Understanding Polynomial Functions - Math

Card 1 of 12

Didn't Know

Knew It

1 of 1211 left

Question

Solve the following system of equations:

Tap to reveal answer

Answer

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

← Didn't Know|Knew It →

Question

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

Tap to reveal answer

Answer

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

← Didn't Know|Knew It →

Question

Let and . Evaluate .

Tap to reveal answer

Answer

Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

← Didn't Know|Knew It →

Question

Solve the following system of equations:

Tap to reveal answer

Answer

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

← Didn't Know|Knew It →

Question

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

Tap to reveal answer

Answer

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

← Didn't Know|Knew It →

Question

Let and . Evaluate .

Tap to reveal answer

Answer

Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

← Didn't Know|Knew It →

Question

Solve the following system of equations:

Tap to reveal answer

Answer

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

← Didn't Know|Knew It →

Question

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

Tap to reveal answer

Answer

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

← Didn't Know|Knew It →

Question

Let and . Evaluate .

Tap to reveal answer

Answer

Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

← Didn't Know|Knew It →

Question

Solve the following system of equations:

Tap to reveal answer

Answer

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

← Didn't Know|Knew It →

Question

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

Tap to reveal answer

Answer

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

← Didn't Know|Knew It →

Question

Let and . Evaluate .

Tap to reveal answer

Answer

Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

← Didn't Know|Knew It →

Knew It

Understanding Polynomial Functions - Math

Solve the following system of equations:

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get: Then add this new equation, to the second original equation, to get: or Plugging this value of back into the first original equation, gives: or

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

Let and . Evaluate .

Substitute into , and then substitute the answer into .

Solve the following system of equations:

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get: Then add this new equation, to the second original equation, to get: or Plugging this value of back into the first original equation, gives: or

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

Let and . Evaluate .

Substitute into , and then substitute the answer into .

Solve the following system of equations:

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get: Then add this new equation, to the second original equation, to get: or Plugging this value of back into the first original equation, gives: or

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

Let and . Evaluate .

Substitute into , and then substitute the answer into .

Solve the following system of equations:

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get: Then add this new equation, to the second original equation, to get: or Plugging this value of back into the first original equation, gives: or

It took Jack 25 minutes to travel 14 miles, what was Jack's average speed in mph?

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

Let and . Evaluate .

Substitute into , and then substitute the answer into .

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$

We will solve this system of equations by Elimination. Multiply both sides of the first equation by 2, to get:

Then add this new equation, to the second original equation, to get:

or

Plugging this value of back into the first original equation, gives:

or

$speed=\frac{distance}{time}$$

$speed=\frac{14\ miles}{25\ minutes }$$

* We have to change the time from minutes to hours, there are 60 minutes in one hour.

$speed= $\frac{14\ miles}{25\ minutes}$ * $\frac{60\ minutes}{1\ hour}$$

$speed= 33.6\ mph$

Substitute into , and then substitute the answer into .

$f(x)= $3x^{2}$-2$

$f(5) $=3(5)^{2}$-2= 75 -2 = 73$