How to add negative numbers - GRE Quantitative Reasoning

The answer is $2x^{4}$+9

Make sure to distribute negatives throughout the second half of the equation.

$(7+x+3x^{4}$$)-(x^{4}$+x-2)

$(3x^{4}$$+x+7)+(-x^{4}$-x+2)

$2x^{4}$+9

To solve this problem, first you must add to both sides of the problem. This will yield a result on the right side of the equation of , because a negative number added to a negative number will create a lower number (i.e. further away from zero, and still negative). Then you divide both sides by two, and you are left with .

The answer is $2x^{4}$+9

Make sure to distribute negatives throughout the second half of the equation.

$(7+x+3x^{4}$$)-(x^{4}$+x-2)

$(3x^{4}$$+x+7)+(-x^{4}$-x+2)

$2x^{4}$+9

To solve this problem, you need to get your variable isolated on one side of the equation:

Taking this step will elminate the on the side with :

Now divide by to solve for :

The important step here is to be able to add the negative numbers. When you add negative numbers, they create lower negative numbers (if you prefer to think about it another way, you can think of adding negative numbers as subtracting one of the negative numbers from the other).

To solve this problem, first you must add to both sides of the problem. This will yield a result on the right side of the equation of , because a negative number added to a negative number will create a lower number (i.e. further away from zero, and still negative). Then you divide both sides by two, and you are left with .

The answer is $2x^{4}$+9

Make sure to distribute negatives throughout the second half of the equation.

$(7+x+3x^{4}$$)-(x^{4}$+x-2)

$(3x^{4}$$+x+7)+(-x^{4}$-x+2)

$2x^{4}$+9

To solve this problem, you need to get your variable isolated on one side of the equation:

Taking this step will elminate the on the side with :

Now divide by to solve for :

The important step here is to be able to add the negative numbers. When you add negative numbers, they create lower negative numbers (if you prefer to think about it another way, you can think of adding negative numbers as subtracting one of the negative numbers from the other).

To solve this problem, first you must add to both sides of the problem. This will yield a result on the right side of the equation of , because a negative number added to a negative number will create a lower number (i.e. further away from zero, and still negative). Then you divide both sides by two, and you are left with .

The answer is $2x^{4}$+9

Make sure to distribute negatives throughout the second half of the equation.

$(7+x+3x^{4}$$)-(x^{4}$+x-2)

$(3x^{4}$$+x+7)+(-x^{4}$-x+2)

$2x^{4}$+9

To solve this problem, you need to get your variable isolated on one side of the equation:

Taking this step will elminate the on the side with :

Now divide by to solve for :

The important step here is to be able to add the negative numbers. When you add negative numbers, they create lower negative numbers (if you prefer to think about it another way, you can think of adding negative numbers as subtracting one of the negative numbers from the other).

To solve this problem, first you must add to both sides of the problem. This will yield a result on the right side of the equation of , because a negative number added to a negative number will create a lower number (i.e. further away from zero, and still negative). Then you divide both sides by two, and you are left with .

The answer is $2x^{4}$+9

Make sure to distribute negatives throughout the second half of the equation.

$(7+x+3x^{4}$$)-(x^{4}$+x-2)

$(3x^{4}$$+x+7)+(-x^{4}$-x+2)

$2x^{4}$+9

To solve this problem, you need to get your variable isolated on one side of the equation:

Taking this step will elminate the on the side with :

Now divide by to solve for :

The important step here is to be able to add the negative numbers. When you add negative numbers, they create lower negative numbers (if you prefer to think about it another way, you can think of adding negative numbers as subtracting one of the negative numbers from the other).

To solve this problem, first you must add to both sides of the problem. This will yield a result on the right side of the equation of , because a negative number added to a negative number will create a lower number (i.e. further away from zero, and still negative). Then you divide both sides by two, and you are left with .

The answer is $2x^{4}$+9

Make sure to distribute negatives throughout the second half of the equation.

$(7+x+3x^{4}$$)-(x^{4}$+x-2)

$(3x^{4}$$+x+7)+(-x^{4}$-x+2)

$2x^{4}$+9

To solve this problem, you need to get your variable isolated on one side of the equation:

Taking this step will elminate the on the side with :

Now divide by to solve for :

The important step here is to be able to add the negative numbers. When you add negative numbers, they create lower negative numbers (if you prefer to think about it another way, you can think of adding negative numbers as subtracting one of the negative numbers from the other).

To solve this problem, first you must add to both sides of the problem. This will yield a result on the right side of the equation of , because a negative number added to a negative number will create a lower number (i.e. further away from zero, and still negative). Then you divide both sides by two, and you are left with .

The answer is $2x^{4}$+9

Make sure to distribute negatives throughout the second half of the equation.

$(7+x+3x^{4}$$)-(x^{4}$+x-2)

$(3x^{4}$$+x+7)+(-x^{4}$-x+2)

$2x^{4}$+9

To solve this problem, you need to get your variable isolated on one side of the equation:

Taking this step will elminate the on the side with :

Now divide by to solve for :

The important step here is to be able to add the negative numbers. When you add negative numbers, they create lower negative numbers (if you prefer to think about it another way, you can think of adding negative numbers as subtracting one of the negative numbers from the other).