ISEE Middle Level Quantitative Reasoning Flashcards: Rates And Unit Conversions

What this deck covers

This deck focuses on Rates And Unit Conversions, giving you a quick way to review the definitions, rules, and examples that matter most for ISEE Middle Level Quantitative Reasoning.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: Find the unit rate: $18 for $6\ \text{tickets}$.

Answer: \3\ \text{per ticket}$. Divide total cost by number of tickets to find the rate per unit.

Flashcard 2: Convert $3.5\ \text{ft}$ to inches.

Answer: $42\ \text{in}$. Multiply by $12$ since $1$ foot equals $12$ inches.

Flashcard 3: State the formula for time in terms of distance and rate.

Answer: $t=\frac{d}{r}$. Time is found by dividing distance by rate to solve for duration.

Flashcard 4: State the formula that relates distance, rate, and time.

Answer: $d=rt$. The distance equals rate multiplied by time, forming the fundamental relationship in rate problems.

Flashcard 5: Convert $2500\ \text{mL}$ to liters.

Answer: $2.5\ \text{L}$. Divide by $1000$ because $1$ liter equals $1000$ milliliters.

Flashcard 6: Convert $2\ \text{hr}$ to minutes.

Answer: $120\ \text{min}$. Multiply by $60$ because $1$ hour equals $60$ minutes.

Flashcard 7: A recipe uses $\frac{3}{4}\ \text{cup}$ sugar per batch. How much sugar for $4$ batches?

Answer: $3\ \text{cups}$. Multiply the amount per batch by the number of batches to find the total required.

Flashcard 8: A car travels $150\ \text{mi}$ in $3\ \text{hr}$. What is its rate?

Answer: $50\ \text{mi/hr}$. Divide distance by time using $r=\frac{d}{t}$ to find the constant rate.

Flashcard 9: Convert $1500\ \text{g}$ to kilograms.

Answer: $1.5\ \text{kg}$. Divide by $1000$ since $1$ kilogram equals $1000$ grams.

Flashcard 10: What unit must distance have if rate is in $\text{mi/hr}$ and time is in hours?

Answer: $\text{miles}$. Units must be consistent in the distance formula, so distance uses miles when rate is miles per hour and time is hours.

Flashcard 11: Convert $4\ \text{kg}$ to grams.

Answer: $4000\ \text{g}$. Multiply by $1000$ because $1$ kilogram equals $1000$ grams.

Flashcard 12: At $12\ \text{mi/hr}$, how far do you travel in $30\ \text{min}$?

Answer: $6\ \text{mi}$. Convert minutes to hours and multiply rate by time using $d=rt$.

Flashcard 13: Convert $0.5\ \text{hr}$ to seconds.

Answer: $1800\ \text{s}$. Convert hours to minutes by multiplying by $60$, then minutes to seconds by multiplying by $60$.

Flashcard 14: State the formula for rate in terms of distance and time.

Answer: $r=\frac{d}{t}$. Rate is calculated by dividing distance by time to determine speed or pace.

Flashcard 15: Convert $2\ \text{yd}$ to feet.

Answer: $6\ \text{ft}$. Multiply by $3$ as $1$ yard equals $3$ feet.

Flashcard 16: What is $2\ \text{mi/min}$ in $\text{mi/hr}$?

Answer: $120\ \text{mi/hr}$. Multiply by $60$ to convert from per minute to per hour, since an hour has $60$ minutes.

Flashcard 17: Convert $180\ \text{s}$ to minutes.

Answer: $3\ \text{min}$. Divide by $60$ since $1$ minute equals $60$ seconds.

Flashcard 18: Convert $3\ \text{L}$ to milliliters.

Answer: $3000\ \text{mL}$. Multiply by $1000$ as $1$ liter equals $1000$ milliliters.

Flashcard 19: At $8\ \text{ft/s}$, how long does it take to go $200\ \text{ft}$?

Answer: $25\ \text{s}$. Divide distance by rate using $t=\frac{d}{r}$ to solve for time.

Flashcard 20: What is the cost per ounce if $12\ \text{oz}$ costs $3?

Answer: \0.25\ \text{per oz}$. Divide total cost by total ounces to determine the unit price.

Flashcard 21: Convert $1.5\ \text{yd}$ to inches.

Answer: $54\ \text{in}$. Convert yards to feet by multiplying by $3$, then feet to inches by multiplying by $12$.