How to find the height of of an acute / obtuse isosceles triangle - Math
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Question
An isosceles triangle has a base of 12 cm and an area of 42 $cm^{2}$. What must be the height of this triangle?
An isosceles triangle has a base of 12 cm and an area of 42 $cm^{2}$. What must be the height of this triangle?
Answer
A=\frac{1}{2}$bh.
6x=42
x=7
A=\frac{1}{2}$bh.
6x=42
x=7
Compare your answer with the correct one above
Question
An isosceles triangle has a base of 12 cm and an area of 42 $cm^{2}$. What must be the height of this triangle?
An isosceles triangle has a base of 12 cm and an area of 42 $cm^{2}$. What must be the height of this triangle?
Answer
A=\frac{1}{2}$bh.
6x=42
x=7
A=\frac{1}{2}$bh.
6x=42
x=7
Compare your answer with the correct one above
Question
An isosceles triangle has a base of 12 cm and an area of 42 $cm^{2}$. What must be the height of this triangle?
An isosceles triangle has a base of 12 cm and an area of 42 $cm^{2}$. What must be the height of this triangle?
Answer
A=\frac{1}{2}$bh.
6x=42
x=7
A=\frac{1}{2}$bh.
6x=42
x=7
Compare your answer with the correct one above
Question
An isosceles triangle has a base of 12 cm and an area of 42 $cm^{2}$. What must be the height of this triangle?
An isosceles triangle has a base of 12 cm and an area of 42 $cm^{2}$. What must be the height of this triangle?
Answer
A=\frac{1}{2}$bh.
6x=42
x=7
A=\frac{1}{2}$bh.
6x=42
x=7
Compare your answer with the correct one above
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