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  2. ISEE Middle Level Quantitative Reasoning
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ISEE Middle Level Quantitative Reasoning Flashcards: Calculating Averages

Study Calculating Averages in ISEE Middle Level Quantitative Reasoning with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Calculating Averages, giving you a quick way to review the definitions, rules, and examples that matter most for ISEE Middle Level Quantitative Reasoning.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

ISEE Middle Level Quantitative Reasoning Flashcards: Calculating Averages

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QUESTION

State the formula for the arithmetic mean of nnn numbers x1,x2,…,xnx_1, x_2, \dots, x_nx1​,x2​,…,xn​.

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ANSWER

mean=x1+x2+⋯+xnn\text{mean}=\frac{x_1+x_2+\cdots+x_n}{n}mean=nx1​+x2​+⋯+xn​​. The arithmetic mean is the sum of all values divided by the number of values.

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Flashcard 1: State the formula for the arithmetic mean of nnn numbers x1,x2,…,xnx_1, x_2, \dots, x_nx1​,x2​,…,xn​.

Answer: mean=x1+x2+⋯+xnn\text{mean}=\frac{x_1+x_2+\cdots+x_n}{n}mean=nx1​+x2​+⋯+xn​​. The arithmetic mean is the sum of all values divided by the number of values.

Flashcard 2: What is the mean of the data set 4,6,104, 6, 104,6,10?

Answer: 203\frac{20}{3}320​. Sum the values 4+6+10=204+6+10=204+6+10=20 and divide by 333 to find the average.

Flashcard 3: What is the mean of the data set 7,7,7,7,77, 7, 7, 7, 77,7,7,7,7?

Answer: 777. When all data points are identical, the mean equals that common value.

Flashcard 4: What is the mean of the data set 2,3,5,102, 3, 5, 102,3,5,10?

Answer: 555. Sum the values 2+3+5+10=202+3+5+10=202+3+5+10=20 and divide by 444 to compute the average.

Flashcard 5: What is the mean of the data set 1,2,3,4,101, 2, 3, 4, 101,2,3,4,10?

Answer: 444. Sum the values 1+2+3+4+10=201+2+3+4+10=201+2+3+4+10=20 and divide by 555 for the mean.

Flashcard 6: What is the mean of the data set 12,15,1812, 15, 1812,15,18?

Answer: 151515. Sum the values 12+15+18=4512+15+18=4512+15+18=45 and divide by 333 to obtain the mean.

Flashcard 7: What is the mean of the data set 0,5,10,150, 5, 10, 150,5,10,15?

Answer: 152\frac{15}{2}215​. Sum the values 0+5+10+15=300+5+10+15=300+5+10+15=30 and divide by 444 to find the average.

Flashcard 8: What is the mean of the data set −2,0,6-2, 0, 6−2,0,6?

Answer: 43\frac{4}{3}34​. Sum the values −2+0+6=4-2+0+6=4−2+0+6=4 and divide by 333 to calculate the mean.

Flashcard 9: What is the mean of the data set −3,−1,2,6-3, -1, 2, 6−3,−1,2,6?

Answer: 111. Sum the values −3+(−1)+2+6=4-3+(-1)+2+6=4−3+(−1)+2+6=4 and divide by 444 for the average.

Flashcard 10: Identify the mean of the data set 12,12,32\frac{1}{2}, \frac{1}{2}, \frac{3}{2}21​,21​,23​.

Answer: 56\frac{5}{6}65​. Sum the fractions 12+12+32=52\frac{1}{2}+\frac{1}{2}+\frac{3}{2}=\frac{5}{2}21​+21​+23​=25​ and divide by 333.

Flashcard 11: What is the mean of the data set 0.2,0.3,0.50.2, 0.3, 0.50.2,0.3,0.5?

Answer: 13\frac{1}{3}31​. Sum the decimals 0.2+0.3+0.5=1.00.2+0.3+0.5=1.00.2+0.3+0.5=1.0 and divide by 333 to find the mean.

Flashcard 12: State the formula for a weighted mean with values xix_ixi​ and weights wiw_iwi​.

Answer: weighted mean=∑wixi∑wi\text{weighted mean}=\frac{\sum w_i x_i}{\sum w_i}weighted mean=∑wi​∑wi​xi​​. The weighted mean is the sum of each value multiplied by its weight, divided by the total weight.

Flashcard 13: What is the weighted mean of 808080 (weight 222) and 909090 (weight 333)?

Answer: 868686. Compute (80×2+90×3)/(2+3)(80 \times 2 + 90 \times 3)/(2+3)(80×2+90×3)/(2+3) to account for the weights.

Flashcard 14: What is the weighted mean of scores 70,80,9070, 80, 9070,80,90 with weights 1,2,11, 2, 11,2,1?

Answer: 808080. Calculate (70×1+80×2+90×1)/(1+2+1)(70 \times 1 + 80 \times 2 + 90 \times 1)/(1+2+1)(70×1+80×2+90×1)/(1+2+1) using the given weights.

Flashcard 15: What is the mean if the sum of 888 numbers is 606060?

Answer: 152\frac{15}{2}215​. Divide the total sum 606060 by the number of values 888 to find the average.

Flashcard 16: What is the sum of a data set with mean 121212 and 555 values?

Answer: 606060. Multiply the mean 121212 by the number of values 555 to obtain the total sum.

Flashcard 17: A set has mean 101010 for 666 numbers. What is the new mean after adding 161616?

Answer: 767\frac{76}{7}776​. Original sum is 10×6=6010 \times 6 = 6010×6=60; add 161616 for new sum 767676, divide by 777.

Flashcard 18: A set has mean 888 for 555 numbers. What is the new mean after removing a value of 333?

Answer: 374\frac{37}{4}437​. Original sum is 8×5=408 \times 5 = 408×5=40; subtract 333 for new sum 373737, divide by 444.

Flashcard 19: A set has mean 999 for 444 numbers. What value must be added to make the new mean 101010?

Answer: 141414. Original sum is 9×4=369 \times 4 = 369×4=36; for new mean 101010 with 555 numbers, new sum is 505050, so add 141414.

Flashcard 20: The mean of 555 numbers is 666. Four numbers are 4,5,7,84, 5, 7, 84,5,7,8. What is the fifth number?

Answer: 666. Total sum is 6×5=306 \times 5 = 306×5=30; subtract sum of known numbers 4+5+7+8=244+5+7+8=244+5+7+8=24 to find the fifth.

Flashcard 21: What is the mean of consecutive integers 5,6,7,8,95, 6, 7, 8, 95,6,7,8,9?

Answer: 777. Sum the integers 5+6+7+8+9=355+6+7+8+9=355+6+7+8+9=35 and divide by 555 for the mean.

Flashcard 22: What is the mean of the consecutive integers from 111 to 999 inclusive?

Answer: 555. The mean of consecutive integers from 111 to 999 is the middle value, which is 555.

Flashcard 23: State the mean of two numbers aaa and bbb using a formula.

Answer: a+b2\frac{a+b}{2}2a+b​. The mean of two numbers is their sum divided by 222.

Flashcard 24: Find and correct the mean: For 2,4,6,82, 4, 6, 82,4,6,8, a student wrote 2+4+6+83=7\frac{2+4+6+8}{3}=732+4+6+8​=7.

Answer: 2+4+6+84=5\frac{2+4+6+8}{4}=542+4+6+8​=5. The student divided by 333 instead of 444; correct by using the proper count of values.