How to find the square of an integer - GRE Quantitative Reasoning
Card 0 of 24
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Compare your answer with the correct one above
Quantity A: 9
Quantity B: √(25 + 55)
Quantity A: 9
Quantity B: √(25 + 55)
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
Compare your answer with the correct one above
Quantity A: $x^{2}$
Quantity B: 399
Quantity A: $x^{2}$
Quantity B: 399
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Compare your answer with the correct one above
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Compare your answer with the correct one above
Quantity A: 9
Quantity B: √(25 + 55)
Quantity A: 9
Quantity B: √(25 + 55)
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
Compare your answer with the correct one above
Quantity A: $x^{2}$
Quantity B: 399
Quantity A: $x^{2}$
Quantity B: 399
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Compare your answer with the correct one above
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Compare your answer with the correct one above
Quantity A: 9
Quantity B: √(25 + 55)
Quantity A: 9
Quantity B: √(25 + 55)
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
Compare your answer with the correct one above
Quantity A: $x^{2}$
Quantity B: 399
Quantity A: $x^{2}$
Quantity B: 399
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Compare your answer with the correct one above
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Compare your answer with the correct one above
Quantity A: 9
Quantity B: √(25 + 55)
Quantity A: 9
Quantity B: √(25 + 55)
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
Compare your answer with the correct one above
Quantity A: $x^{2}$
Quantity B: 399
Quantity A: $x^{2}$
Quantity B: 399
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Compare your answer with the correct one above
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Compare your answer with the correct one above
Quantity A: 9
Quantity B: √(25 + 55)
Quantity A: 9
Quantity B: √(25 + 55)
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
Compare your answer with the correct one above
Quantity A: $x^{2}$
Quantity B: 399
Quantity A: $x^{2}$
Quantity B: 399
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Compare your answer with the correct one above
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Compare your answer with the correct one above
Quantity A: 9
Quantity B: √(25 + 55)
Quantity A: 9
Quantity B: √(25 + 55)
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
Compare your answer with the correct one above
Quantity A: $x^{2}$
Quantity B: 399
Quantity A: $x^{2}$
Quantity B: 399
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Since x is between 10 and 20, it can be any real number between 100 and 400. Therefore, the relationship cannot be determined since x could fall anywhere between these two limits, including between 399 and 400.
Compare your answer with the correct one above
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Neither x nor y is equal to 0.
xy = 4y/x
Quantity A: x
Quantity B: 2
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Given xy = 4y/x and x and y not 0.
Therefore you are able to divide both sides by 'y' such that:
x = 4/x
Multiply both sides by x:
x2 = 4 or x = +2 or –2.
Because of the fact that x could equal –2, the relationship cannot be determined from the information given.
Compare your answer with the correct one above
Quantity A: 9
Quantity B: √(25 + 55)
Quantity A: 9
Quantity B: √(25 + 55)
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
In order to determine the relationship between Quantity A and Quantity B, let's convert both to square roots. In order to do this, we must square Quantity A so it becomes √81 which is equivalent to 9. Now to Quantity B, we must simplify by adding the two values together (25 + 55) to get √80.
√81 is greater than the √80 because 81 is greater than 80. Thus Quantity A is greater.
Compare your answer with the correct one above