How to find the length of the side of a 45/45/90 right isosceles triangle

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Math › How to find the length of the side of a 45/45/90 right isosceles triangle

Questions 1 - 3

What is the area of a square that has a diagonal whose endpoints in the coordinate plane are located at (-8, 6) and (2, -4)?

100

100√2

50√2

200√2

Explanation

Square_part1

Square_part2

Square_part3

Isosceles

An isosceles triangle has a hypotenuse of . Find the length of its sides, .

Not enough information to solve

Explanation

An isosceles triangle is a special triangle due to the values of its angles. These triangles are referred to as $45^{\circ}-45^{\circ}-90^{\circ}$ triangles and their side lengths follow a specific pattern that states you can calculate the length of the legs of an isoceles triangle by dividing the length of the hypotenuse by the square root of 2

$x=\frac{h}{\sqrt{2}}$

$x=\frac{7in}{\sqrt{2}}$

$\rightarrow 4.95in$

Isosceles

The measure of the sides of this isosceles right triangle are $x=3\sqrt{2}$ . Find the measure of its hypotenuse, .

Not enough information to solve

Explanation

An isosceles triangle is a special triangle due to the values of its angles. These triangles are referred to as $45^{\circ}-45^{\circ}-90^{\circ}$ triangles and their side lenghts follow a specific pattern that states you can calculate the length of the hypotenuse of an isoceles triangle by multiplying the length of one of the legs by the square root of 2.

$h=x\sqrt{2}$

$h=3\sqrt{2}*\sqrt{2}$

$\rightarrow6$

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