GMAT Quantitative · Question of the Day

GMAT Quantitative Question of the Day

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Saturday, September 5, 2026

A box contains 10 balls: 4 red, 3 green, and 3 yellow. If 3 balls are drawn simultaneously, what is the probability that no two balls have the same color?

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Question of the Day

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A box contains 10 balls: 4 red, 3 green, and 3 yellow. If 3 balls are drawn simultaneously, what is the probability that no two balls have the same color?

  1. 310\frac{3}{10} (correct answer)
  2. 36120\frac{36}{120}
  3. 13\frac{1}{3}
  4. 25\frac{2}{5}

Explanation: For no two balls to have the same color, we need exactly one ball of each color. Ways to choose 1 red from 4: C(4,1) = 4. Ways to choose 1 green from 3: C(3,1) = 3. Ways to choose 1 yellow from 3: C(3,1) = 3. Total favorable outcomes = 4 × 3 × 3 = 36. Total ways to choose 3 balls from 10: C(10,3) = 120. Probability = 36/120 = 3/10. Choice B shows the unreduced fraction 36/120. Choice C (1/3) would result from 40/120. Choice D (2/5) would result from 48/120. The correct answer is A.