Understanding Arcsine, Arccosine, and Arctangent - Math

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Question

What is $\theta$ if and ?

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Answer

In order to find $\theta$ we need to utilize the given information in the problem. We are given the opposite and adjacent sides. We can then, by definition, find the $\tan$ of $\theta$ and its measure in degrees by utilizing the $\arctan$ function.

$\tan=\frac{opposite}{adjacent}$$

$\tan=\frac{10}{8}$$

$\tan=1.25$

Now to find the measure of the angle using the $\arctan$ function.

$\theta=\arctan1.25$

$\rightarrow $51.34^{\circ}$$

If you calculated the angle's measure to be then your calculator was set to radians and needs to be set on degrees.

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Question

$o=7.6, h=15.7, \Theta = ?$

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Answer

In order to find $\theta$ we need to utilize the given information in the problem. We are given the opposite and hypotenuse sides. We can then, by definition, find the $\sin$ of $\theta$ and its measure in degrees by utilizing the $\arcsin$ function.

$\sin=\frac{opposite}{hypotenuse}$$

$\sin=\frac{7.6}{15.7}$$

$\sin=0.4841$

Now to find the measure of the angle using the $\arcsin$ function.

$\theta=\arcsin0.4841$

$\rightarrow $28.95^{\circ}$$

If you calculated the angle's measure to be $\dpi{100} $0.50^{\circ}$}$ then your calculator was set to radians and needs to be set on degrees.

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Question

$\sin(x^\circ)=\frac{1}{2}$$

What is ?

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Answer

To get rid of $\sin(x^\circ)$ , we take the $\arcsin$ or of both sides.

$\sin(x^\circ)=\frac{1}{2}$$

$x^$\circ=\sin^{-1}$($\frac{1}{2}$)$

$x^\circ=30^\circ$

← Didn't Know|Knew It →

Question

What is $\theta$ if and ?

Tap to reveal answer

Answer

In order to find $\theta$ we need to utilize the given information in the problem. We are given the opposite and adjacent sides. We can then, by definition, find the $\tan$ of $\theta$ and its measure in degrees by utilizing the $\arctan$ function.

$\tan=\frac{opposite}{adjacent}$$

$\tan=\frac{10}{8}$$

$\tan=1.25$

Now to find the measure of the angle using the $\arctan$ function.

$\theta=\arctan1.25$

$\rightarrow $51.34^{\circ}$$

If you calculated the angle's measure to be then your calculator was set to radians and needs to be set on degrees.

← Didn't Know|Knew It →

Question

$o=7.6, h=15.7, \Theta = ?$

Tap to reveal answer

Answer

In order to find $\theta$ we need to utilize the given information in the problem. We are given the opposite and hypotenuse sides. We can then, by definition, find the $\sin$ of $\theta$ and its measure in degrees by utilizing the $\arcsin$ function.

$\sin=\frac{opposite}{hypotenuse}$$

$\sin=\frac{7.6}{15.7}$$

$\sin=0.4841$

Now to find the measure of the angle using the $\arcsin$ function.

$\theta=\arcsin0.4841$

$\rightarrow $28.95^{\circ}$$

If you calculated the angle's measure to be $\dpi{100} $0.50^{\circ}$}$ then your calculator was set to radians and needs to be set on degrees.

← Didn't Know|Knew It →

Question

$\sin(x^\circ)=\frac{1}{2}$$

What is ?

Tap to reveal answer

Answer

To get rid of $\sin(x^\circ)$ , we take the $\arcsin$ or of both sides.

$\sin(x^\circ)=\frac{1}{2}$$

$x^$\circ=\sin^{-1}$($\frac{1}{2}$)$

$x^\circ=30^\circ$

← Didn't Know|Knew It →

Question

What is $\theta$ if and ?

Tap to reveal answer

Answer

In order to find $\theta$ we need to utilize the given information in the problem. We are given the opposite and adjacent sides. We can then, by definition, find the $\tan$ of $\theta$ and its measure in degrees by utilizing the $\arctan$ function.

$\tan=\frac{opposite}{adjacent}$$

$\tan=\frac{10}{8}$$

$\tan=1.25$

Now to find the measure of the angle using the $\arctan$ function.

$\theta=\arctan1.25$

$\rightarrow $51.34^{\circ}$$

If you calculated the angle's measure to be then your calculator was set to radians and needs to be set on degrees.

← Didn't Know|Knew It →

Question

$o=7.6, h=15.7, \Theta = ?$

Tap to reveal answer

Answer

In order to find $\theta$ we need to utilize the given information in the problem. We are given the opposite and hypotenuse sides. We can then, by definition, find the $\sin$ of $\theta$ and its measure in degrees by utilizing the $\arcsin$ function.

$\sin=\frac{opposite}{hypotenuse}$$

$\sin=\frac{7.6}{15.7}$$

$\sin=0.4841$

Now to find the measure of the angle using the $\arcsin$ function.

$\theta=\arcsin0.4841$

$\rightarrow $28.95^{\circ}$$

If you calculated the angle's measure to be $\dpi{100} $0.50^{\circ}$}$ then your calculator was set to radians and needs to be set on degrees.

← Didn't Know|Knew It →

Question

$\sin(x^\circ)=\frac{1}{2}$$

What is ?

Tap to reveal answer

Answer

To get rid of $\sin(x^\circ)$ , we take the $\arcsin$ or of both sides.

$\sin(x^\circ)=\frac{1}{2}$$

$x^$\circ=\sin^{-1}$($\frac{1}{2}$)$

$x^\circ=30^\circ$

← Didn't Know|Knew It →

Question

What is $\theta$ if and ?

Tap to reveal answer

Answer

In order to find $\theta$ we need to utilize the given information in the problem. We are given the opposite and adjacent sides. We can then, by definition, find the $\tan$ of $\theta$ and its measure in degrees by utilizing the $\arctan$ function.

$\tan=\frac{opposite}{adjacent}$$

$\tan=\frac{10}{8}$$

$\tan=1.25$

Now to find the measure of the angle using the $\arctan$ function.

$\theta=\arctan1.25$

$\rightarrow $51.34^{\circ}$$

If you calculated the angle's measure to be then your calculator was set to radians and needs to be set on degrees.

← Didn't Know|Knew It →

Question

$o=7.6, h=15.7, \Theta = ?$

Tap to reveal answer

Answer

In order to find $\theta$ we need to utilize the given information in the problem. We are given the opposite and hypotenuse sides. We can then, by definition, find the $\sin$ of $\theta$ and its measure in degrees by utilizing the $\arcsin$ function.

$\sin=\frac{opposite}{hypotenuse}$$

$\sin=\frac{7.6}{15.7}$$

$\sin=0.4841$

Now to find the measure of the angle using the $\arcsin$ function.

$\theta=\arcsin0.4841$

$\rightarrow $28.95^{\circ}$$

If you calculated the angle's measure to be $\dpi{100} $0.50^{\circ}$}$ then your calculator was set to radians and needs to be set on degrees.

← Didn't Know|Knew It →

Question

$\sin(x^\circ)=\frac{1}{2}$$

What is ?

Tap to reveal answer

Answer

To get rid of $\sin(x^\circ)$ , we take the $\arcsin$ or of both sides.

$\sin(x^\circ)=\frac{1}{2}$$

$x^$\circ=\sin^{-1}$($\frac{1}{2}$)$

$x^\circ=30^\circ$

← Didn't Know|Knew It →

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