ISEE Upper Level Quantitative Reasoning Flashcards: Arithmetic And Geometric Patterns

Study Arithmetic And Geometric Patterns in ISEE Upper Level Quantitative Reasoning with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

ISEE Upper Level Quantitative Reasoning

Arithmetic And Geometric Patterns

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QUESTION
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What is the common ratio rr for the geometric sequence 3,6,12,24,3, -6, 12, -24, \dots?

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ANSWER

r=2r=-2. Divide consecutive terms to determine the constant ratio of -2 in this geometric sequence.

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What this deck covers

This deck focuses on Arithmetic And Geometric Patterns, giving you a quick way to review the definitions, rules, and examples that matter most for ISEE Upper Level Quantitative Reasoning.

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Flashcard 1: What is the common ratio rr for the geometric sequence 3,6,12,24,3, -6, 12, -24, \dots?

Answer: r=2r=-2. Divide consecutive terms to determine the constant ratio of -2 in this geometric sequence.

Flashcard 2: What is the next term in the arithmetic sequence 18,13,8,3,18, 13, 8, 3, \dots?

Answer: 2-2. Subtract the common difference of -5 from the last term to obtain the next term.

Flashcard 3: What is the common difference dd for the arithmetic sequence 4,1,6,11,-4, 1, 6, 11, \dots?

Answer: d=5d=5. Subtract consecutive terms to find the constant difference of 5 in this arithmetic sequence.

Flashcard 4: Which term equals 3232 in the geometric sequence an=22n1a_n=2\cdot 2^{n-1}?

Answer: n=5n=5. Set the geometric formula equal to 32 and solve for nn to determine the term number.

Flashcard 5: What is the explicit formula for the nnth term of a geometric sequence with first term a1a_1 and ratio rr?

Answer: an=a1rn1a_n=a_1\cdot r^{n-1}. The formula calculates the nnth term by multiplying the first term by the ratio raised to (n1)(n-1).

Flashcard 6: What is the next term in the geometric sequence 160,80,40,20,160, 80, 40, 20, \dots?

Answer: 1010. Multiply the last term by the common ratio of 12\frac{1}{2} to find the subsequent term.

Flashcard 7: What is the next term in the geometric sequence 12,14,18,116,\frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, \dots?

Answer: 132\frac{1}{32}. Multiply the last term by the common ratio of 12\frac{1}{2} in this geometric sequence.

Flashcard 8: What is the next term in the Fibonacci-type pattern 2,3,5,8,13,2, 3, 5, 8, 13, \dots?

Answer: 2121. Add the last two terms, 8 and 13, to generate the next in this Fibonacci-like sequence.

Flashcard 9: Identify whether 0.5,1,2,4,0.5, 1, 2, 4, \dots is arithmetic or geometric.

Answer: Geometric. A constant ratio of 2 between terms confirms the sequence is geometric.

Flashcard 10: Identify the pattern type for 1,1,2,3,5,8,1, 1, 2, 3, 5, 8, \dots (each term from previous terms).

Answer: Fibonacci-type: an=an1+an2a_n=a_{n-1}+a_{n-2}. Each term is the sum of the two preceding terms, defining a Fibonacci sequence variant.

Flashcard 11: What is the next term in the pattern 2,6,12,20,2, 6, 12, 20, \dots?

Answer: 3030. Each term follows the pattern n(n+1)n(n+1) for increasing values of nn starting from 1.

Flashcard 12: What is the next term in the geometric sequence 81,27,9,3,-81, 27, -9, 3, \dots?

Answer: 1-1. Multiply the last term by the common ratio of 13-\frac{1}{3} to find the next term.

Flashcard 13: What is the common difference dd if an arithmetic sequence has consecutive terms xx and yy?

Answer: d=yxd=y-x. Subtract the first term from the second to find the constant difference in an arithmetic sequence.

Flashcard 14: What is the next term in the pattern 1,4,9,16,1, 4, 9, 16, \dots?

Answer: 2525. The pattern consists of squares of consecutive integers: 12,22,32,42,521^2, 2^2, 3^2, 4^2, 5^2.

Flashcard 15: Find the missing term in the geometric sequence 4,,364, _, 36.

Answer: 1212. The middle term is the geometric mean of 4 and 36, since ratios are constant.

Flashcard 16: Identify whether 5,15,45,135,5, 15, 45, 135, \dots is arithmetic or geometric.

Answer: Geometric. The constant ratio of 3 between terms identifies the sequence as geometric.

Flashcard 17: What is the next term in the alternating pattern 3,1,3,1,3, -1, 3, -1, \dots?

Answer: 33. The sequence alternates between 3 and -1, so it repeats 3 after -1.

Flashcard 18: Which term equals 00 in the arithmetic sequence an=123(n1)a_n=12-3(n-1)?

Answer: n=5n=5. Set the arithmetic formula equal to 0 and solve for nn to identify the term position.

Flashcard 19: Find the missing term in the arithmetic sequence 9,,179, _, 17.

Answer: 1313. The middle term is the arithmetic mean of 9 and 17, as the differences are equal.

Flashcard 20: What is a7a_7 for the geometric sequence with a1=2a_1=2 and r=3r=3?

Answer: a7=1458a_7=1458. Apply the geometric sequence formula with a1=2a_1=2, r=3r=3, and n=7n=7 to find the term.

Flashcard 21: Identify whether 7,12,17,22,7, 12, 17, 22, \dots is arithmetic or geometric.

Answer: Arithmetic. The constant difference of 5 between terms classifies the sequence as arithmetic.

Flashcard 22: What is a10a_{10} for the arithmetic sequence with a1=4a_1=4 and d=3d=3?

Answer: a10=31a_{10}=31. Substitute a1=4a_1=4, d=3d=3, and n=10n=10 into the arithmetic sequence formula to compute the term.

Flashcard 23: What is the common ratio rr if a geometric sequence has consecutive terms xx and yy?

Answer: r=yxr=\frac{y}{x}. Divide the second term by the first to obtain the constant ratio in a geometric sequence.

Flashcard 24: What is the explicit formula for the nnth term of an arithmetic sequence with first term a1a_1 and difference dd?

Answer: an=a1+(n1)da_n=a_1+(n-1)d. The formula computes the nnth term by adding (n1)(n-1) times the common difference to the first term.