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  3. ISEE Middle Level Quantitative Reasoning

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ISEE Middle Level Quantitative Reasoning Flashcards: Function Rules And Output

Study Function Rules And Output in ISEE Middle Level Quantitative Reasoning with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Function Rules And Output, giving you a quick way to review the definitions, rules, and examples that matter most for ISEE Middle Level Quantitative Reasoning.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

ISEE Middle Level Quantitative Reasoning Flashcards: Function Rules And Output

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QUESTION

What is the output of h(x)=2(x−1)h(x)=2(x-1)h(x)=2(x−1) when x=6x=6x=6?

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ANSWER

h(6)=10h(6)=10h(6)=10. Substitute x=6x=6x=6 into h(x)=2(x−1)h(x)=2(x-1)h(x)=2(x−1) to get 2(5)=102(5)=102(5)=10.

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Flashcard 1: What is the output of h(x)=2(x−1)h(x)=2(x-1)h(x)=2(x−1) when x=6x=6x=6?

Answer: h(6)=10h(6)=10h(6)=10. Substitute x=6x=6x=6 into h(x)=2(x−1)h(x)=2(x-1)h(x)=2(x−1) to get 2(5)=102(5)=102(5)=10.

Flashcard 2: What is the output of f(x)=3x+2f(x)=3x+2f(x)=3x+2 when x=4x=4x=4?

Answer: f(4)=14f(4)=14f(4)=14. Substitute x=4x=4x=4 into the linear function f(x)=3x+2f(x)=3x+2f(x)=3x+2 to get 3(4)+2=143(4)+2=143(4)+2=14.

Flashcard 3: What is the output of J(x)=6xJ(x)=\frac{6}{x}J(x)=x6​ when x=−3x=-3x=−3?

Answer: J(−3)=−2J(-3)=-2J(−3)=−2. Substitute x=−3x=-3x=−3 into J(x)=6xJ(x)=\frac{6}{x}J(x)=x6​ to get 6−3=−2\frac{6}{-3}=-2−36​=−2.

Flashcard 4: What is the output of L(x)=2xL(x)=2^xL(x)=2x when x=5x=5x=5?

Answer: L(5)=32L(5)=32L(5)=32. Substitute x=5x=5x=5 into L(x)=2xL(x)=2^xL(x)=2x to get 25=322^5=3225=32.

Flashcard 5: What is the output of M(x)=x+1M(x)=\sqrt{x+1}M(x)=x+1​ when x=8x=8x=8?

Answer: M(8)=3M(8)=3M(8)=3. Substitute x=8x=8x=8 into M(x)=x+1M(x)=\sqrt{x+1}M(x)=x+1​ to get 9=3\sqrt{9}=39​=3.

Flashcard 6: What is the output of c(y)=2y−3c(y)=2y-3c(y)=2y−3 when y=−5y=-5y=−5?

Answer: c(−5)=−13c(-5)=-13c(−5)=−13. Substitute y=−5y=-5y=−5 into c(y)=2y−3c(y)=2y-3c(y)=2y−3 to get −10−3=−13-10-3=-13−10−3=−13.

Flashcard 7: What is the output of d(t)= rac{1}{2}t+6 when t=10t=10t=10?

Answer: d(10)=11d(10)=11d(10)=11. Substitute t=10t=10t=10 into d(t)=12t+6d(t)=\frac{1}{2}t+6d(t)=21​t+6 to get 5+6=115+6=115+6=11.

Flashcard 8: What is the output of F(x)=2x2−3xF(x)=2x^2-3xF(x)=2x2−3x when x=5x=5x=5?

Answer: F(5)=35F(5)=35F(5)=35. Substitute x=5x=5x=5 into F(x)=2x2−3xF(x)=2x^2-3xF(x)=2x2−3x to get 50−15=3550-15=3550−15=35.

Flashcard 9: What is the output of G(x)=x+12G(x)=\frac{x+1}{2}G(x)=2x+1​ when x=7x=7x=7?

Answer: G(7)=4G(7)=4G(7)=4. Substitute x=7x=7x=7 into G(x)=x+12G(x)=\frac{x+1}{2}G(x)=2x+1​ to get 82=4\frac{8}{2}=428​=4.

Flashcard 10: What is the output of g(x)=x2−5g(x)=x^2-5g(x)=x2−5 when x=3x=3x=3?

Answer: g(3)=4g(3)=4g(3)=4. Substitute x=3x=3x=3 into g(x)=x2−5g(x)=x^2-5g(x)=x2−5 to get 9−5=49-5=49−5=4.

Flashcard 11: What is the output of N(x)=16−xN(x)=\sqrt{16-x}N(x)=16−x​ when x=7x=7x=7?

Answer: N(7)=3N(7)=3N(7)=3. Substitute x=7x=7x=7 into N(x)=16−xN(x)=\sqrt{16-x}N(x)=16−x​ to get 9=3\sqrt{9}=39​=3.

Flashcard 12: What is the output of P(x)=3x4P(x)=\frac{3x}{4}P(x)=43x​ when x=12x=12x=12?

Answer: P(12)=9P(12)=9P(12)=9. Substitute x=12x=12x=12 into P(x)=3x4P(x)=\frac{3x}{4}P(x)=43x​ to get 364=9\frac{36}{4}=9436​=9.

Flashcard 13: What is the output of R(x)=−(x−3)2+1R(x)=-(x-3)^2+1R(x)=−(x−3)2+1 when x=5x=5x=5?

Answer: R(5)=−3R(5)=-3R(5)=−3. Substitute x=5x=5x=5 into R(x)=−(x−3)2+1R(x)=-(x-3)^2+1R(x)=−(x−3)2+1 to get −(2)2+1=−3-(2)^2+1=-3−(2)2+1=−3.

Flashcard 14: What is the output of S(x)=x2−1x−1S(x)=\frac{x^2-1}{x-1}S(x)=x−1x2−1​ when x=4x=4x=4?

Answer: S(4)=5S(4)=5S(4)=5. Substitute x=4x=4x=4 into S(x)=x2−1x−1S(x)=\frac{x^2-1}{x-1}S(x)=x−1x2−1​ to get 153=5\frac{15}{3}=5315​=5.

Flashcard 15: What is the output of T(x)=3−x2T(x)=3-\frac{x}{2}T(x)=3−2x​ when x=−6x=-6x=−6?

Answer: T(−6)=6T(-6)=6T(−6)=6. Substitute x=−6x=-6x=−6 into T(x)=3−x2T(x)=3-\frac{x}{2}T(x)=3−2x​ to get 3−(−3)=63-(-3)=63−(−3)=6.

Flashcard 16: What is the output of k(x)=4x2k(x)=4x^2k(x)=4x2 when x= rac{1}{2}?

Answer: k(12)=1k\left(\frac{1}{2}\right)=1k(21​)=1. Substitute x=12x=\frac{1}{2}x=21​ into k(x)=4x2k(x)=4x^2k(x)=4x2 to get 4(14)=14(\frac{1}{4})=14(41​)=1.

Flashcard 17: What is the output of a(x)=x2+2x+1a(x)=x^2+2x+1a(x)=x2+2x+1 when x=−3x=-3x=−3?

Answer: a(−3)=4a(-3)=4a(−3)=4. Substitute x=−3x=-3x=−3 into a(x)=x2+2x+1a(x)=x^2+2x+1a(x)=x2+2x+1 to get 9−6+1=49-6+1=49−6+1=4.

Flashcard 18: What is the output of b(x)=3(x+4)b(x)=3(x+4)b(x)=3(x+4) when x=−2x=-2x=−2?

Answer: b(−2)=6b(-2)=6b(−2)=6. Substitute x=−2x=-2x=−2 into b(x)=3(x+4)b(x)=3(x+4)b(x)=3(x+4) to get 3(2)=63(2)=63(2)=6.

Flashcard 19: What is the output of e(x)=x3e(x)=x^3e(x)=x3 when x=−2x=-2x=−2?

Answer: e(−2)=−8e(-2)=-8e(−2)=−8. Substitute x=−2x=-2x=−2 into e(x)=x3e(x)=x^3e(x)=x3 to get (−2)3=−8(-2)^3=-8(−2)3=−8.

Flashcard 20: What is the output of s(x)=∣x−5∣s(x)=|x-5|s(x)=∣x−5∣ when x=9x=9x=9?

Answer: s(9)=4s(9)=4s(9)=4. Substitute x=9x=9x=9 into s(x)=∣x−5∣s(x)=|x-5|s(x)=∣x−5∣ to get ∣9−5∣=4|9-5|=4∣9−5∣=4.

Flashcard 21: What is the output of r(x)=∣x−5∣r(x)=|x-5|r(x)=∣x−5∣ when x=2x=2x=2?

Answer: r(2)=3r(2)=3r(2)=3. Substitute x=2x=2x=2 into r(x)=∣x−5∣r(x)=|x-5|r(x)=∣x−5∣ to get ∣2−5∣=3|2-5|=3∣2−5∣=3.

Flashcard 22: What is the output of q(n)=5−2nq(n)=5-2nq(n)=5−2n when n=8n=8n=8?

Answer: q(8)=−11q(8)=-11q(8)=−11. Substitute n=8n=8n=8 into q(n)=5−2nq(n)=5-2nq(n)=5−2n to get 5−16=−115-16=-115−16=−11.

Flashcard 23: What is the output of p(t)= rac{t}{3}+7 when t=9t=9t=9?

Answer: p(9)=10p(9)=10p(9)=10. Substitute t=9t=9t=9 into p(t)=t3+7p(t)=\frac{t}{3}+7p(t)=3t​+7 to get 3+7=103+7=103+7=10.