How to find the height of of an acute / obtuse isosceles triangle - Math

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Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

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