A sequence of two reflections across two parallel lines results in a single translation. If a figure is reflected first across the line y = –2 and then across the line y = 3, what is the total vertical distance of the resulting translation?
- 1 unit
- 5 units
- 10 units (correct answer)
- 2.5 units
Explanation: The distance of the translation resulting from two reflections over parallel lines is twice the distance between the lines. The distance between the line y = –2 and y = 3 is |3 – (–2)| = 5 units. Therefore, the distance of the translation is 2 × 5 = 10 units.