How to find x or y intercept - Math

The intercepts cross an axis.

For the intercept, set to get

For the intercept, set to get

So the sum of the intercepts is .

The -intercept is the point where the y-value is equal to 0. Therefore,

To find the x-intercept, we simply plug into our function. giving us . We can factor that equation, making it . We can not solve for , and we get . To find the y-intercept, we do the same thing, however this time, we plug in instead. This leaves us with . With an x-intercept of and a y-intercept of , it is clear that the y-intercept is greater than the x-intercept.

To find the x-intercept, set y equal to 0.

Now solve for x by dividing by 3 on both sides.

This reduces to,

To find the y-intercept, set x equal to 0.

Now solve for y.

The x-intercept of a line is the x-value where the line hits the x-axis. This occurs when y is 0. To determine the x-value, plug in 0 for y in the original equation, then solve for x:

add 5 to both sides

divide by 2

The x-intercepts of any curve are the x-values where the curve is intersecting the x-axis. This happens when y = 0. To figure out these x-values, plug in 0 for y in the original equation and solve for x:

adding 0 or 0 square doesn't change the value

take the square root of both sides

this means there are two different potential values for x, and we will have to solve for both. First:

add 4 to both sides

Second: again, add 4 to both sides

Our two answers are and .

The y-intercept(s) occur where the graph intersects with the y-axis. This is where x=0, so we can find these y-values by plugging in 0 for x in the equation:

The x-intercept(s) occur where the graph intersects with the x-axis. This is where y=0, so we can find these x-values by plugging in 0 for y in the equation:

add 16 to both sides

take the square root

To find where the graph hits the y-axis, plug in 0 for x:

first evaluate 0 - 2

then square -2

add 4 to both sides

take the square root of both sides

now we have 2 potential solutions and need to solve for both

a)

b)

To determine the x-intercept, plug in for , since the x-axis is where .

subtract from both sides

multiply both sides by

divide both sides by

The x-intercept is

To find the x-intercept, plug in for , since the x-axis is where .

add to both sides

divide both sides by

To find the y-intercept, plug in 0 for x, since the y-axis is where x = 0.

subtract 24 from both sides

divide by -3

The y-intercept is

To find the x-intercept, plug in 0 for y, since the x-axis is where y = 0

subtract 5 from both sides

multiply both sides by -3

The x-intercept is

To solve, you must find the zeros or x-intercepts for the function h(t).

To find x-intercepts, we must plug in 0 for h(t).

Factor to solve - divide by 16t.

Set both parts equat to zero.

The answer is t=16 because when t=0, that is when the rocket is first being fired from the ground, the rocket then returns to the ground after having spent 16 seconds in the air.

To find the y-intercept for any equation, plug in 0 for x in the original equation.

Simplify

Subtract 25 from both sides

Take the square root of both sides

Subtract 2 from both sides to get the y-intercept.

This circle has one y-intercept.

It is possible for a circle to have one y-intercept, two y-intercepts or no y-intercepts.

Here all we have to remember is that when given a linear equation to find the y-intercept, or where the line crosses the y-axis, we just need to set x=0 and solve for y. This solution is shown below:

The x-intercepts occur when y is equal to zero. So to figure out the x-intercepts, plug in 0 for y:

subtract 9 from both sides

take the square root of both sides

there are 2 possibilities here since and also

One solution: subtract 1 from both sides

The other solution: subtract 1 from both sides

The y-intercept occurs when x is 0, so plug in 0 for x:

To find the x-intercept, plug in 0 for y:

subtract 5 from both sides

divide both sides by -2

since x is 2.5 and y is 0, this point is

To find the y-intercept, plug in 0 for x:

This gives the point