How to find the length of a radius - Math

To solve, simply use the formula for the circumference of a circle and solve for r. Thus,

To solve, simply use the formula for the diameter and solve for r. Thus,

Therefore, when solved for r,

Plug in d and:

To Find your answer, we would use the formula: C=2πr. We are given that C = 29.5. Thus we can plug in to get \[29.5\]=2πr and then multiply 2π to get 29.5=(6.28)r. Lastly, we divide both sides by 6.28 to get 4.70=r. (The information given of 22 ounces is useless)

For the circle to be tangent to the y-axis, it must have its outer edge on the axis. The center is 8 units from the edge.

We know that the formula for the area of a circle is πr_2. Therefore, we must set 49_π equal to this formula to solve for the radius of the circle.

49_π_ = _πr_2

49 = _r_2

7 = r

To solve, simply use the formula of the circumference and solve for r. Thus,

We know that the formula for the area of a circle is π_r_2. Therefore, we must set 36π equal to this formula to solve for the radius of the circle.

36π = π_r_2

36 = _r_2

6 = r

Find the total area of the circle, then use the area formula to find the radius.

Area of section A = section B = section C

Area of circle X = A + B + C = 12π+ 12π + 12π = 36π

Area of circle = where r is the radius of the circle

36π = πr2

36 = r2

√36 = r

6 = r

The area of a circle is

Substitute 1 for :

This is the radius in yards. The radius in inches is 36 times this.

20.3 inches is the radius.

The formula for the area of a circle is . We can fill in what we know, the area, and then solve for the radius, .

Divide each side of the equation by :

Take the square root of each side:

The circumference of a circle is given by , where is the circumference and is the radius.

Plug in the given circumference for and solve for :

The radius is the distance from the center of a circle to any point on it's perimeter.

A chord is a line segment which joins two points on a curve. A chord does not go through the center of a circle.

The radius is half of the diameter. To find the radius, simply divide the diameter by 2.

Notice that the diagonal of the square is also the hypotenuse of a right isosceles triangle whose legs are also the sides of the square. You should also notice that the diameter of the circle has the same length as that of a side of the square.

In order to find the radius of the circle, we need to first use the Pythagorean theorem to find the length of the side of the square.

Now, substitute in the value of the diagonal to find the length of a side of the square.

Simplify.

Now keep in mind the following relationship between the diameter and the side of the square:

Recall the relationship between the diameter and the radius.

Substitute in the value of the radius by plugging in the value of the diameter.

Solve.

Notice that the diagonal of the square is also the hypotenuse of a right isosceles triangle whose legs are also the sides of the square. You should also notice that the diameter of the circle has the same length as that of a side of the square.

In order to find the radius of the circle, we need to first use the Pythagorean theorem to find the length of the side of the square.

Now, substitute in the value of the diagonal to find the length of a side of the square.

Simplify.

Now keep in mind the following relationship between the diameter and the side of the square:

Recall the relationship between the diameter and the radius.

Substitute in the value of the radius by plugging in the value of the diameter.

Solve.

Notice that the diagonal of the square is also the hypotenuse of a right isosceles triangle whose legs are also the sides of the square. You should also notice that the diameter of the circle has the same length as that of a side of the square.

In order to find the radius of the circle, we need to first use the Pythagorean theorem to find the length of the side of the square.

Now, substitute in the value of the diagonal to find the length of a side of the square.

Simplify.

Now keep in mind the following relationship between the diameter and the side of the square:

Recall the relationship between the diameter and the radius.

Substitute in the value of the radius by plugging in the value of the diameter.

Solve.

Notice that the diagonal of the square is also the hypotenuse of a right isosceles triangle whose legs are also the sides of the square. You should also notice that the diameter of the circle has the same length as that of a side of the square.

In order to find the radius of the circle, we need to first use the Pythagorean theorem to find the length of the side of the square.

Now, substitute in the value of the diagonal to find the length of a side of the square.

Simplify.

Now keep in mind the following relationship between the diameter and the side of the square:

Recall the relationship between the diameter and the radius.

Substitute in the value of the radius by plugging in the value of the diameter.

Solve.

Notice that the diagonal of the square is also the hypotenuse of a right isosceles triangle whose legs are also the sides of the square. You should also notice that the diameter of the circle has the same length as that of a side of the square.

In order to find the radius of the circle, we need to first use the Pythagorean theorem to find the length of the side of the square.

Now, substitute in the value of the diagonal to find the length of a side of the square.

Simplify.

Now keep in mind the following relationship between the diameter and the side of the square:

Recall the relationship between the diameter and the radius.

Substitute in the value of the radius by plugging in the value of the diameter.

Solve.