Acute / Obtuse Triangles - Math
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A triangle has sides of length 8, 13, and L. Which of the following cannot equal L?
A triangle has sides of length 8, 13, and L. Which of the following cannot equal L?
The sum of the lengths of two sides of a triangle cannot be less than the length of the third side. 8 + 4 = 12, which is less than 13.
The sum of the lengths of two sides of a triangle cannot be less than the length of the third side. 8 + 4 = 12, which is less than 13.
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Two sides of a triangle are 20 and 32. Which of the following CANNOT be the third side of this triangle.
Two sides of a triangle are 20 and 32. Which of the following CANNOT be the third side of this triangle.
Please remember the Triangle Inequality Theorem, which states that the sum of any two sides of a triangle must be greater than the third side. Therefore, the correct answer is 10 because the sum of 10 and 20 would not be greater than the third side 32.
Please remember the Triangle Inequality Theorem, which states that the sum of any two sides of a triangle must be greater than the third side. Therefore, the correct answer is 10 because the sum of 10 and 20 would not be greater than the third side 32.
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A triangle has a perimeter of 36 inches, and one side that is 12 inches long. The lengths of the other two sides have a ratio of 3:5. What is the length of the longest side of the triangle?
A triangle has a perimeter of 36 inches, and one side that is 12 inches long. The lengths of the other two sides have a ratio of 3:5. What is the length of the longest side of the triangle?
We know that the perimeter is 36 inches, and one side is 12. This means, the sum of the lengths of the other two sides are 24. The ratio between the two sides is 3:5, giving a total of 8 parts. We divide the remaining length, 24 inches, by 8 giving us 3. This means each part is 3. We multiply this by the ratio and get 9:15, meaning the longest side is 15 inches.
We know that the perimeter is 36 inches, and one side is 12. This means, the sum of the lengths of the other two sides are 24. The ratio between the two sides is 3:5, giving a total of 8 parts. We divide the remaining length, 24 inches, by 8 giving us 3. This means each part is 3. We multiply this by the ratio and get 9:15, meaning the longest side is 15 inches.
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A triangle has sides of length 5, 7, and x. Which of the following can NOT be a value of x?
A triangle has sides of length 5, 7, and x. Which of the following can NOT be a value of x?
The sum of the lengths of any two sides of a triangle must exceed the length of the third side; therefore, 5+7 > x, which cannot happen if x = 13.
The sum of the lengths of any two sides of a triangle must exceed the length of the third side; therefore, 5+7 > x, which cannot happen if x = 13.
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Two sides of a triangle have lengths 4 and 7. Which of the following represents the set of all possible lengths of the third side, x?
Two sides of a triangle have lengths 4 and 7. Which of the following represents the set of all possible lengths of the third side, x?
The set of possible lengths is: 7-4 < x < 7+4, or 3 < X < 11.
The set of possible lengths is: 7-4 < x < 7+4, or 3 < X < 11.
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If two sides of a triangle have lengths 8 and 10, what could the length of the third side NOT be?
If two sides of a triangle have lengths 8 and 10, what could the length of the third side NOT be?
According to the Triangle Inequality Theorem, the sums of the lengths of any two sides of a triangle must be greater than the length of the third side. Since 10 + 8 is 18, the only length out of the answer choices that is not possible is 19.
According to the Triangle Inequality Theorem, the sums of the lengths of any two sides of a triangle must be greater than the length of the third side. Since 10 + 8 is 18, the only length out of the answer choices that is not possible is 19.
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The lengths of two sides of a triangle are 9 and 7. Which of the following could be the length of the third side?
The lengths of two sides of a triangle are 9 and 7. Which of the following could be the length of the third side?
Let us call the third side x. According to the Triangle Inequality Theorem, the sum of any two sides of a triangle must be larger than the other two sides. Thus, all of the following must be true:
x + 7 > 9
x + 9 > 7
7 + 9 > x
We can solve these three inequalities to determine the possible values of x.
x + 7 > 9
Subtract 7 from both sides.
x > 2
Now, we can look at x + 9 > 7. Subtracting 9 from both sides, we obtain
x > –2
Finally, 7 + 9 > x, which means that 16 > x.
Therefore, x must be greater than 2, greater than –2, but also less than 16. The only number that satisfies all of these requirements is 12.
The answer is 12.
Let us call the third side x. According to the Triangle Inequality Theorem, the sum of any two sides of a triangle must be larger than the other two sides. Thus, all of the following must be true:
x + 7 > 9
x + 9 > 7
7 + 9 > x
We can solve these three inequalities to determine the possible values of x.
x + 7 > 9
Subtract 7 from both sides.
x > 2
Now, we can look at x + 9 > 7. Subtracting 9 from both sides, we obtain
x > –2
Finally, 7 + 9 > x, which means that 16 > x.
Therefore, x must be greater than 2, greater than –2, but also less than 16. The only number that satisfies all of these requirements is 12.
The answer is 12.
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The lengths of a triangle are 8, 12, and x. Which of the following inequalities shows all of the possible values of x?
The lengths of a triangle are 8, 12, and x. Which of the following inequalities shows all of the possible values of x?
According to the Triangle Inequality Theorem, the sum of any two sides of a triangle must be greater (not greater than or equal) than the remaining side. Thus, the following inequalities must all be true:
x + 8 > 12
x + 12 > 8
8 + 12 > x
Let's solve each inequality.
x + 8 > 12
Subtract 8 from both sides.
x > 4
Next, let's look at the inequality x + 12 > 8
x + 12 > 8
Subtract 12 from both sides.
x > –4
Lastly, 8 + 12 > x, which means that x < 20.
This means that x must be less than twenty, but greater than 4 and greater than –4. Since any number greater than 4 is also greater than –4, we can exclude the inequality x > –4.
To summarize, x must be greater than 4 and less than 20. We can write this as 4 < x < 20.
The answer is 4 < x < 20.
According to the Triangle Inequality Theorem, the sum of any two sides of a triangle must be greater (not greater than or equal) than the remaining side. Thus, the following inequalities must all be true:
x + 8 > 12
x + 12 > 8
8 + 12 > x
Let's solve each inequality.
x + 8 > 12
Subtract 8 from both sides.
x > 4
Next, let's look at the inequality x + 12 > 8
x + 12 > 8
Subtract 12 from both sides.
x > –4
Lastly, 8 + 12 > x, which means that x < 20.
This means that x must be less than twenty, but greater than 4 and greater than –4. Since any number greater than 4 is also greater than –4, we can exclude the inequality x > –4.
To summarize, x must be greater than 4 and less than 20. We can write this as 4 < x < 20.
The answer is 4 < x < 20.
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If 2 sides of the triangle are have lengths equal to 8 and 14, what is one possible length of the third side?
If 2 sides of the triangle are have lengths equal to 8 and 14, what is one possible length of the third side?
The sum of the lengths of 2 sides of a triangle must be greater than—but not equal to—the length of the third side. Further, the third side must be longer than the difference between the greater and the lesser of the other two sides; therefore, 20 is the only possible answer.
The sum of the lengths of 2 sides of a triangle must be greater than—but not equal to—the length of the third side. Further, the third side must be longer than the difference between the greater and the lesser of the other two sides; therefore, 20 is the only possible answer.
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In 
the length of AB is 15 and the length of side AC is 5. What is the least possible integer length of side BC?
In
Rule - the length of one side of a triangle must be greater than the differnce and less than the sum of the lengths of the other two sides.
Given lengths of two of the sides of the 
are 15 and 5. The length of the third side must be greater than 15-5 or 10 and less than 15+5 or 20.
The question asks what is the least possible integer length of BC, which would be 11
Rule - the length of one side of a triangle must be greater than the differnce and less than the sum of the lengths of the other two sides.
Given lengths of two of the sides of the
The question asks what is the least possible integer length of BC, which would be 11
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Two similiar triangles exist where the ratio of perimeters is 4:5 for the smaller to the larger triangle. If the larger triangle has sides of 6, 7, and 12 inches, what is the perimeter, in inches, of the smaller triangle?
Two similiar triangles exist where the ratio of perimeters is 4:5 for the smaller to the larger triangle. If the larger triangle has sides of 6, 7, and 12 inches, what is the perimeter, in inches, of the smaller triangle?
The larger triangle has a perimeter of 25 inches. Therefore, using a 4:5 ratio, the smaller triangle's perimeter will be 20 inches.
The larger triangle has a perimeter of 25 inches. Therefore, using a 4:5 ratio, the smaller triangle's perimeter will be 20 inches.
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If a = 7 and b = 4, which of the following could be the perimeter of the triangle?
I. 11
II. 15
III. 25
If a = 7 and b = 4, which of the following could be the perimeter of the triangle?
I. 11
II. 15
III. 25
Consider the perimeter of a triangle:
P = a + b + c
Since we know a and b, we can find c.
In I:
11 = 7 + 4 + c
11 = 11 + c
c = 0
Note that if c = 0, the shape is no longer a trial. Thus, we can eliminate I.
In II:
15 = 7 + 4 + c
15 = 11 + c
c = 4.
This is plausible given that the other sides are 7 and 4.
In III:
25 = 7 + 4 + c
25 = 11 + c
c = 14.
It is not possible for one side of a triangle to be greater than the sum of both of the other sides, so eliminate III.
Thus we are left with only II.
Consider the perimeter of a triangle:
P = a + b + c
Since we know a and b, we can find c.
In I:
11 = 7 + 4 + c
11 = 11 + c
c = 0
Note that if c = 0, the shape is no longer a trial. Thus, we can eliminate I.
In II:
15 = 7 + 4 + c
15 = 11 + c
c = 4.
This is plausible given that the other sides are 7 and 4.
In III:
25 = 7 + 4 + c
25 = 11 + c
c = 14.
It is not possible for one side of a triangle to be greater than the sum of both of the other sides, so eliminate III.
Thus we are left with only II.
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Two sides of an isosceles triangle are 20 and 30. What is the difference of the largest and the smallest possible perimeters?
Two sides of an isosceles triangle are 20 and 30. What is the difference of the largest and the smallest possible perimeters?
The trick here is that we don't know which is the repeated side. Our possible triangles are therefore 20 + 20 + 30 = 70 or 30 + 30 + 20 = 80. The difference is therefore 80 – 70 or 10.
The trick here is that we don't know which is the repeated side. Our possible triangles are therefore 20 + 20 + 30 = 70 or 30 + 30 + 20 = 80. The difference is therefore 80 – 70 or 10.
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Two similiar triangles have a ratio of perimeters of 
.
If the smaller triangle has sides of 3, 7, and 5, what is the perimeter of the larger triangle.
Two similiar triangles have a ratio of perimeters of
If the smaller triangle has sides of 3, 7, and 5, what is the perimeter of the larger triangle.
Adding the sides gives a perimeter of 15 for the smaller triangle. Multipying by the given ratio of 
, yields 52.5.
Adding the sides gives a perimeter of 15 for the smaller triangle. Multipying by the given ratio of
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Find the height of a triangle if the area of the triangle = 18 and the base = 4.
Find the height of a triangle if the area of the triangle = 18 and the base = 4.
The area of a triangle = (1/2)bh where b is base and h is height. 18 = (1/2)4h which gives us 36 = 4h so h =9.
The area of a triangle = (1/2)bh where b is base and h is height. 18 = (1/2)4h which gives us 36 = 4h so h =9.
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The ratio of the side lengths of a triangle is 7:10:11. In a similar triangle, the middle side is 9 inches long. What is the length of the longest side of the second triangle?
The ratio of the side lengths of a triangle is 7:10:11. In a similar triangle, the middle side is 9 inches long. What is the length of the longest side of the second triangle?
Side lengths of similar triangles can be expressed in proportions. Establish a proportion comparing the middle and long sides of your triangles.
10/11 = 9/x
Cross multiply and solve for x.
10x = 99
x = 9.9
Side lengths of similar triangles can be expressed in proportions. Establish a proportion comparing the middle and long sides of your triangles.
10/11 = 9/x
Cross multiply and solve for x.
10x = 99
x = 9.9
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and 
are similar triangles. The perimeter of Triangle A is 45” and the length of two of its sides are 15” and 10”. If the perimeter of Triangle B is 135” and what are lengths of two of its sides?
The perimeter is equal to the sum of the three sides. In similar triangles, each side is in proportion to its correlating side. The perimeters are also in equal proportion.
Perimeter A = 45” and perimeter B = 135”
The proportion of Perimeter A to Perimeter B is 
.
This applies to the sides of the triangle. Therefore to get the any side of Triangle B, just multiply the correlating side by 3.
15” x 3 = 45”
10” x 3 = 30“
The perimeter is equal to the sum of the three sides. In similar triangles, each side is in proportion to its correlating side. The perimeters are also in equal proportion.
Perimeter A = 45” and perimeter B = 135”
The proportion of Perimeter A to Perimeter B is
This applies to the sides of the triangle. Therefore to get the any side of Triangle B, just multiply the correlating side by 3.
15” x 3 = 45”
10” x 3 = 30“
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Two triangles are similar to each other. The bigger one has side lengths of 12, 3, and 14.
The smaller triangle's shortest side is 1 unit in length. What is the length of the smaller triangle's longest side?
Two triangles are similar to each other. The bigger one has side lengths of 12, 3, and 14.
The smaller triangle's shortest side is 1 unit in length. What is the length of the smaller triangle's longest side?
Because the triangles are similar, a ratio can be set up between the triangles' longest sides and shortest sides as such: 14/3 = x/1. Solving for x, we obtain that the shortest side of the triangle is 14/3 units long.
Because the triangles are similar, a ratio can be set up between the triangles' longest sides and shortest sides as such: 14/3 = x/1. Solving for x, we obtain that the shortest side of the triangle is 14/3 units long.
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A triangle with two equal angles is called a(n) .
A triangle with two equal angles is called a(n) .
An isoceles triangle is a triangle that has at least two congruent sides (and therefore, at least two congruent angles as well).
An isoceles triangle is a triangle that has at least two congruent sides (and therefore, at least two congruent angles as well).
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Are the triangles similar? If so, solve for 
. (Not drawn to scale).
Are the triangles similar? If so, solve for
The triangles are similar because of the side-angle-side postulate.
Side: 
Angle: 
Side: 
The third side must also have a 2:3 ratio.
Cross-multiply, and solve for 
.
The triangles are similar because of the side-angle-side postulate.
Side:
Angle:
Side:
The third side must also have a 2:3 ratio.
Cross-multiply, and solve for
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