DSQ: Calculating an angle in a polygon - GMAT Quantitative

Information about the hexagon is irrelevant, so Statement 2 has no bearing on the answer to the question.

The measures of the exterior angles of any pentagon, one per vertex, total , and they are congruent if the pentagon is regular, so if this is the case, each would measure . But if Statement 1 is true, then an exterior angle of the pentagon measures . Therefore, Statement 1 is enough to answer the question in the negative.

The sum of the measures of the angles of a hexagon is

Therefore,

Suppose we only know that , , and are the first three terms of an arithmetic sequence, in order. Then for some common difference ,

Suppose we only know that . Then

With no further information, we cannot determine .

To show that the rhombus is a square, you need to demonstrate that one of its angles is a right angle - that is, . Both statements together are insufficent - if , you would need to demonstrate that is true or false, and the fact that the triangle is not equilateral is not enough to prove or to disprove this.

From Statement 1, you can calculate the measure of an interior angle as follows:

From Statement 2, since an interior angle and an exterior angle at the same vertex form a linear pair, they are supplementary, so you can subtract 18 from 180:

All of the interior angles of a regular polygon are congruent, as are all of its sides. Statement 1 violates the former condition; statement 2 violates the latter.

The sum of the degree measures of the exterior angles, one per vertex, of any polygon is 360, so each exterior angle of a regular polygon with sides measures .

For to be an integer, every factor of must be a factor of 360. This does not happen if 7 is a factor of , so Statement 1 disproves this. This may or may not happen if 10 is a factor of - , but , so Statement 2 does not provide an answer.

The sum of the degree measures of the exterior angles, one per vertex, of any polygon is 360, so each exterior angle of a regular polygon with sides measures . Therefore, the measure of one exterior angle of a regular polygon is an integer if and only if is a factor of 360.

If is a factor of a factor of 360, however, then is a factor of 360. 30 and 40 are both factors of 360: and . Therefore, it follows from either statement that the number of sides is a factor of 360, and each exterior angle has a degree measure that is an integer.

An exterior angle of an equilateral triangle measures . An interior angle of a regular hexagon measures . Either statement is sufficient.

Each angle of a regular nonagon measures

Therefore, each of the two statements proves that the nonagon is not regular.

If a shape is regular, that means that all of its sides are equal. It also means that all of its interior angles are equal. Finally, if all of the interior angles are equal, then the exterior angles will all be equal to each other as well.

In a regular polygon, we can find the measure of ANY exterior angle by using the formula

where is equal to the number of sides.

Each exterior angle of a regular (five-sided) pentagon measures

Statement 1 alone neither proves nor disproves that the pentagon is regular. We now know that one exterior angle is , but we do not know if any of the other exterior angles are also .

Statement 2, however, proves that the pentagon is not regular, as it has at least one exterior angle that does not have measure .

The sum of the measures of the six interior angles of any hexagon is , so if Statement 1 is true, then the sum of the six numbers is 720, regardless of the individual values.

Statement 2 is not enough, however, for us to deduce this sum; this only tells us the mean of the third- and fourth-highest values.

The sum of the measures of the five interior angles of any pentagon is , so if Statement 1 is true, then the sum of the five numbers is 540, regardless of the individual values.

The mean of five data values multiplied by 5 is the sum of the values, so if Statement 2 is true, then their sum is .

The relationship between the number of sides of a regular polygon and the measure of a single angle is

If we are given that , then we can substitute and solve for :

making the figure a nine-sided polygon.

Knowing only the measure of each side is neither necessary nor helpful; for example, it is possible to construct an equilateral triangle with sidelength 8 or a square with sidelength 8.

The correct answer is that Statement 1 alone is sufficient to answer the question, but not Statement 2 alone.

Information about the hexagon is irrelevant, so Statement 2 has no bearing on the answer to the question.

The measures of the exterior angles of any pentagon, one per vertex, total , and they are congruent if the pentagon is regular, so if this is the case, each would measure . But if Statement 1 is true, then an exterior angle of the pentagon measures . Therefore, Statement 1 is enough to answer the question in the negative.

The sum of the measures of the angles of a hexagon is

Therefore,

Suppose we only know that , , and are the first three terms of an arithmetic sequence, in order. Then for some common difference ,

Suppose we only know that . Then

With no further information, we cannot determine .

To show that the rhombus is a square, you need to demonstrate that one of its angles is a right angle - that is, . Both statements together are insufficent - if , you would need to demonstrate that is true or false, and the fact that the triangle is not equilateral is not enough to prove or to disprove this.

From Statement 1, you can calculate the measure of an interior angle as follows:

From Statement 2, since an interior angle and an exterior angle at the same vertex form a linear pair, they are supplementary, so you can subtract 18 from 180:

All of the interior angles of a regular polygon are congruent, as are all of its sides. Statement 1 violates the former condition; statement 2 violates the latter.

The sum of the degree measures of the exterior angles, one per vertex, of any polygon is 360, so each exterior angle of a regular polygon with sides measures .

For to be an integer, every factor of must be a factor of 360. This does not happen if 7 is a factor of , so Statement 1 disproves this. This may or may not happen if 10 is a factor of - , but , so Statement 2 does not provide an answer.