How to find the height of of an acute / obtuse isosceles triangle

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Math › How to find the height of of an acute / obtuse isosceles triangle

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An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$7\ cm$

$6\ cm$

$8\ cm$

$9\ cm$

$10\ cm$

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$