Understanding Polynomial Functions - Math

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Solve the following system of equations:

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We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

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$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

Let and . Evaluate .

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Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

Solve the following system of equations:

Tap to see back →

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

Tap to see back →

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

Let and . Evaluate .

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Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

Solve the following system of equations:

Tap to see back →

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

Tap to see back →

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

Let and . Evaluate .

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Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

Solve the following system of equations:

Tap to see back →

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

Tap to see back →

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

Let and . Evaluate .

Tap to see back →

Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$