Finding the Center and Radius - Math

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Find the center and radius of the circle defined by the equation:

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The equation of a circle is: $(x-x_${1})^2$+(y-y_${1})^2$$=r^2$$ where is the radius and is the center.

In this problem, the equation is already in the format required to determine center and radius. To find the -coordinate of the center, we must find the value of that makes equal to 0, which is 3. We do the same to find the y-coordinate of the center and find that . To find the radius we take the square root of the constant on the right side of the equation which is 6.

Find the center and radius of the circle defined by the equation:

Tap to see back →

The equation of a circle is: $(x-x_${1})^2$+(y-y_${1})^2$$=r^2$$ where is the radius and is the center.

In this problem, the equation is already in the format required to determine center and radius. To find the -coordinate of the center, we must find the value of that makes equal to , which is . We do the same to find the y-coordinate of the center and find that . To find the radius we take the square root of the constant on the right side of the equation which is 10.

Find the center and radius of the circle defined by the equation:

Tap to see back →

The equation of a circle is: $(x-x_${1})^2$+(y-y_${1})^2$$=r^2$$ where is the radius and is the center.

In this problem, the equation is already in the format required to determine center and radius. To find the -coordinate of the center, we must find the value of that makes equal to 0, which is 3. We do the same to find the y-coordinate of the center and find that . To find the radius we take the square root of the constant on the right side of the equation which is 6.

Find the center and radius of the circle defined by the equation:

Tap to see back →

The equation of a circle is: $(x-x_${1})^2$+(y-y_${1})^2$$=r^2$$ where is the radius and is the center.

In this problem, the equation is already in the format required to determine center and radius. To find the -coordinate of the center, we must find the value of that makes equal to , which is . We do the same to find the y-coordinate of the center and find that . To find the radius we take the square root of the constant on the right side of the equation which is 10.

Find the center and radius of the circle defined by the equation:

Tap to see back →

The equation of a circle is: $(x-x_${1})^2$+(y-y_${1})^2$$=r^2$$ where is the radius and is the center.

In this problem, the equation is already in the format required to determine center and radius. To find the -coordinate of the center, we must find the value of that makes equal to 0, which is 3. We do the same to find the y-coordinate of the center and find that . To find the radius we take the square root of the constant on the right side of the equation which is 6.

Find the center and radius of the circle defined by the equation:

Tap to see back →

The equation of a circle is: $(x-x_${1})^2$+(y-y_${1})^2$$=r^2$$ where is the radius and is the center.

In this problem, the equation is already in the format required to determine center and radius. To find the -coordinate of the center, we must find the value of that makes equal to , which is . We do the same to find the y-coordinate of the center and find that . To find the radius we take the square root of the constant on the right side of the equation which is 10.

Find the center and radius of the circle defined by the equation:

Tap to see back →

The equation of a circle is: $(x-x_${1})^2$+(y-y_${1})^2$$=r^2$$ where is the radius and is the center.

In this problem, the equation is already in the format required to determine center and radius. To find the -coordinate of the center, we must find the value of that makes equal to 0, which is 3. We do the same to find the y-coordinate of the center and find that . To find the radius we take the square root of the constant on the right side of the equation which is 6.

Find the center and radius of the circle defined by the equation:

Tap to see back →

The equation of a circle is: $(x-x_${1})^2$+(y-y_${1})^2$$=r^2$$ where is the radius and is the center.

In this problem, the equation is already in the format required to determine center and radius. To find the -coordinate of the center, we must find the value of that makes equal to , which is . We do the same to find the y-coordinate of the center and find that . To find the radius we take the square root of the constant on the right side of the equation which is 10.