Calculating whether point is on a line with an equation - GMAT Quantitative

Card 1 of 48

0

Didn't Know

0

Didn't Know

Knew It

0

1 of 2019 left

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug into the variable of the equation and solve for :

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug 1 into the variable of the equation and solve for :

$x=\frac{1}{2}$$

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug into the variable of the equation and solve for :

← Didn't Know|Knew It →

Question

Consider segment $\overline{JK}$ which passes through the points $\left ( 4,5\right )$ and $\left ( 144,75\right )$ .

If the point $\left ( 16,y\right )$ is on $\overline{JK}$ , what is the value of y?

Tap to reveal answer

Answer

First, use the points to find the equation of JK:

Given that JK passes through (4,5) and (144,75) we can find the slope as follows:

Slope is found via:

$m=\frac{y'-y}{x'-x}$$

Plug in and calculate:

$\small \small m=\frac{75-5}{144-4}$=\frac{70}{140}$=\frac{1}{2}$$

Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).

$\small 5=\frac{1}{2}$*4+b$

$\small b=5-2=3$

So our answer is:

$\small y=\frac{x}{2}$+3$

To find y, we need to plug in 16 for x and solve:

$\small \small y=\frac{16}{2}$+3=8+3=11$

← Didn't Know|Knew It →

Question

If is defined as follows, is the point $\left ( -2,5\right )$ on ?

$\small f(x)=4x+13$

Tap to reveal answer

Answer

To find out if (-2,5) is on f(x), simply plug the point into f(x)

$\small f(x)=4x+13$

Becomes,

$\small \small 5=4*-2+13=-8+13=5$

So yes, it does!

← Didn't Know|Knew It →

Question

Which of the following are points along if

.

Tap to reveal answer

Answer

One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)

If we plug in 3 we get

,

So our point is (3,28).

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug into the variable of the equation and solve for :

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug 1 into the variable of the equation and solve for :

$x=\frac{1}{2}$$

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug into the variable of the equation and solve for :

← Didn't Know|Knew It →

Question

Consider segment $\overline{JK}$ which passes through the points $\left ( 4,5\right )$ and $\left ( 144,75\right )$ .

If the point $\left ( 16,y\right )$ is on $\overline{JK}$ , what is the value of y?

Tap to reveal answer

Answer

First, use the points to find the equation of JK:

Given that JK passes through (4,5) and (144,75) we can find the slope as follows:

Slope is found via:

$m=\frac{y'-y}{x'-x}$$

Plug in and calculate:

$\small \small m=\frac{75-5}{144-4}$=\frac{70}{140}$=\frac{1}{2}$$

Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).

$\small 5=\frac{1}{2}$*4+b$

$\small b=5-2=3$

So our answer is:

$\small y=\frac{x}{2}$+3$

To find y, we need to plug in 16 for x and solve:

$\small \small y=\frac{16}{2}$+3=8+3=11$

← Didn't Know|Knew It →

Question

If is defined as follows, is the point $\left ( -2,5\right )$ on ?

$\small f(x)=4x+13$

Tap to reveal answer

Answer

To find out if (-2,5) is on f(x), simply plug the point into f(x)

$\small f(x)=4x+13$

Becomes,

$\small \small 5=4*-2+13=-8+13=5$

So yes, it does!

← Didn't Know|Knew It →

Question

Which of the following are points along if

.

Tap to reveal answer

Answer

One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)

If we plug in 3 we get

,

So our point is (3,28).

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug into the variable of the equation and solve for :

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug 1 into the variable of the equation and solve for :

$x=\frac{1}{2}$$

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug into the variable of the equation and solve for :

← Didn't Know|Knew It →

Question

Consider segment $\overline{JK}$ which passes through the points $\left ( 4,5\right )$ and $\left ( 144,75\right )$ .

If the point $\left ( 16,y\right )$ is on $\overline{JK}$ , what is the value of y?

Tap to reveal answer

Answer

First, use the points to find the equation of JK:

Given that JK passes through (4,5) and (144,75) we can find the slope as follows:

Slope is found via:

$m=\frac{y'-y}{x'-x}$$

Plug in and calculate:

$\small \small m=\frac{75-5}{144-4}$=\frac{70}{140}$=\frac{1}{2}$$

Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).

$\small 5=\frac{1}{2}$*4+b$

$\small b=5-2=3$

So our answer is:

$\small y=\frac{x}{2}$+3$

To find y, we need to plug in 16 for x and solve:

$\small \small y=\frac{16}{2}$+3=8+3=11$

← Didn't Know|Knew It →

Question

If is defined as follows, is the point $\left ( -2,5\right )$ on ?

$\small f(x)=4x+13$

Tap to reveal answer

Answer

To find out if (-2,5) is on f(x), simply plug the point into f(x)

$\small f(x)=4x+13$

Becomes,

$\small \small 5=4*-2+13=-8+13=5$

So yes, it does!

← Didn't Know|Knew It →

Question

Which of the following are points along if

.

Tap to reveal answer

Answer

One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)

If we plug in 3 we get

,

So our point is (3,28).

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug into the variable of the equation and solve for :

← Didn't Know|Knew It →

Question

Solve for in the coordinate on line ?

Tap to reveal answer

Answer

To solve for for , we have to plug 1 into the variable of the equation and solve for :

$x=\frac{1}{2}$$

← Didn't Know|Knew It →

0

Knew It