Optics - GRE Subject Test: Physics
Card 1 of 24
A beam of light travels through a medium with index of refraction 
until it reaches an interface with another material, with index of refraction 
. No light is transmitted into the second material. At what angle (measured from the plane of the interface between the two materials) does the beam hit the second material?
A beam of light travels through a medium with index of refraction
Tap to reveal answer
Total internal reflection occurs at the angle:
However, this angle is measured from a line normal to the plane of the interface; the angle we want, therefore, is 
, which is 
.
Total internal reflection occurs at the angle:
However, this angle is measured from a line normal to the plane of the interface; the angle we want, therefore, is
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A beam of light travels through a medium with index of refraction until it reaches an interface with another material, with index of refraction . No light is transmitted into the second material. At what angle (measured from the plane of the interface between the two materials) does the beam hit the second material?
A beam of light travels through a medium with index of refraction
Tap to reveal answer
Total internal reflection occurs at the angle:
However, this angle is measured from a line normal to the plane of the interface; the angle we want, therefore, is , which is .
Total internal reflection occurs at the angle:
However, this angle is measured from a line normal to the plane of the interface; the angle we want, therefore, is
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The focal length of a thin convex lens is 
. A candle is placed 
to the left of the lens. Approximately where is the image of the candle?
The focal length of a thin convex lens is
Tap to reveal answer
Because the object is beyond 2 focal lengths of the lens, the image must be between 1 and 2 focal lengths on the opposite side. Therefore, the image must be between 
on the right side of the lens.
Alternatively, one can apply the thin lens equation:
Where 
is the object distance 
and 
is the focal length 
. Plug in these values and solve.
Because the object is beyond 2 focal lengths of the lens, the image must be between 1 and 2 focal lengths on the opposite side. Therefore, the image must be between
Alternatively, one can apply the thin lens equation:
Where
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A candle 
tall is placed 
to the left of a thin convex lens with focal length 
. What is the height and orientation of the image created?
A candle
Tap to reveal answer
First, find the image distance 
from the thin lens equation:
Magnification of a lens is given by:
Where 
and 
are the image height and object height, respectively. The given object height is 
, which we can use to solve for the image height:
Because the sign is negative, the image is inverted.
First, find the image distance
Magnification of a lens is given by:
Where
Because the sign is negative, the image is inverted.
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Sirius is a binary star system, consisting of two white dwarfs with an angular separation of 3 arcseconds. What is the approximate minimum diameter lens needed to resolve the two stars in Sirius for an observation at 
?
Sirius is a binary star system, consisting of two white dwarfs with an angular separation of 3 arcseconds. What is the approximate minimum diameter lens needed to resolve the two stars in Sirius for an observation at
Tap to reveal answer
The Rayleigh Criterion gives the diffraction limit on resolution of a particular lens at a particular wavelength:
Where theta is the angular resolution in radians, 
is the wavelength of light, and 
is the diameter the lens in question. Solving for 
and converting 3 arcseconds into radians, one can approximate the diameter to be about 
:
The Rayleigh Criterion gives the diffraction limit on resolution of a particular lens at a particular wavelength:
Where theta is the angular resolution in radians,
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A beam of unpolarized light passes through two linear polarizers whose polarization axes are at an angle theta with each other. The light initially has an intensity 
, and has an intensity of 
after passing through both polarizes. Find 
?
A beam of unpolarized light passes through two linear polarizers whose polarization axes are at an angle theta with each other. The light initially has an intensity
Tap to reveal answer
Initially unpolarized light passing though a linear polarizer decreases in intensity by a factor of two:
Malus's Law gives the change in intensity of polarized light passing through a linear polarizer in terms of the change in angle of polarization:
Combining the two equations, we get:
Solving for 
:
Initially unpolarized light passing though a linear polarizer decreases in intensity by a factor of two:
Malus's Law gives the change in intensity of polarized light passing through a linear polarizer in terms of the change in angle of polarization:
Combining the two equations, we get:
Solving for
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The focal length of a thin convex lens is . A candle is placed to the left of the lens. Approximately where is the image of the candle?
The focal length of a thin convex lens is
Tap to reveal answer
Because the object is beyond 2 focal lengths of the lens, the image must be between 1 and 2 focal lengths on the opposite side. Therefore, the image must be between on the right side of the lens.
Alternatively, one can apply the thin lens equation:
Where is the object distance and is the focal length . Plug in these values and solve.
Because the object is beyond 2 focal lengths of the lens, the image must be between 1 and 2 focal lengths on the opposite side. Therefore, the image must be between
Alternatively, one can apply the thin lens equation:
Where
← Didn't Know|Knew It →
A candle tall is placed to the left of a thin convex lens with focal length . What is the height and orientation of the image created?
A candle
Tap to reveal answer
First, find the image distance from the thin lens equation:
Magnification of a lens is given by:
Where and are the image height and object height, respectively. The given object height is , which we can use to solve for the image height:
Because the sign is negative, the image is inverted.
First, find the image distance
Magnification of a lens is given by:
Where
Because the sign is negative, the image is inverted.
← Didn't Know|Knew It →
Sirius is a binary star system, consisting of two white dwarfs with an angular separation of 3 arcseconds. What is the approximate minimum diameter lens needed to resolve the two stars in Sirius for an observation at ?
Sirius is a binary star system, consisting of two white dwarfs with an angular separation of 3 arcseconds. What is the approximate minimum diameter lens needed to resolve the two stars in Sirius for an observation at
Tap to reveal answer
The Rayleigh Criterion gives the diffraction limit on resolution of a particular lens at a particular wavelength:
Where theta is the angular resolution in radians, is the wavelength of light, and is the diameter the lens in question. Solving for and converting 3 arcseconds into radians, one can approximate the diameter to be about :
The Rayleigh Criterion gives the diffraction limit on resolution of a particular lens at a particular wavelength:
Where theta is the angular resolution in radians,
← Didn't Know|Knew It →
The focal length of a thin convex lens is . A candle is placed to the left of the lens. Approximately where is the image of the candle?
The focal length of a thin convex lens is
Tap to reveal answer
Because the object is beyond 2 focal lengths of the lens, the image must be between 1 and 2 focal lengths on the opposite side. Therefore, the image must be between on the right side of the lens.
Alternatively, one can apply the thin lens equation:
Where is the object distance and is the focal length . Plug in these values and solve.
Because the object is beyond 2 focal lengths of the lens, the image must be between 1 and 2 focal lengths on the opposite side. Therefore, the image must be between
Alternatively, one can apply the thin lens equation:
Where
← Didn't Know|Knew It →
A candle tall is placed to the left of a thin convex lens with focal length . What is the height and orientation of the image created?
A candle
Tap to reveal answer
First, find the image distance from the thin lens equation:
Magnification of a lens is given by:
Where and are the image height and object height, respectively. The given object height is , which we can use to solve for the image height:
Because the sign is negative, the image is inverted.
First, find the image distance
Magnification of a lens is given by:
Where
Because the sign is negative, the image is inverted.
← Didn't Know|Knew It →
Sirius is a binary star system, consisting of two white dwarfs with an angular separation of 3 arcseconds. What is the approximate minimum diameter lens needed to resolve the two stars in Sirius for an observation at ?
Sirius is a binary star system, consisting of two white dwarfs with an angular separation of 3 arcseconds. What is the approximate minimum diameter lens needed to resolve the two stars in Sirius for an observation at
Tap to reveal answer
The Rayleigh Criterion gives the diffraction limit on resolution of a particular lens at a particular wavelength:
Where theta is the angular resolution in radians, is the wavelength of light, and is the diameter the lens in question. Solving for and converting 3 arcseconds into radians, one can approximate the diameter to be about :
The Rayleigh Criterion gives the diffraction limit on resolution of a particular lens at a particular wavelength:
Where theta is the angular resolution in radians,
← Didn't Know|Knew It →
A beam of light travels through a medium with index of refraction until it reaches an interface with another material, with index of refraction . No light is transmitted into the second material. At what angle (measured from the plane of the interface between the two materials) does the beam hit the second material?
A beam of light travels through a medium with index of refraction
Tap to reveal answer
Total internal reflection occurs at the angle:
However, this angle is measured from a line normal to the plane of the interface; the angle we want, therefore, is , which is .
Total internal reflection occurs at the angle:
However, this angle is measured from a line normal to the plane of the interface; the angle we want, therefore, is
← Didn't Know|Knew It →
The focal length of a thin convex lens is . A candle is placed to the left of the lens. Approximately where is the image of the candle?
The focal length of a thin convex lens is
Tap to reveal answer
Because the object is beyond 2 focal lengths of the lens, the image must be between 1 and 2 focal lengths on the opposite side. Therefore, the image must be between on the right side of the lens.
Alternatively, one can apply the thin lens equation:
Where is the object distance and is the focal length . Plug in these values and solve.
Because the object is beyond 2 focal lengths of the lens, the image must be between 1 and 2 focal lengths on the opposite side. Therefore, the image must be between
Alternatively, one can apply the thin lens equation:
Where
← Didn't Know|Knew It →
A candle tall is placed to the left of a thin convex lens with focal length . What is the height and orientation of the image created?
A candle
Tap to reveal answer
First, find the image distance from the thin lens equation:
Magnification of a lens is given by:
Where and are the image height and object height, respectively. The given object height is , which we can use to solve for the image height:
Because the sign is negative, the image is inverted.
First, find the image distance
Magnification of a lens is given by:
Where
Because the sign is negative, the image is inverted.
← Didn't Know|Knew It →
Sirius is a binary star system, consisting of two white dwarfs with an angular separation of 3 arcseconds. What is the approximate minimum diameter lens needed to resolve the two stars in Sirius for an observation at ?
Sirius is a binary star system, consisting of two white dwarfs with an angular separation of 3 arcseconds. What is the approximate minimum diameter lens needed to resolve the two stars in Sirius for an observation at
Tap to reveal answer
The Rayleigh Criterion gives the diffraction limit on resolution of a particular lens at a particular wavelength:
Where theta is the angular resolution in radians, is the wavelength of light, and is the diameter the lens in question. Solving for and converting 3 arcseconds into radians, one can approximate the diameter to be about :
The Rayleigh Criterion gives the diffraction limit on resolution of a particular lens at a particular wavelength:
Where theta is the angular resolution in radians,
← Didn't Know|Knew It →
A reflective sphere has a diameter of 
. The surface of the sphere makes a convex spherical mirror; what is its focal point?
A reflective sphere has a diameter of
Tap to reveal answer
The focal length of a spherical mirror is one half of the radius, which is one quarter of the diameter. In the case of convex mirrors, the focal point is considered behind the surface, which gives the answer its negative sign.
The focal length of a spherical mirror is one half of the radius, which is one quarter of the diameter. In the case of convex mirrors, the focal point is considered behind the surface, which gives the answer its negative sign.
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A reflective sphere has a diameter of . The surface of the sphere makes a convex spherical mirror; what is its focal point?
A reflective sphere has a diameter of
Tap to reveal answer
The focal length of a spherical mirror is one half of the radius, which is one quarter of the diameter. In the case of convex mirrors, the focal point is considered behind the surface, which gives the answer its negative sign.
The focal length of a spherical mirror is one half of the radius, which is one quarter of the diameter. In the case of convex mirrors, the focal point is considered behind the surface, which gives the answer its negative sign.
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A beam of unpolarized light passes through two linear polarizers whose polarization axes are at an angle theta with each other. The light initially has an intensity , and has an intensity of after passing through both polarizes. Find ?
A beam of unpolarized light passes through two linear polarizers whose polarization axes are at an angle theta with each other. The light initially has an intensity
Tap to reveal answer
Initially unpolarized light passing though a linear polarizer decreases in intensity by a factor of two:
Malus's Law gives the change in intensity of polarized light passing through a linear polarizer in terms of the change in angle of polarization:
Combining the two equations, we get:
Solving for :
Initially unpolarized light passing though a linear polarizer decreases in intensity by a factor of two:
Malus's Law gives the change in intensity of polarized light passing through a linear polarizer in terms of the change in angle of polarization:
Combining the two equations, we get:
Solving for
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A beam of light travels through a medium with index of refraction until it reaches an interface with another material, with index of refraction . No light is transmitted into the second material. At what angle (measured from the plane of the interface between the two materials) does the beam hit the second material?
A beam of light travels through a medium with index of refraction
Tap to reveal answer
Total internal reflection occurs at the angle:
However, this angle is measured from a line normal to the plane of the interface; the angle we want, therefore, is , which is .
Total internal reflection occurs at the angle:
However, this angle is measured from a line normal to the plane of the interface; the angle we want, therefore, is
← Didn't Know|Knew It →