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  2. MCAT Biological and Biochemical Foundations of Living Systems
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MCAT Biological and Biochemical Foundations of Living Systems Flashcards: 1d Carbohydrate Metabolism

Study 1d Carbohydrate Metabolism in MCAT Biological and Biochemical Foundations of Living Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on 1d Carbohydrate Metabolism, giving you a quick way to review the definitions, rules, and examples that matter most for MCAT Biological and Biochemical Foundations of Living Systems.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

MCAT Biological and Biochemical Foundations of Living Systems Flashcards: 1d Carbohydrate Metabolism

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QUESTION

What structural feature makes a sugar a reducing sugar?

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ANSWER

A free anomeric carbon that can form an open-chain aldehyde/ketone. Allows the sugar to tautomerize and expose a carbonyl for oxidation, enabling reduction of reagents like Cu2+^{2+}2+.

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Flashcard 1: What structural feature makes a sugar a reducing sugar?

Answer: A free anomeric carbon that can form an open-chain aldehyde/ketone. Allows the sugar to tautomerize and expose a carbonyl for oxidation, enabling reduction of reagents like Cu2+^{2+}2+.

Flashcard 2: What is mutarotation in aqueous solution?

Answer: Interconversion of b and b anomers via the open-chain form. Enables equilibrium between cyclic forms in solution, resulting in a change in optical rotation.

Flashcard 3: In a Haworth projection of a D-sugar, what defines the b anomer?

Answer: Anomeric OH is on the same side as the CH2OHCH_2OHCH2​OH group (cis). Identifies the β configuration in D-sugars where anomeric OH and CH2_22​OH are cis in the ring plane.

Flashcard 4: Which glycolysis steps are irreversible and what enzymes catalyze them?

Answer: Hexokinase, PFK-111, and pyruvate kinase steps are irreversible. Require bypassing in gluconeogenesis due to unfavorable thermodynamics in the reverse direction.

Flashcard 5: What is the rate-limiting enzyme of the pentose phosphate pathway oxidative phase?

Answer: Glucose-666-phosphate dehydrogenase (G6PD). Controls NADPH production for biosynthesis and antioxidant defense in the irreversible oxidative branch.

Flashcard 6: What is the net energy cost of gluconeogenesis to make 111 glucose from 222 pyruvate?

Answer: Consumes 444 ATP, 222 GTP, and 222 NADH. Offsets the ATP yield of glycolysis and provides reducing power for biosynthetic reactions.

Flashcard 7: What enzyme bypasses pyruvate kinase in gluconeogenesis (final step to PEP)?

Answer: PEP carboxykinase (with pyruvate carboxylase upstream). Bypasses the irreversible pyruvate kinase step by forming PEP from oxaloacetate in two enzyme reactions.

Flashcard 8: What is the rate-limiting enzyme of gluconeogenesis?

Answer: Fructose-1,61,61,6-bisphosphatase. Regulates gluconeogenesis by reversing the PFK-1 step, controlled by energy status and hormones.

Flashcard 9: What enzyme converts pyruvate to lactate during anaerobic glycolysis?

Answer: Lactate dehydrogenase. Reduces pyruvate using NADH, regenerating NAD+^++ to continue anaerobic ATP production.

Flashcard 10: What is the primary purpose of fermentation in human cells?

Answer: Regenerate NAD+^++ from NADH to sustain glycolysis. Maintains glycolytic flux under anaerobic conditions by recycling the electron acceptor for GAPDH.

Flashcard 11: What enzyme converts pyruvate to acetyl-CoA, and what cofactors are required?

Answer: Pyruvate dehydrogenase; TPP, lipoate, FAD, NAD+^++, CoA. Facilitates entry into the TCA cycle via a multienzyme complex using these cofactors for decarboxylation and CoA attachment.

Flashcard 12: What is the net yield of glycolysis per glucose under aerobic conditions?

Answer: Net 222 ATP, 222 NADH, and 222 pyruvate. Represents the energy and reducing power gained from glucose breakdown before pyruvate oxidation.

Flashcard 13: What glycolysis step produces NADH, and which enzyme catalyzes it?

Answer: Glyceraldehyde-333-phosphate d 1,3-BPG; GAPDH. Oxidizes the aldehyde to carboxylic acid, generating NADH in the payoff phase of glycolysis.

Flashcard 14: What is the committed step of glycolysis and its enzyme?

Answer: Fructose-666-phosphate d fructose-1,61,61,6-bisphosphate; PFK-111. Marks the regulatory committed step in glycolysis, catalyzed by phosphofructokinase-1 under allosteric control.

Flashcard 15: Which disaccharide is nonreducing because both anomeric carbons are in the bond?

Answer: Sucrose. Features a glycosidic bond tying both anomeric carbons, preventing opening to a reducing form.

Flashcard 16: What is the anomeric carbon in a cyclic monosaccharide?

Answer: The carbonyl carbon in the open-chain form (hemiacetal/hemiketal carbon). Serves as the site of hemiacetal or hemiketal formation during cyclization of the sugar.

Flashcard 17: What is an anomer in carbohydrate chemistry?

Answer: Stereoisomers differing at the anomeric carbon after cyclization. Results from the creation of a new chiral center upon ring closure, yielding α and β forms.

Flashcard 18: In a Fischer projection, what determines whether a sugar is D (not L)?

Answer: The OH on the highest-numbered chiral carbon is on the right. Mirrors the configuration of D-glyceraldehyde in Fischer projections for assignment to the D series.

Flashcard 19: What does the D/L designation of a monosaccharide refer to in a Fischer projection?

Answer: Configuration at the highest-numbered chiral carbon vs D/L glyceraldehyde. Assigns the sugar to the D or L series based on similarity to glyceraldehyde enantiomers at the penultimate chiral carbon.

Flashcard 20: What functional group defines a ketose monosaccharide (rather than an aldose)?

Answer: Ketone group on an internal carbon (usually C2C_2C2​). Determines the classification as a ketose, contrasting with aldoses that have a terminal aldehyde group.

Flashcard 21: What functional group defines an aldose monosaccharide (rather than a ketose)?

Answer: Aldehyde group at the terminal carbon (usually C1C_1C1​). Determines the classification as an aldose, contrasting with ketoses that have an internal ketone group.