Bar Graphs - GED Math

Julio scored the highest of the three with 71, so we are looking for a high school whose median score was above 71. Of the four choices, only Garner fits this criterion.

The median score at Wallace was 69, so Juanita scored above the median. By definition, she outscored at least half the seniors, which means that she must have outscored at least of them. The correct response must be greater than or equal to 94, and the only choice that fits that criterion is 105.

Of the five schools, only Burr had median scores below 70 in both 2012 and 2013. The correct choice is "one".

Wallace, Gerry, and Burr all saw improvement, as the bars representing their 2013 median scores are longer than the ones for 2012. A visual inspection shows that the greatest difference is between the two bars representing Wallace High, so Wallace is the correct choice.

The number of students who scored in the 601-700 range is 16; in the 701-800 range, 10. Add them to get 26 students total.

The graph only provides information about how many students scored in each range (201-300, 301-400, etc.) on the test; it provides no information about the mean, median, or mode. The only question that can be answered is the number of students total who took the test - this can be answered by adding the numbers on top of the bars.

The lowest score is not indicated anywhere on the graph, so the question "What was the lowest score on the test?" is the one that cannot be answered. The other three can be determined, in part or completely, by adding the number of students in one or more ranges, and in two cases, also adding the number of students total.

40 students achieved a score of 501-600; 16 achieved a score of 601-700; 10 achieved a score of 701-800. Add these:

The number of students who took the test is the sum of the students who finished in the six ranges:

The question is now to find out what percent 66 is of 120, which can be calculated as follows:

By making a 673, Clarissa finished in the second-highest range shown (601-700). She was outscored by at least 10 students (the ones in the 701-800 range), but by at most 25 students (the 10 in the 701-800 range plus the other 15 in the 601-700 range). She finished between 11th and 26th, inclusive, so the only plausible choice is 14th.

students achieved scores between 200 and 500, and Yasmin outscored all of them.

students achieved scores between 200 and 600, but Yasmin did not outscore all of them.

Her score fell in the range between 501 and 600, so of the four choices, the only plausible score was 565.

Let's look at the bar graph.

The bottom of the bar graph lists the different classes. The height of each bar displays a quantity that matches up with the scale on the left side. This quantity represents the number of students in that class.

You can either use the left scale to determine the number of students, or you can see the quantities posted on each bar.

So, we will find the bar that corresponds to Art class. We can see it is the 3rd class listed. Now, we can see that bar goes up to 21.

Therefore, the number of students in Art class is 21.

Let's look at the bar graph.

We can see the months are listed along the bottom axis. We can also see the scale on the left ranges from 0 to 25. These numbers represent the number of enrollments.

Now, to find the approximate number of enrollments for April, we will first find April. We can see it is the last month listed.

Now, we can see the value of the bar is between 20 and 25. We can also see that it is fairly close to 20.

Therefore, we can approximate the number of enrollments for April is 21.

Let's look at the bar graph.

We can see the different pizza toppings on listed on the bottom. We can also see the number of people who like a specific pizza topping is shown on the bar.

Now, we want to find how many more people like cheese than pepperoni. To d that, we need to find the difference of those who like cheese and those who like pepperoni.

So, we can see cheese is the last topping listed. It shows 48 people. We can see pepperoni is the first topping listed. It shows 26 people like it.

Now, we will find the difference. We get

Therefore, 22 more people like cheese than pepperoni.

Let's look at the bar graph

To find the number of students in the largest class, we will essentially be looking at the class with the most students (or the class with the tallest bar).

We can see the class with the tallest bar is Art. We can see it has 31 students.

Therefore, the largest class has 31 students.

Let's look at the graph:

We can see the bars represent the number of enrollments in the 12th grade for different years.

To find the difference of enrollments from 2012 to 2015, we will first find the number of enrollments from those years, then we will subtract them.

So, we can see the number of enrollments in 2012 was 89. We can see the number of enrollments in 2015 was 148. Now, we subtract. We get

Therefore, the difference of 12th grade enrollments from 2012 to 2015 is 59.

Let's look at the graph.

To find the year with the most enrollments, we will find the year that has the tallest bar.

We can see the tallest bar shows 152 enrollments. It corresponds to the year 2016.

Therefore, the year with the most enrollments is 2016.

From the graph, we can see that students do not have any pets.

We can see that students have just one pet. From these students, the class has pets.

Next, notice that students have pets. From these students, the class has pets.

Next, students have pets. From these students, the class has pets.

Then, students have pets. From these students, the class has pets.

Finally, students have pets. From these students, the class has pets.

To find the total number of pets owned by the students, add these values together:

Recall how to find the average of a set of numbers:

Start by finding the total number of pets that the students in the class own.

From the graph, we can see that students do not have any pets.

We can see that students have just one pet. From these students, the class has pets.

Next, notice that students have pets. From these students, the class has pets.

Next, students have pets. From these students, the class has pets.

Then, students have pets. From these students, the class has pets.

Finally, students have pets. From these students, the class has pets.

To find the total number of pets owned by the students, add these values together:

Since we know that there are students, we can then find the average:

Recall that the mode in a set of data is the number that is repeated most often. For this question, this means that the mode number of pets owned will be the number that correlates to the most number of students. Since students do not own any pets, pets must be the mode.