How to find x or y intercept - Math
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True or false: The lines of the equations
and
have the same 
-intercept.
True or false: The lines of the equations
and
have the same
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The 
-intercept of a line is the point at which it intersects the 
-axis; its 
-coordinate at this point is 0, so its 
-coordinate can be found by substituting 0 for 
in the equation and solving for 
. Do this with both equations:
The 
-intercept of the line is at 
.
The 
-intercept of the line is at 
.
The two lines have different 
-intercepts.
The
The
The
The two lines have different
True or false: the lines of the equations
and
have the same 
-intercept.
True or false: the lines of the equations
and
have the same
Tap to see back →
The -intercept of a line is the point at which it intersects the -axis; its -coordinate at this point is 0.
The -coordinate of the line of the equation
can be found by substituting 0 for in the equation and solving for :
The 
-intercept of this line is at 
.
The line with equation 
is a horizontal line with its 
-intercept at 
, so the 
-intercept line of the equation 
has its 
-intercept at 
as well.
Both lines indeed have the same 
-intercept.
The
The
can be found by substituting 0 for
The
The line with equation
Both lines indeed have the same
What is the x-intercept for the line 
?
What is the x-intercept for the line
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To find the x-intercept, plug in 
for 
, since the x-axis is where 
.
add 
to both sides
divide both sides by 
To find the x-intercept, plug in
Find the y-intercept of the line 
.
Find the y-intercept of the line
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Recall that at the y-intercept, the line crosses the y-axis. This means that at the y-intercept, the value of the x-coordinate is 
.
Plug in 
for 
into the equation to find the y-intercept.
The y-intercept for this line is 
.
Recall that at the y-intercept, the line crosses the y-axis. This means that at the y-intercept, the value of the x-coordinate is
Plug in
The y-intercept for this line is
What are the 
and 
-intercepts of the line defined by the equation:
What are the
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To find the intercepts of a line, we must set the 
and 
values equal to zero and then solve.
To find the intercepts of a line, we must set the
Given the line 
what is the sum of the 
and 
intercepts?
Given the line
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The intercepts cross an axis.
For the 
intercept, set 
to get 
For the 
intercept, set 
to get 
So the sum of the intercepts is 
.
The intercepts cross an axis.
For the
For the
So the sum of the intercepts is
Find the y-intercept of the line 
.
Find the y-intercept of the line
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Recall that at the y-intercept, the line crosses the y-axis. This means that at the y-intercept, the value of the x-coordinate is 
.
Plug in 
for 
into the equation to find the y-intercept.
The y-intercept for this line is 
.
Recall that at the y-intercept, the line crosses the y-axis. This means that at the y-intercept, the value of the x-coordinate is
Plug in
The y-intercept for this line is
What is the 
-intercept of the following line:
What is the
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The 
-intercept is the point where the y-value is equal to 0. Therefore,
The
Which of the following statements regarding the x and y intercepts of the equation 
is true?
Which of the following statements regarding the x and y intercepts of the equation
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To find the x-intercept, we simply plug 
into our function. giving us 
. We can factor that equation, making it 
. We can not solve for 
, and we get 
. To find the y-intercept, we do the same thing, however this time, we plug in 
instead. This leaves us with 
. With an x-intercept of 
and a y-intercept of 
, it is clear that the y-intercept is greater than the x-intercept.
To find the x-intercept, we simply plug
Find the 
-intercept of the following function.
Find the
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To find the x-intercept, set y equal to 0.
Now solve for x by dividing by 3 on both sides.
This reduces to,
To find the x-intercept, set y equal to 0.
Now solve for x by dividing by 3 on both sides.
This reduces to,
Find the 
-intercept of the following function.
Find the
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To find the y-intercept, set x equal to 0.
Now solve for y.
To find the y-intercept, set x equal to 0.
Now solve for y.
Which is the x-intercept for the line 
?
Which is the x-intercept for the line
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The x-intercept of a line is the x-value where the line hits the x-axis. This occurs when y is 0. To determine the x-value, plug in 0 for y in the original equation, then solve for x:
add 5 to both sides
divide by 2
The x-intercept of a line is the x-value where the line hits the x-axis. This occurs when y is 0. To determine the x-value, plug in 0 for y in the original equation, then solve for x:
Find the x-intercept(s) for the circle 
Find the x-intercept(s) for the circle
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The x-intercepts of any curve are the x-values where the curve is intersecting the x-axis. This happens when y = 0. To figure out these x-values, plug in 0 for y in the original equation and solve for x:
adding 0 or 0 square doesn't change the value
take the square root of both sides
this means there are two different potential values for x, and we will have to solve for both. First:
add 4 to both sides
Second: 
again, add 4 to both sides
Our two answers are 
and 
.
The x-intercepts of any curve are the x-values where the curve is intersecting the x-axis. This happens when y = 0. To figure out these x-values, plug in 0 for y in the original equation and solve for x:
Second:
Our two answers are
Which is neither an x- or y-intercept for the parabola 
Which is neither an x- or y-intercept for the parabola
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The y-intercept(s) occur where the graph intersects with the y-axis. This is where x=0, so we can find these y-values by plugging in 0 for x in the equation:
The x-intercept(s) occur where the graph intersects with the x-axis. This is where y=0, so we can find these x-values by plugging in 0 for y in the equation:
add 16 to both sides
take the square root
The y-intercept(s) occur where the graph intersects with the y-axis. This is where x=0, so we can find these y-values by plugging in 0 for x in the equation:
The x-intercept(s) occur where the graph intersects with the x-axis. This is where y=0, so we can find these x-values by plugging in 0 for y in the equation:
Give the coordinate pair(s) where 
intersects with the y-axis.
Give the coordinate pair(s) where
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To find where the graph hits the y-axis, plug in 0 for x:
first evaluate 0 - 2
then square -2
add 4 to both sides
take the square root of both sides
now we have 2 potential solutions and need to solve for both
a) 
b) 
To find where the graph hits the y-axis, plug in 0 for x:
a)
b)
What is the x-intercept of the line 
What is the x-intercept of the line
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To determine the x-intercept, plug in 
for 
, since the x-axis is where 
.
subtract 
from both sides
multiply both sides by 
divide both sides by 
The x-intercept is 
To determine the x-intercept, plug in
The x-intercept is
Find the y-intercept for the line
.
Find the y-intercept for the line
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To find the y-intercept, plug in 0 for x, since the y-axis is where x = 0.
subtract 24 from both sides
divide by -3
The y-intercept is 
To find the y-intercept, plug in 0 for x, since the y-axis is where x = 0.
The y-intercept is
Find the x-intercept for the line
.
Find the x-intercept for the line
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To find the x-intercept, plug in 0 for y, since the x-axis is where y = 0
subtract 5 from both sides
multiply both sides by -3
The x-intercept is 
To find the x-intercept, plug in 0 for y, since the x-axis is where y = 0
The x-intercept is
A rocket is fired that follows the below parabolic path where h(t) represents the height (in feet) over time (in seconds). How much time did the rocket spend in the air?
A rocket is fired that follows the below parabolic path where h(t) represents the height (in feet) over time (in seconds). How much time did the rocket spend in the air?
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To solve, you must find the zeros or x-intercepts for the function h(t).
To find x-intercepts, we must plug in 0 for h(t).
Factor to solve - divide by 16t.
Set both parts equat to zero.
The answer is t=16 because when t=0, that is when the rocket is first being fired from the ground, the rocket then returns to the ground after having spent 16 seconds in the air.
To solve, you must find the zeros or x-intercepts for the function h(t).
To find x-intercepts, we must plug in 0 for h(t).
Factor to solve - divide by 16t.
Set both parts equat to zero.
The answer is t=16 because when t=0, that is when the rocket is first being fired from the ground, the rocket then returns to the ground after having spent 16 seconds in the air.
Find the y-intercept(s) for the circle given by the equation below:
Find the y-intercept(s) for the circle given by the equation below:
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To find the y-intercept for any equation, plug in 0 for x in the original equation.
Simplify
Subtract 25 from both sides
Take the square root of both sides
Subtract 2 from both sides to get the y-intercept.
This circle has one y-intercept.
It is possible for a circle to have one y-intercept, two y-intercepts or no y-intercepts.
To find the y-intercept for any equation, plug in 0 for x in the original equation.
Simplify
Subtract 25 from both sides
Take the square root of both sides
Subtract 2 from both sides to get the y-intercept.
This circle has one y-intercept.
It is possible for a circle to have one y-intercept, two y-intercepts or no y-intercepts.