A box contains 10 balls: 4 red, 3 green, and 3 yellow. If 3 balls are drawn simultaneously, what is the probability that no two balls have the same color?
- (correct answer)
Explanation: For no two balls to have the same color, we need exactly one ball of each color. Ways to choose 1 red from 4: C(4,1) = 4. Ways to choose 1 green from 3: C(3,1) = 3. Ways to choose 1 yellow from 3: C(3,1) = 3. Total favorable outcomes = 4 × 3 × 3 = 36. Total ways to choose 3 balls from 10: C(10,3) = 120. Probability = 36/120 = 3/10. Choice B shows the unreduced fraction 36/120. Choice C (1/3) would result from 40/120. Choice D (2/5) would result from 48/120. The correct answer is A.