How to find the area of a right triangle

Help Questions

GRE Quantitative Reasoning › How to find the area of a right triangle

Questions 1 - 6
1

What is the area of a right triangle with hypotenuse of 13 and base of 12?

25

30

60

78

156

Explanation

Area = 1/2(base)(height). You could use Pythagorean theorem to find the height or, if you know the special right triangles, recognize the 5-12-13. The area = 1/2(12)(5) = 30.

2

Quantitative Comparison

Quantity A: the area of a right triangle with sides 10, 24, 26

Quantity B: twice the area of a right triangle with sides 5, 12, 13

Quantity A is greater.

Quantity B is greater.

The two quantities are equal.

The relationship cannot be determined from the information given.

Explanation

Quantity A: area = base * height / 2 = 10 * 24 / 2 = 120

Quantity B: 2 * area = 2 * base * height / 2 = base * height = 5 * 12 = 60

Therefore Quantity A is greater.

3

Quantitative Comparison

Gre_quant_171_01

Column A

Area

Column B

Perimeter

  

Column A is greater

Column B is greater

Column A and B are equal

Cannot be determined

Explanation

To find the perimeter, add up the sides, here 5 + 12 + 13 = 30. To find the area, multiply the two legs together and divide by 2, here (5 * 12)/2 = 30.

4

Gre_quant_179_01

Given triangle ACE where B is the midpoint of AC, what is the area of triangle ABD?

96

48

72

24

Explanation

If B is a midpoint of AC, then we know AB is 12. Moreover, triangles ACE and ABD share angle DAB and have right angles which makes them similar triangles. Thus, their sides will all be proportional, and BD is 4. 1/2bh gives us 1/2 * 12 * 4, or 24.

5

Quantitative Comparison

Quantity A: The area of a triangle with a height of 6 and a base of 7

Quantity B: Half the area of a trapezoid with a height of 6, a base of 6, and another base of 10

Quantity A is greater.

Quantity B is greater.

The two quantities are equal.

The relationship cannot be determined from the information given.

Explanation

Quantity A: Area = 1/2 * b * h = 1/2 * 6 * 7 = 42/2 = 21

Quantity B: Area = 1/2 * (_b_1 + _b_2) * h = 1/2 * (6 + 10) * 6 = 48

Half of the area = 48/2 = 24

Quantity B is greater.

6

The radius of the circle is 2. What is the area of the shaded equilateral triangle?

Capture3

\dpi{100} \small 3\sqrt{3}

\dpi{100} \small 2\sqrt{2}

\dpi{100} \small \pi \sqrt{3}

\dpi{100} \small \pi \sqrt{2}

\dpi{100} \small 3\pi

Explanation

This is easier to see when the triangle is divided into six parts (blue). Each one contains an angle which is half of 120 degrees and contains a 90 degree angle. This means each triangle is a 30/60/90 triangle with its long side equal to the radius of the circle. Knowing that means that the height of each triangle is \dpi{100} \small \frac{r\sqrt{3}}{2} and the base is \dpi{100} \small \frac{r}{2}.

Applying \dpi{100} \small \frac{bh}{2} and multiplying by 6 gives \dpi{100} \small 3\sqrt{3}).

Capture4

Return to subject