The graph only provides information about how many students scored in each range (201-300, 301-400, etc.) on the test; it provides no information about the mean, median, or mode. The only question that can be answered is the number of students total who took the test - this can be answered by adding the numbers on top of the bars.

Let's look at the bar graph.

The bottom of the bar graph lists the different classes. The height of each bar displays a quantity that matches up with the scale on the left side. This quantity represents the number of students in that class.

You can either use the left scale to determine the number of students, or you can see the quantities posted on each bar.

So, we will find the bar that corresponds to Art class. We can see it is the 3rd class listed. Now, we can see that bar goes up to 21.

Therefore, the number of students in Art class is 21.

Recall that the mode in a set of data is the number that is repeated most often. For this question, this means that the mode number of pets owned will be the number that correlates to the most number of students. Since students do not own any pets, pets must be the mode.

The bar representing Japan will reflect a total energy usage of about ; since the first will be hidden due to the starting point of the vertical axis, the bar will only show

By similar reasoning, the bar representing India will only show

Through some rounding, we see that about Japan is represented by a bar about

as long as the bar that represents India.

From the graph, we can see that students do not have any pets.

We can see that students have just one pet. From these students, the class has pets.

Next, notice that students have pets. From these students, the class has pets.

Next, students have pets. From these students, the class has pets.

Then, students have pets. From these students, the class has pets.

Finally, students have pets. From these students, the class has pets.

To find the total number of pets owned by the students, add these values together:

40 students achieved a score of 501-600; 16 achieved a score of 601-700; 10 achieved a score of 701-800. Add these:

The number of students who took the test is the sum of the students who finished in the six ranges:

The question is now to find out what percent 66 is of 120, which can be calculated as follows:

By making a 673, Clarissa finished in the second-highest range shown (601-700). She was outscored by at least 10 students (the ones in the 701-800 range), but by at most 25 students (the 10 in the 701-800 range plus the other 15 in the 601-700 range). She finished between 11th and 26th, inclusive, so the only plausible choice is 14th.

Let's look at the bar graph.

We can see the months are listed along the bottom axis. We can also see the scale on the left ranges from 0 to 25. These numbers represent the number of enrollments.

Now, to find the approximate number of enrollments for April, we will first find April. We can see it is the last month listed.

Now, we can see the value of the bar is between 20 and 25. We can also see that it is fairly close to 20.

Therefore, we can approximate the number of enrollments for April is 21.

The median score at Wallace was 69, so Juanita scored above the median. By definition, she outscored at least half the seniors, which means that she must have outscored at least of them. The correct response must be greater than or equal to 94, and the only choice that fits that criterion is 105.

Let's look at the bar graph

To find the number of students in the largest class, we will essentially be looking at the class with the most students (or the class with the tallest bar).

We can see the class with the tallest bar is Art. We can see it has 31 students.

Therefore, the largest class has 31 students.