ISEE Middle Level Quantitative Reasoning Flashcards: Rates And Unit Conversions

What this deck covers

This deck focuses on Rates And Unit Conversions, giving you a quick way to review the definitions, rules, and examples that matter most for ISEE Middle Level Quantitative Reasoning.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: What is $2\ \text{mi/min}$ in $\text{mi/hr}$?

Answer: $120\ \text{mi/hr}$. Multiply by $60$ to convert from per minute to per hour, since an hour has $60$ minutes.

Flashcard 2: State the formula for rate in terms of distance and time.

Answer: $r=\frac{d}{t}$. Rate is calculated by dividing distance by time to determine speed or pace.

Flashcard 3: State the formula that relates distance, rate, and time.

Answer: $d=rt$. The distance equals rate multiplied by time, forming the fundamental relationship in rate problems.

Flashcard 4: A recipe uses $\frac{3}{4}\ \text{cup}$ sugar per batch. How much sugar for $4$ batches?

Answer: $3\ \text{cups}$. Multiply the amount per batch by the number of batches to find the total required.

Flashcard 5: At $12\ \text{mi/hr}$, how far do you travel in $30\ \text{min}$?

Answer: $6\ \text{mi}$. Convert minutes to hours and multiply rate by time using $d=rt$.

Flashcard 6: A car travels $150\ \text{mi}$ in $3\ \text{hr}$. What is its rate?

Answer: $50\ \text{mi/hr}$. Divide distance by time using $r=\frac{d}{t}$ to find the constant rate.

Flashcard 7: What is the cost per ounce if $12\ \text{oz}$ costs \3$?

Answer: \0.25\ \text{per oz}$. Divide total cost by total ounces to determine the unit price.

Flashcard 8: At $8\ \text{ft/s}$, how long does it take to go $200\ \text{ft}$?

Answer: $25\ \text{s}$. Divide distance by rate using $t=\frac{d}{r}$ to solve for time.

Flashcard 9: Find the unit rate: \18$for$6\ \text{tickets}$.

Answer: \3\ \text{per ticket}$. Divide total cost by number of tickets to find the rate per unit.

Flashcard 10: Convert $4\ \text{kg}$ to grams.

Answer: $4000\ \text{g}$. Multiply by $1000$ because $1$ kilogram equals $1000$ grams.

Flashcard 11: Convert $1500\ \text{g}$ to kilograms.

Answer: $1.5\ \text{kg}$. Divide by $1000$ since $1$ kilogram equals $1000$ grams.

Flashcard 12: Convert $3\ \text{L}$ to milliliters.

Answer: $3000\ \text{mL}$. Multiply by $1000$ as $1$ liter equals $1000$ milliliters.

Flashcard 13: Convert $2500\ \text{mL}$ to liters.

Answer: $2.5\ \text{L}$. Divide by $1000$ because $1$ liter equals $1000$ milliliters.

Flashcard 14: Convert $0.5\ \text{hr}$ to seconds.

Answer: $1800\ \text{s}$. Convert hours to minutes by multiplying by $60$, then minutes to seconds by multiplying by $60$.

Flashcard 15: Convert $180\ \text{s}$ to minutes.

Answer: $3\ \text{min}$. Divide by $60$ since $1$ minute equals $60$ seconds.

Flashcard 16: Convert $2\ \text{hr}$ to minutes.

Answer: $120\ \text{min}$. Multiply by $60$ because $1$ hour equals $60$ minutes.

Flashcard 17: Convert $1.5\ \text{yd}$ to inches.

Answer: $54\ \text{in}$. Convert yards to feet by multiplying by $3$, then feet to inches by multiplying by $12$.

Flashcard 18: Convert $2\ \text{yd}$ to feet.

Answer: $6\ \text{ft}$. Multiply by $3$ as $1$ yard equals $3$ feet.

Flashcard 19: Convert $3.5\ \text{ft}$ to inches.

Answer: $42\ \text{in}$. Multiply by $12$ since $1$ foot equals $12$ inches.

Flashcard 20: State the formula for time in terms of distance and rate.

Answer: $t=\frac{d}{r}$. Time is found by dividing distance by rate to solve for duration.

Flashcard 21: What unit must distance have if rate is in $\text{mi/hr}$ and time is in hours?

Answer: $\text{miles}$. Units must be consistent in the distance formula, so distance uses miles when rate is miles per hour and time is hours.