All flashcards
Flashcard 1: What structural feature makes a sugar a reducing sugar?
Answer: A free anomeric carbon that can form an open-chain aldehyde/ketone. Allows the sugar to tautomerize and expose a carbonyl for oxidation, enabling reduction of reagents like Cu2+.
Flashcard 2: What is mutarotation in aqueous solution?
Answer: Interconversion of b and b anomers via the open-chain form. Enables equilibrium between cyclic forms in solution, resulting in a change in optical rotation.
Flashcard 3: In a Haworth projection of a D-sugar, what defines the b anomer?
Answer: Anomeric OH is on the same side as the CH2OH group (cis). Identifies the β configuration in D-sugars where anomeric OH and CH2OH are cis in the ring plane.
Flashcard 4: Which glycolysis steps are irreversible and what enzymes catalyze them?
Answer: Hexokinase, PFK-1, and pyruvate kinase steps are irreversible. Require bypassing in gluconeogenesis due to unfavorable thermodynamics in the reverse direction.
Flashcard 5: What is the rate-limiting enzyme of the pentose phosphate pathway oxidative phase?
Answer: Glucose-6-phosphate dehydrogenase (G6PD). Controls NADPH production for biosynthesis and antioxidant defense in the irreversible oxidative branch.
Flashcard 6: What is the net energy cost of gluconeogenesis to make 1 glucose from 2 pyruvate?
Answer: Consumes 4 ATP, 2 GTP, and 2 NADH. Offsets the ATP yield of glycolysis and provides reducing power for biosynthetic reactions.
Flashcard 7: What enzyme bypasses pyruvate kinase in gluconeogenesis (final step to PEP)?
Answer: PEP carboxykinase (with pyruvate carboxylase upstream). Bypasses the irreversible pyruvate kinase step by forming PEP from oxaloacetate in two enzyme reactions.
Flashcard 8: What is the rate-limiting enzyme of gluconeogenesis?
Answer: Fructose-1,6-bisphosphatase. Regulates gluconeogenesis by reversing the PFK-1 step, controlled by energy status and hormones.
Flashcard 9: What enzyme converts pyruvate to lactate during anaerobic glycolysis?
Answer: Lactate dehydrogenase. Reduces pyruvate using NADH, regenerating NAD+ to continue anaerobic ATP production.
Flashcard 10: What is the primary purpose of fermentation in human cells?
Answer: Regenerate NAD+ from NADH to sustain glycolysis. Maintains glycolytic flux under anaerobic conditions by recycling the electron acceptor for GAPDH.
Flashcard 11: What enzyme converts pyruvate to acetyl-CoA, and what cofactors are required?
Answer: Pyruvate dehydrogenase; TPP, lipoate, FAD, NAD+, CoA. Facilitates entry into the TCA cycle via a multienzyme complex using these cofactors for decarboxylation and CoA attachment.
Flashcard 12: What is the net yield of glycolysis per glucose under aerobic conditions?
Answer: Net 2 ATP, 2 NADH, and 2 pyruvate. Represents the energy and reducing power gained from glucose breakdown before pyruvate oxidation.
Flashcard 13: What glycolysis step produces NADH, and which enzyme catalyzes it?
Answer: Glyceraldehyde-3-phosphate d 1,3-BPG; GAPDH. Oxidizes the aldehyde to carboxylic acid, generating NADH in the payoff phase of glycolysis.
Flashcard 14: What is the committed step of glycolysis and its enzyme?
Answer: Fructose-6-phosphate d fructose-1,6-bisphosphate; PFK-1. Marks the regulatory committed step in glycolysis, catalyzed by phosphofructokinase-1 under allosteric control.
Flashcard 15: Which disaccharide is nonreducing because both anomeric carbons are in the bond?
Answer: Sucrose. Features a glycosidic bond tying both anomeric carbons, preventing opening to a reducing form.
Flashcard 16: What is the anomeric carbon in a cyclic monosaccharide?
Answer: The carbonyl carbon in the open-chain form (hemiacetal/hemiketal carbon). Serves as the site of hemiacetal or hemiketal formation during cyclization of the sugar.
Flashcard 17: What is an anomer in carbohydrate chemistry?
Answer: Stereoisomers differing at the anomeric carbon after cyclization. Results from the creation of a new chiral center upon ring closure, yielding α and β forms.
Flashcard 18: In a Fischer projection, what determines whether a sugar is D (not L)?
Answer: The OH on the highest-numbered chiral carbon is on the right. Mirrors the configuration of D-glyceraldehyde in Fischer projections for assignment to the D series.
Flashcard 19: What does the D/L designation of a monosaccharide refer to in a Fischer projection?
Answer: Configuration at the highest-numbered chiral carbon vs D/L glyceraldehyde. Assigns the sugar to the D or L series based on similarity to glyceraldehyde enantiomers at the penultimate chiral carbon.
Flashcard 20: What functional group defines a ketose monosaccharide (rather than an aldose)?
Answer: Ketone group on an internal carbon (usually C2). Determines the classification as a ketose, contrasting with aldoses that have a terminal aldehyde group.
Flashcard 21: What functional group defines an aldose monosaccharide (rather than a ketose)?
Answer: Aldehyde group at the terminal carbon (usually C1). Determines the classification as an aldose, contrasting with ketoses that have an internal ketone group.