How to subtract decimals - GRE Quantitative Reasoning

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Question

Quantity A:

Quantity B:

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Answer

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

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Question

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=?$

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Answer

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses:

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=$

$0.327+\left($\frac{3}{8}$-(2.224)\right)$

Convert the fraction to a decimal and once again complete the operations inside the parentheses:

$$\frac{3}{8}$=0.375$

The answer is .

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Question

Solve for :

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Answer

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

← Didn't Know|Knew It →

Question

Quantity A:

Quantity B:

Tap to reveal answer

Answer

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

← Didn't Know|Knew It →

Question

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=?$

Tap to reveal answer

Answer

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses:

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=$

$0.327+\left($\frac{3}{8}$-(2.224)\right)$

Convert the fraction to a decimal and once again complete the operations inside the parentheses:

$$\frac{3}{8}$=0.375$

The answer is .

← Didn't Know|Knew It →

Question

Solve for :

Tap to reveal answer

Answer

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

← Didn't Know|Knew It →

Question

Quantity A:

Quantity B:

Tap to reveal answer

Answer

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

← Didn't Know|Knew It →

Question

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=?$

Tap to reveal answer

Answer

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses:

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=$

$0.327+\left($\frac{3}{8}$-(2.224)\right)$

Convert the fraction to a decimal and once again complete the operations inside the parentheses:

$$\frac{3}{8}$=0.375$

The answer is .

← Didn't Know|Knew It →

Question

Solve for :

Tap to reveal answer

Answer

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

← Didn't Know|Knew It →

Question

Quantity A:

Quantity B:

Tap to reveal answer

Answer

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

← Didn't Know|Knew It →

Question

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=?$

Tap to reveal answer

Answer

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses:

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=$

$0.327+\left($\frac{3}{8}$-(2.224)\right)$

Convert the fraction to a decimal and once again complete the operations inside the parentheses:

$$\frac{3}{8}$=0.375$

The answer is .

← Didn't Know|Knew It →

Question

Solve for :

Tap to reveal answer

Answer

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

← Didn't Know|Knew It →

Question

Quantity A:

Quantity B:

Tap to reveal answer

Answer

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

← Didn't Know|Knew It →

Question

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=?$

Tap to reveal answer

Answer

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses:

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=$

$0.327+\left($\frac{3}{8}$-(2.224)\right)$

Convert the fraction to a decimal and once again complete the operations inside the parentheses:

$$\frac{3}{8}$=0.375$

The answer is .

← Didn't Know|Knew It →

Question

Solve for :

Tap to reveal answer

Answer

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

← Didn't Know|Knew It →

Question

Quantity A:

Quantity B:

Tap to reveal answer

Answer

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

← Didn't Know|Knew It →

Question

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=?$

Tap to reveal answer

Answer

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses:

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=$

$0.327+\left($\frac{3}{8}$-(2.224)\right)$

Convert the fraction to a decimal and once again complete the operations inside the parentheses:

$$\frac{3}{8}$=0.375$

The answer is .

← Didn't Know|Knew It →

Question

Solve for :

Tap to reveal answer

Answer

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

← Didn't Know|Knew It →

Question

Quantity A:

Quantity B:

Tap to reveal answer

Answer

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

← Didn't Know|Knew It →

Question

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=?$

Tap to reveal answer

Answer

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses:

$0.327+\left($\frac{3}{8}$-(0.048+2.176)\right)=$

$0.327+\left($\frac{3}{8}$-(2.224)\right)$

Convert the fraction to a decimal and once again complete the operations inside the parentheses:

$$\frac{3}{8}$=0.375$

The answer is .

← Didn't Know|Knew It →

Knew It

How to subtract decimals - GRE Quantitative Reasoning

Quantity A: Quantity B:

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses: Convert the fraction to a decimal and once again complete the operations inside the parentheses: The answer is .

Solve for :

To solve for , subtract from both sides of the equation. , therefore, . If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A: Quantity B:

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses: Convert the fraction to a decimal and once again complete the operations inside the parentheses: The answer is .

Solve for :

To solve for , subtract from both sides of the equation. , therefore, . If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A: Quantity B:

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses: Convert the fraction to a decimal and once again complete the operations inside the parentheses: The answer is .

Solve for :

To solve for , subtract from both sides of the equation. , therefore, . If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A: Quantity B:

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses: Convert the fraction to a decimal and once again complete the operations inside the parentheses: The answer is .

Solve for :

To solve for , subtract from both sides of the equation. , therefore, . If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A: Quantity B:

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses: Convert the fraction to a decimal and once again complete the operations inside the parentheses: The answer is .

Solve for :

To solve for , subtract from both sides of the equation. , therefore, . If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A: Quantity B:

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses: Convert the fraction to a decimal and once again complete the operations inside the parentheses: The answer is .

Solve for :

To solve for , subtract from both sides of the equation. , therefore, . If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A: Quantity B:

Use the values of .5 and 2 as possible x values. If x = 2, Quantity A is positive and greater, but if x = .5, Quantity A is negative and therefore smaller. As such, the relationship cannot be determined.

Make sure to follow the order of operations. Begin by combining all terms inside the parentheses: Convert the fraction to a decimal and once again complete the operations inside the parentheses: The answer is .

Quantity A:

Quantity B:

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A:

Quantity B:

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A:

Quantity B:

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A:

Quantity B:

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A:

Quantity B:

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A:

Quantity B:

To solve for , subtract from both sides of the equation. , therefore, .

If you have trouble subtracting the decimals, you can multiply both of them by to get whole numbers, then subtract as normal, then divide your result by .

Quantity A:

Quantity B: