Coordinate Geometry
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Math › Coordinate Geometry
Define a function as follows:
Give the vertical aysmptote of the graph of .
The graph of does not have a vertical asymptote.
Explanation
Since any number, positive or negative, can appear as an exponent, the domain of the function is the set of all real numbers; in other words,
is defined for all real values of
. It is therefore impossible for the graph to have a vertical asymptote.
Define a function as follows:
Give the horizontal aysmptote of the graph of .
Explanation
The horizontal asymptote of an exponential function can be found by noting that a positive number raised to any power must be positive. Therefore, and
for all real values of
. The graph will never crosst the line of the equatin
, so this is the horizontal asymptote.
The point on the coordinate plane with coordinates lies
on an axis.
in Quadrant IV.
in Quadrant III.
in Quadrant I.
in Quadrant II.
Explanation
On the coordinate plane, a point with 0 as one of its coordinates lies on an axis.
The point on the coordinate plane with coordinates lies
in Quadrant II.
in Quadrant III.
in Quadrant IV.
in Quadrant I.
on an axis.
Explanation
On the coordinate plane, a point with a negative -coordinate and a positive
-coordinate lies in the upper left quadrant - Quadrant II.
Explanation
True or false: The graph of has as a vertical asymptote the graph of the equation
.
False
True
Explanation
The vertical asymptote(s) of the graph of a rational function such as can be found by evaluating the zeroes of the denominator after the rational expression is reduced.
First, factor the numerator. It is a quadratic trinomial with lead term , so look to factor
by using the grouping technique. We try finding two integers whose sum is and whose product is
; with some trial and error we find that these are
and
, so:
Break the linear term:
Regroup:
Factor the GCF twice:
Therefore, can be rewritten as
Cancel the common factor from both halves; the function can be rewritten as
Set the denominator equal to 0 and solve for :
The graph of therefore has one vertical asymptotes, the line of the equations
. The line of the equation
is not a vertical asymptote.
Which of the following are the equations of the vertical asymptotes of the graph of ?
(a)
(b)
(b) only
(a) only
Both (a) and (b)
Neither (a) nor (b)
Explanation
The vertical asymptote(s) of the graph of a rational function such as can be found by evaluating the zeroes of the denominator after the rational expression is reduced.
First, factor the denominator. It is a quadratic trinomial with lead term , so look to "reverse-FOIL" it as
by finding two integers with sum 6 and product 5. By trial and error, these integers can be found to be 1 and 5, so
Therefore, can be rewritten as
Set the denominator equal to 0 and solve for :
By the Zero Factor Principle,
or
Therefore, the binomial factor can be cancelled, and the function can be rewritten as
If , then
, so the denominator has only this one zero, and the only vertical asymptote is the line of the equation
.
The chord of a central angle of a circle with area
has what length?
Explanation
The radius of a circle with area
can be found as follows:
The circle, the central angle, and the chord are shown below:

By way of the Isosceles Triangle Theorem, can be proved equilateral, so
, the correct response.
Give the domain of the function
The set of all real numbers
Explanation
The domain of any polynomial function, such as , is the set of real numbers, as a polynomial can be evaluated for any real value of
.
In which quadrant does the complex number lie?
Explanation
If we graphed the given complex number on a set of real-imaginary axes, we would plot the real value of the complex number as the x coordinate, and the imaginary value of the complex number as the y coordinate. Because the given complex number is as follows:
We are essentially doing the same as plotting the point on a set of Cartesian axes. We move
units right in the x direction, and
units down in the y direction, which puts us in the fourth quadrant, or in terms of Roman numerals: