation linearizes the pendulum equation, enabling SHM by equating sine to the angle in radians.

Flashcard 19: State the period of a small-angle simple pendulum in terms of length LLL and gravity ggg.

Answer: T=2πLgT=2\pi\sqrt{\frac{L}{g}}T=2πgL​​. For small angles, pendulum period approximates from torque balance, scaling with square root of length over gravitational acceleration.

Flashcard 20: State the angular frequency of a mass-spring oscillator in terms of mmm and kkk.

Answer: ω=km\omega=\sqrt{\frac{k}{m}}ω=mk​​. Angular frequency emerges from the SHM equation of motion, as the square root of spring constant over mass for oscillatory behavior.

Flashcard 21: State the period of a mass-spring oscillator in terms of mass mmm and spring constant kkk.

Answer: T=2πmkT=2\pi\sqrt{\frac{m}{k}}T=2πkm​​. The period derives from solving the differential equation for a mass-spring system, depending on the square root of mass over spring constant.

Flashcard 22: State the SHM relation between acceleration and displacement for a mass on a spring.

Answer: a=−ω2xa=-\omega^2 xa=−ω2x. In SHM, acceleration is proportional to negative displacement, with ω2\omega^2ω2 as the constant from restoring force dynamics.

Flashcard 23: What is the maximum speed of a mass in SHM in terms of AAA and ω\omegaω?

Answer: vmax⁡=Aωv_{\max}=A\omegavmax​=Aω. Maximum speed in SHM occurs at equilibrium, derived from velocity function or energy conservation as amplitude times angular frequency.

Flashcard 24: State the standard displacement function for simple harmonic motion using amplitude AAA and phase ϕ\phiϕ.

Answer: x(t)=Acos⁡(ωt+ϕ)x(t)=A\cos(\omega t+\phi)x(t)=Acos(ωt+ϕ). This equation models oscillatory displacement as a cosine function, capturing amplitude, angular frequency, time, and initial phase.

Flashcard 25: What is the relationship among period TTT, frequency fff, and angular frequency ω\omegaω?

Answer: f=1Tf=\frac{1}{T}f=T1​ and ω=2πf=2πT\omega=2\pi f=\frac{2\pi}{T}ω=2πf=T2π​. Frequency is the reciprocal of period, and angular frequency equals 2π2\pi2π times frequency, linking time-based oscillatory parameters.