How to find the area of a right triangle - ISEE Upper Level Quantitative Reasoning

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Question

One angle of a right triangle measures 45 degrees, and the hypotenuse measures 8 centimeters. Give the area of the triangle.

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Answer

This triangle has two angles of 45 and 90 degrees, so the third angle must measure 45 degrees; this is therefore an isosceles right triangle.

By the Pythagorean Theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Let hypotenuse and side length.

$\Rightarrow s=$\sqrt{32}$=$\sqrt{16\times 2}$=4$\sqrt{2}$\ cm$

We can then plug this side length into the formula for area.

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Question

The legs of a right triangle measure $2 $\frac{2}{5}$$ and $3 $\frac{1}{5}$$ . What is its perimeter?

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Answer

The hypotenuse of the triangle can be calculated using the Pythagorean Theorem. Set $a = 2 $\frac{2}{5}$ = $\frac{12}{5}$ , b=3 $\frac{1}{5}$= $\frac{16}{5}$$ :

$c ^{2} = a ^{2} + b ^{2}$

$c ^{2} = \left ( $\frac{12}{5}$ \right ) ^{2} + \left ( $\frac{16}{5}$ \right ) ^{2}$

$c ^{2} = $\frac{144}{25}$ + $\frac{256}{25}$$

$c ^{2} = $\frac{400}{25}$ = 16$

$c = $\sqrt{16}$ = 4$

Add the three sidelengths:

$P =2 $\frac{2}{5}$ + 3 $\frac{1}{5}$ + 4 = 9 $\frac{3}{5}$$

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Question

Figure NOT drawn to scale

$\bigtriangleup ABC$ is a right triangle with altitude $\overline{BX}$ . Give the ratio of the area of $\bigtriangleup BXC$ to that of $\bigtriangleup AXB$ .

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Answer

The altitude of a right triangle from the vertex of its right angle - which, here, is $\overline{BX}$ - divides the triangle into two triangles similar to each other. The ratio of the hypotenuse of the white triangle to that of the gray triangle (which are corresponding sides) is

$\frac{BC}{AB}$ = $\frac{40}{30}$ =\frac{4}{3}$ ,

making this the similarity ratio. The ratio of the areas of two similar triangles is the square of their similarity ratio, which here is

$\left( $\frac{4}{3}$ \right $)^{2}$ = $$\frac{4^{2}$$$}{3^{2}$} = $\frac{16}{9}$$ , or .

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Question

Find the area of a right triangle with a base of 7cm and a height of 20cm.

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Answer

To find the area of a right triangle, we will use the following formula:

$A = $\frac{1}{2}$ \cdot b \cdot h$

where b is the base and h is the height of the triangle.

We know the base of the triangle is 7cm. We know the height of the triangle is 20cm. Knowing this, we can substitute into the formula. We get

$A = $\frac{1}{2}$ \cdot 7$\text{cm}$ \cdot 20$\text{cm}$$

$A = 7$\text{cm}$ \cdot 10$\text{cm}$$

$A = $70$\text{cm}$^2$$

← Didn't Know|Knew It →

Question

One angle of a right triangle measures 45 degrees, and the hypotenuse measures 8 centimeters. Give the area of the triangle.

Tap to reveal answer

Answer

This triangle has two angles of 45 and 90 degrees, so the third angle must measure 45 degrees; this is therefore an isosceles right triangle.

By the Pythagorean Theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Let hypotenuse and side length.

$\Rightarrow s=$\sqrt{32}$=$\sqrt{16\times 2}$=4$\sqrt{2}$\ cm$

We can then plug this side length into the formula for area.

← Didn't Know|Knew It →

Question

The legs of a right triangle measure $2 $\frac{2}{5}$$ and $3 $\frac{1}{5}$$ . What is its perimeter?

Tap to reveal answer

Answer

The hypotenuse of the triangle can be calculated using the Pythagorean Theorem. Set $a = 2 $\frac{2}{5}$ = $\frac{12}{5}$ , b=3 $\frac{1}{5}$= $\frac{16}{5}$$ :

$c ^{2} = a ^{2} + b ^{2}$

$c ^{2} = \left ( $\frac{12}{5}$ \right ) ^{2} + \left ( $\frac{16}{5}$ \right ) ^{2}$

$c ^{2} = $\frac{144}{25}$ + $\frac{256}{25}$$

$c ^{2} = $\frac{400}{25}$ = 16$

$c = $\sqrt{16}$ = 4$

Add the three sidelengths:

$P =2 $\frac{2}{5}$ + 3 $\frac{1}{5}$ + 4 = 9 $\frac{3}{5}$$

← Didn't Know|Knew It →

Question

Figure NOT drawn to scale

$\bigtriangleup ABC$ is a right triangle with altitude $\overline{BX}$ . Give the ratio of the area of $\bigtriangleup BXC$ to that of $\bigtriangleup AXB$ .

Tap to reveal answer

Answer

The altitude of a right triangle from the vertex of its right angle - which, here, is $\overline{BX}$ - divides the triangle into two triangles similar to each other. The ratio of the hypotenuse of the white triangle to that of the gray triangle (which are corresponding sides) is

$\frac{BC}{AB}$ = $\frac{40}{30}$ =\frac{4}{3}$ ,

making this the similarity ratio. The ratio of the areas of two similar triangles is the square of their similarity ratio, which here is

$\left( $\frac{4}{3}$ \right $)^{2}$ = $$\frac{4^{2}$$$}{3^{2}$} = $\frac{16}{9}$$ , or .

← Didn't Know|Knew It →

Question

Find the area of a right triangle with a base of 7cm and a height of 20cm.

Tap to reveal answer

Answer

To find the area of a right triangle, we will use the following formula:

$A = $\frac{1}{2}$ \cdot b \cdot h$

where b is the base and h is the height of the triangle.

We know the base of the triangle is 7cm. We know the height of the triangle is 20cm. Knowing this, we can substitute into the formula. We get

$A = $\frac{1}{2}$ \cdot 7$\text{cm}$ \cdot 20$\text{cm}$$

$A = 7$\text{cm}$ \cdot 10$\text{cm}$$

$A = $70$\text{cm}$^2$$

← Didn't Know|Knew It →

Question

One angle of a right triangle measures 45 degrees, and the hypotenuse measures 8 centimeters. Give the area of the triangle.

Tap to reveal answer

Answer

This triangle has two angles of 45 and 90 degrees, so the third angle must measure 45 degrees; this is therefore an isosceles right triangle.

By the Pythagorean Theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Let hypotenuse and side length.

$\Rightarrow s=$\sqrt{32}$=$\sqrt{16\times 2}$=4$\sqrt{2}$\ cm$

We can then plug this side length into the formula for area.

← Didn't Know|Knew It →

Question

The legs of a right triangle measure $2 $\frac{2}{5}$$ and $3 $\frac{1}{5}$$ . What is its perimeter?

Tap to reveal answer

Answer

The hypotenuse of the triangle can be calculated using the Pythagorean Theorem. Set $a = 2 $\frac{2}{5}$ = $\frac{12}{5}$ , b=3 $\frac{1}{5}$= $\frac{16}{5}$$ :

$c ^{2} = a ^{2} + b ^{2}$

$c ^{2} = \left ( $\frac{12}{5}$ \right ) ^{2} + \left ( $\frac{16}{5}$ \right ) ^{2}$

$c ^{2} = $\frac{144}{25}$ + $\frac{256}{25}$$

$c ^{2} = $\frac{400}{25}$ = 16$

$c = $\sqrt{16}$ = 4$

Add the three sidelengths:

$P =2 $\frac{2}{5}$ + 3 $\frac{1}{5}$ + 4 = 9 $\frac{3}{5}$$

← Didn't Know|Knew It →

Question

Figure NOT drawn to scale

$\bigtriangleup ABC$ is a right triangle with altitude $\overline{BX}$ . Give the ratio of the area of $\bigtriangleup BXC$ to that of $\bigtriangleup AXB$ .

Tap to reveal answer

Answer

The altitude of a right triangle from the vertex of its right angle - which, here, is $\overline{BX}$ - divides the triangle into two triangles similar to each other. The ratio of the hypotenuse of the white triangle to that of the gray triangle (which are corresponding sides) is

$\frac{BC}{AB}$ = $\frac{40}{30}$ =\frac{4}{3}$ ,

making this the similarity ratio. The ratio of the areas of two similar triangles is the square of their similarity ratio, which here is

$\left( $\frac{4}{3}$ \right $)^{2}$ = $$\frac{4^{2}$$$}{3^{2}$} = $\frac{16}{9}$$ , or .

← Didn't Know|Knew It →

Question

Find the area of a right triangle with a base of 7cm and a height of 20cm.

Tap to reveal answer

Answer

To find the area of a right triangle, we will use the following formula:

$A = $\frac{1}{2}$ \cdot b \cdot h$

where b is the base and h is the height of the triangle.

We know the base of the triangle is 7cm. We know the height of the triangle is 20cm. Knowing this, we can substitute into the formula. We get

$A = $\frac{1}{2}$ \cdot 7$\text{cm}$ \cdot 20$\text{cm}$$

$A = 7$\text{cm}$ \cdot 10$\text{cm}$$

$A = $70$\text{cm}$^2$$

← Didn't Know|Knew It →

Question

One angle of a right triangle measures 45 degrees, and the hypotenuse measures 8 centimeters. Give the area of the triangle.

Tap to reveal answer

Answer

This triangle has two angles of 45 and 90 degrees, so the third angle must measure 45 degrees; this is therefore an isosceles right triangle.

By the Pythagorean Theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Let hypotenuse and side length.

$\Rightarrow s=$\sqrt{32}$=$\sqrt{16\times 2}$=4$\sqrt{2}$\ cm$

We can then plug this side length into the formula for area.

← Didn't Know|Knew It →

Question

The legs of a right triangle measure $2 $\frac{2}{5}$$ and $3 $\frac{1}{5}$$ . What is its perimeter?

Tap to reveal answer

Answer

The hypotenuse of the triangle can be calculated using the Pythagorean Theorem. Set $a = 2 $\frac{2}{5}$ = $\frac{12}{5}$ , b=3 $\frac{1}{5}$= $\frac{16}{5}$$ :

$c ^{2} = a ^{2} + b ^{2}$

$c ^{2} = \left ( $\frac{12}{5}$ \right ) ^{2} + \left ( $\frac{16}{5}$ \right ) ^{2}$

$c ^{2} = $\frac{144}{25}$ + $\frac{256}{25}$$

$c ^{2} = $\frac{400}{25}$ = 16$

$c = $\sqrt{16}$ = 4$

Add the three sidelengths:

$P =2 $\frac{2}{5}$ + 3 $\frac{1}{5}$ + 4 = 9 $\frac{3}{5}$$

← Didn't Know|Knew It →

Question

Figure NOT drawn to scale

$\bigtriangleup ABC$ is a right triangle with altitude $\overline{BX}$ . Give the ratio of the area of $\bigtriangleup BXC$ to that of $\bigtriangleup AXB$ .

Tap to reveal answer

Answer

The altitude of a right triangle from the vertex of its right angle - which, here, is $\overline{BX}$ - divides the triangle into two triangles similar to each other. The ratio of the hypotenuse of the white triangle to that of the gray triangle (which are corresponding sides) is

$\frac{BC}{AB}$ = $\frac{40}{30}$ =\frac{4}{3}$ ,

making this the similarity ratio. The ratio of the areas of two similar triangles is the square of their similarity ratio, which here is

$\left( $\frac{4}{3}$ \right $)^{2}$ = $$\frac{4^{2}$$$}{3^{2}$} = $\frac{16}{9}$$ , or .

← Didn't Know|Knew It →

Question

Find the area of a right triangle with a base of 7cm and a height of 20cm.

Tap to reveal answer

Answer

To find the area of a right triangle, we will use the following formula:

$A = $\frac{1}{2}$ \cdot b \cdot h$

where b is the base and h is the height of the triangle.

We know the base of the triangle is 7cm. We know the height of the triangle is 20cm. Knowing this, we can substitute into the formula. We get

$A = $\frac{1}{2}$ \cdot 7$\text{cm}$ \cdot 20$\text{cm}$$

$A = 7$\text{cm}$ \cdot 10$\text{cm}$$

$A = $70$\text{cm}$^2$$

← Didn't Know|Knew It →

Knew It

How to find the area of a right triangle - ISEE Upper Level Quantitative Reasoning

One angle of a right triangle measures 45 degrees, and the hypotenuse measures 8 centimeters. Give the area of the triangle.

The legs of a right triangle measure and . What is its perimeter?

The hypotenuse of the triangle can be calculated using the Pythagorean Theorem. Set : Add the three sidelengths:

Figure NOT drawn to scale is a right triangle with altitude . Give the ratio of the area of to that of .

Find the area of a right triangle with a base of 7cm and a height of 20cm.

To find the area of a right triangle, we will use the following formula: where b is the base and h is the height of the triangle. We know the base of the triangle is 7cm. We know the height of the triangle is 20cm. Knowing this, we can substitute into the formula. We get

One angle of a right triangle measures 45 degrees, and the hypotenuse measures 8 centimeters. Give the area of the triangle.

The legs of a right triangle measure and . What is its perimeter?

The hypotenuse of the triangle can be calculated using the Pythagorean Theorem. Set : Add the three sidelengths:

Figure NOT drawn to scale is a right triangle with altitude . Give the ratio of the area of to that of .

Find the area of a right triangle with a base of 7cm and a height of 20cm.

To find the area of a right triangle, we will use the following formula: where b is the base and h is the height of the triangle. We know the base of the triangle is 7cm. We know the height of the triangle is 20cm. Knowing this, we can substitute into the formula. We get

One angle of a right triangle measures 45 degrees, and the hypotenuse measures 8 centimeters. Give the area of the triangle.

The legs of a right triangle measure and . What is its perimeter?

The hypotenuse of the triangle can be calculated using the Pythagorean Theorem. Set : Add the three sidelengths:

Figure NOT drawn to scale is a right triangle with altitude . Give the ratio of the area of to that of .

Find the area of a right triangle with a base of 7cm and a height of 20cm.

To find the area of a right triangle, we will use the following formula: where b is the base and h is the height of the triangle. We know the base of the triangle is 7cm. We know the height of the triangle is 20cm. Knowing this, we can substitute into the formula. We get

One angle of a right triangle measures 45 degrees, and the hypotenuse measures 8 centimeters. Give the area of the triangle.

The legs of a right triangle measure and . What is its perimeter?

The hypotenuse of the triangle can be calculated using the Pythagorean Theorem. Set : Add the three sidelengths:

Figure NOT drawn to scale is a right triangle with altitude . Give the ratio of the area of to that of .

Find the area of a right triangle with a base of 7cm and a height of 20cm.

To find the area of a right triangle, we will use the following formula: where b is the base and h is the height of the triangle. We know the base of the triangle is 7cm. We know the height of the triangle is 20cm. Knowing this, we can substitute into the formula. We get

The legs of a right triangle measure $2 $\frac{2}{5}$$ and $3 $\frac{1}{5}$$ . What is its perimeter?

Figure NOT drawn to scale

$\bigtriangleup ABC$ is a right triangle with altitude $\overline{BX}$ . Give the ratio of the area of $\bigtriangleup BXC$ to that of $\bigtriangleup AXB$ .

The legs of a right triangle measure $2 $\frac{2}{5}$$ and $3 $\frac{1}{5}$$ . What is its perimeter?

Figure NOT drawn to scale

$\bigtriangleup ABC$ is a right triangle with altitude $\overline{BX}$ . Give the ratio of the area of $\bigtriangleup BXC$ to that of $\bigtriangleup AXB$ .

The legs of a right triangle measure $2 $\frac{2}{5}$$ and $3 $\frac{1}{5}$$ . What is its perimeter?

Figure NOT drawn to scale

$\bigtriangleup ABC$ is a right triangle with altitude $\overline{BX}$ . Give the ratio of the area of $\bigtriangleup BXC$ to that of $\bigtriangleup AXB$ .

The legs of a right triangle measure $2 $\frac{2}{5}$$ and $3 $\frac{1}{5}$$ . What is its perimeter?

Figure NOT drawn to scale

$\bigtriangleup ABC$ is a right triangle with altitude $\overline{BX}$ . Give the ratio of the area of $\bigtriangleup BXC$ to that of $\bigtriangleup AXB$ .