Understanding Rational Expressions - Math

Card 1 of 8

Didn't Know

Knew It

1 of 87 left

Question

Solve:

If varies directly as , and when , find when .

Tap to reveal answer

Answer

The formula for a direct variation is:

$\frac{x_1}{x_2}$=\frac{y_1}{y_2}$

Plugging in our values, we get:

$\frac{7}{x}$=\frac{21}{-5}$

$x= $\frac{-5}{3}$$

← Didn't Know|Knew It →

Question

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is $60\ cm$ long and $40\ cm$ wide. A second box (same depth and capacity) is $5\ cm$ long. How wide is it?

Tap to reveal answer

Answer

The formula for an indirect variation is:

$\frac{x_1}{x_2}$=\frac{y_2}{y_1}$

Plugging in our values, we get:

$\frac{60\ cm}{5\ cm}$=\frac{y}{40\ cm}$

$5y=2400\ cm$

$y=480\ cm$

← Didn't Know|Knew It →

Question

Solve:

If varies directly as , and when , find when .

Tap to reveal answer

Answer

The formula for a direct variation is:

$\frac{x_1}{x_2}$=\frac{y_1}{y_2}$

Plugging in our values, we get:

$\frac{7}{x}$=\frac{21}{-5}$

$x= $\frac{-5}{3}$$

← Didn't Know|Knew It →

Question

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is $60\ cm$ long and $40\ cm$ wide. A second box (same depth and capacity) is $5\ cm$ long. How wide is it?

Tap to reveal answer

Answer

The formula for an indirect variation is:

$\frac{x_1}{x_2}$=\frac{y_2}{y_1}$

Plugging in our values, we get:

$\frac{60\ cm}{5\ cm}$=\frac{y}{40\ cm}$

$5y=2400\ cm$

$y=480\ cm$

← Didn't Know|Knew It →

Question

Solve:

If varies directly as , and when , find when .

Tap to reveal answer

Answer

The formula for a direct variation is:

$\frac{x_1}{x_2}$=\frac{y_1}{y_2}$

Plugging in our values, we get:

$\frac{7}{x}$=\frac{21}{-5}$

$x= $\frac{-5}{3}$$

← Didn't Know|Knew It →

Question

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is $60\ cm$ long and $40\ cm$ wide. A second box (same depth and capacity) is $5\ cm$ long. How wide is it?

Tap to reveal answer

Answer

The formula for an indirect variation is:

$\frac{x_1}{x_2}$=\frac{y_2}{y_1}$

Plugging in our values, we get:

$\frac{60\ cm}{5\ cm}$=\frac{y}{40\ cm}$

$5y=2400\ cm$

$y=480\ cm$

← Didn't Know|Knew It →

Question

Solve:

If varies directly as , and when , find when .

Tap to reveal answer

Answer

The formula for a direct variation is:

$\frac{x_1}{x_2}$=\frac{y_1}{y_2}$

Plugging in our values, we get:

$\frac{7}{x}$=\frac{21}{-5}$

$x= $\frac{-5}{3}$$

← Didn't Know|Knew It →

Question

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is $60\ cm$ long and $40\ cm$ wide. A second box (same depth and capacity) is $5\ cm$ long. How wide is it?

Tap to reveal answer

Answer

The formula for an indirect variation is:

$\frac{x_1}{x_2}$=\frac{y_2}{y_1}$

Plugging in our values, we get:

$\frac{60\ cm}{5\ cm}$=\frac{y}{40\ cm}$

$5y=2400\ cm$

$y=480\ cm$

← Didn't Know|Knew It →

Knew It

Understanding Rational Expressions - Math

Solve: If varies directly as , and when , find when .

The formula for a direct variation is: Plugging in our values, we get:

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is long and wide. A second box (same depth and capacity) is long. How wide is it?

The formula for an indirect variation is: Plugging in our values, we get:

Solve: If varies directly as , and when , find when .

The formula for a direct variation is: Plugging in our values, we get:

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is long and wide. A second box (same depth and capacity) is long. How wide is it?

The formula for an indirect variation is: Plugging in our values, we get:

Solve: If varies directly as , and when , find when .

The formula for a direct variation is: Plugging in our values, we get:

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is long and wide. A second box (same depth and capacity) is long. How wide is it?

The formula for an indirect variation is: Plugging in our values, we get:

Solve: If varies directly as , and when , find when .

The formula for a direct variation is: Plugging in our values, we get:

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is long and wide. A second box (same depth and capacity) is long. How wide is it?

The formula for an indirect variation is: Plugging in our values, we get:

Solve:

If varies directly as , and when , find when .

The formula for a direct variation is:

$\frac{x_1}{x_2}$=\frac{y_1}{y_2}$

Plugging in our values, we get:

$\frac{7}{x}$=\frac{21}{-5}$

$x= $\frac{-5}{3}$$

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is $60\ cm$ long and $40\ cm$ wide. A second box (same depth and capacity) is $5\ cm$ long. How wide is it?

The formula for an indirect variation is:

$\frac{x_1}{x_2}$=\frac{y_2}{y_1}$

Plugging in our values, we get:

$\frac{60\ cm}{5\ cm}$=\frac{y}{40\ cm}$

$5y=2400\ cm$

$y=480\ cm$

Solve:

If varies directly as , and when , find when .

The formula for a direct variation is:

$\frac{x_1}{x_2}$=\frac{y_1}{y_2}$

Plugging in our values, we get:

$\frac{7}{x}$=\frac{21}{-5}$

$x= $\frac{-5}{3}$$

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is $60\ cm$ long and $40\ cm$ wide. A second box (same depth and capacity) is $5\ cm$ long. How wide is it?

The formula for an indirect variation is:

$\frac{x_1}{x_2}$=\frac{y_2}{y_1}$

Plugging in our values, we get:

$\frac{60\ cm}{5\ cm}$=\frac{y}{40\ cm}$

$5y=2400\ cm$

$y=480\ cm$

Solve:

If varies directly as , and when , find when .

The formula for a direct variation is:

$\frac{x_1}{x_2}$=\frac{y_1}{y_2}$

Plugging in our values, we get:

$\frac{7}{x}$=\frac{21}{-5}$

$x= $\frac{-5}{3}$$

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is $60\ cm$ long and $40\ cm$ wide. A second box (same depth and capacity) is $5\ cm$ long. How wide is it?

The formula for an indirect variation is:

$\frac{x_1}{x_2}$=\frac{y_2}{y_1}$

Plugging in our values, we get:

$\frac{60\ cm}{5\ cm}$=\frac{y}{40\ cm}$

$5y=2400\ cm$

$y=480\ cm$

Solve:

If varies directly as , and when , find when .

The formula for a direct variation is:

$\frac{x_1}{x_2}$=\frac{y_1}{y_2}$

Plugging in our values, we get:

$\frac{7}{x}$=\frac{21}{-5}$

$x= $\frac{-5}{3}$$

If two boxes have the same depth and capacity, the length is inversely proportional to the width. One box is $60\ cm$ long and $40\ cm$ wide. A second box (same depth and capacity) is $5\ cm$ long. How wide is it?

The formula for an indirect variation is:

$\frac{x_1}{x_2}$=\frac{y_2}{y_1}$

Plugging in our values, we get:

$\frac{60\ cm}{5\ cm}$=\frac{y}{40\ cm}$

$5y=2400\ cm$

$y=480\ cm$