How to find the volume of a pyramid - Math

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Pyramid 1 has a square base with sidelength ; its height is .

Pyramid 2 has a square base with sidelength ; its height is .

Which is the greater quantity?

(a) The volume of Pyramid 1

(b) The volume of Pyramid 2

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Use the formula $V = \frac {1}{3} Bh$ on each pyramid.

(a) $B = $x^{2}$; h = 2x$

$V = \frac {1}{3} Bh = \frac {1}{3} \cdot $x^{2}$ \cdot 2x = \frac {2}{3} $x^{3}$$

(b) $B = (2 $x)^{2}$ = $4x^{2}$; h = x$

$V = \frac {1}{3} Bh = \frac {1}{3} \cdot $4x^{2}$ \cdot x = \frac {4}{3} $x^{3}$$

Regardless of , (b) is the greater quantity.

Which is the greater quantity?

(a) The volume of a pyramid with height 4, the base of which has sidelength 1

(b) The volume of a pyramid with height 1, the base of which has sidelength 2

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The volume of a pyramid with height and a square base with sidelength is

$V = $\frac{1}{3}$ Bh = $\frac{1}{3}$ $s^{2}$h$ .

(a) Substitute : $V = $\frac{1}{3}$ $s^{2}$h = $\frac{1}{3}$ \cdot $1^{2}$ \cdot 4 = $\frac{4}{3}$$

(b) Substitute : $V = $\frac{1}{3}$ $s^{2}$h = $\frac{1}{3}$ \cdot $2^{2}$ \cdot 1 = $\frac{4}{3}$$

The two pyramids have equal volume.

Which is the greater quantity?

(a) The volume of a pyramid whose base is a square with sidelength 8 inches

(b) The volume of a pyramid whose base is an equilateral triangle with sidelength one foot

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The volume of a pyramid is one-third of the product of the height and the area of the base. The areas of the bases can be calculated, but no information is given about the heights of the pyramids. There is not enough information to determine which one has the greater volume.

A pyramid with a square base has height equal to the perimeter of its base. Its volume is . In terms of , what is the length of each side of its base?

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The volume of a pyramid is given by the formula

$V = $\frac{1}{3}$ A h$

where is the area of its base and is its height.

Let be the length of one side of the square base. Then the height is equal to the perimeter of that square, so

and the area of the base is

$A = $s^{2}$$

So the volume formula becomes

$$\frac{1}{3}$ \cdot $s^{2}$ \cdot 4s = V$

Solve for :

$$\frac{4}{3}$ \cdot $s^{3}$ = V$

$$\frac{3}{4}$ \cdot $\frac{4}{3}$ \cdot $s^{3}$ =\frac{3}{4}$ \cdot V$

$s =\sqrt[3]{$\frac{3V}{4}$}$

An architect wants to make a square pyramid and fill it with 12,000 cubic feet of sand. If the base of the pyramid is 30 feet on each side, how tall does he need to make it?

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Volume of Pyramid = 1/3 * Area of Base * Height

12,000 ft3 = 1/3 * 30ft * 30ft * H

12,000 = 300 * H

H = 12,000 / 300 = 40

H = 40 ft

The volume of a 6-foot-tall square pyramid is 8 cubic feet. How long are the sides of the base?

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Volume of a pyramid is

$$\frac{1}{3}$\cdot (Area\ of\ the\ base)\cdot (height)$

Thus:

$8=\frac{1}{3}$\cdot (Area\ of\ the\ base)\cdot (6)$

$8=2\cdot (Area\ of\ the\ base)$

Area of the base is $4\ $ft^{2}$$ .

Therefore, each side is $2\ ft$ .

What is the sum of the number of vertices, edges, and faces of a square pyramid?

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A square pyramid has one square base and four triangular sides.

Vertices (where two or more edges come together): 5. There are four vertices on the base (one at each corner of the square) and a fifth at the top of the pyramid.

Edges (where two faces come together): 8. There are four edges on the base (one along each side) and four more along the sides of the triangular faces extending from the corners of the base to the top vertex.

Faces (planar surfaces): 5. The base is one face, and there are four triangular faces that form the top of the pyramid.

Total

What is the volume of a pyramid with a height of and a square base with a side length of ?

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To find the volume of a pyramid we must use the equation

$Volume: of: pyramid=\frac{1}{3}$(area\ of\ base)(height)$

We must first solve for the area of the square using

$A=(side\ $length^{2}$)$

We plug in and square it to get

We then plug our answer into the equation for the pyramid with the height to get

$V=\frac{1}{3}$(49)(15)$

We multiply the result to get our final answer for the volume of the pyramid

.

Find the volume of the following pyramid. Round the answer to the nearest integer.

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The formula for the volume of a pyramid is:

$V = $\frac{wlh}{3}$$

where is the width of the base, is the length of the base, and is the height of the pyramid.

In order to determine the height of the pyramid, you will need to use the Pythagoream Theorem to find the slant height:

Now we can use the slant height to find the pyramid height, once again using the Pythagoream Theorem:

$A = $\sqrt{119}$m$

Plugging in our values, we get:

$V = $\frac{wlh}{3}$$

$V = $\frac{(10m)(10m)(\sqrt{119}$m)}{3}$

$V = $$\frac{100\sqrt{119}$m^3$}{3} \approx $364m^3$$

Find the volume of the following pyramid.

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The formula for the volume of a pyramid is:

$V = $\frac{1}{3}$ (base)(height)$

$V = $\frac{1}{3}$ (l)(w)(h)$

Where is the length of the base, is the width of the base, and is the height of the pyramid

Use the Pythagorean Theorem to find the length of the slant height:

Now, use the Pythagorean Theorem again to find the length of the height:

$A = 2$\sqrt{7}$m$

Plugging in our values, we get:

$V = $\frac{1}{3}$ (12m)(12m)(2$\sqrt{7}$m)$

$V = $96$\sqrt{7}$m^3$$

Pyramid 1 has a square base with sidelength ; its height is .

Pyramid 2 has a square base with sidelength ; its height is .

Which is the greater quantity?

(a) The volume of Pyramid 1

(b) The volume of Pyramid 2

Tap to see back →

Use the formula $V = \frac {1}{3} Bh$ on each pyramid.

(a) $B = $x^{2}$; h = 2x$

$V = \frac {1}{3} Bh = \frac {1}{3} \cdot $x^{2}$ \cdot 2x = \frac {2}{3} $x^{3}$$

(b) $B = (2 $x)^{2}$ = $4x^{2}$; h = x$

$V = \frac {1}{3} Bh = \frac {1}{3} \cdot $4x^{2}$ \cdot x = \frac {4}{3} $x^{3}$$

Regardless of , (b) is the greater quantity.

Which is the greater quantity?

(a) The volume of a pyramid with height 4, the base of which has sidelength 1

(b) The volume of a pyramid with height 1, the base of which has sidelength 2

Tap to see back →

The volume of a pyramid with height and a square base with sidelength is

$V = $\frac{1}{3}$ Bh = $\frac{1}{3}$ $s^{2}$h$ .

(a) Substitute : $V = $\frac{1}{3}$ $s^{2}$h = $\frac{1}{3}$ \cdot $1^{2}$ \cdot 4 = $\frac{4}{3}$$

(b) Substitute : $V = $\frac{1}{3}$ $s^{2}$h = $\frac{1}{3}$ \cdot $2^{2}$ \cdot 1 = $\frac{4}{3}$$

The two pyramids have equal volume.

Which is the greater quantity?

(a) The volume of a pyramid whose base is a square with sidelength 8 inches

(b) The volume of a pyramid whose base is an equilateral triangle with sidelength one foot

Tap to see back →

The volume of a pyramid is one-third of the product of the height and the area of the base. The areas of the bases can be calculated, but no information is given about the heights of the pyramids. There is not enough information to determine which one has the greater volume.

A pyramid with a square base has height equal to the perimeter of its base. Its volume is . In terms of , what is the length of each side of its base?

Tap to see back →

The volume of a pyramid is given by the formula

$V = $\frac{1}{3}$ A h$

where is the area of its base and is its height.

Let be the length of one side of the square base. Then the height is equal to the perimeter of that square, so

and the area of the base is

$A = $s^{2}$$

So the volume formula becomes

$$\frac{1}{3}$ \cdot $s^{2}$ \cdot 4s = V$

Solve for :

$$\frac{4}{3}$ \cdot $s^{3}$ = V$

$$\frac{3}{4}$ \cdot $\frac{4}{3}$ \cdot $s^{3}$ =\frac{3}{4}$ \cdot V$

$s =\sqrt[3]{$\frac{3V}{4}$}$

An architect wants to make a square pyramid and fill it with 12,000 cubic feet of sand. If the base of the pyramid is 30 feet on each side, how tall does he need to make it?

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Volume of Pyramid = 1/3 * Area of Base * Height

12,000 ft3 = 1/3 * 30ft * 30ft * H

12,000 = 300 * H

H = 12,000 / 300 = 40

H = 40 ft

The volume of a 6-foot-tall square pyramid is 8 cubic feet. How long are the sides of the base?

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Volume of a pyramid is

$$\frac{1}{3}$\cdot (Area\ of\ the\ base)\cdot (height)$

Thus:

$8=\frac{1}{3}$\cdot (Area\ of\ the\ base)\cdot (6)$

$8=2\cdot (Area\ of\ the\ base)$

Area of the base is $4\ $ft^{2}$$ .

Therefore, each side is $2\ ft$ .

What is the sum of the number of vertices, edges, and faces of a square pyramid?

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A square pyramid has one square base and four triangular sides.

Vertices (where two or more edges come together): 5. There are four vertices on the base (one at each corner of the square) and a fifth at the top of the pyramid.

Edges (where two faces come together): 8. There are four edges on the base (one along each side) and four more along the sides of the triangular faces extending from the corners of the base to the top vertex.

Faces (planar surfaces): 5. The base is one face, and there are four triangular faces that form the top of the pyramid.

Total

What is the volume of a pyramid with a height of and a square base with a side length of ?

Tap to see back →

To find the volume of a pyramid we must use the equation

$Volume: of: pyramid=\frac{1}{3}$(area\ of\ base)(height)$

We must first solve for the area of the square using

$A=(side\ $length^{2}$)$

We plug in and square it to get

We then plug our answer into the equation for the pyramid with the height to get

$V=\frac{1}{3}$(49)(15)$

We multiply the result to get our final answer for the volume of the pyramid

.

Find the volume of the following pyramid. Round the answer to the nearest integer.

Tap to see back →

The formula for the volume of a pyramid is:

$V = $\frac{wlh}{3}$$

where is the width of the base, is the length of the base, and is the height of the pyramid.

In order to determine the height of the pyramid, you will need to use the Pythagoream Theorem to find the slant height:

Now we can use the slant height to find the pyramid height, once again using the Pythagoream Theorem:

$A = $\sqrt{119}$m$

Plugging in our values, we get:

$V = $\frac{wlh}{3}$$

$V = $\frac{(10m)(10m)(\sqrt{119}$m)}{3}$

$V = $$\frac{100\sqrt{119}$m^3$}{3} \approx $364m^3$$

Find the volume of the following pyramid.

Tap to see back →

The formula for the volume of a pyramid is:

$V = $\frac{1}{3}$ (base)(height)$

$V = $\frac{1}{3}$ (l)(w)(h)$

Where is the length of the base, is the width of the base, and is the height of the pyramid

Use the Pythagorean Theorem to find the length of the slant height:

Now, use the Pythagorean Theorem again to find the length of the height:

$A = 2$\sqrt{7}$m$

Plugging in our values, we get:

$V = $\frac{1}{3}$ (12m)(12m)(2$\sqrt{7}$m)$

$V = $96$\sqrt{7}$m^3$$