Math - How to solve two-step equations with integers in pre-algebra

Solve for .

Explanation

Perform the same operation on both sides of the equation.

Add 3 to both sides.

Divide both sides by 4 and simplify the fraction.

$\frac{4x}{4}=\frac{16}{4}$

Solve for X in the following equation:

Explanation

To solve for X, we must isolate X on one side of the equation. In this case, we do this by subtracting 3X and adding 11 to both sides.

We now have isolated X on one side of the equation, so we need only to reduce 3X to 1X. We can do this by dividing both sides by 3:

Solve for when

Explanation

To solve for , begin by subtracting from both sides of the equation:

Then divide both sides by :

$\frac{5x}{5}=\frac{40}{5}$

Solve for when

Explanation

To solve for , first add to both sides of the equation:

Then divide each side of the equation by :

$\frac{7x}{7}=\frac{84}{7}$

Solve for when $\frac{x}{13}-8=6$

Explanation

To solve for , first add to both sides of the equation:

$\frac{x}{13}-8+8=6+8$

$\frac{x}{13}=14$

Then multiply both sides of the equation by :

$\frac{x}{13}\cdot 13=14\cdot 13$

Solve for if,

Explanation

To perform a two step algebra problem with addition and multiplication we must remove the numbers from so it is by itself on one side of the equation.

To do this we first look to see if a number is being added or subtracted from .

In this case a number is being added so we must subtract the number, , from each side of the equation

Perform the math so our equation looks becomes

Then we divide each side of the equation by the number that is in front of , , to get by itself

$\frac{5x}{5}=\frac{40}{5}$

Perform the math to find the answer

Solve for if,

Explanation

To perform a two-step algebra problem with addition and multiplication we must remove the numbers from so it is by itself on one side of the equation.

To do this we first look to see if a number is being added or subtracted from .

In this case a number is being added so we must subtract the number, , from each side of the equation

Perform the math so our equation becomes

Then we divide each side of the equation by the number that is in front of , , to get by itself $\frac{9x}{9}=\frac{81}{9}$

Perform the math to find the answer

Solve for if

Explanation

To perform a two-step algebra problem with addition and multiplication we must remove the numbers from so it is by itself on one side of the equation.

To do this we first look to see if a number is being added or subtracted from .

In this case a number is being added so we must subtract the number, , from each side of the equation:

Perform the math so that our equation becomes .

Then we divide each side of the equation by the number that is in front of , , to get by itself

$\frac{3x}{3}=\frac{24}{3}$

Perform the math to find the answer

Solve for if

$\frac{x}{8}-17=32$

Explanation

To perform a two-step algebra problem with addition and division we must remove the numbers from so it is by itself on one side of the equation.

To do this we first look to see if a number is being added or subtracted from .

In this case a number is being subtracted so we must add the number, , to each side of the equation.

$\frac{x}{8}-17+17=32+17$

Perform the math so our equation looks like

$\frac{x}{8}=49$

Then we multiply each side of the equation by the number that is under to get by itself

$(8)\cdot \frac{x}{8}=49\cdot (8)$

Perform the math to find the answer .

Solve for if .

Explanation

To perform a two-step algebra problem with addition and multiplication we must remove the numbers from so it is by itself on one side of the equation.

To do this we first look to see if a number is being added or subtracted from .

In this case a number is being subtracted so we must add the number, , to each side of the equation