Comparing Fractions - ISEE Lower Level: Quantitative Reasoning
Card 1 of 24
Which option is greatest: $frac{14}{27}$ or $frac{1}{2}$?
Which option is greatest: $frac{14}{27}$ or $frac{1}{2}$?
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$\frac{14}{27}$. Cross-multiplying yields $14 \times 2 = 28 > 1 \times 27 = 27$, so $\frac{14}{27}$ is greater.
$\frac{14}{27}$. Cross-multiplying yields $14 \times 2 = 28 > 1 \times 27 = 27$, so $\frac{14}{27}$ is greater.
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Which option is greatest: $frac{12}{25}$ or $frac{5}{11}$?
Which option is greatest: $frac{12}{25}$ or $frac{5}{11}$?
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$\frac{12}{25}$. Cross-multiplying shows $12 \times 11 = 132 > 5 \times 25 = 125$, confirming $\frac{12}{25}$ is greater.
$\frac{12}{25}$. Cross-multiplying shows $12 \times 11 = 132 > 5 \times 25 = 125$, confirming $\frac{12}{25}$ is greater.
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Which option is greatest: $frac{8}{9}$ or $frac{15}{16}$?
Which option is greatest: $frac{8}{9}$ or $frac{15}{16}$?
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$\frac{15}{16}$. Cross-multiplying results in $8 \times 16 = 128 < 15 \times 9 = 135$, confirming $\frac{15}{16}$ is greater.
$\frac{15}{16}$. Cross-multiplying results in $8 \times 16 = 128 < 15 \times 9 = 135$, confirming $\frac{15}{16}$ is greater.
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Which option is greatest: $frac{3}{10}$ or $frac{7}{20}$?
Which option is greatest: $frac{3}{10}$ or $frac{7}{20}$?
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$\frac{7}{20}$. Converting to twentieths yields $\frac{3}{10} = \frac{6}{20} < \frac{7}{20}$, or cross-multiplying $3 \times 20 = 60 < 7 \times 10 = 70$.
$\frac{7}{20}$. Converting to twentieths yields $\frac{3}{10} = \frac{6}{20} < \frac{7}{20}$, or cross-multiplying $3 \times 20 = 60 < 7 \times 10 = 70$.
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Which option is greatest: $frac{2}{9}$ or $frac{1}{4}$?
Which option is greatest: $frac{2}{9}$ or $frac{1}{4}$?
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$\frac{1}{4}$. Cross-multiplying gives $2 \times 4 = 8 < 1 \times 9 = 9$, indicating $\frac{1}{4}$ is greater.
$\frac{1}{4}$. Cross-multiplying gives $2 \times 4 = 8 < 1 \times 9 = 9$, indicating $\frac{1}{4}$ is greater.
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Which option is greatest: $frac{7}{15}$ or $frac{9}{20}$?
Which option is greatest: $frac{7}{15}$ or $frac{9}{20}$?
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$\frac{7}{15}$. Cross-multiplying results in $7 \times 20 = 140 > 9 \times 15 = 135$, indicating $\frac{7}{15}$ is greater.
$\frac{7}{15}$. Cross-multiplying results in $7 \times 20 = 140 > 9 \times 15 = 135$, indicating $\frac{7}{15}$ is greater.
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Which option is greatest: $frac{10}{21}$ or $frac{1}{2}$?
Which option is greatest: $frac{10}{21}$ or $frac{1}{2}$?
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$\frac{1}{2}$. Cross-multiplying yields $10 \times 2 = 20 < 1 \times 21 = 21$, so $\frac{1}{2}$ is greater.
$\frac{1}{2}$. Cross-multiplying yields $10 \times 2 = 20 < 1 \times 21 = 21$, so $\frac{1}{2}$ is greater.
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Which option is greatest: $frac{9}{14}$ or $frac{5}{7}$?
Which option is greatest: $frac{9}{14}$ or $frac{5}{7}$?
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$\frac{5}{7}$. Cross-multiplying gives $9 \times 7 = 63 < 5 \times 14 = 70$, confirming $\frac{5}{7}$ is greater.
$\frac{5}{7}$. Cross-multiplying gives $9 \times 7 = 63 < 5 \times 14 = 70$, confirming $\frac{5}{7}$ is greater.
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Which option is greatest: $frac{5}{14}$ or $frac{3}{7}$?
Which option is greatest: $frac{5}{14}$ or $frac{3}{7}$?
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$\frac{3}{7}$. Converting to fourteenths gives $\frac{3}{7} = \frac{6}{14} > \frac{5}{14}$, or cross-multiplying $5 \times 7 = 35 < 3 \times 14 = 42$.
$\frac{3}{7}$. Converting to fourteenths gives $\frac{3}{7} = \frac{6}{14} > \frac{5}{14}$, or cross-multiplying $5 \times 7 = 35 < 3 \times 14 = 42$.
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Which option is greatest: $frac{1}{2}$ or $frac{4}{9}$?
Which option is greatest: $frac{1}{2}$ or $frac{4}{9}$?
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$\frac{1}{2}$. Cross-multiplying yields $1 \times 9 = 9 > 4 \times 2 = 8$, so $\frac{1}{2}$ is greater.
$\frac{1}{2}$. Cross-multiplying yields $1 \times 9 = 9 > 4 \times 2 = 8$, so $\frac{1}{2}$ is greater.
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Which option is greatest: $frac{6}{11}$ or $frac{7}{13}$?
Which option is greatest: $frac{6}{11}$ or $frac{7}{13}$?
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$\frac{6}{11}$. Cross-multiplying shows $6 \times 13 = 78 > 7 \times 11 = 77$, indicating $\frac{6}{11}$ is greater.
$\frac{6}{11}$. Cross-multiplying shows $6 \times 13 = 78 > 7 \times 11 = 77$, indicating $\frac{6}{11}$ is greater.
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Which option is greatest: $frac{4}{9}$ or $frac{4}{11}$?
Which option is greatest: $frac{4}{9}$ or $frac{4}{11}$?
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$\frac{4}{9}$. With the same numerator, $\frac{4}{9}$ is greater because its smaller denominator divides the whole into fewer parts, making each part larger.
$\frac{4}{9}$. With the same numerator, $\frac{4}{9}$ is greater because its smaller denominator divides the whole into fewer parts, making each part larger.
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Which option is greatest: $frac{3}{7}$ or $frac{5}{7}$?
Which option is greatest: $frac{3}{7}$ or $frac{5}{7}$?
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$\frac{5}{7}$. With the same denominator, $\frac{5}{7}$ is greater because its numerator is larger, representing more sevenths.
$\frac{5}{7}$. With the same denominator, $\frac{5}{7}$ is greater because its numerator is larger, representing more sevenths.
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Which option is greatest: $frac{7}{12}$ or $frac{5}{8}$?
Which option is greatest: $frac{7}{12}$ or $frac{5}{8}$?
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$\frac{5}{8}$. Cross-multiplying yields $7 \times 8 = 56 < 5 \times 12 = 60$, confirming $\frac{5}{8}$ is greater.
$\frac{5}{8}$. Cross-multiplying yields $7 \times 8 = 56 < 5 \times 12 = 60$, confirming $\frac{5}{8}$ is greater.
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Which option is greatest: $frac{2}{3}$ or $frac{3}{5}$?
Which option is greatest: $frac{2}{3}$ or $frac{3}{5}$?
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$\frac{2}{3}$. Cross-multiplying gives $2 \times 5 = 10 > 3 \times 3 = 9$, so $\frac{2}{3}$ is greater.
$\frac{2}{3}$. Cross-multiplying gives $2 \times 5 = 10 > 3 \times 3 = 9$, so $\frac{2}{3}$ is greater.
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What method compares $frac{a}{b}$ and $frac{c}{d}$ by comparing $ad$ and $bc$ (with $b,d>0$)?
What method compares $frac{a}{b}$ and $frac{c}{d}$ by comparing $ad$ and $bc$ (with $b,d>0$)?
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Cross-multiply: compare $ad$ and $bc$. This method determines which fraction is larger by comparing the cross products $ad$ and $bc$, where if $ad > bc$ then $\frac{a}{b} > \frac{c}{d}$ for positive denominators.
Cross-multiply: compare $ad$ and $bc$. This method determines which fraction is larger by comparing the cross products $ad$ and $bc$, where if $ad > bc$ then $\frac{a}{b} > \frac{c}{d}$ for positive denominators.
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What is the rule for comparing $frac{a}{b}$ and $frac{c}{b}$ when denominators are equal and $b>0$?
What is the rule for comparing $frac{a}{b}$ and $frac{c}{b}$ when denominators are equal and $b>0$?
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Greater numerator gives the greater fraction. When denominators are identical and positive, the fraction with the larger numerator represents a greater value since it takes a bigger portion of the same whole.
Greater numerator gives the greater fraction. When denominators are identical and positive, the fraction with the larger numerator represents a greater value since it takes a bigger portion of the same whole.
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What is the rule for comparing $frac{a}{b}$ and $frac{a}{d}$ when numerators are equal and $b,d>0$?
What is the rule for comparing $frac{a}{b}$ and $frac{a}{d}$ when numerators are equal and $b,d>0$?
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Smaller denominator gives the greater fraction. When numerators are identical and denominators positive, the fraction with the smaller denominator is larger because the whole is divided into fewer parts.
Smaller denominator gives the greater fraction. When numerators are identical and denominators positive, the fraction with the smaller denominator is larger because the whole is divided into fewer parts.
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Which option is greatest: $frac{5}{6}$ or $frac{6}{7}$?
Which option is greatest: $frac{5}{6}$ or $frac{6}{7}$?
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$\frac{6}{7}$. Cross-multiplying shows $5 \times 7 = 35 < 6 \times 6 = 36$, so $\frac{6}{7}$ is greater.
$\frac{6}{7}$. Cross-multiplying shows $5 \times 7 = 35 < 6 \times 6 = 36$, so $\frac{6}{7}$ is greater.
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Which option is greatest: $frac{9}{10}$ or $frac{17}{20}$?
Which option is greatest: $frac{9}{10}$ or $frac{17}{20}$?
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$\frac{9}{10}$. Converting to twentieths gives $\frac{9}{10} = \frac{18}{20} > \frac{17}{20}$, or cross-multiplying $9 \times 20 = 180 > 17 \times 10 = 170$.
$\frac{9}{10}$. Converting to twentieths gives $\frac{9}{10} = \frac{18}{20} > \frac{17}{20}$, or cross-multiplying $9 \times 20 = 180 > 17 \times 10 = 170$.
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Which option is greatest: $frac{11}{15}$ or $frac{3}{4}$?
Which option is greatest: $frac{11}{15}$ or $frac{3}{4}$?
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$\frac{3}{4}$. Cross-multiplying results in $11 \times 4 = 44 < 3 \times 15 = 45$, indicating $\frac{3}{4}$ is greater.
$\frac{3}{4}$. Cross-multiplying results in $11 \times 4 = 44 < 3 \times 15 = 45$, indicating $\frac{3}{4}$ is greater.
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Which option is greatest: $frac{13}{18}$ or $frac{7}{9}$?
Which option is greatest: $frac{13}{18}$ or $frac{7}{9}$?
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$\frac{7}{9}$. Cross-multiplying gives $13 \times 9 = 117 < 7 \times 18 = 126$, so $\frac{7}{9}$ is greater.
$\frac{7}{9}$. Cross-multiplying gives $13 \times 9 = 117 < 7 \times 18 = 126$, so $\frac{7}{9}$ is greater.
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Which option is greatest: $frac{4}{5}$ or $frac{13}{15}$?
Which option is greatest: $frac{4}{5}$ or $frac{13}{15}$?
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$\frac{13}{15}$. Cross-multiplying shows $4 \times 15 = 60 < 13 \times 5 = 65$, so $\frac{13}{15}$ is greater.
$\frac{13}{15}$. Cross-multiplying shows $4 \times 15 = 60 < 13 \times 5 = 65$, so $\frac{13}{15}$ is greater.
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Which option is greatest: $frac{5}{12}$ or $frac{3}{8}$?
Which option is greatest: $frac{5}{12}$ or $frac{3}{8}$?
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$\frac{5}{12}$. Cross-multiplying yields $5 \times 8 = 40 > 3 \times 12 = 36$, confirming $\frac{5}{12}$ is greater.
$\frac{5}{12}$. Cross-multiplying yields $5 \times 8 = 40 > 3 \times 12 = 36$, confirming $\frac{5}{12}$ is greater.
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